When i executed the below query in Oracle
select TO_CHAR((CURRENT_DATE),'DD-Mon-YYYY HH24:MI:SS') from dual;
O/P : 04-Mar-2014 14:25:14
I would like to select current date only without current time as below
select TO_CHAR(trunc(CURRENT_DATE),'DD-Mon-YYYY HH24:MI:SS') from dual;
O/P : 04-Mar-2014 00:00:00
To achieve the only way is to apply function trunc() on the query? Is there any another way?
Edit : Thanks for your ans.Can it be done without any function?(wihout using to_char or trunc)
{sorry for missing this info}
The answer is simply no, there is no function that only gets the date part of the date / time (even current_date or sysdate are functions after all).
You should always use trunc to get the current date, without the time.
It isn't necessary to do a trunc and a to_char together. Keep to_char and don't specify the time part.
This is sufficient:
To get the date as varchar:
select TO_CHAR(CURRENT_DATE,'DD-Mon-YYYY') from dual
To get the date as date, with the time part as 00:00:00:
select trunc(CURRENT_DATE) from dual
You can do this:
select TO_CHAR(CURRENT_DATE,'DD-Mon-YYYY')||' 00:00:00' from dual;
there is also EXTRACT function which can be used like that:
SELECT extract(DAY FROM sysdate)
||'-' ||
extract(MONTH FROM sysdate)
|| '-' || extract(YEAR FROM sysdate)
FROM dual;
result: 4-3-2014
Use This Query...
select (TO_CHAR(TRUNC(CURRENT_DATE),'DD-Mon-YYYY HH24:MI:SS')) from dual
Related
I am using oracle 11g and I have normal timestamps (starttime) which produce an output as follows:
23.09.14 05:15:00,000000000
Now I want an output like
23.09.14 05
Also ok would be:
23.09.14 05:00:00,000000000
but when I use something like
round(starttime, 'HH') or trunc(starttime ,'HH24') I always get
23.09.14
with no hours at all.
Looking around here at stackoverflow I found
substr(TO_CHAR(starttime),0,LENGTH(TO_CHAR(starttime))-13)
which produces the correct output as char but when I want to sort dates it wont work because it sorts alphabetically. (so for example, 1.3., 1.4, 1.5.... instead of 1.3., 2.3., 3.3,...),
Any idea how I can get a timestamp which is rounded to the full hour?
I will have to use the statement in a group by clause. The complete statement would look like:
select round(starttime, 'HH24'), sum(counter) from wmsconsolidationorderdwct group by round(starttime, 'HH24') order by round(starttime, 'HH24') desc;
So I cannot display the rounded time and sort by the full timestamp since this would violate the group by clause.
This will truncate to the hour:
trunc(SYSTIMESTAMP) + extract(hour from SYSTIMESTAMP)/24
Edit:
I just tried it and
SELECT TRUNC(SYSTIMESTAMP ,'HH24') FROM DUAL;
returns the correct result.
Fiddle
If your purpose is to display, then use TO_CHAR with desired format model.
For example,
SQL> SELECT TO_CHAR(SYSTIMESTAMP, 'DD.MM.YY HH24') FROM dual;
TO_CHAR(SYS
-----------
28.05.15 15
SQL>
If your purpose is to do date arithmetic then you need to leave the data type as date.
For example,
SQL> alter session set nls_date_format='DD-MM-YYYY HH24:MI:SS'
2 /
Session altered.
SQL> SELECT TRUNC(SYSTIMESTAMP ,'HH24') FROM DUAL
2 /
TRUNC(SYSTIMESTAMP,
-------------------
28-05-2015 15:00:00
SQL>
If you have a timestamp object:
select my_number from(
SELECT TO_NUMBER(TO_CHAR(TO_DATE (TO_CHAR (SYSTIMESTAMP, 'DD.MM.YY HH24:MI'),
'DD.MM.YY HH24:MI'
),'HH24')) AS my_number
FROM DUAL)
order by 1
This could be simplified to:
select my_number from(
SELECT TO_NUMBER(TO_CHAR(SYSTIMESTAMP, 'HH24')) AS my_number
FROM DUAL)
order by 1
I have a column of type DATE stored data are contains date and time . I can see value when i do
select CAST(MSG_DT AS TIMESTAMP) from table;
this is the output
17-MAR-08 15:38:59,000000000
I have to select the row using
Only date
select CAST(MSG_DT AS TIMESTAMP) from
MWRB_RECEIVE where
MSG_DT >= TO_DATE( '2000-02-03' ,'YYYY-MM-DD')
and
MSG_DT <= TO_DATE( '2010-02-03' ,'YYYY-MM-DD')
Only time (eg: every message between 12:00:11 and 23:02:55)
In DB2 i can do
SELECT *
FROM TABLE
WHERE DATE(INS_TMS) = '2014-02-18'
SELECT *
FROM TABLE
WHERE TIME(INS_TMS) > '09.55.00'
In ORACLE I can't see the equivalent.
Try this:
SELECT *
FROM your_table
WHERE TO_CHAR (start_date, 'yyyy-mm-dd') = '2014-10-06'
AND TO_CHAR (start_date, 'hh24:mi:ss') > '10:00:00'
Why are you casting the column value to a TIMESTAMP when the column in the database is a DATE type? The fractional part of the seconds will always be 0, as DATE only has resolution to the seconds value. You need to add the hours,minutes, and seconds format specifier to the query:
select MSG_DT from
MWRB_RECEIVE
where MSG_DT between TO_DATE( '2000-02-03 12:00:11' ,'YYYY-MM-DD HH24:MI:SS') AND
TO_DATE( '2010-02-03 23:02:55' ,'YYYY-MM-DD HH24:MI:SS')
There is no need to split date and hour, you can have it in a single where clause
where field > to_date('20121212 12:12:12, 'YYYYMMDD HH24:MI:SS')
Check for your reference oracle to_date() as it seems the only thing you need
I want to select a date field from oracle database, using
select to_date(trndt, 'yyyymmdd') from cf20gldt, but the system was showing an error.
Reference
Change it as to_char
SELECT TO_CHAR(trndt, 'yyyymmdd') FROM cf20gldt;
if your trndt column is not date type then you have to change it as
SELECT TO_CHAR(TO_DATE(trndt), 'yyyymmdd') FROM cf20gldt;
For example display system date
SELECT TO_CHAR(sysdate,'yyyymmdd') FROM dual;
To_date is to convert a column to date format . If your trndt is not date already then use below :
select to_char(to_date(trndt), 'yyyymmdd') from cf20gldt;
Or if your column trndate is already in date format then use below:-
select to_char(trndt, 'yyyymmdd') from cf20gldt;
You could use:
SELECT to_char(sysdate, 'yyyy-mm-dd') date,
to_char(sysdate, 'hh24:mm:ss') hr
FROM DUAL;
Change sysdate by your field type Date.
I have table that has date field. When I run a query, I see this:
01/10/2009 22:10:39
How can I retrieve only the time (IE: 22:10:39)
you can try this:
SELECT TO_CHAR(yourval, 'DD-MON-YYYY HH:MI:SS') FROM yourtable;
SELECT TO_CHAR(yourval, 'HH:MI:SS') FROM yourtable;
Edit:
as #steven pointed out, to have 24 hours style use
SELECT TO_CHAR(yourval, 'HH24:MI:SS') FROM yourtable;
You need the format HH24, since HH is only a 12 hour date.
select to_char(SYSDATE, 'HH24:MI:SS') from dual
select to_char(YourDateColumn, 'HH24:MI:SS') from YourTable
SELECT TO_CHAR (SYSDATE, 'hh:mi:ss')
FROM DUAL
SELECT TO_CHAR(DATE_COLUMN,'HH24:MI:SS') from TABLE;
I need to add the current year as a variable in an SQL statement, how can I retrieve the current year using SQL?
i.e.
BETWEEN
TO_DATE('01/01/**currentYear** 00:00:00', 'DD/MM/YYYY HH24:MI:SS')
AND
TO_DATE('31/12/**currentYear** 23:59:59', 'DD/MM/YYYY HH24:MI:SS')
Using to_char:
select to_char(sysdate, 'YYYY') from dual;
In your example you can use something like:
BETWEEN trunc(sysdate, 'YEAR')
AND add_months(trunc(sysdate, 'YEAR'), 12)-1/24/60/60;
The comparison values are exactly what you request:
select trunc(sysdate, 'YEAR') begin_year
, add_months(trunc(sysdate, 'YEAR'), 12)-1/24/60/60 last_second_year
from dual;
BEGIN_YEAR LAST_SECOND_YEAR
----------- ----------------
01/01/2009 31/12/2009
Another option is:
SELECT *
FROM TABLE
WHERE EXTRACT( YEAR FROM date_field) = EXTRACT(YEAR FROM sysdate)
Use extract(datetime) function it's so easy, simple.
It returns year, month, day, minute, second
Example:
select extract(year from sysdate) from dual;
Yet another option would be:
SELECT * FROM mytable
WHERE TRUNC(mydate, 'YEAR') = TRUNC(SYSDATE, 'YEAR');
Since we are doing this one to death - you don't have to specify a year:
select * from demo
where somedate between to_date('01/01 00:00:00', 'DD/MM HH24:MI:SS')
and to_date('31/12 23:59:59', 'DD/MM HH24:MI:SS');
However the accepted answer by FerranB makes more sense if you want to specify all date values that fall within the current year.
Why not use YEAR function?
SELECT * FROM table WHERE YEAR(date_field)=YEAR(SYSDATE);
To display the current system date in oracle-sql
select sysdate from dual;