Right SQL statement to get the late and OT of employees - sql

Question

Here is my sql query as of the moment:
select Employee_Number, Cast([DateTime] as Date) as 'DateTime', MIN([DateTime]) as 'MIN', MAX([DateTime]) as 'MAX' , [Hours Worked] =
CAST((DATEDIFF(HOUR ,min([DateTime]), max([DateTime])) / 24) AS VARCHAR) +
' Days ' +
CAST((DATEDIFF(HOUR , min([DateTime]), max([DateTime])) % 24) AS VARCHAR) +
' Hours ' +
CAST((DATEDIFF(MINUTE, min([DateTime]), max([DateTime])) % 60) AS VARCHAR) +
' Minutes ' +
CAST((DATEDIFF(SECOND, min([DateTime]), max([DateTime])) % 60) AS VARCHAR) +
' Seconds ' , [Over Time] = CAST((DATEDIFF(HOUR, '17:30:00:000', MAX([DateTime])) % 24) AS VARCHAR) + ' Hours ' +
CAST((DATEDIFF(MINUTE, '17:30:00:000', max([DateTime])) % 60) AS VARCHAR) + ' Minutes', [LATE] =
CAST((DATEDIFF(HOUR, '08:30:00:000',Min([DATETIME])) % 24) AS VARCHAR) + ' Hours ' + CAST((DATEDIFF(MINUTE, '08:30:00:000', MIN([DateTime])) % 60) AS VARCHAR) + ' Minutes'
from tblExtract group by Employee_Number, Cast([DateTime] as Date)
And this is what this query shows:
The problem arose if the employee entered early before 8:30 and if he leaves early as well before 17:30
How can I correct this? How Can I get a Case where if the Employee leaves or arrive early the LATE or Overtime Column would have a value of '0 hours 0 minutes'?

Answer 1

If you want to display '0 Hours 0 Minutes' if a person arrives/leaves early, you can use CASE for that.
select Employee_Number, Cast([DateTime] as Date) as 'DateTime', MIN([DateTime]) as 'MIN', MAX([DateTime]) as 'MAX' , [Hours Worked] =
CAST((DATEDIFF(HOUR ,min([DateTime]), max([DateTime])) / 24) AS VARCHAR) +
' Days ' +
CAST((DATEDIFF(HOUR , min([DateTime]), max([DateTime])) % 24) AS VARCHAR) +
' Hours ' +
CAST((DATEDIFF(MINUTE, min([DateTime]), max([DateTime])) % 60) AS VARCHAR) +
' Minutes ' +
CAST((DATEDIFF(SECOND, min([DateTime]), max([DateTime])) % 60) AS VARCHAR) +
' Seconds ' , [Over Time] = CASE WHEN DATEDIFF(MINUTE, '17:30:00:000', CONVERT(TIME, MAX([DateTime]))) < 0
THEN '0 Hours 0 Minutes'
ELSE
CAST((DATEDIFF(HOUR, '17:30:00:000', MAX([DateTime])) % 24) AS VARCHAR) + ' Hours ' +
CAST((DATEDIFF(MINUTE, '17:30:00:000', max([DateTime])) % 60) AS VARCHAR) + ' Minutes'
END,
[LATE] = CASE WHEN DATEDIFF(MINUTE, '08:30:00:000', CONVERT(TIME, MIN([DateTime]))) < 0
THEN '0 Hours 0 Minutes'
ELSE
CAST((DATEDIFF(HOUR, '08:30:00:000',Min([DATETIME])) % 24) AS VARCHAR) +
' Hours ' + CAST((DATEDIFF(MINUTE, '08:30:00:000', MIN([DateTime])) % 60) AS VARCHAR) + ' Minutes'
END
from Extraction
group by Employee_Number, Cast([DateTime] as Date)
SQL Fiddle demo