RANKING for counting phone numbers - sql

Question

Thanks for all your suggestions.It works fine on a small test data but I guess I under-estimated the total rows and plans so I guess I will have to post some biggers sample data
Here it is:
CREATE TABLE MasterTable
(`Date` datetime, `PhNO` int, `Plan_name` varchar(13), `Plan_price` varchar(3))
;
INSERT INTO MasterTable
(`Date`, `PhNO`, `Plan_name`, `Plan_price`)
VALUES
('2014-01-01 13:00:00', 3232222, 'Basepack1', '$32'),
('2014-01-01 13:00:00', 3232222, 'Basepack2', '$31'),
('2014-01-01 13:00:00', 3221111, 'Basepack6', '$21'),
('2014-01-01 13:00:00', 543222, 'BaseValuePack', '$76'),
('2014-01-01 13:00:00', 543222, 'Basepack1', '$30'),
('2014-01-01 13:00:00', 32322221, 'Basepack1', '$37'),
('2014-01-01 13:00:00', 32322221, 'Basepack2', '$21'),
('2014-01-01 13:00:00', 32322354, 'Basepack7', '$23'),
('2014-01-01 13:00:00', 32322254, 'Basepack8', '$11'),
('2014-01-01 13:00:00', 3267767, 'Non-base1', '$21'),
('2014-01-01 13:00:00', 3267762, 'Non-base1', '$21'),
('2014-01-01 13:00:00', 32677676, 'Non-base3', '$76'),
('2014-01-01 13:00:00', 5267767, 'Non-base9', '$21')
Now I basically want to group all the 'Non-base%' plans under 'Casual' category
Here is the desired output:
Date Plan_name Phone_no_count
'2014-01-01 13:00:00' 'Basepack1' 2
'2014-01-01 13:00:00' 'Basepack2' 0
'2014-01-01 13:00:00' 'Basepack6' 1
'2014-01-01 13:00:00' 'BaseValuepack' 1
'2014-01-01 13:00:00' 'Casual' 4
Thanks
...........................................
Previous request:
I need to count all the phone nos categorised by certain plans. But to group those plans, I need to rank them first based on their price.
Here is the ddl
CREATE TABLE MasterTable
(`Date` datetime, `PhNO` int, `Plan_name` varchar(13), `Plan_price` varchar(3))
;
INSERT INTO MasterTable
(`Date`, `PhNO`, `Plan_name`, `Plan_price`)
VALUES
('2014-01-01 13:00:00', 3232222, 'Basepack1', '$32'),
('2014-01-01 13:00:00', 3232222, 'Basepack2', '$31'),
('2014-01-01 13:00:00', 3221111, 'Basepack6', '$21'),
('2014-01-01 13:00:00', 543222, 'BaseValuePack', '$76'),
('2014-01-01 13:00:00', 543222, 'Basepack1', '$30'),
('2014-01-01 13:00:00', 32322221, 'Basepack1', '$37'),
('2014-01-01 13:00:00', 32322221, 'Basepack2', '$21')
;
Now the rule is, I only need to count a phone no once who has more than 1 plan based on their plan price(higher one) .
But there is also a scenario where a phone no has two different 'packs'- Basepack and valuepack, which means I need to count that phone no only once categorised under value pack(in this case we need to ignore the price).
Here is the desired output.
Date Plan_name Phone_no_count
-------------------------------------------------
'2014-01-01 13:00:00' 'Basepack1' 2
'2014-01-01 13:00:00' 'Basepack2' 0
'2014-01-01 13:00:00' 'Basepack6' 1
'2014-01-01 13:00:00' 'BaseValuepack' 1
How do I use the rank function to achieve this result?

Answer 1

Try this code, Assuming it is mysql as the code posted looks like mysql
SELECT date,
plan_name,
Sum((SELECT Count(1)
FROM mastertable T2
WHERE t2.phno = tt.phno
AND t2.date = Tt.date
AND ( tt.plan_price > t2.plan_price
OR TT.count = 1 ))) CNT
FROM (SELECT *,
(SELECT Count(1)
FROM mastertable Ti
WHERE ti.date = T.date
AND ti.phno = t.phno) AS Count
FROM mastertable T) Tt
GROUP BY date,
plan_name
Here is the SQL Fiddle Demo

Answer 2

;with cte as
(
select *,ROW_NUMBER()over(partition by phno order by plan_price desc)rn
from #MasterTable
)
,
cte1 as
(
select a.Plan_name,count(*)[Phone_no_count] from cte a
where rn=1
group by a.Plan_name
)
select distinct a.dates,a.Plan_name,isnull(b.Phone_no_count,0)[[Phone_no_count]
from #MasterTable a left join cte1 b on a.Plan_name=b.Plan_name