Scenario : I am working on Users Accounts where Users add amount to there account (Credit) and they withdraw their desire amount from their account (Debit), all is going correct but when User credit or debit on same dates it gives me wrong result (Balance). here refno is reference of user. here is my Query
declare #startdate date='2013-01-02',
#enddate date='2013-01-12';
With summary(id,refno,transdate,cr,dr,balance)
as
(
select id,
RefNo,
Cast(TransDate as Varchar),
cr,
dr,
(cr-dr)+( Select ISNULL(Sum(l.Cr-l.Dr) ,0)
From Ledger l
Where l.TransDate<Ledger.TransDate and refno=001 ) as balance
from Ledger
),
openingbalance(id,refno,transdate,cr,dr,balance)
As (
select top 1 '' id,'OPENING BAL','','','',balance
from summary
where transdate<#startdate
order by transdate desc
)
select *
from openingbalance
union
Select *
From summary
where transdate between #startdate and #enddate and refno=001 order by transdate
If you are using SQL 2012 or above, then instead of
SELECT id, RefNo, TransDate,cr, dr, (cr-dr) + (Select ISNULL(Sum(l.Cr-l.Dr) ,0)
FROM Ledger l
WHERE Cast(l.TransDate as datetime) < Cast(Ledger.TransDate as datetime)
AND refno=001) as balance from Ledger
Use:
SELECT id, RefNo, TransDate, cr, dr, SUM(cr- dr) OVER(ORDER BY TransDate ROWS
BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW) AS balance
The issue is because when you query for the previous balance you are only looking at records that have a transdate earlier than the current record, so this means any records that have the same date will not be included.
The solution here would be to use a more unique sequential value, in your example you could use the ID value as the sequential identifier instead. However, ID values are not always the best for ensuring sequence. I would recommend extending your transdate column to use a more precise value and include the time of the transactions. Seconds would likely be enough precision if you can guarantee that there will never be multiple transactions made within a given second, but whatever you decide you need to be confident there will not be any duplicates.
In an attempt to provide a code change solution that will work with your existing data you can try the following, which uses the id value to determine if a record is prior to the current record:
Change the following line:
Where l.TransDate<Ledger.TransDate and refno=001 ) as balance
to this:
Where l.ID<Ledger.ID and refno=001 ) as balance
After hint by #musefan i made changes to query and it is working as i want. here is query for Date Base
declare #startdate date='2013-01-02',
#enddate date='2013-01-12';
With summary(id,refno,transdate,cr,dr,balance)
as
(
select id,
RefNo,
TransDate,
cr,
dr,
(cr-dr)+( Select ISNULL(Sum(l.Cr-l.Dr) ,0)
From Ledger l
Where Cast(l.TransDate as datetime)< Cast(Ledger.TransDate as datetime) and refno=001 ) as balance
from Ledger
),
openingbalance(id,refno,transdate,cr,dr,balance)
As (
select top 1 '' id,'OPENING BAL','','','',balance
from summary
where transdate<#startdate
order by transdate desc
)
select id,refno,Cast(TransDate as varchar) as datetime,cr,dr,balance
from openingbalance
union
Select id,refno,Cast(TransDate as varchar)as datetime,cr,dr,balance
From summary
where transdate between #startdate and #enddate and refno=001 order by Cast(TransDate as varchar)
and Another Query Id Based
declare #startdate date='2013-01-02',
#enddate date='2013-01-12';
With summary(id,refno,transdate,cr,dr,balance)
as
(
select id,
RefNo,
TransDate,
cr,
dr,
(cr-dr)+( Select ISNULL(Sum(l.Cr-l.Dr) ,0)
From Ledger l
Where l.id < Ledger.id and refno=001 ) as balance
from Ledger
),
openingbalance(id,refno,transdate,cr,dr,balance)
As (
select top 1 '' id,'OPENING BAL','','','',balance
from summary
where transdate<#startdate
order by transdate desc
)
select id,refno,Cast(TransDate as varchar) as datetime,cr,dr,balance
from openingbalance
union
Select id,refno,Cast(TransDate as varchar)as datetime,cr,dr,balance
From summary
where transdate between #startdate and #enddate and refno=001 order by id
Related
I have some prices for the month of January.
Date,Price
1,100
2,100
3,115
4,120
5,120
6,100
7,100
8,120
9,120
10,120
Now, the o/p I need is a non-overlapping date range for each price.
price,from,To
100,1,2
115,3,3
120,4,5
100,6,7
120,8,10
I need to do this using SQL only.
For now, if I simply group by and take min and max dates, I get the below, which is an overlapping range:
price,from,to
100,1,7
115,3,3
120,4,10
This is a gaps-and-islands problem. The simplest solution is the difference of row numbers:
select price, min(date), max(date)
from (select t.*,
row_number() over (order by date) as seqnum,
row_number() over (partition by price, order by date) as seqnum2
from t
) t
group by price, (seqnum - seqnum2)
order by min(date);
Why this works is a little hard to explain. But if you look at the results of the subquery, you will see how the adjacent rows are identified by the difference in the two values.
SELECT Lag.price,Lag.[date] AS [From], MIN(Lead.[date]-Lag.[date])+Lag.[date] AS [to]
FROM
(
SELECT [date],[Price]
FROM
(
SELECT [date],[Price],LAG(Price) OVER (ORDER BY DATE,Price) AS LagID FROM #table1 A
)B
WHERE CASE WHEN Price <> ISNULL(LagID,1) THEN 1 ELSE 0 END = 1
)Lag
JOIN
(
SELECT [date],[Price]
FROM
(
SELECT [date],Price,LEAD(Price) OVER (ORDER BY DATE,Price) AS LeadID FROM [#table1] A
)B
WHERE CASE WHEN Price <> ISNULL(LeadID,1) THEN 1 ELSE 0 END = 1
)Lead
ON Lag.[Price] = Lead.[Price]
WHERE Lead.[date]-Lag.[date] >= 0
GROUP BY Lag.[date],Lag.[price]
ORDER BY Lag.[date]
Another method using ROWS UNBOUNDED PRECEDING
SELECT price, MIN([date]) AS [from], [end_date] AS [To]
FROM
(
SELECT *, MIN([abc]) OVER (ORDER BY DATE DESC ROWS UNBOUNDED PRECEDING ) end_date
FROM
(
SELECT *, CASE WHEN price = next_price THEN NULL ELSE DATE END AS abc
FROM
(
SELECT a.* , b.[date] AS next_date, b.price AS next_price
FROM #table1 a
LEFT JOIN #table1 b
ON a.[date] = b.[date]-1
)AA
)BB
)CC
GROUP BY price, end_date
I have a table which has the following columns: DeskID *, ProductID *, Date *, Amount (where the columns marked with * make the primary key). The products in use vary over time, as represented in the image below.
Table format on the left, and a (hopefully) intuitive representation of the data on the right for one desk
The objective is to have the sum of the latest amounts of products by desk and date, including products which are no longer in use, over a date range.
e.g. using the data above the desired table is:
So on the 1st Jan, the sum is 1 of Product A
On the 2nd Jan, the sum is 2 of A and 5 of B, so 7
On the 4th Jan, the sum is 1 of A (out of use, so take the value from the 3rd), 5 of B, and 2 of C, so 8 in total
etc.
I have tried using a partition on the desk and product ordered by date to get the most recent value and turned the following code into a function (Function1 below) with #date Date parameter
select #date 'Date', t.DeskID, SUM(t.Amount) 'Sum' from (
select #date 'Date', t.DeskID, t.ProductID, t.Amount
, row_number() over (partition by t.DeskID, t.ProductID order by t.Date desc) as roworder
from Table1 t
where 1 = 1
and t.Date <= #date
) t
where t.roworder = 1
group by t.DeskID
And then using a utility calendar table and cross apply to get the required values over a time range, as below
select * from Calendar c
cross apply Function1(c.CalendarDate)
where c.CalendarDate >= '20190101' and c.CalendarDate <= '20191009'
This has the expected results, but is far too slow. Currently each desk uses around 50 products, and the products roll every month, so after just 5 years each desk has a history of ~3000 products, which causes the whole thing to grind to a halt. (Roughly 30 seconds for a range of a single month)
Is there a better approach?
Change your function to the following should be faster:
select #date 'Date', t.DeskID, SUM(t.Amount) 'Sum'
FROM (SELECT m.DeskID, m.ProductID, MAX(m.[Date) AS MaxDate
FROM Table1 m
where m.[Date] <= #date) d
INNER JOIN Table1 t
ON d.DeskID=t.DeskID
AND d.ProductID=t.ProductID
and t.[Date] = d.MaxDate
group by t.DeskID
The performance of TVF usually suffers. The following removes the TVF completely:
-- DROP TABLE Table1;
CREATE TABLE Table1 (DeskID int not null, ProductID nvarchar(32) not null, [Date] Date not null, Amount int not null, PRIMARY KEY ([Date],DeskID,ProductID));
INSERT Table1(DeskID,ProductID,[Date],Amount)
VALUES (1,'A','2019-01-01',1),(1,'A','2019-01-02',2),(1,'B','2019-01-02',5),(1,'A','2019-01-03',1)
,(1,'B','2019-01-03',4),(1,'C','2019-01-03',3),(1,'B','2019-01-04',5),(1,'C','2019-01-04',2),(1,'C','2019-01-05',2)
GO
DECLARE #StartDate date=N'2019-01-01';
DECLARE #EndDate date=N'2019-01-05';
;WITH cte_p
AS
(
SELECT DISTINCT DeskID,ProductID
FROM Table1
WHERE [Date] <= #EndDate
),
cte_a
AS
(
SELECT #StartDate AS [Date], p.DeskID, p.ProductID, ISNULL(a.Amount,0) AS Amount
FROM (
SELECT t.DeskID, t.ProductID
, MAX(t.Date) AS FirstDate
FROM Table1 t
WHERE t.Date <= #StartDate
GROUP BY t.DeskID, t.ProductID) f
INNER JOIN Table1 a
ON f.DeskID=a.DeskID
AND f.ProductID=a.ProductID
AND f.[FirstDate]=a.[Date]
RIGHT JOIN cte_p p
ON p.DeskID=a.DeskID
AND p.ProductID=a.ProductID
UNION ALL
SELECT DATEADD(DAY,1,a.[Date]) AS [Date], t.DeskID, t.ProductID, t.Amount
FROM Table1 t
INNER JOIN cte_a a
ON t.DeskID=a.DeskID
AND t.ProductID=a.ProductID
AND t.[Date] > a.[Date]
AND t.[Date] <= DATEADD(DAY,1,a.[Date])
WHERE a.[Date]<#EndDate
UNION ALL
SELECT DATEADD(DAY,1,a.[Date]) AS [Date], a.DeskID, a.ProductID, a.Amount
FROM cte_a a
WHERE NOT EXISTS(SELECT 1 FROM Table1 t
WHERE t.DeskID=a.DeskID
AND t.ProductID=a.ProductID
AND t.[Date] > a.[Date]
AND t.[Date] <= DATEADD(DAY,1,a.[Date]))
AND a.[Date]<#EndDate
)
SELECT [Date], DeskID, SUM(Amount)
FROM cte_a
GROUP BY [Date], DeskID;
I am trying to write SQL to calculate the start and end date from a single date called effective date for each item. Below is a idea of how my data looks. There are times when the last effective date for an item will be in the past so I want the end date for that to be a year from today. The other two items in the table example have effective dates in the future so no need to create and end date of a year from today.
I have tried a few ways but always run into bad data. Below is an example of my query and the bad results
select distinct tb1.itemid,tb1.EffectiveDate as startdate
, case
when dateadd(d,-1,tb2.EffectiveDate) < getdate()
or tb2.EffectiveDate is null
then getdate() +365
else dateadd(d,-1,tb2.EffectiveDate)
end as enddate
from #test tb1
left join #test as tb2 on (tb2.EffectiveDate > tb1.EffectiveDate
or tb2.effectivedate is null) and tb2.itemid = tb1.itemid
left join #test tb3 on (tb1.EffectiveDate < tb3.EffectiveDate
andtb3.EffectiveDate <tb2.EffectiveDate or tb2.effectivedate is null)
and tb1.itemid = tb3.itemid
left join #test tb4 on tb1.effectivedate = tb4.effectivedate \
and tb1.itemid = tb4.itemid
where tb1.itemID in (62741,62740, 65350)
Results - there is an extra line for 62740
Bad Results
I expect to see below since the first two items have a future end date no need to create an end date of today + 365 but the last one only has one effective date so we have to calculate the end date.
I think I've read your question correctly. If you could provide your expected output it would help a lot.
Test Data
CREATE TABLE #TestData (itemID int, EffectiveDate date)
INSERT INTO #TestData (itemID, EffectiveDate)
VALUES
(62741,'2016-06-25')
,(62741,'2016-06-04')
,(62740,'2016-07-09')
,(62740,'2016-06-25')
,(62740,'2016-06-04')
,(65350,'2016-05-28')
Query
SELECT
a.itemID
,MIN(a.EffectiveDate) StartDate
,MAX(CASE WHEN b.MaxDate > GETDATE() THEN b.MaxDate ELSE CONVERT(date,DATEADD(yy,1,GETDATE())) END) EndDate
FROM #TestData a
JOIN (SELECT itemID, MAX(EffectiveDate) MaxDate FROM #TestData GROUP BY itemID) b
ON a.itemID = b.itemID
GROUP BY a.itemID
Result
itemID StartDate EndDate
62740 2016-06-04 2016-07-09
62741 2016-06-04 2016-06-25
65350 2016-05-28 2017-06-24
This should do it:
SELECT itemid
,effective_date AS "Start"
,(SELECT MIN(effective_date)
FROM effective_date_tbl
WHERE effective_date > edt.effective_date
AND itemid = edt.itemid) AS "End"
FROM effective_date_tbl edt
WHERE effective_date <
(SELECT MAX(effective_date) FROM effective_date_tbl WHERE itemid = edt.itemid)
UNION ALL
SELECT itemid
,effective_date AS "Start"
,(SYSDATE + 365) AS "End"
FROM effective_date_tbl edt
WHERE 1 = ( SELECT COUNT(*) FROM effective_date_table WHERE itemid = edt.itemid )
ORDER BY 1, 2, 3;
I did this exercise for Items that have multiple EffectiveDate in the table
you can create this view
CREATE view [VW_TESTDATA]
AS ( SELECT * FROM
(SELECT ROW_NUMBER() OVER (ORDER BY Item,CONVERT(datetime,EffectiveDate,110)) AS ID, Item, DATA
FROM MyTable ) AS Q
)
so use a select to compare the same Item
select * from [VW_TESTDATA] as A inner join [VW_TESTDATA] as B on A.Item = B.Item and A.id = B.id-1
in this way you always minor and major Date
I did not understand how to handle dates with only one Item , but it seems the simplest thing and can be added to this query with a UNION ALL, because the view not cover individual Item
You also need to figure out how to deal with Item with two equal EffectiveDate
you should use the case when statement..
[wrong query because a misunderstand of the requirements]
SELECT
ItemID AS Item,
StartDate,
CASE WHEN EndDate < Sysdate THEN Sysdate + 365 ELSE EndDate END AS EndDate
FROM
(
SELECT tabStartDate.ItemID, tabStartDate.EffectiveDate AS StartDate, tabEndDate.EffectiveDate AS EndDate
FROM TableItems tabStartDate
JOIN TableItems tabEndDate on tabStartDate.ItemID = tabEndDate.ItemID
) TableDatesPerItem
WHERE StartDate < EndDate
update after clarifications in the OP and some comments
I found a solution quite portable, because it doesn't make use of partioning but endorses on a sort of indexing rule that make to correspond the dates of each item with others with the same id, in order of time's succession.
The portability is obviously related to the "difficult" part of query, while row numbering mechanism and conversion go adapted, but I think that it isn't a problem.
I sended a version for MySql that it can try on SQL Fiddle..
Table
CREATE TABLE ITEMS
(`ItemID` int, `EffectiveDate` Date);
INSERT INTO ITEMS
(`ItemID`, `EffectiveDate`)
VALUES
(62741, DATE(20160625)),
(62741, DATE(20160604)),
(62740, DATE(20160709)),
(62740, DATE(20160625)),
(62740, DATE(20160604)),
(62750, DATE(20160528))
;
Query
SELECT
RESULT.ItemID AS ItemID,
DATE_FORMAT(RESULT.StartDate,'%m/%d/%Y') AS StartDate,
CASE WHEN RESULT.EndDate < CURRENT_DATE
THEN DATE_FORMAT((CURRENT_DATE + INTERVAL 365 DAY),'%m/%d/%Y')
ELSE DATE_FORMAT(RESULT.EndDate,'%m/%d/%Y')
END AS EndDate
FROM
(
SELECT
tabStartDate.ItemID AS ItemID,
tabStartDate.StartDate AS StartDate,
tabEndDate.EndDate
,tabStartDate.IDX,
tabEndDate.IDX AS IDX2
FROM
(
SELECT
tabStartDateIDX.ItemID AS ItemID,
tabStartDateIDX.EffectiveDate AS StartDate,
#rownum:=#rownum+1 AS IDX
FROM ITEMS AS tabStartDateIDX
ORDER BY tabStartDateIDX.ItemID, tabStartDateIDX.EffectiveDate
)AS tabStartDate
JOIN
(
SELECT
tabEndDateIDX.ItemID AS ItemID,
tabEndDateIDX.EffectiveDate AS EndDate,
#rownum:=#rownum+1 AS IDX
FROM ITEMS AS tabEndDateIDX
ORDER BY tabEndDateIDX.ItemID, tabEndDateIDX.EffectiveDate
)AS tabEndDate
ON tabStartDate.ItemID = tabEndDate.ItemID AND (tabEndDate.IDX - tabStartDate.IDX = ((select count(*) from ITEMS)+1) )
,(SELECT #rownum:=0) r
UNION
(
SELECT
tabStartDateSingleItem.ItemID AS ItemID,
tabStartDateSingleItem.EffectiveDate AS StartDate,
tabStartDateSingleItem.EffectiveDate AS EndDate
,0 AS IDX,0 AS IDX2
FROM ITEMS AS tabStartDateSingleItem
Group By tabStartDateSingleItem.ItemID
HAVING Count(tabStartDateSingleItem.ItemID) = 1
)
) AS RESULT
;
I use SqlExpress
Following is the query using which I get the attached result.
SELECT ReceiptId, Date, Amount, Fine, [Transaction]
FROM (
SELECT ReceiptId, Date, Amount, 'DR' AS [Transaction]
FROM ReceiptCRDR
WHERE (Amount > 0)
UNION ALL
SELECT ReceiptId, Date, Amount, 'CR' AS [Transaction]
FROM ReceiptCR
WHERE (Amount > 0)
UNION ALL
SELECT strInvoiceNo AS ReceiptId, CONVERT(datetime, dtInvoiceDt, 103) AS Date, floatTotal AS Amount, 'DR' AS [Transaction]
FROM tblSellDetails
) AS t
ORDER BY Date
Result
want a new column which would show balance amount.
For example. 1 Row should show -2500, 2nd should -3900, 3rd should -700 and so on.
basically, it requires previous row' Account column's data and carry out calculation based on transaction type.
Sample Result
Well, that looks like SQL-Server , if you are using 2012+ , then use SUM() OVER() :
SELECT t.*,
SUM(CASE WHEN t.transactionType = 'DR'
THEN t.amount*-1
ELSE t.amount END)
OVER(PARTITION BY t.date ORDER BY t.receiptId,t.TransactionType DESC) as Cumulative_Col
FROM (YourQuery Here) t
This will SUM the value when its CR and the value*-1 when its DR
Right now I grouped by date, meaning each day will recalculate this column, if you want it for all time, replace the OVER() with this:
OVER(ORDER BY t.date,t.receiptId,t.TransactionType DESC) as Cumulative_Col
Also, I didn't understand why in the same date, for the same ReceiptId DR is calculated before CR , I've add it to the order by but if thats not what you want then explain the logic better.
i have tow field for example credit an debit in one table.
and i need to sum them and get result at each line for example :
date debit credit amount
2015/01/01 20 0 20
2015/01/02 0 5 15
2015/01/03 0 30 -15
i hope you help me to get the amount by a query
thanks
With SQL-Server 2012 or newer you can use this:
SELECT [date], debit, credit, amount,
SUM(debit-credit) OVER(ORDER BY [date] ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW) AS amount
FROM TableName
ORDER BY [date]
Read: OVER-clause, especially the ROWS | RANGE part
With other versions you have to use a correlated subquery:
SELECT [date], debit, credit, amount,
(SELECT SUM(debit-credit)
FROM TableName t2
WHERE [date] <= t1.[date]) AS amount
FROM TableName t1
ORDER BY [date]
I agree with Tim's answer, I added some extra lines:
declare #credit as table (
[date] datetime,
amount int
)
declare #debit as table (
[date] datetime,
amount int
)
insert into #debit values
('2015-01-01', 20)
insert into #credit values
('2015-01-02', 5),
('2015-01-03', 30)
select
[date], debit, credit, SUM(debit-credit) OVER(ORDER BY [date] ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW) AS amount
from(
select
[date], sum(debit) debit, sum(credit) credit
from
(
select
[date], 0 credit, d.amount debit
from
#debit d
union all
select
[date], c.amount credit, 0 debit
from
#credit c
) j group by j.date
) x