I have different simple SQL request that return only one value. Example
SELECT COUNT(*) FROM Person
OR
SELECT COUNT(*) FROM Category
I would to get all these infos in a unique request, with a column by request...
I tried something like that but it doesn't work :
SELECT COUNT(C.CategoryId) As nbPeople, COUNT(P.PersonID) As nbCategories FROM Category C, Person P
This works but I get only one column, and a row by request
SELECT COUNT(*) FROM Person UNION SELECT COUNT(*) FROM Category
How Can I simply do that ?
Thanks
When using SQL Server, you can try this:
SELECT ( select COUNT(C.CategoryId)
from Category C
) As nbPeople
, ( select COUNT(P.PersonID)
from Person P
) As nbCategories
In Oracle for example, you need to add this at the bottom
FROM dual
You can use UNION ALL like following:
SELECT '' AS [StatisticName], 1 AS [StatisticCount]
WHERE 1=0
UNION ALL
SELECT 'PersonCount', COUNT(*) FROM [Person]
UNION ALL
SELECT 'CathegoryCount', COUNT(*) FROM [Category]
First select with WHERE 1=0 is for create column header names only and is not necessary.
Try this.
select * from
(select count(*) cnt1
from Table1) t1
join
(select count(*) as cnt2
from Table2) t2 on 1=1
Related
I want to see counts have Tables at 1 time, instead of Running each.
For EX:
select COUNT(*) from "Fact_MASTER ";
select COUNT(*) from "Dim_MASTER ";
select COUNT(*) from "Fact2 ";
select COUNT(*) from "Dim2";
select COUNT(*) from "Fact3";
select COUNT(*) from "Dim3"
Is there any way we can write a CTE to pull as Record count for each in a temp table or so like below:
You can use union all:
select 'Fact_MASTER', COUNT(*) from "Fact_MASTER " union all
select 'Dim_MASTER', COUNT(*) from "Dim_MASTER " union all
select 'Fact2', COUNT(*) from "Fact2 " union all
select 'Dim2', COUNT(*) from "Dim2" union all
select 'Fact3', COUNT(*) from "Fact3" union all
select 'Dim3', COUNT(*) from "Dim3"
It looks like you want each count in a separate column. If so, you can turn each query to a separate subquery, and select them:
select
(select count(*) from "Fact_MASTER") as fact_master,
(select count(*) from "Dim_MASTER ") as dim_master,
(select count(*) from "Fact2") as fact2,
(select count(*) from "Dim2") as dim2,
(select count(*) from "Fact3") as fact3
(select count(*) from "Dim3") as dim3
Have you tried simply running:
SHOW TABLES;
If you then want to use that information for something else, you can then follow-up with something like:
select "rows" as cnt
from table(result_scan(last_query_id()))
where "name" in (...);
If you have a set list of tables that you want to PIVOT you can also use the result_scan() function to pivot the data:
https://docs.snowflake.com/en/sql-reference/constructs/pivot.html
i need help on HAVING COUNT , i have a result set of data below:
CREATE TABLE #tmpTest1 (Code VARCHAR(50), Name VARCHAR(100))
INSERT INTO [#tmpTest1]
(
[Code],
[Name]
)
SELECT '160215-039','ROBIN'
UNION ALL SELECT '160215-039','ROBIN'
UNION ALL SELECT '160215-046','SENGAROB'
UNION ALL SELECT '160215-046','BABYPANGET'
UNION ALL SELECT '160215-045','JONG'
UNION ALL SELECT '160215-045','JAPZ'
UNION ALL SELECT '160215-044','AGNES'
UNION ALL SELECT '160215-044','AGNES'
UNION ALL SELECT '160215-041','BABYTOT'
UNION ALL SELECT '160215-041','BABYTOT'
UNION ALL SELECT '160215-041','BABYTOT'
i want to show only the rows that have the same code but different name , so in this case my expected result is below since those are have the same code but different name:
160215-045 JAPZ
160215-045 JONG
160215-046 BABYPANGET
160215-046 SENGAROB
but when i try to group the two columns then use the having count, below is my query:
SELECT [Code], [Name] FROM [#tmpTest1]
GROUP BY [Code], [Name] HAVING COUNT([Code]) > 1
It gives me wrong result below which have the rows that have the same code and name, it is the opposite of what i want.
160215-044 AGNES
160215-041 BABYTOT
160215-039 ROBIN
How can i get my expected output ?
Thanks in advance, any help would much appreciated.
I believe this query will give you the result you want, although your original question is a bit unclear.
SELECT t1.[Code], t1.[Name]
FROM [#tmpTest1] t1
INNER JOIN
(
SELECT [Code]
FROM [#tmpTest1]
GROUP BY [Code]
HAVING COUNT(DISTINCT [Name]) > 1
) t2
ON t1.[Code] = t2.[Code]
Follow the link below for a running demo:
SQLFiddle
If you want rows with the same code and name, then use window functions:
select t.*
from (select t.*, count(*) over (partition by code, name) as cnt
from #temptest1 t
) t
where cnt >= 2;
From your comment
if there is 1 different name for the codes , i want to show those
records for me to know that there is one differs to others..
This sounds like an exists query because you want to check if another row with the same code but different name exists.
select * from [#tmpTest1] t1
where exists (
select 1 from [#tmpTest] t2
where t2.code = t1.code
and t2.name <> t1.name
)
since I am not as good with more complex SQL SELECT Statements I thought of just asking here, since it's hard to find something right on topic.
I got two tables who have exactly the same structure like
TABLE A (id (INT(11)), time (VARCHAR(10));)
TABLE B (id (INT(11)), time (VARCHAR(10));)
Now I want a single SELECT to count the entrys of an specific id in both tables.
SELECT COUNT(*) FROM TABLE A WHERE id = '1';
SELECT COUNT(*) FROM TABLE B WHERE id = '1';
So I thought it would be much better for the database performance if I use one SELECT instead of one.
Thanks for helping out
SELECT COUNT(*) as count, 'tableA' as table_name FROM TABLEA WHERE id = '1'
union all
SELECT COUNT(*), 'tableB' FROM TABLEB WHERE id = '1'
If you want the separate counts in a single row, you can use subqueries
SELECT
(SELECT COUNT(*) FROM TABLE A WHERE id = '1') a_count,
(SELECT COUNT(*) FROM TABLE B WHERE id = '1') b_count;
You could do it like:
select count(*)
from (
select id from t1 where id = 1
union all
select id from t2 where id = 1
) as t
Another alternative is:
select sum(cnt)
from (
select count(*) as cnt from t1 where id = 1
union all
select count(*) as cnt from t2 where id = 1
) as t
I tried the sql query given below:
SELECT * FROM (SELECT *
FROM TABLE_A ORDER BY COLUMN_1)DUMMY_TABLE
UNION ALL
SELECT * FROM TABLE_B
It results in the following error:
The ORDER BY clause is invalid in views, inline functions, derived
tables, subqueries, and common table expressions, unless TOP or FOR
XML is also specified.
I need to use order by in union all. How do I accomplish this?
SELECT *
FROM
(
SELECT * FROM TABLE_A
UNION ALL
SELECT * FROM TABLE_B
) dum
-- ORDER BY .....
but if you want to have all records from Table_A on the top of the result list, the you can add user define value which you can use for ordering,
SELECT *
FROM
(
SELECT *, 1 sortby FROM TABLE_A
UNION ALL
SELECT *, 2 sortby FROM TABLE_B
) dum
ORDER BY sortby
You don't really need to have parenthesis. You can sort directly:
SELECT *, 1 AS RN FROM TABLE_A
UNION ALL
SELECT *, 2 AS RN FROM TABLE_B
ORDER BY RN, COLUMN_1
Not an OP direct response, but I thought I would jimmy in here responding to the the OP's ERROR messsage, which may point you in another direction entirely!
All these answers are referring to an overall ORDER BY once the record set has been retrieved and you sort the lot.
What if you want to ORDER BY each portion of the UNION independantly, and still have them "joined" in the same SELECT?
SELECT pass1.* FROM
(SELECT TOP 1000 tblA.ID, tblA.CustomerName
FROM TABLE_A AS tblA ORDER BY 2) AS pass1
UNION ALL
SELECT pass2.* FROM
(SELECT TOP 1000 tblB.ID, tblB.CustomerName
FROM TABLE_B AS tblB ORDER BY 2) AS pass2
Note the TOP 1000 is an arbitary number. Use a big enough number to capture all of the data you require.
There will be times when you need to do something like this :
Pull top 5 from table 1 based on a sort
and bottom 5 from table 2 based on another sort
and union these together.
solution
select * from (
-- top 5 records
select top 5 col1, col2, col3
from table1
group by col1, col2
order by col3 desc ) z
union all
select * from (
-- bottom 5 records
select top 5 col1, col2, col3
from table2
group by col1, col2
order by col3 ) z
this was the only way i was able to get around the error and worked fine for me.
SELECT * FROM (SELECT *
FROM TABLE_A ORDER BY COLUMN_1)DUMMY_TABLE
UNION ALL
SELECT * FROM TABLE_B
ORDER BY 2;
2 is column number here .. In Oracle SQL you can use the column number by which you want to sort the data
This solved my SELECT statement:
SELECT * FROM
(SELECT id,name FROM TABLE_A
UNION ALL
SELECT id,name FROM TABLE_B ) dum
order by dum.id , dum.name
where id and name columns available in tables and you can use your columns .
Simply use that , no need parenthesis or anything else
SELECT *, id as TABLE_A_ID FROM TABLE_A
UNION ALL
SELECT *, id as TABLE_B_ID FROM TABLE_B
ORDER BY TABLE_A_ID, TABLE_B_ID
ORDER BY after the last UNION should apply to both datasets joined by union.
The solution shown below:
SELECT *,id AS sameColumn1 FROM Locations
UNION ALL
SELECT *,id AS sameColumn2 FROM Cities
ORDER BY sameColumn1,sameColumn2
select CONCAT(Name, '(',substr(occupation, 1, 1), ')') AS f1
from OCCUPATIONS
union
select temp.str AS f1 from
(select count(occupation) AS counts, occupation, concat('There are a total of ' ,count(occupation) ,' ', lower(occupation),'s.') As str from OCCUPATIONS group by occupation order by counts ASC, occupation ASC
) As temp
order by f1
I need to count rows in more than one table in SQL Server 2008. I do this:
select count(*) from (select * from tbl1 union all select * from tbl2)
But it gives me an error of incorrect syntax near ). Why?
PS. The actual number of tables can be more than 2.
In case you have different number of columns in your tables try this way
SELECT count(*)
FROM (
SELECT NULL as columnName
FROM tbl1
UNION ALL
SELECT NULL
FROM tbl2
) T
try this:
You have to give a name to your derived table
select count(*) from
(select * from tbl1 union all select * from tbl2)a
I think you have to alias the SELECT in the FROM clause:
select count(*)
from
(
select * from tbl1
union all
select * from tbl2
) AS SUB
You also need to ensure that the * in both tables tbl1 and tbl2 return exactly the same number of columns and they have to be matched in their type.
I don't like doing the union before doing the count. It gives the SQL optimizer an opportunithy to choose to do more work.
AlexK's (deleted) solution is fine. You could also do:
select (select count(*) from tbl1) + (select count(*) from tbl2) as cnt