My result of is like this
date acc cr date acc dr
---------------------------------------------------
null null 0 13/3/12 A 1300
null null 0 13/3/12 c 1200
null null 0 13/3/12 D 1100
13/3/12 A 1000 null null 0
18/3/12 E 2000 null null 0
19/3/12 F 3000 null null 0
31/3/12 G 3000 null null 0
this result i got from following query bu joining 2 tables to get cash book
select(case when mli.voucher_type = 1 THEN tav.voucher_date end)pdate,
(case when mli.voucher_type = 1 THEN mli.description end) acc,
(case when tav.voucher_type_id = 1 then sum(tvl.amount) else 0 end) cr,
(case when mli.voucher_type = 2 THEN tav.voucher_dateend) rdate,
(case when mli.voucher_type = 2 THEN mli.description end) acc,
(case when tav.voucher_type_id = 2 then sum(tvl.amount) else 0 end) dr
from t_acc_voucher tav
join t_voucher_ledger tvl on tvl.voucher_id = tav.voucher_id
join m_ledger_index mli on mli.ledger_index_id = tvl.ledger_index_id
group by mli.description, mli.voucher_type, tav.voucher_type_id,tav.voucher_date
I want result like this
date acc cr date acc dr
---------------------------------------------------
13/3/12 A 1000 13/3/12 A 1300
18/3/12 E 2000 13/3/12 c 1200
19/3/12 F 3000 13/3/12 D 1100
31/3/12 G 3000 null null 0
can any body help me.or give some suggestion is it write way to get it or i can try with 2 diffrent query.
thanks in advance
Break your query into two separate queries, one for credit and another for debit and do a full outer join based on descending date, you can order by any column in fact. From the original query, I assumed that VOUCHER_TYPE = 1 is credits and VOUCHER_TYPE = 2 is debit.
Try this (not tested)
with CREDITS as (select TAV.VOUCHER_DATE PDATE,
MLI.DESCRIPTION ACC,
(case when TAV.VOUCHER_TYPE_ID = 1 then SUM(TVL.AMOUNT) else 0 end) CR
from t_acc_voucher tav
join t_voucher_ledger tvl
on tvl.voucher_id = tav.voucher_id
join M_LEDGER_INDEX MLI
on MLI.LEDGER_INDEX_ID = TVL.LEDGER_INDEX_ID
where MLI.VOUCHER_TYPE = 1
group by MLI.DESCRIPTION,
MLI.VOUCHER_TYPE,
TAV.VOUCHER_TYPE_ID,
TAV.VOUCHER_DATE),
debits as (select TAV.VOUCHER_DATE RDATE,
MLI.DESCRIPTION ACC,
(case when TAV.VOUCHER_TYPE_ID = 2 then SUM(TVL.AMOUNT) else 0 end) DR
from T_ACC_VOUCHER TAV
where mli.voucher_type = 2
join t_voucher_ledger tvl
on tvl.voucher_id = tav.voucher_id
join M_LEDGER_INDEX MLI
on MLI.LEDGER_INDEX_ID = TVL.LEDGER_INDEX_ID
group by MLI.DESCRIPTION,
MLI.VOUCHER_TYPE,
TAV.VOUCHER_TYPE_ID,
TAV.VOUCHER_DATE )
select T1.PDATE, T1.ACC, T1.CR, T2.RDATE, T2.ACC, T2.DR
from (select a.*, row_number() over (order by a.PDATE) RN
from credits a) T1
full outer join
select b.*, row_number() over (order by b.RDATE) RN
from debits b) T2
on (t1.rn = t2.rn);
select t1.date1, t1.acc1, t1.cr, t2.date2, t2.acc2, t2.dr
from (the table or query) t1
join (the table or query) t2 on t1.acc1=t2.acc2
where t1.acc1 is not null
we join the same query (or table) twice joinint to itself by acc.
Related
I have two tables:
list_table:
id
name
1
a
2
b
3
c
vt_table:
id
list_id
amount
direction_id
1
1
20
1
2
1
12
2
3
1
15
1
4
2
23
1
5
1
20
1
6
1
20
2
7
1
18
1
I need this result:
amount (dir_id = 1 - dir_id = 2), list_id
amount
list_id
41
1
23
2
0
3
Amount is sum of all amount fields in table vt_table where direction_id = 1 minus sum of all amount fileds in table vt_table where direction_id = 2
And I need group this calculations by list_id, and if table have no rows with list_id 3, as example, amount must be 0.
I'm trying to do it with this query:
SELECT vt.list_id
, ((SELECT COALESCE(SUM(vt.amount), 0)
FROM table_name vt
WHERE vt.direction_id = 1)
-
(SELECT COALESCE(SUM(vt.amount), 0)
FROM table_name vt
WHERE direction_id = 2)) AS result
FROM table_name vt
GROUP BY vt.list_id
But I don't know how to group it correctly and make it so that if there were no entries for some list_id, then the amount was 0 for this list_id.
I use PostgreSQL 12.
Here the examples
You can try to use OUTER JOIN with condition aggregate function with COALESCE fucntion.
Query 1:
SELECT l.id,
SUM(COALESCE(CASE WHEN vt.direction_id = 1 THEN vt.amount END,0)) -
SUM(COALESCE(CASE WHEN vt.direction_id = 2 THEN vt.amount END,0)) AS result
FROM table_name vt
RIGHT JOIN list l ON vt.list_id = l.id
GROUP BY l.id
ORDER BY l.id
Results:
| id | result |
|----|--------|
| 1 | 41 |
| 2 | 23 |
| 3 | 0 |
Try something like this, as a start:
SELECT vt.list_id
, COALESCE(SUM(CASE WHEN direction_id = 1 THEN amount END), 0)
- COALESCE(SUM(CASE WHEN direction_id = 2 THEN amount END), 0) AS result
FROM table_name vt
GROUP BY vt.list_id
;
Result using your fiddle:
list_id
result
1
41
2
23
This just misses the cases where there are no vt rows for some list.
Use an outer join to address those cases.
SELECT SUM(CASE WHEN vt.direction_id = 1 THEN vt.amount ELSE 0 END) - SUM(CASE WHEN vt.direction_id = 2 THEN vt.amount ELSE 0 END) as amount,
lt.id as list_id
FROM list_table lt
LEFT OUTER JOIN vt_table vt
ON lt.id = vt.list_id
GROUP BY lt.id
ORDER BY lt.id
I need to select/concat data from 2 tables in SQL Server I'm using Left Join, but the data is returned as multiple records.
Below are the sample tables
Table1
Id Name Age
1 Sk 20
2 Rb 30
Table2
ID Bike Price Table1Id
1 RX 200 1
2 CD 250 1
3 FZ 300 1
4 R1 400 2
The desired output is
ID Name Age Bike1 Price1 Bike2 Price2 Bike3 Price3
1 Sk 20 RX 200 CD 250 FZ 300
2 Rb 30 R1 400 NULL NULL NULL NULL
A sample format of the query I'm using
SELECT A.ID, A.Name, B.Bike, B.Price FROM Table1 A LEFT JOIN Table2 B ON
A.id = B.Table1Id order by A.id
The output I'm getting from the above query is
ID Name Age Bike Price
1 Sk 20 RX 200
1 Sk 20 CD 250
1 Sk 20 FZ 300
2 Rb 30 R1 400
I need the data as one record for a particular ID and not multiple records (As seen in the desired output). Tired using offset, but offset will return only limited result not the entire records.
Any suggestions on how this can be achieved?
If you know the maximum number of bikes per person, you can use conditional aggregation:
SELECT ID, Name,
MAX(CASE WHEN seqnm = 1 THEN Bike END) as bike_1,
MAX(CASE WHEN seqnm = 1 THEN Price END) as price_1,
MAX(CASE WHEN seqnm = 2 THEN Bike END) as bike_2,
MAX(CASE WHEN seqnm = 2 THEN Price END) as price_2,
MAX(CASE WHEN seqnm = 3 THEN Bike END) as bike_3,
MAX(CASE WHEN seqnm = 3 THEN Price END) as price_3
FROM (SELECT A.ID, A.Name, B.Bike, B.Price,
ROW_NUMBER() OVER (PARTITION BY A.id ORDER BY B.Price) as seqnum
FROM Table1 A LEFT JOIN
Table2 B
ON A.id = B.Table1Id
) ab
GROUP BY ID, Name,
ORDER BY id
I have the following code that looks at the SalesVol of different products and groups it by transaction_week
SELECT a.transaction_week,
SUM(CASE WHEN record_type IN (6,37,13) THEN quantity ELSE 0 END) as SalesVol
FROM table 1 a
LEFT JOIN table 2 b ON b.Date = a.transaction_date
LEFT JOIN table 3 c ON c.sku = a.product
WHERE series in (62,236,501,52)
GROUP BY a.transaction_week
ORDER BY a.transaction_week
| tw | SalesVol |
| 1 | 4768 |
| 2 | 4567 |
| 3 | 4354 |
| 4 | 4678 |
I want to be able to have multiple subqueries where I change the series numbers for example.
SELECT a.transaction_week,
(SELECT SUM(CASE WHEN record_type IN (6,37,13) THEN quantity ELSE 0 END) as SalesVol
FROM table 1 a
LEFT JOIN table 2 b ON b.Date = a.transaction_date
LEFT JOIN table 3 c ON c.sku = a.product
WHERE series in (62,236,501,52)) as personal care
(SELECT SUM(CASE WHEN record_type IN (6,37,13) THEN quantity ELSE 0 END) as SalesVol
FROM table 1 a
LEFT JOIN table 2 b ON b.Date = a.transaction_date
LEFT JOIN table 3 c ON c.sku = a.product
WHERE series in (37,202,203,456)) as white goods
FROM table 1 a
LEFT JOIN table 2 b ON b.Date = a.transaction_date
LEFT JOIN table 3 c ON c.sku = a.product
GROUP BY a.transaction_week
ORDER BY a.transaction_week
I can't get the subqueries at work as it is giving me the overall sum value and not grouping it by transaction_week
Instead of using subqueries, add series to the condition of the CASE statements:
SELECT a.transaction_week,
sum(CASE WHEN series IN (62,236,501,52) AND record_type IN (6,37,13)
THEN quantity ELSE 0 END) as personal_care,
sum(CASE WHEN series IN (37,202,203,456) AND record_type IN (6,37,13)
THEN quantity ELSE 0 END) as white_goods
FROM table 1 a
LEFT JOIN table 2 b ON b.Date = a.transaction_date
LEFT JOIN table 3 c ON c.sku = a.product
GROUP BY a.transaction_week
ORDER BY a.transaction_week;
You just miss the a.transaction_week in you subquery. The JOIN in outer query is unneccessary.
SELECT a.transaction_week,
(
SELECT SUM(CASE WHEN record_type IN (6,37,13) THEN quantity ELSE 0 END) as SalesVol
FROM table 1 a2
LEFT JOIN table 2 b ON b.Date = a2.transaction_date
LEFT JOIN table 3 c ON c.sku = a2.product
WHERE series in (62,236,501,52) AND a2.transaction_week = a.transaction_week
) as personal care,
(
SELECT SUM(CASE WHEN record_type IN (6,37,13) THEN quantity ELSE 0 END) as SalesVol
FROM table 1 a 2
LEFT JOIN table 2 b ON b.Date = a2.transaction_date
LEFT JOIN table 3 c ON c.sku = a2.product
WHERE series in (37,202,203,456) AND a2.transaction_week = a.transaction_week
) as white goods
FROM table 1 a
GROUP BY a.transaction_week
ORDER BY a.transaction_week
Try this it would work fast as well as up to your requirement:
SELECT a.transaction_week ,
whitegoods.SalesVol AS 'White Goods' ,
personalcare.SalesVol1 AS 'Personal Care'
FROM table1 a
LEFT JOIN table2 b ON b.[Date] = a.transaction_date
LEFT JOIN table3 c ON c.sku = a.product
CROSS APPLY ( SELECT SUM(CASE WHEN record_type IN ( 6, 37, 13 )
THEN quantity
ELSE 0
END) AS SalesVol
FROM table1 a2
WHERE b.[Date] = a2.transaction_date
AND c.sku = a2.product
AND series IN ( 37, 202, 203, 456 )
AND a2.transaction_week = a.transaction_week
) whitegoods
CROSS APPLY ( SELECT SUM(CASE WHEN record_type IN ( 6, 37, 13 )
THEN quantity
ELSE 0
END) AS SalesVol1
FROM table1 a2
WHERE b.[Date] = a2.transaction_date
AND c.sku = a2.product
AND series IN ( 62, 236, 501, 52 )
AND a2.transaction_week = a.transaction_week
) personalcare
GROUP BY a.transaction_week
ORDER BY a.transaction_week
You should use the UNION operator. Please refer to the query below:
select a.transaction_week, SalesVol from
(SELECT a.transaction_week as transaction_week,
SUM(CASE WHEN record_type IN (6,37,13) THEN quantity ELSE 0 END) as SalesVol
FROM table 1 a
LEFT JOIN table 2 b ON b.Date = a.transaction_date
LEFT JOIN table 3 c ON c.sku = a.product
WHERE series in (62,236,501,52)
UNION
SELECT a.transaction_week as transaction_week,
SUM(CASE WHEN record_type IN (6,37,13) THEN quantity ELSE 0 END) as SalesVol
FROM table 1 a
LEFT JOIN table 2 b ON b.Date = a.transaction_date
LEFT JOIN table 3 c ON c.sku = a.product
WHERE series in (37,202,203,456)
) AS tbl1
GROUP BY tbl1.transaction_week
ORDER BY tbl1.transaction_week
I have two tables as below:
Invoice
InvId | Amount | Name
-----------------------
1 | 50 | John
2 | 30 | Mike
3 | 20 | John
Detail
MetalType| Weight | InvId
-------------------------
Gold | 2 | 2
Silver | 4 | 3
Silver | 3 | 3
Gold | 5 | 1
I would like to have the following output, but my query will only provide the total for silver and gold for John. How can I build a query that will also include the total invoice amount for John.
Total Invoice Amount For John = 70
Total Silver Weight = 7
total Gold Weith = 5
SELECT
SUM(IFF(D.MetalType=”Gold”, D.Weight, 0)) AS TotGold,
SUM((IFF(D.MetalType=”Silver”, D.Weight, 0)) AS TotSilver
FROM Invoice I INNER JOIN Detail D ON I.InvId = D.InvId WHERE I.Name = “John”
Try this:
For Sql-Server:
SELECT
SUM(TotalAmount) AS TotalAmount,
SUM(TotGold) AS TotGold,
SUM(TotSilver) AS TotSilver
FROM(
SELECT
SUM (I.Amount) OVER (Partition by D.Invid) AS TotalAmount,
SUM(CASE WHEN D.MetalType='Gold' THEN D.Weight ELSE 0 END) AS TotGold,
SUM(CASE WHEN D.MetalType='Silver' THEN D.Weight ELSE 0 END) AS TotSilver
FROM Invoice I INNER JOIN Detail D ON I.InvId = D.InvId
WHERE I.Name = 'John'
GROUP BY D.InvId, I.Amount) n
Here is an SQL Fiddle - now it kills the duplicate detail and counts it only once.
EDITED for Access:
SELECT
n.Name,
MAX(TotalAmount),
SUM(TotGold) AS TotGold,
SUM(TotSilver) AS TotSilver
FROM(
SELECT
I.Name,
SUM(CASE WHEN D.MetalType='Gold' THEN D.Weight ELSE 0 END) AS TotGold,
SUM(CASE WHEN D.MetalType='Silver' THEN D.Weight ELSE 0 END) AS TotSilver
FROM Invoice I
INNER JOIN Detail D ON I.InvId = D.InvId
GROUP BY I.Name, D.InvId, I.Amount) n
INNER JOIN (
SELECT
I.Name, SUM (I.Amount) AS TotalAmount
FROM Invoice I
GROUP BY I.Name) m ON m.Name = n.Name
GROUP BY n.Name
Try with this:
With tbl3 (Amt,Gold,Silver)
as
(
SELECT
SUM (I.Amount) OVER (Partition by D.Invid) AS TotalAmount,
SUM(CASE WHEN D.MetalType='Gold' THEN D.Weight ELSE 0 END) AS TotGold,
SUM(CASE WHEN D.MetalType='Silver' THEN D.Weight ELSE 0 END) AS TotSilver
FROM Invoice I Right JOIN Detail D ON I.InvId = D.InvId
WHERE I.Name = 'John' Group by D.InvId, I.Amount
)
Select SUM(Amt) as Total_Invoice_Amount_For_John,
SUM(Gold) as Total_Silver_Weight,
SUM(Silver) as Total_Gold_Width from tbl3
SQL Fiddle
I havent tried out the other queries already posted and they might already be suitable for what you want but here's my take on it :-
SELECT X.NAME, X.METALTYPE, X.WEIGHT, Y.TOTAL
FROM
(SELECT NAME, METALTYPE, SUM(Weight) AS WEIGHT
FROM INVOICE i
INNER JOIN DETAIL d ON i.InvId = d.InvId
GROUP BY NAME, METALTYPE) X
INNER JOIN
(SELECT SUM(AMOUNT) AS Total, NAME
FROM INVOICE
GROUP BY NAME)Y
ON X.NAME = Y.NAME
ORDER BY NAME, TOTAL, METALTYPE
select name, sum(Amount) as 'total invoice',sum(Gold) as 'Gold',sum(Silver) as Silver from(
select aa.Name,aa.Amount,
sum(case when bb.MetalType='Gold' then bb.Weight else 0 end) as 'Gold',
sum(case when bb.MetalType='Silver' then bb.Weight else 0 end) as 'Silver'
from a aa left outer join b bb on aa.InvID=bb.InvID group by aa.InvID) as c group by c.name
I have two tables. Table A has an id column. Table B has an Aid column and a type column. Example data:
A: id
--
1
2
B: Aid | type
----+-----
1 | 1
1 | 1
1 | 3
1 | 1
1 | 4
1 | 5
1 | 4
2 | 2
2 | 4
2 | 3
I want to get all the IDs from table A where there is a certain amount of type 1 and type 3 actions. My query looks like this:
SELECT id
FROM A
WHERE (SELECT COUNT(type)
FROM B
WHERE B.Aid = A.id
AND B.type = 1) = 3
AND (SELECT COUNT(type)
FROM B
WHERE B.Aid = A.id
AND B.type = 3) = 1
so on the data above, just the id 1 should be returned.
Can I combine the 2 subqueries somehow? The goal is to make the query run faster.
Does postgres support CTEs?
WITH counts (Counts, Type, Aid) as (
select count(type), type
from b group by Type, Aid
)
select id
from A
join Counts B1 on b1.Aid = a.id and b1.type = 1
join Counts B3 on b3.Aid = a.id and b3.type = 3
where
b1.counts = 3 and b3.counts = 1
I'd suggest comparing the execution plans, but I suspect it would be similar since everything should get collapsed before execution.
Select ...
From A
Join (
Select B.Id
, Sum ( Case When B.Type = 1 Then 1 Else 0 End ) As Type1Count
, Sum ( Case When B.Type = 3 Then 1 Else 0 End ) As Type3Count
From B
Where B.Type In(1,3)
Group By B.Id
) As Z
On Z.Id = A.Id
Where Z.Type1Count = 3
And Z.Type3Count = 1
This works in TSQL, does it work in Postgres?
SELECT A.ID
FROM A
WHERE A.ID in
(
SELECT AID
FROM B
GROUP BY AID
HAVING
SUM(CASE WHEN Type = 1 THEN 1 ELSE 0 END) = 3
OR SUM(CASE WHEN Type = 3 THEN 1 ELSE 0 END) = 1
)
Another alternative:
SELECT DISTINCT Aid FROM (
SELECT Aid,type,count(*) as n from B
GROUP BY Aid,type, ) as g
WHERE ( g.n=1 AND g.type = 3 )
OR ( g.n=3 AND g.type = 1 )
I doubt this will perform better than your original, though.
You seem to be doing the best strategy: counting only the candidate rows.
Perhaps some redundant prefiltering might help:
SELECT DISTINCT Aid FROM (
SELECT Aid,type,count(*) as n from B
WHERE g.type = 3 OR g.type = 1 -- prefilter
GROUP BY Aid,type, ) as g
WHERE ( g.n=1 AND g.type = 3 )
OR ( g.n=3 AND g.type = 1 )