My sample sql query
SELECT EID,p,p1,p2,p3 FROM table 1 GROUP BY EID;
Giving error not part of aggregate function.I wanted to group by only EID not all other p,p1,p2,p3. How do i specify that in sql query.
In most dialects of SQL, you have to specify which column you want, if the column is not in the group by clause. For instance, maybe you want the minimum value:
SELECT EID, min(p), min(p1), min(p2), min(p3)
FROM table 1
GROUP BY EID;
Or, if you wanted all the values from a particular record, use first or last:
SELECT EID, first(p), first(p1), first(p2), first(p3)
FROM table 1
GROUP BY EID;
Related
Can you filter a SQL table based on an aggregated value, but still show column values that weren't in the aggregate statement?
My table has only 3 columns: "Composer_Tune", "_Year", and "_Rank".
I want to use SQL to find which "Composer_Tune" values are repeated in each annual list, as well as which ranks the duplicated items had.
Since I am grouping by "Composer_Tune" & "Year", I can't list "_Rank" with my current code.
The image shows the results of my original "find the duplicates" query vs what I want:
Current vs Desired Results
I tried applying the concepts in this Aggregate Subquery StackOverflow post but am still getting "_Rank is invalid in the select list because it is not contained in either an aggregate function or the GROUP BY clause" from this code:
WITH DUPE_DB AS (SELECT * FROM DB.dbo.[NAME] GROUP BY Composer_Tune, _Year HAVING COUNT(*)>1)
SELECT Composer_Tune, _Year, _Rank
FROM DUPE_DB
You need to explicitly declare the columns used in the Group By expression in the select columns.
You can use the following documentation if you are using transact sql for the proper use of Group By.
Simply join the aggregated resultset to original unit level table:
WITH DUPE_DB AS (
SELECT Composer_Tune, _Year
FROM DB.dbo.[NAME]
GROUP BY Composer_Tune, _Year
HAVING COUNT(*) > 1
)
SELECT n.Composer_Tune, n._Year, n._Rank
FROM DB.dbo.[NAME] n
INNER JOIN DUPE_DB
ON n.Compuser_Tune = DUPE_DB.Composer_Tune
AND n._Year = DUPE_DB._Year
ORDER n.Composer_Tune, n._Year
I need to know where the mistake is in this oracle query?
SELECT(KEY1),COUNT(*) FROM TABLE1 GROUP BY AGE
SELECT KEY1,COUNT(*) FROM TABLE1 GROUP BY KEY1
There are two problems. First one: You cannot close the parenthesis after the first keyword. Second: You have to group by all keys that are in the query that are not all row dependend. In that case "KEY1". If you want to order by age you have to query age as parameter.
SELECT AGE,COUNT(*) FROM TABLE1 GROUP BY AGE
Your table naming is not very good. I assume you should have a look at group by tutorials like https://www.w3schools.com/sql/sql_groupby.asp or the sql tutorial https://www.w3schools.com/sql/
Your query had an issue. You have to modify your query as below
SELECT KEY1,COUNT(*) FROM TABLE1 GROUP BY KEY1.
Observation:
All the columns that are added in the select statement alongside the aggregate functions, should be included the group by columns.
Your first column does have the bracket in it which should be removed.
I want to select a field in select statement and order by with another field but sql server doesn't allows this as it says order by item must appear in the select statement if select distinct is specified.
This is what I tried :
select DISTINCT format_type
from Labels_Add_Label
where external_group_id= 2826
order by group_sequence
What changes are required to do in this query?
Please provide the changed query
You can rewrite your query this way (equivalent to distinct):
SELECT format_type
FROM Labels_Add_Label
WHERE external_group_id= 2826
GROUP BY format_type;
and you can't use ORDER BY group_sequence here. There may be more than one row with same format_type but different group_sequence. SQL server doesn't know which one should be used for the ordering.
You can however use aggregate functions with a GROUP BY query:
SELECT format_type
FROM Labels_Add_Label
WHERE external_group_id= 2826
GROUP BY format_type;
ORDER BY MIN(group_sequence) ; -- or MAX(group_sequence)
I just took this question to test my knowledge and have come with the following solution (using CTE in MS SQL Server), please correct me if I'm wrong - Using the NORTHWIND Database (Employees Table) on MS SQL Server, I have written this query - This could be one other option that could be used, if there be a need to!
WITH CTE_Employees(FirstName, LastName, BirthDate)
AS
(
SELECT FirstName, LastName, BirthDate
FROM Employees
WHERE Region IS NOT NULL
)
SELECT FirstName FROM CTE_Employees ORDER BY BirthDate DESC
As mentioned above, there can be a same Employee FirstName but with a different LastName, hence SQL Server imposes a condition where we can't use DISTINCT in conjunction with ORDER BY...
Hope this helps!
How can I use a Distinct or Group by statement on 1 field with a SELECT of All or at least several ones?
Example: Using SQL SERVER!
SELECT id_product,
description_fr,
DiffMAtrice,
id_mark,
id_type,
NbDiffMatrice,
nom_fr,
nouveaute
From C_Product_Tempo
And I want Distinct or Group By nom_fr
JUST GOT THE ANSWER:
select id_product, description_fr, DiffMAtrice, id_mark, id_type, NbDiffMatrice, nom_fr, nouveaute
from (
SELECT rn = row_number() over (partition by [nom_fr] order by id_mark)
, id_product, description_fr, DiffMAtrice, id_mark, id_type, NbDiffMatrice, nom_fr, nouveaute
From C_Product_Tempo
) d
where rn = 1
And this works prfectly!
If I'm understanding you correctly, you just want the first row per nom_fr. If so, you can simply use a subquery to get the lowest id_product per nom_fr, and just get the corresponding rows;
SELECT * FROM C_Product_Tempo WHERE id_product IN (
SELECT MIN(id_product) FROM C_Product_Tempo GROUP BY nom_fr
);
An SQLfiddle to test with.
You need to decide what to do with the other fields. For example, for numeric fields, do you want a sum? Average? Max? Min? For non-numeric fields to you want the values from a particular record if there are more than one with the same nom_fr?
Some SQL Systems allow you to get a "random" record when you do a GROUP BY, but SQL Server will not - you must define the proper aggregation for columns that are not in the GROUP BY.
GROUP BY is used to group in conjunction with an aggregate function (see http://www.w3schools.com/sql/sql_groupby.asp), so it's no use grouping without counting, summing up etc. DISTINCT eleminates duplicates but how that matches with the other columns you want to extract, I can't imagine, because some rows will be removed from the result.
I want to find the average amount of a field where it meets a criterion. It is embedded in a big table but I would like this average field in there instead of doing it in a separate table.
This is what I have so far:
Select....
Avg( (currbal) where (select * from table
where ament2 in ('r1','r2'))
From table
If you want to AVG only a subset of a query use case when ... then to replace value in non-matching rows with null as nulls are ignored by avg().
Select id,
sum(something) SomethingSummed,
avg(case when ament2 in ('r1','r2') then currbal end) CurrbalAveragedForR1R2
From [table]
group by id
You can put all the other sums which you want to be embedded into the AVG statement, inside the table reference inside the FROM clause. Something like:
SELECT AVG(currbal)
FROM
(
SELECT * -- other sums
FROM table
WHERE ament2 IN ('r1','r2')
) t
You can write a full sub-select into the select list:
SELECT ...,
(SELECT AVG(Currbal) FROM Table WHERE ament2 IN ('r1', 'r2')) AS avg_currbal,
...
FROM ...
Whether that will do exactly what you want depends on a number of things. You might need to make that into a correlated subquery; assuming 'ament2' is in Table, it is not a correlated sub-query at the moment.