Get day of the week in month (2nd Tuesday, etc.) - sql

Question

I need an algorithm for calculating the number of the day of the week in the month. Like 1st Friday of the month, 3rd Monday of the month, etc.)
Any ideas are appreciated.
Here is the final result:
declare #dt date = GetDate()
declare #DayOfWeek tinyint = datepart(weekday,#dt)
declare #DayOfMonth smallint = day(#dt)
declare #FirstDayOfMonth date = dateadd(month,datediff(month,0,#dt),0)
declare #DayOfWeekInMonth tinyint = #DayOfMonth / 7 + 1 -
(case when day(#FirstDayOfMonth) > day(#dt) then 1 else 0 end)
declare #Suffix varchar(2) =
case
when #DayOfWeekInMonth = 1 then 'st'
when #DayOfWeekInMonth = 2 then 'nd'
when #DayOfWeekInMonth = 3 then 'rd'
when #DayOfWeekInMonth > 3 then 'th'
end
select
cast(#DayOfWeekInMonth as varchar(2))
+ #Suffix
+ ' '
+ datename(weekday,#Dt)
+ ' of '
+ datename(month,#dt)
+ ', '
+ datename(year,#Dt)
PS: And if you can think of a better way to state the problem, please do.

Answer 1

Followint code will give you 1st Wednesday of April 2014 for today:
SELECT cast((DATEPART(d, GETDATE() - 1) / 7) + 1 as varchar(12))
+ 'st ' + DATENAME(WEEKDAY, getdate()) + ' of ' +
DATENAME(month, getdate()) + ' ' + DATENAME(year, getdate());
For any date use the code below. It gives 5th Tuesday of April 2014 for #mydate = '2014-04-29' in the example:
DECLARE #mydate DATETIME;
SET #mydate = '2014-04-29';
SELECT
case
when DATEPART(d, #mydate) = 1 then cast((DATEPART(d, #mydate ) / 7) + 1 as varchar(12))
else cast((DATEPART(d, #mydate - 1) / 7) + 1 as varchar(12))
end
+
case
when (DATEPART(d, #mydate - 1) / 7) + 1 = 1 then 'st '
when (DATEPART(d, #mydate - 1) / 7) + 1 = 2 then 'nd '
when (DATEPART(d, #mydate - 1) / 7) + 1 = 3 then 'rd '
else 'th '
end
+ DATENAME(WEEKDAY, #mydate) + ' of ' +
DATENAME(month, #mydate) + ' ' + DATENAME(year, #mydate) as [Long Date Name]

Answer 2

Okeeeey my tuuuurn ,
Please rate my answer Metaphor hhh, Here's the cooode :
declare #v_month nvarchar(2) = '04'
,#v_annee nvarchar(4) = '2014'
declare #v_date date = convert(date,#v_annee+'-'+#v_month+'-01')
declare #v_date_2 date = dateadd(M,1,#v_date)
if OBJECT_ID('temp') is not null
drop table temp
create table temp(_date date, _DayOfMonth nvarchar(20), _order int)
while (#v_date<#v_date_2)
begin
set #v_date =#v_date;
WITH _DayOfWeek AS (
SELECT 1 id, 'monday' Name UNION ALL
SELECT 2 id, 'tuesday' Name UNION ALL
SELECT 3 id, 'wednesday' Name UNION ALL
SELECT 4 id, 'thursday' Name UNION ALL
SELECT 5 id, 'friday' Name UNION ALL
SELECT 6 id, 'saturday' Name UNION ALL
SELECT 7 id, 'sunday' Name)
insert into temp(_date,_DayOfMonth)
SELECT
#v_date
,(select Name from _DayOfWeek where id = DATEPART(WEEKDAY,#v_date))
SET #v_date = DATEADD(DAY,1,#v_date)
END
UPDATE tmp1
SET _order = _order_2
FROM temp tmp1
INNER JOIN
(SELECT *, ROW_NUMBER() OVER(PARTITION BY _DayOfMonth ORDER BY _date ASC) AS _order_2 FROM temp) tmp2
ON tmp1._date = tmp2._date
SELECT * FROM temp
SELECT *
FROM temp
WHERE _DayOfMonth = 'thursday'
AND _order = 3
I hope this will help you :)
Good Luck

Answer 3

OK, here's what I came up with, I'll +1 everyone who answered anyway:
declare #dt date = GetDate()
declare #DayOfWeek tinyint = datepart(weekday,#dt)
declare #DayOfMonth smallint = day(#dt)
declare #FirstDayOfMonth date = dateadd(month,datediff(month,0,#dt),0)
declare #DayOfWeekInMonth tinyint =
#DayOfMonth / 7 + 1
- (case when day(#FirstDayOfMonth) > day(#dt) then 1 else 0 end)
declare #Suffix varchar(2) =
case
when #DayOfWeekInMonth = 1 then 'st'
when #DayOfWeekInMonth = 2 then 'nd'
when #DayOfWeekInMonth = 3 then 'rd'
when #DayOfWeekInMonth > 3 then 'th'
end
select
cast(#DayOfWeekInMonth as varchar(2))
+ #Suffix
+ ' '
+ datename(weekday,#Dt)
+ ' of '
+ datename(month,#dt)
+ ', '
+ datename(year,#Dt)

Answer 4

declare #dt date = getdate()
declare #DayOfMonth smallint = datepart(d, #dt)
declare #Suffix varchar(2) =
case
when floor((#DayOfMonth - 1) / 7.0) = 0 then 'st' -- implies there were no such days previously in the month
when floor((#DayOfMonth - 1) / 7.0) = 1 then 'nd'
when floor((#DayOfMonth - 1) / 7.0) = 2 then 'rd'
else 'th'
end
select cast(floor((#DayOfMonth - 1) / 7.0) + 1 as varchar(1)) + #Suffix +
' ' + datename(weekday, #dt) + ' of ' + datename(month, #dt) +
', ' + datename(year, #dt)

Answer 5

DECLARE #dt DATETIME
SET #dt = DATEADD(d, 6, GETDATE())
SELECT #dt,
CAST((DAY(#dt) / 7) + CASE WHEN DATEPART(weekday, #dt) >= DATEPART(weekday, CAST(MONTH(#dt) AS NVARCHAR) + '/01/' + CAST(YEAR(#dt) AS NVARCHAR)) THEN 1 ELSE 0 END AS NVARCHAR)
+ '' + CASE (DAY(#dt) / 7) + CASE WHEN DATEPART(weekday, #dt) >= DATEPART(weekday, CAST(MONTH(#dt) AS NVARCHAR) + '/01/' + CAST(YEAR(#dt) AS NVARCHAR)) THEN 1 ELSE 0 END
WHEN 1 THEN N'st'
WHEN 2 THEN N'nd'
WHEN 3 THEN N'rd'
ELSE N'th'
END
+ ' ' + DATENAME(dw, #dt)
+ ' of ' + DATENAME(M, #dt)
+ ', ' + CAST(YEAR(#dt) AS NVARCHAR)
Result is a single SELECT (provided the assignment of #dt happened earlier) but is, essentially, the same logic as yours.

Answer 6

This following code will give you DATE for any day of the week in any month or year that you specify. All the variables that I have are to reduce repeating logic to improve code speed.
This code gives you date for 1st Monday in February in 2013
DECLARE #DayNumber INT = 1
,#DayWeekNumber INT = 2
,#MonthNumber INT = 2
,#YearNumber INT = 2013
,#FoM DATE
,#FoMWD INT;
SET #FoM = DATEFROMPARTS(#YearNumber,#MonthNumber,1)
SET #fomwd = DATEPART(WEEKDAY, #FoM);
SELECT CASE WHEN #fomwd = #DayWeekNumber THEN DATEADD(WEEK, #DayNumber - 1, #FoM)
WHEN #fomwd < #DayWeekNumber THEN DATEADD(DAY, #DayWeekNumber - #fomwd, DATEADD(WEEK, #DayNumber - 1, #FoM))
WHEN #fomwd > #DayWeekNumber THEN DATEADD(DAY, #DayWeekNumber - #fomwd, DATEADD(WEEK, #DayNumber, #FoM))
END AS DateOfDay;