I thought I had a good grasp on table joins but there is one problem here I can't figure out.
I am trying to track the progress of students on specifically required courses. Some students are required to complete an exact list of courses before further qualification.
Tables (simplified):
students
--------
id INT PRIMARY KEY
name VARCHAR(50)
student_courses
---------------
student_id INT PRIMARY KEY
course_id TINYINT PRIMARY KEY
course_status TINYINT (Not done, Started, Completed)
steps_done TINYINT
total_steps TINYINT
date_created DATETIME
date_modified DATETIME
courses
-------
id TINYINT PRIMARY KEY
name VARCHAR(50)
I want to insert a list of required courses, for example 5 different courses in the courses table and then select a specific student and get list of all the courses required, whether a row exists for that course in the student_courses table or not.
I guess I could insert all rows from the courses table in the student_courses table for each student, but I don't want that because not all students need to do these courses. And what if new courses are added later.
I just want a result which is something like this:
students table:
id name
--- ------------------
1 George Smith
2 Dana Jones
3 Maria Cobblestone
SELECT * FROM students (JOIN bla bla bla - this is the point where I'm lost...)
WHERE students.id = 1
Result:
id name course_id courses.name course_status steps_done
--- ------------------ --------- ------------ ------------- ----------
1 George Smith 1 Botany Not started 0
1 George Smith 2 Biology NULL NULL
1 George Smith 3 Physics NULL NULL
1 George Smith 4 Algebra Completed 34
1 George Smith 5 Sewing Started 2
If the course_status or steps_done is NULL it means that no row exists for this student for this course in the student_courses table.
The idea is then using this in MS Access (or some other system) and have the row automatically inserted in the student_courses table once you enter a value in the NULL field.
You can't just use an outer join to do this, you need to create a list of all students/classes combinations that you're interested in first, then use that list in a LEFT JOIN. Can be done in a cte/subquery using CROSS JOIN:
;WITH cte AS (SELECT DISTINCT s.id Student_ID
,s.name
,c.id Course_ID
,c.name Class_Name
FROM Students s
CROSS JOIN Courses c)
SELECT cte.*,sc.status
FROM cte
LEFT JOIN student_courses sc
ON cte.course_id = sc.course_id
Can also use a subquery if needs to be done in Access (not 100% on syntax in Access):
SELECT sub.*,sc.status
FROM (SELECT DISTINCT s.id Student_ID
,s.name
,c.id Course_ID
,c.name Class_Name
FROM Students s
CROSS JOIN Courses c
) AS sub
LEFT JOIN student_courses sc
ON sub.course_id = sc.course_id
Demo: SQL Fiddle
You want a left outer join. The first table is from the courses table and is used for the required courses (defined in the where clause).
select s.id, s.name, c.id, c.name, c.course_status, c.steps_done
from (courses as c left join
student_courses as sc
on sc.course_id = c.id and
sc.student_id = 1
) left join
students as s
on sc.student_id = s.id
where c.id in (<list of required courses>)
order by s.id, c.id;
I think I have all the "Access"isms in there.
Actually, the above will be missing the student name when s/he is missing a course. The following is more correct:
select s.id, s.name, c.id, c.name, c.course_status, c.steps_done
from (courses as c left join
student_courses as sc
on sc.course_id = c.id and
sc.student_id = 1
) cross join
students as s
on s.id = 1
where c.id in (<list of required courses>)
order by s.id, c.id;
Related
I have three tables I want to iterate over. The tables are pretty big so I will show a small snippet of the tables. First table is Students:
id
name
address
1
John Smith
New York
2
Rebeka Jens
Miami
3
Amira Sarty
Boston
Second one is TakingCourse. This is the course the students are taking, so student_id is the id of the one in Students.
id
student_id
course_id
20
1
26
19
2
27
18
3
28
Last table is Courses. The id is the same as the course_id in the previous table. These are the courses the students are following and looks like this:
id
type
26
History
27
Maths
28
Science
I want to return a table with the location (address) and the type of courses that are taken there. So the results table should look like this:
address
type
The pairs should be unique, and that is what's going wrong. I tried this:
select S.address, C.type
from Students S, Courses C, TakingCourse TC
where TC.course_id = C.id
and S.id = TC.student_id
And this does work, but the pairs are not all unique. I tried select distinct and it's still the same.
Multiple students can (and will) reside at the same address. So don't expect unique results from this query.
Only an overview is needed, so that's why I don''t want duplicates
So fold duplicates. Simple way with DISTINCT:
SELECT DISTINCT s.address, c.type
FROM students s
JOIN takingcourse t ON s.id = t.student_id
JOIN courses c ON t.course_id = c.id;
Or to avoid DISTINCT (why would you for this task?) and, optionally, get counts, too:
SELECT c.type, s.address, count(*) AS ct
FROM students s
JOIN takingcourse t ON s.id = t.student_id
JOIN courses c ON t.course_id = c.id
GROUP BY c.type, s.address
ORDER BY c.type, s.address;
A missing UNIQUE constraint on takingcourse(student_id, course_id) could be an additional source of duplicates. See:
How to implement a many-to-many relationship in PostgreSQL?
I have two tables which is
Student
ID
Name
Gender
Address
1
Abby
Girl
street
2
Mark
Boy
street
3
Lula
Girl
street
4
Bren
boy
street
Lessons
ID
Lessons_code
3
MK2234
5
22324KL
6
KCS233
and I want to join these tables then get the sum result of the students that didn't took a lesson then group it by gender like this:
Gender
total
Boy
2
girl
1
I know it use sum() and left outer join (?) but I don't know how to implement it.
I would suggest not exists:
select s.gender, count(*)
from students s
where not exists (select 1
from lessons l
where l.id = s.id
)
group by s.gender;
You have a very awkward data model. I would expect a column called lessons.id to refer to the primary key of the lessons table. Instead. it seems to refer to a student. A better name would be student_id.
I'm trying to work with 3 tables and create a derived table to get some data together that shows a percentage of completion.
The 3 tables I have that I'm working with are Student, Tests and Results. I'm trying to join the 3 together and create a derived table that shows the student and the progress they have made, in a percentage of tests completed.
As an example, lets assume the 3 students I want to track have all been assigned 3 tests (out of a table with hundreds) and I want to see how far along they are. If they completed all 3 tests the derived table should store the value 100%.
StudentID SName
-----------------
1 Ken
2 Tom
3 Bob
TestID TName
----------------
11 Test 101
22 Test 102
33 Test 103
ResultsID TestID StudentID Passed
--------------------------------------
1 11 Tom 0
2 11 Bob 1
3 22 Bob 1
4 33 Bob 1
Derived table:
StudentID SName %Completed
---------------------------
1 Ken 0%
2 Tom 0%
3 Bob 100%
I have tried a lot of different methods and don't know which one to even show because I feel like all the attempts have been completely wrong. Any ideas? Sorry if the formatting isn't great, it's my first post here :)
Thanks!
From the data, we can't see that Ken has been assigned to the 3 tests, so we must assume that all tracked students have been assigned to all tracked tests.
Here's what I would do:
Build a set of all combinations of tracked students and tests (CROSS JOIN with 2 WHERE conditions)
Determine the results using a LEFT OUTER JOIN (replace NULL with 0)
Calculate the AVG result (casted to a number) while I GROUP BY student
This can be written in a single SELECT statement:
SELECT s.StudentID, s.SName, AVG(CAST(ISNULL(r.Passed, 0) as float)) AS Completed
FROM Students s CROSS JOIN Tests t
LEFT OUTER JOIN Results r ON t.TestID = r.TestID AND s.StudentID = r.StudentID
WHERE s.StudentID IN (1, 2, 3)
AND t.TestID IN (11, 22, 33)
GROUP BY s.StudentID, s.SName
The formatting (as percentage) of the Completed value should be done in the client application.
To get all possible combinations of students with the tests.
One could cross join to a sub-query of the tests the students should pass.
Then all possible combinations of student/test can be left joined to the actual results.
After that, it's a simple GROUP BY with an average.
select
stu.StudentID,
stu.SName,
concat(AVG(coalesce(res.Passed,0)*100),'%') as [%Completed]
from Students as stu
cross join (
select TestID, TName
from Tests
where TestID in (11,22,33)
) as tst
left join Results as res on (res.StudentID = stu.StudentID and res.TestID = tst.TestID)
group by stu.StudentID, stu.SName
Example snippet:
-- Sample data
-- Using table variables for demonstration
declare #Students table (StudentID int identity(1,1) primary key, SName varchar(30));
insert into #Students (Sname) values
('Ken'),
('Tom'),
('Bob'),
('Jane');
declare #Tests table (TestID int primary key, TName varchar(30));
insert into #Tests (TestID, TName) values
(11,'Test 101'),
(22,'Test 102'),
(33,'Test 103');
declare #Results table (ResultsID int identity(1,1) primary key, TestID int, StudentID int, Passed bit);
insert into #Results (TestID, StudentID, Passed) values
(11,2,0),
(11,3,1),(22,3,1),(33,3,1),
(11,4,1);
-- Query
select
stu.StudentID,
stu.SName,
concat(AVG(coalesce(res.Passed,0)*100),'%') as [%Completed]
from #Students as stu
cross join (
select TestID, TName
from #Tests
where TestID in (11,22,33)
) as tst
left join #Results as res on (res.StudentID = stu.StudentID and res.TestID = tst.TestID)
group by stu.StudentID, stu.SName;
Result:
StudentID SName %Completed
--------- ----- ----------
1 Ken 0%
2 Tom 0%
3 Bob 100%
4 Jane 33%
This seems like a join and group by with a twist:
select s.StudentID, s.SName,
sum(case when r.passed = 1 then 1.0 else 0 end) / t.cnt as ratio
from students s left join
results r
on s.studentid = r.studentid cross join
(select count(*) as cnt
from tests
) t
group by s.StudentID, s.SName, t.cnt;
I am having a question in SQL Joins. I have table employee with employeeid as primary key and some other columns for employee. And there is another table called employeeaddress where there can be multiple employeeid is a foreign key. One employee can have many employeeaddresses just to explain one to many relationship.
If I want to write a query which will fetch the following columns
employee.employeeid, employee.empname,
employeeaddress.employeeaddressid, employeeaddress.addr1,
employeeaddress.addr2
So there can be an employee with no employeeaddress. But anyway I wanted to fetch all the employees who may have zero or multiple addresses.
Do I need to apply left join or left outer join? I want the following result for a table that has 2 employees John and Michael where John has two employeeaddresses with employeeaddressid 21 and 22 and Michael has no employeeaddress
1, John, 21, addr1 for John, addr2 for John
1, John, 22, another addr1 for John, another addr2 for John
2, Michael, NULL , NULL , NULL
The above result is arranged in the following fashion
employee.employeeid, employee.empname, employeeaddress.employeeaddressid, employeeaddress.addr1, employeeaddress.addr2
Please help.
Based on your description it sounds like you're looking for a query as follows. If you also wanted the address details, you'll just have to add a left join to the outer query.
Also, as comments have eluded to, LEFT JOIN is shorthand for LEFT OUTER JOIN, they will produce the same results.
SELECT *
FROM employee
inner join
(
SELECT
employeeid,
count(*) as addresscount
FROM employee
left join employeeaddress ON employeeaddress.employeeaddressid = employee.employeeaddressid
group by employeeid
) counts on counts.employeeid = employee.employeeid
WHERE counts.addresscount = 0 -- Or 1, or 5 or > 1, etc.
LEFT JOIN should be all you need.
SQL Fiddle Example
SELECT e.employeeID ,
e.empName ,
ea.employeeAddressID ,
ea.addr1 ,
ea.addr2
FROM Employee e
LEFT JOIN EmployeeAddress ea ON ea.employeeID = e.employeeID
first time asking a question on Stack Overflow... Amazing resource, but there's just one thing that's really baffling me as a newcomer to SQL.
I have three tables and I would like to obtain the names of all the Mentors who are linked to Bob's students.
Table 1: TEACHERS
================
ID Name
================
1 Bob
Table 2: STUDENTS
===================================
STUDENT_ID Name TEACHER_ID
===================================
1 Jayne 1
2 Billy 5
3 Mark 2
Table 3: MENTOR_RELATIONSHIPS
==============================
ID STUDENT_ID MENTOR_ID
==============================
1 1 3
2 2 2
3 3 3
Table 4: MENTORS
=====================
MENTOR_ID Name
=====================
1 Sally
2 Gillian
3 Sean
I would like to run a query to find all of the mentors of Bob's students. So the mentors for all students with TEACHER_ID = 1
In this case Sean would be the result.
I know that it is something to do with Joins, or could I find this using a normal query??
Any help is much appreciated! Many thanks...
this should do the work
select distinct m.name from students s
inner join mentor_ralationships mr on mr.student_id=s.student_id
inner join mentors m on m.mentoir_id=mr.mentor_id
where s.teacher_id=1;
Without joins (not preferred)
SELECT mentors.name FROM mentors
WHERE mentors.id
IN (SELECT MENTOR_RELATIONSHIPS.mentor FROM MENTOR_RELATIONSHIPS
WHERE MENTOR_RELATIONSHIPS.student
IN (SELECT students.id FROM students WHERE students.teacher
= (SELECT teachers.id FROM teachers WHERE teachers.name = 'bob')));
It could be helpful for you as I had to retrieve data from three tables AssignedSubject, Section and SchoolClass when a teacher assigned to specific subject then I have to find out the his class and section details including subjectid which I did this way
select a.StaffID, a.SubjectID, s.ID as SectionId, s.Name as SectionName, S.Remarks as SectionRemarks, sc.ID as ClassId, sc.Name as ClassName, sc.Remarks as ClassRemarks from AssignedSubject a
inner join Section s on a.SectionId=s.ID
inner join SchoolClass sc on sc.ID=s.ClassId where a.StaffID=3068
You could try the following:
SELECT DISTINCT m.name
FROM students s INNER JOIN TEACHERS t ON t.ID = a.TEACHER_ID
INNER JOIN MENTOR_RELATIONSHIPS mr ON mr.Student_id = s.Student_id
INNER JOIN Mentors m ON mr.MENTOR_ID = s.MENTOR_ID
WHERE s.teacher_id = 1 WHERE t.Name = 'Bob';
SELECT TEACHER.NAME, STUDENTS.NAME AS STUDENT NAME, MENTORS.NAME AS MENTOR
FROM TEACHERS JOIN STUDENTS ON TEACHERS.ID = STUDENTS.TEACHER_ID
JOIN MENTOR_RELATIONSHIPS ON STUDENTS.STUDENT_ID =
MENTOR_RELATIONSHIPS.STUDENT_ID
JOIN MENTORS ON MENTOR_RELATIONSHIPS.MENTOR_ID = MENTORS.MENTOR_ID
WHERE TEACHER.NAME = 'Bob' ;