NoFlo - how to start a graph / network - noflo

Pure Data has a loadbang component, which does what it says: sends one bang when the graph starts running. NoFlo's core/Kick doesn't send its data until its IN input is hit, and you can't save a bang IIP in noflo-ui.

core/Repeat with an IIP (any string) on the IN port will do what you're looking for. Here is a browser example that shows a popup alert when the network starts:
loadbang(core/Repeat) OUT -> IN alert(core/MakeFunction)
'alert("hi");' -> FUNCTION alert
':-)' -> IN loadbang
Related discussion: https://github.com/noflo/noflo-ui/issues/97

Related

How to close a QInputDialog with after a defined amount of time

I'm currently working on an application that run in the background and sometime create an input dialog for the user to answer. If the user doesn't interact, I'd like to close the dialog after 30 seconds. I made a QThread that act like a timer and the "finished" signal should close the dialog. I unfortunately cannot find a way to close it.
At this point I'm pretty much lost. I completely new to QThread and a beginner in PyQt5
Here is a simplified version of the code (we are inside a class running a UI):
def Myfunction(self,q):
# q : [q1,q2,q3]
self.popup = counter_thread()
self.popup.start()
self.dial = QInputDialog
self.popup.finished.connect(self.dial.close)
text, ok = self.dial.getText(self, 'Time to compute !', '%s %s %s = ?'%(q[0], q[2], q[1]))
#[...]
I tried ".close()" and others but i got this error message:
TypeError: close(self): first argument of unbound method must have type 'QWidget'
I did it in a separated function but got the same problem...
You cannot close it because the self.dial you created is just an alias (another reference) to a class, not an instance.
Also, getText() is a static function that internally creates the dialog instance, and you have no access to it.
While it is possible to get that dialog through some tricks (installing an event filter on the QApplication), there's no point in complicating things: instead of using the static function, create a full instance of QInputDialog.
def Myfunction(self,q):
# q : [q1,q2,q3]
self.popup = counter_thread()
self.dial = QInputDialog(self) # <- this is an instance!
self.dial.setInputMode(QInputDialog.TextInput)
self.dial.setWindowTitle('Time to compute !')
self.dial.setLabelText('%s %s %s = ?'%(q[0], q[2], q[1]))
self.popup.finished.connect(self.dial.reject)
self.popup.start()
if self.dial.exec():
text = self.dial.textValue()
Note that I started the thread just before showing the dialog, in the rare case it may return immediately, and also because, for the same reason, the signal should be connected before starting it.

Why are my flows not connecting?

Just starting with noflo, I'm baffled as why I'm not able to get a simple flow working. I started today, installing noflo and core components following the example pages, and the canonical "Hello World" example
Read(filesystem/ReadFile) OUT -> IN Display(core/Output)
'package.json' -> IN Read
works... so far fine, then I wanted to change it slightly adding "noflo-rss" to the mix, and then changing the example to
Read(rss/FetchFeed) OUT -> IN Display(core/Output)
'http://xkcd.com/rss.xml' -> IN Read
Running like this
$ /node_modules/.bin/noflo-nodejs --graph graphs/rss.fbp --batch --register=false --debug
... but no cigar -- there is no output, it just sits there with no output at all
If I stick a console.log into the sourcecode of FetchFeed.coffee
parser.on 'readable', ->
while item = #read()
console.log 'ITEM', item ## Hack the code here
out.send item
then I do see the output and the content of the RSS feed.
Question: Why does out.send in rss/FetchFeed not feed the data to the core/Output for it to print? What dark magic makes the first example work, but not the second?
When running with --batch the process will exit when the network has stopped, as determined by a non-zero number of open connections between nodes.
The problem is that rss/FetchFeed does not open a connection on its outport, so the connection count drops to zero and the process exists.
One workaround is to run without --batch. Another one I just submitted as a pull request (needs review).

Elm output port is not working with a signal derived from StartApp

We're learning Elm basics and building a simple application with some audio output with the following setup:
We are using Elm's StartApp.
We have ports/audio.js with some POC audio logic (and console.log).
ATM we are using elm-live to run the application.
With a signal derived from Time.every the port works (code in ports/audio.js is run). In addition, we get "ping" logs with Debug.log.
port audio : Signal Int
port audio =
Signal.map (always 400) (Time.every Time.second)
|> Signal.map (Debug.log "ping")
However, when we use a signal derived from StartApp's App.model, we get a signal (since "ping" logs with Debug.log are logged) but port to JS doesn't work (code in ports/audio.js is not run)?
port audio : Signal Int
port audio =
Signal.map (always 400) signalDerivedFromStartApp
|> Signal.map (Debug.log "ping")
This might be some basic thing related to Elm signals/ports/StartApp?
Our expert friend found the issue: Our setup was broken since we used Elm.main at two places
ports/audio.js had Elm.worker(Elm.Main, {});
index.html had script with Elm.fullscreen(Elm.Main)
-> after removing Elm.worker things from audio.js and plugging audio.js to port implementation at index.html things were fixed.
(This is probably not a perfect/final solution for the case but fixed the issue for our current setup)

How to print a message within a process when it gets the right from another process in erlang?

I'm all new to erlang, and i got this task:
Write a function "setalarm(T,Message)" what starts two processes at
the same time. After T miliseconds the first process sends a message
to the second process, and that message will be the Message arg.
It's forbidden to use function library, only primitives (send, receive, spawn)
Me as a novice useful to write more code, so I suggest such an option:
setalarm(T,Message)->
S = spawn(sotest,second,[]),
Pid = spawn(sotest,first,[S,T,Message]).
first(Pid,T,Message) ->
receive
after T -> Pid ! Message
end.
second() ->
receive
Message -> io:format("The message is ~p~n",[Message])
end.

Erlang process event error

I'm basically following the tutorial on this site Learn you some Erlang:Designing a concurrent application and I tried to run the code below with the following commands and got an error on line 48. I did turn off my firewall just in case that was the problem but no luck. I'm on windows xp SP3.
9> c(event).
{ok,event}
10> f().
ok
11> event:start("Event",0).
=ERROR REPORT==== 9-Feb-2013::15:05:07 ===
Error in process <0.61.0> with exit value: {function_clause,[{event,time_to_go,[0],[{file,"event.erl"},{line,48}]},{event,init,3,[{file,"event.erl"},{line,31}]}]}
<0.61.0>
12>
-module(event).
-export([start/2, start_link/2, cancel/1]).
-export([init/3, loop/1]).
-record(state, {server,
name="",
to_go=0}).
%%% Public interface
start(EventName, DateTime) ->
spawn(?MODULE, init, [self(), EventName, DateTime]).
start_link(EventName, DateTime) ->
spawn_link(?MODULE, init, [self(), EventName, DateTime]).
cancel(Pid) ->
%% Monitor in case the process is already dead
Ref = erlang:monitor(process, Pid),
Pid ! {self(), Ref, cancel},
receive
{Ref, ok} ->
erlang:demonitor(Ref, [flush]),
ok;
{'DOWN', Ref, process, Pid, _Reason} ->
ok
end.
%%% Event's innards
init(Server, EventName, DateTime) ->
loop(#state{server=Server,
name=EventName,
to_go=time_to_go(DateTime)}).
%% Loop uses a list for times in order to go around the ~49 days limit
%% on timeouts.
loop(S = #state{server=Server, to_go=[T|Next]}) ->
receive
{Server, Ref, cancel} ->
Server ! {Ref, ok}
after T*1000 ->
if Next =:= [] ->
Server ! {done, S#state.name};
Next =/= [] ->
loop(S#state{to_go=Next})
end
end.
%%% private functions
time_to_go(TimeOut={{_,_,_}, {_,_,_}}) ->
Now = calendar:local_time(),
ToGo = calendar:datetime_to_gregorian_seconds(TimeOut) -
calendar:datetime_to_gregorian_seconds(Now),
Secs = if ToGo > 0 -> ToGo;
ToGo =< 0 -> 0
end,
normalize(Secs).
%% Because Erlang is limited to about 49 days (49*24*60*60*1000) in
%% milliseconds, the following function is used
normalize(N) ->
Limit = 49*24*60*60,
[N rem Limit | lists:duplicate(N div Limit, Limit)].
It's running purely locally on your machine so the firewall will not affect it.
The problem is the second argument you gave when you started it event:start("Event",0).
The error reason:
{function_clause,[{event,time_to_go,[0],[{file,"event.erl"},{line,48}]},{event,init,3,[{file,"event.erl"},{line,31}]}]}
says that it is a function_clause error which means that there was no clause in the function definition which matched the arguments. It also tells you that it was the function event:time_to_go/1 on line 48 which failed and that it was called with the argument 0.
It you look at the function time_to_go/ you will see that it expects its argument to be a tuple of 2 elements where each element is a tuple of 3 elements:
time_to_go(TimeOut={{_,_,_}, {_,_,_}}) ->
The structure of this argument is {{Year,Month,Day},{Hour,Minute,Second}}. If you follow this argument backwards you that time_to_go/ is called from init/3 where the argument to time_to_go/1, DateTime, is the 3rd argument to init/3. Almost there now. Now init/3 is the function which the process spawned in start/2 (and start_link/2) and the 3rd argument toinit/3is the second argument tostart/2`.
So when you call event:start("Event",0). it is the 0 here which is passed into the call time_to_go/1 function in the new peocess. And the format is wrong. You should be calling it with something like event:start("Event", {{2013,3,24},{17,53,62}}).
To add background to rvirding's answer, you get the error because the
example works up until the final code snippet as far
as I know. The normalize function is used first, which deals with the
problem. Then the paragraph right after the example in the question
above, the text says:
And it works! The last thing annoying with the event module is that we
have to input the time left in seconds. It would be much better if we
could use a standard format such as Erlang's datetime ({{Year, Month,
Day}, {Hour, Minute, Second}}). Just add the following function that
will calculate the difference between the current time on your
computer and the delay you inserted:
The next snippet introduces the code bit that takes only a date/time and
changes it to the final time left.
I could not easily link to all transitional versions of the file, which
is why trying the linked file directly with the example doesn't work
super easily in this case. If the code is followed step by step, snippet
by snippet, everything should work fine. Sorry for the confusion.