Why I can't get time this way - objective-c

Question

strTime=#"13:00";
NSDateFormatter * df = [[NSDateFormatter alloc]init];
[df setDateFormat:#"hh:mm"];
NSDate * date = [df dateFromString:strTime];
Everything seems fine.
Yet the content of date is nil.
Why?
What did I do wrong?
Also I changed to #"HH:mm"
NSDateFormatter * df = [[NSDateFormatter alloc]init];
[df setDateFormat:#"HH:mm"];
NSDate * date = [df dateFromString:strTime];
Result is the following:
(lldb) po strTime
13:00
(lldb) po date
2000-01-01 06:00:00 +0000
(lldb) po strTime
15:45
(lldb) po date
2000-01-01 08:45:00 +0000
I think I want something closer to today's date

Answer 1

I suppose what you did wrong is not read the documentation enough. But it's actually pretty obscure. The Data Formatting Guide points you to §8 Date Format Pattern, in Unicode Technical Standard #35, which says this about h:
Hour [1-12]. When used in skeleton data or in a skeleton passed in an API for flexible date pattern generation, it should match the 12-hour-cycle format preferred by the locale (h or K); it should not match a 24-hour-cycle format (H or k). Use hh for zero padding.
And says this about H:
Hour [0-23]. When used in skeleton data or in a skeleton passed in an API for flexible date pattern generation, it should match the 24-hour-cycle format preferred by the locale (H or k); it should not match a 12-hour-cycle format (h or K). Use HH for zero padding.
So you should try using HH:mm as your format:
[df setDateFormat:#"HH:mm"];