I captured request and response time for procedure i need to calculate time take by substract both request -response to find time taken.
P_REQUEST_TIME :='20/MAR/2014 03:03:50.785662 PM';
P_RESPONSE_TIME :='20/MAR/2014 03:03:50.785816 PM';
SELECT TO_TIMESTAMP(P_REQUEST_TIME)-TO_TIMESTAMP(P_RESPONSE_TIME)
into l_actual_time
FROM dual;
Getting result is Result:='-000000000 00:00:00.000154000';
I need this as seconds.
Use EXTRACT function.
SELECT EXTRACT(SECOND FROM TO_TIMESTAMP(P_REQUEST_TIME)-TO_TIMESTAMP(P_RESPONSE_TIME)) diff_seconds
FROM <table_name>;
select extract( day from diff ) days,
extract( hour from diff ) hours,
extract( minute from diff ) minutes,
extract( second from diff ) seconds
from (SELECT TO_TIMESTAMP(REQUEST_DTTM)-TO_TIMESTAMP(RESPONS_DTTM) diff FROM hit_tracer);
if u want the difference between two timestamps in seconds, this is the query
SELECT (P_REQUEST_TIME-P_RESPONSE_TIME) *24 *60*60
into l_actual_time
FROM dual;
Related
i'm having trouble in converting seconds in Bigquery, is there any function to convert seconds to hour:minute:second format in Bigquery? i already tried the TIMESTAMP_SECONDS() function but it also returns some date and i can't use it if the hour more than 23.
for example:
second= 100000
result= 27:46:40
or maybe as 1 day 3 hour 46 minute 40 second
and i also want it in timestamp datatype so i can order it ascending or descending.
Below is for BigQuery Standard SQL
#standardSQL
select seconds,
regexp_replace(
cast(time(ts) as string),
r'^\d\d',
cast(extract(hour from time(ts)) + 24 * unix_date(date(ts)) as string)
) as option1,
format(
'%i day %i hour %i minute %i second',
unix_date(date(ts)),
extract(hour from time(ts)),
extract(minute from time(ts)),
extract(second from time(ts))
) as option2
from `project.dataset.table`,
unnest([timestamp_seconds(seconds)]) ts
if to apply to sample data from your question as in
with `project.dataset.table` AS (
select 100000 seconds union all
select 200000 union all
select 300000
)
the output is
With recently introduced INTERVAL data type and respective functions - such conversion becomes much easier
select seconds,
make_interval(second => seconds) result,
justify_interval(make_interval(second => seconds)) normalized_result
from `project.dataset.table`
with output like
How can i subtract days to a timestamp in CrateDB SQL query?
Exist something similar to this?
TIMESTAMP_SUB(CURRENT_TIMESTAMP(), INTERVAL 14 DAY)
Don't think there is a built in function but you could do something like this
SELECT DATE_FORMAT(CURRENT_TIMESTAMP - 1000*60*60*24*14) LIMIT 100
in this example (1000 * 60 * 60) * 24 * 14 (24 is to get days and 14 is your number of days)
NB. You can also cast dates into timestamp and perform similar functionality
SELECT ABS(cast('2019-01-1' AS TIMESTAMP) - CURRENT_TIMESTAMP ) / (1000*60*60*24) LIMIT 100
this will get you a number of days between now and 1st of January
So far that's all what they have in their docs
You can subtract INTERVAL from TIMESTAMP, but before any matematichal operation you need to CAST the datatype, you can do it in this way:
SELECT now() - CAST('14 day' AS INTERVAL)
Or the same function of above, but in a contracted way
SELECT now() - '14 day'::INTERVAL;
As a string to be CAST to an INTERVAL you can use a number followed by any of this:
second
minute
hour
day
week
month
quarter
year
Need your help to conclude the query to fetch last date time of the sysdate month.
select to_char(last_day(sysdate),'DD-Mon-YYYY HH24:MI:SS') from dual
it gives last date as expected, but I need time as 23:59:00 which is not possible thru above query.
You could use TRUNC on next day i.e. SYSDATE + 1, and then subtract 60 seconds i.e. 60/86400 to get the desired output.
SQL> SELECT to_char((trunc(last_day(sysdate)) +1) - 60/86400,'DD-Mon-YYYY HH24:MI:SS') dt
2 FROM dual;
DT
--------------------
29-Feb-2016 23:59:00
SQL>
You could also use interval '1' minute or interval '60' second instead of 60/86400.
If you just want it for display for some reason you can hard-code the time into the format mask:
select to_char(last_day(sysdate), 'DD-Mon-YYYY "23:59:00"') from dual;
But you probably really want it as a date object, in which case you can add 23 hours and 59 minutes to the truncated (midnight) date, wchi is 1439 of the 1440 minutes in a day:
select to_char(trunc(last_day(sysdate)) + 1439/1440, 'DD-Mon-YYYY HH24:MI:SS')
from dual;
Or you can go to the next day and remove a minute, either with fractional days or with intervals:
select to_char(trunc(last_day(sysdate)) + interval '1' day - interval '1' minute,
'DD-Mon-YYYY HH24:MI:SS') from dual;
Generally if you're working with time periods you want to include up to 23:59:59, which you can also do with any of those methods, but as Damien_The_Unbeliever said in a comment, it's easier to compare against the start of the next period (e.g. < add_months(trunc(sysdate, 'MM'), 1). It's easy to accidentally miss part of a day by not taking the time into account properly, particularly if you actually have a timestamp rather than a date.
I thought it was really simple but it isn't.
SELECT TO_TIMESTAMP('10/08/2012','DD/MM/YYYY')
- 1/(24*50*60*1000) data
FROM dual;
It simply doesn't work.
Other details:
SELECT TO_TIMESTAMP('10/08/2012','DD/MM/YYYY') -
NUMTODSINTERVAL(1/(24*50*60*1000),'HOUR') data
FROM dual;
doesn't work..
The right seems to be
SELECT TO_TIMESTAMP('10/08/2012','DD/MM/YYYY') -
NUMTODSINTERVAL(1/(24*25*60*1000),'HOUR') data
FROM dual;
Why? How does it work?
For adding or subtracting an amount of time expressed as a literal you can use INTERVAL.
SELECT TO_TIMESTAMP('10/08/2012','DD/MM/YYYY')
- INTERVAL '0.001' SECOND
FROM dual;
As well there are now standard ways to express date and time literals and avoid the use of various database specific conversion functions.
SELECT TIMESTAMP '2012-10-08 00:00:00'
- INTERVAL '0.001' SECOND DATA
FROM dual;
For your original question the time part of a day is stored in fractional days. So one second is:
1 / (hours in day * minutes in hour * seconds in a minute)
Divide by 1000 to get milliseconds.
1 / (24 * 60 * 60 * 1000)
SELECT TO_TIMESTAMP('10/08/2012','DD/MM/YYYY') - NUMTODSINTERVAL(1/(24*50*60*1000),'HOUR') data
FROM dual;
OUTPUT
DATA
---------------------------------
09/AUG/12 11:59:59.999950000 PM
1 row selected.
The answer posted above subtracts a tenth of a millisecond from the date. I think what you want is the following:
SELECT TO_TIMESTAMP('10/08/2012','DD/MM/YYYY')-NUMTODSINTERVAL(1/1000,'SECOND')
FROM dual;
Output:
DATA
---------------------------------------------------------------------------
09-AUG-12 11.59.59.999000000 PM
^^^
|||
tenths|thousandths
|
hundredths
The following NUMTODSINTERVAL(1/(24*25*60*1000),'HOUR') seems to work only because 24*25 = 600. But that number is wrong because 1/(600*60*1000) of an hour is a tenth of a millisecond, not a millisecond. If you want to use 'HOUR' in NUMTODSINTERVAL() you should use 1/(60*60*1000) (sixty minutes in an hour, sixty seconds in a minute, 1000 ms in a second).
This is correct (with a millisecond being 1000th of a second):-
SELECT TO_TIMESTAMP('10/08/2012','DD/MM/YYYY') - NUMTODSINTERVAL(1/1000,'SECOND') data FROM dual;
DATA
-----------------------------
09-AUG-12 23.59.59.999000000
As to why the other code isn't working it's because you aren't calculating a millisecond correctly. An hour must be divided by 60 to give minutes and again by 60 to given seconds then by 1000 to give a millisecond, thus if you must use HOUR as the interval then it is:-
SELECT TO_TIMESTAMP('10/08/2012','DD/MM/YYYY') - NUMTODSINTERVAL(1/(60*60*1000),'HOUR') as data FROM dual;
DATA
---------------------------------------------------------------------------
09-AUG-12 23.59.59.999000000
select TO_CHAR(TO_TIMESTAMP('10.05.2012', 'DD.MM.YYYY') -
NUMTODSINTERVAL(1/1000, 'SECOND'), 'DD.MM.YYYY HH24:MI:SS:FF3') Res
from dual;
RES
-----------------------------
09.05.2012 23:59:59.999
is there any way in oracle to calculate the difference between two time stamps value with time zones in oracle sql plus as it is not possible to use timestampdiff or datediff inside oracle.
Thanks
Just subtract them:
SQL> select (systimestamp + 1) - systimestamp from dual;
(SYSTIMESTAMP+1)-SYSTIMESTAMP
---------------------------------------------------------------------------
+000000000 23:59:59.884789
Consider the following in case you need the number of milliseconds between two timestamps:
create or replace Function msecBetween
(ts1 timestamp with time zone,
ts2 timestamp with time zone,
numDec number default 0
)
Return Number is
i INTERVAL DAY(3) TO SECOND(3) := ts2 - ts1;
Begin
return round (
+ extract( day from i )*24*60*60*1000
+ extract( hour from i )*60*60*1000
+ extract( minute from i )*60*1000
+ extract( second from i )*1000
, numDec);
End;