I am using sql server and this is my table structure
start end interval
1 3 1
9 12 1
16 20 2
100 120 5
expected result
1
2
3
9
10
11
12
16
18
20
100
105
110
115
120
i tried this before posting here
select start as result,end1,interval
from table
union
select result+1,interval,end1,interval
from table
This is a perfect place to use a CTE. The following code should give you the answer you're looking for:
;WITH IntervalCTE AS
(
SELECT [start] AS Value, [end], [interval]
FROM T
UNION ALL
SELECT [Value] + [interval], [end], [interval]
FROM IntervalCTE
WHERE [Value] < [end]
)
SELECT Value FROM IntervalCTE ORDER BY Value
I've also created a SQL Fiddle that you can look at.
Related
I have this data, where I want to generate the last row "on the fly" from the first two:
Group
1yr
2yrs
3yrs
date
code
Port
19
-15
88
1/1/2020
arp
Bench
10
-13
66
1/1/2020
arb
Diff
9
2
22
I am trying to subtract the Port & Bench returns and have the difference on the new row. How can I do this?
Here's my code so far:
Select
date
Group,
Code,
1 yr returnp,
2 yrs returnp,
3yrs return
From timetable
union
Select
date,
Group,
Code,
1 yr returnb,
2 yrs returnb,
3yrs returnb
From timetable
Seems to me that a UNION ALL in concert with a conditional aggregation should do the trick
Note the sum() is wrapped in an abs() to match desired results
Select *
From YourTable
Union All
Select [Group] = 'Diff'
,[1yr] = abs(sum([1yr] * case when [Group]='Bench' then -1 else 1 end))
,[2yrs] = abs(sum([2yrs] * case when [Group]='Bench' then -1 else 1 end))
,[3yrs] = abs(sum([3yrs] * case when [Group]='Bench' then -1 else 1 end))
,[date] = null
,[code] = null
from YourTable
Results
Group 1yr 2yrs 3yrs date code
Port 19 -15 88 2020-01-01 arp
Bench 10 -13 66 2020-01-01 arb
Diff 9 2 22 NULL NULL
If you know there is always 2 rows, something like this would work
SELECT * FROM timetable
UNION ALL
SELECT
MAX(1yr) - MIN(1yr),
MAX(2yrs) - MIN(2yrs),
MAX(3yrs) - MIN(3yrs),
null,
null,
FROM timetable
#1 EDIT
I changed the AND in the WHERE clause for OR and everything worked fine. But I needed to use a JOIN in the recursive part of the CTE and the problem showed up again, because I cannot use a OUTER JOIN here. So, I changed the JOIN for an OUTER APPLY and that worked fine.
SQL Fiddle: http://sqlfiddle.com/#!18/9eecb/81809
I am trying to implement a recursive CTE which receives two ages and increments these ages until both of them are equal to 120. The problem is when I try to add a WHERE clause to the recursive part the predicates are completely ignored:
;with age_cte as (
select
26 as wife_age,
28 as husband_age
union all
select
age_cte.wife_age + 1,
age_cte.husband_age + 1
from age_cte
where wife_age < 120 and husband_age < 120
) select * from age_cte;
As soon as one of the ages reaches 120 the CTE stops. In the example, when the husband age is equal to 120, the wife's age is 118 and then the calculations stop.
I know the database is obeying the logic of the query. My question is what should I do to apply the correct logic to that CTE, that is, return NULL when one age passes 120 until the other age reaches 120?
Example:
. .
. .
. .
118 120
119 NULL
120 NULL
I tried using a CTE with two anchors and two recursive parts like the following from the documentation example ("H. Using multiple anchor and recursive members"):
create table age (
wife_age int,
husband_age int
);
insert into age values(26, 28);
;with age_cte as (
-- first anchor
select
wife_age
from age
union
-- second anchor
select
husband_age
from age
union all
select
age_cte.wife_age + 1
from age_cte
where wife_age < 120
union all
--
select
age_cte.husband_age + 1
from age_cte
where husband_age < 120
) select * from age_cte;
I'm missing something, because it gives me "Invalid column name" for the "husband_age" in the second recursive query.
I also tried this query
;with age_cte as (
select
26 as wife_age,
28 as husband_age
union all
select
case when age_cte.wife_age + 1 > 120 then null else age_cte.wife_age + 1 end,
case when age_cte.husband_age + 1 > 120 then null else age_cte.husband_age + 1 end
from age_cte
where 120 >= case
when age_cte.wife_age + 1 < age_cte.husband_age + 1 then
age_cte.wife_age + 1
else
age_cte.husband_age + 1
end
) select * from age_cte;
But either it gives an infinite loop or the age goes to 119 never reaching 120.
This should do what you want:
with age_cte as (
select 26 as wife_age, 28 as husband_age
union all
select
case when wife_age < 120 then wife_age + 1 end,
case when husband_age < 120 then husband_age + 1 end
from age_cte
where wife_age < 120 or husband_age < 120
)
select * from age_cte;
That is:
you want or in the where clause of the recursive query rather than and, so the query keeps going until both ages reach 120
you can use conditional logic in the select to produce nulls when the age exceeds 120
Demo on DB Fiddle:
wife_age | husband_age
-------: | ----------:
26 | 28
27 | 29
28 | 30
29 | 31
...
116 | 118
117 | 119
118 | 120
119 | null
120 | null
My table structure in SQL Server looks as below.
id startdate enddate value
---------------------------------------
1 2019-02-06 2019-02-07 11
1 2019-01-22 2019-02-05 10
1 2019-01-15 2019-01-21 14
1 2018-12-13 2018-01-14 15
1 2018-12-09 2018-12-12 14
1 2018-08-13 2018-12-08 17
1 2018-07-19 2018-08-12 19
1 2018-06-13 2018-07-18 20
Now my query needs to display value from highest start date for that month. Which is fine and I know what needs to be done but Not start just highest date value for that month, if no value is there for that start date, we carry forward value from last month. So basically if you notice on above data, after December 2018 values, there are no values for November, October, September etc but I want to return MM/YYYY values for that month in result but value for those months should be what we found on earlier month which is August values which in this example is 17. Please note that enddate will always be as of one day before new start date begins. Probably that can be used for back filling and carry forwarding missing month values?
So my result should look like below.
id date value
----------------------------
1 2019-02 11
1 2019-01 10
1 2018-12 15
1 2018-11 17
1 2018-10 17
1 2018-09 17
1 2018-08 17
1 2018-07 19
1 2018-06 20
Do you think this can be done without using cursor here?
Alexander Volok's answer is solid, so I won't go into too much extra code. But I thought I'd explain the reasoning. In essence, what you need to do is create a skeleton date table containing all the dates and primary keys you want returned. I'm guessing you have more than one id value in your real data, so probably something like this (whether you choose to persist it or not is up to you)
create table #skelly
(
id int,
_year int,
_month int
primary key (id, _year, _month)
)
You can get much more precise if you need to be, by only including dates which fall between the min and max StartDate per id, but that's an exercise I leave up to you.
From there, it's then just a matter of filling in the values you care about against that skeleton table. You can do this in a number of ways; by joining, cross applying or a correlated subquery (as Alexander Volok used).
DECLARE #start DATE, #end DATE;
SELECT #start = '20180601', #end = GETDATE();
;WITH Months AS
(
SELECT EOMONTH(DATEADD(month, n-1, #start)) AS DateValue FROM (
SELECT TOP (DATEDIFF(MONTH, #start, #end) + 1)
n = ROW_NUMBER() OVER (ORDER BY [object_id])
FROM sys.all_objects
) D
)
, InputData AS
(
SELECT 1 AS id, '2019-02-06' startdate, '2019-02-07' as enddate, 11 AS [value] UNION ALL
SELECT 1, '2019-01-22', '2019-01-25', 10 UNION ALL
SELECT 1, '2019-01-15', '2019-01-17', 14 UNION ALL
SELECT 1, '2018-12-13', '2018-12-19', 15 UNION ALL
SELECT 1, '2018-12-09', '2018-12-10', 14 UNION ALL
SELECT 1, '2018-08-13', '2018-12-08', 17 UNION ALL
SELECT 1, '2018-07-19', '2018-07-25', 19 UNION ALL
SELECT 1, '2018-06-13', '2018-07-18', 20
)
SELECT FORMAT(m.DateValue, 'yyyy-MM') AS [Month]
, (SELECT TOP 1 I.value FROM InputData I WHERE I.startdate < M.DateValue ORDER BY I.startdate DESC ) [Value]
FROM months m
ORDER BY M.DateValue DESC
Results to:
Month Value
2019-02 11
2019-01 10
2018-12 15
2018-11 17
2018-10 17
2018-09 17
2018-08 17
2018-07 19
2018-06 20
I need some help working out how many people were on site for each hour.
The data looks like this
Id Roomid, NumPeople, Starttime, Closetime.
1 1 4 2018/10/03 09:06 2018/10/03 12:43
2 2 8 2018/10/03 10:16 2018/10/03 13:12
3 1 6 2018/10/03 13:02 2018/10/03 15:01
What I need out is the max count of people during the hour, each hour
Time | PeoplePresent
9 4
10 12
11 12
12 12
13 14
14 6
15 6
Getting the count of people as the arrived is simple enough, but I can’t think where to start to get the presence for each hour. Can anyone suggest a strategy for this. I ok with the simple SQL stuff but I’m certain this requires some advanced SQL functions.
Tested the following in SQL Server 2008 R2:
You can use a recursive CTE to build the list of hours, including the row id and NumPeople values. Then you can sum them together to get your final output. I put together the following test data based on the question.
CREATE TABLE #times
(
Id int
, Roomid INT
, NumPeople INT
, Starttime DATETIME
, Closetime DATETIME
)
INSERT INTO #times
(
Id
,Roomid
,NumPeople
,Starttime
,Closetime
)
VALUES
(1, 1, 4 , '2018/10/03 09:06', '2018/10/03 12:43')
,(2, 2, 8, '2018/10/03 10:16', '2018/10/03 13:12')
,(3, 1, 6, '2018/10/03 13:02', '2018/10/03 15:01')
;WITH recursive_CTE (id, startHour, currentHour, diff, NumPeople) AS
(
SELECT
Id
,startHour = DATEPART(HOUR, t.Starttime)
,currentHour = DATEPART(HOUR, t.Starttime)
,diff = DATEDIFF(HOUR, Starttime, Closetime)
,t.NumPeople
FROM #times t
UNION ALL
SELECT
r.id
,r.startHour
,r.currentHour + 1
,r.diff
,r.NumPeople
FROM recursive_CTE r
WHERE r.currentHour < startHour + diff
)
SELECT
Time = currentHour
,PeoplePresent = SUM(NumPeople)
FROM recursive_CTE
GROUP BY currentHour
DROP TABLE #times
Query results:
Time PeoplePresent
9 4
10 12
11 12
12 12
13 14
14 6
15 6
I have an SQL Table in which I keep project information coming from primavera.
Suppose that i have columns for Start Date,End Date,Duration, and Total Qty as shown below .
How can i distribute Total Qty over Months using these information. What kind of additional columns, sql queries i need in order to get correct monthly distribution?
Thanks in Advance.
Columns in order:
itemname,quantity,startdate,duration,enddate
item1 -- 108 -- 2013-03-25 -- 720 -- 2013-07-26
item2 -- 640 -- 2013-03-25 -- 720 -- 2013-07-26
.
.
I think the key is to break the records apart by month. Here is an example of how to do it:
with months as (
select 1 as mon union all select 2 union all select 3 union all
select 4 as mon union all select 5 union all select 6 union all
select 7 as mon union all select 8 union all select 9 union all
select 10 as mon union all select 11 union all select 12
)
select item, m.mon, quantity / nummonths
from (select t.*, (month(enddate) - month(startdate) + 1) as nummonths
from t
) t join
months m
on month(t.startDate) <= m.mon and
months(t.endDate) >= m.mon;
This works because all the months are within the same year -- as in your example. You are quite vague on how the split should be calculated. So, I assumed that every month from the start to the end gets an equal amount.