Is there a way to check how many shares of url is done on Google+?
The equivalent from Facebook and Twitter would be:
http://graph.facebook.com/http://stackoverflow.com
and
http://urls.api.twitter.com/1/urls/count.json?url=http://stackoverflow.com
Is there an equivalent on Google+?
Are you looking for this?
https://plusone.google.com/_/+1/fastbutton?url=http://stackoverflow.com
If you are searching for the text value, you can search the following line in the source code of the url:
<div id="aggregateCount" class="Oy">{NUMBER_OF_SHARES}</div>
The following JavaScript will extract the number of shares from the url:
parseInt(document.getElementById('aggregateCount').innerHTML.replace('.',''))
Related
I am using the Mendeley API to retrieve documents in the profile of a user.
Specifically, I am using this API:
GET https://api.mendeley.com/search/documents?view=all&limit=25&title=ONTOLOGY
I would like to search for all the documents that match a partial term, i.e. instead of the full word "ONTOLOGY" I would like to get the same result if I do an HTTP call like
GET https://api.mendeley.com/search/documents?view=all&limit=25&title=ONTOLO
How can I achieve that?
Should I put any jolly character?
I tried
ONTOLO*
ONTOLO$
ONTOLO?
with no luck.
I haven't found any documentation related to this feature.
Thanks!!
So I have this bit as a part of the a code that came with the html template that I purchased. I was told that in order for this to work, I need to use the absolute URL of 'api/tweet.php'.
This is all I one line:
(function($){$.fn.twittie=function(options){var settings=$.extend({'count':10,'hideReplies':false,'dateFormat':'%b/%d/%Y','template':'{{date}} - {{tweet}}'},options);var linking=function(tweet){var parts=tweet.split(' ');var twit='';for(var i=0,len=parts.length;i<len;i++){var text=parts[i];var link="https://twitter.com/#!/";if(text.indexOf('#')!==-1){text=''+text+''}if(text.indexOf('#')!==-1){text=''+text+''}if(text.indexOf('http://')!==-1){text=''+text+''}twit+=text+' '}return twit};var dating=function(twt_date){var time=twt_date.split(' ');twt_date=new Date(Date.parse(time[1]+' '+time[2]+', '+time[5]+' '+time[3]+' UTC'));var months=['January','February','March','April','May','June','July','August','September','October','November','December'];var _date={'%d':twt_date.getDate(),'%m':twt_date.getMonth()+1,'%b':months[twt_date.getMonth()].substr(0,3),'%B':months[twt_date.getMonth()],'%y':String(twt_date.getFullYear()).slice(-2),'%Y':twt_date.getFullYear()};var date=settings.dateFormat;var format=settings.dateFormat.match(/%[dmbByY]/g);for(var i=0,len=format.length;i<len;i++){date=date.replace(format[i],_date[format[i]])}return date};var templating=function(data){var temp=settings.template;var temp_variables=['date','tweet','avatar'];for(var i=0,len=temp_variables.length;i<len;i++){temp=temp.replace(new RegExp('{{'+temp_variables[i]+'}}','gi'),data[temp_variables[i]])}return temp};this.html('<span>Loading...</span>');var that=this;$.getJSON('api/tweet.php',{count:settings.count,exclude_replies:settings.hideReplies},function(twt){that.find('span').fadeOut('fast',function(){that.html('<ul></ul>');for(var i=0;i<settings.count;i++){if(twt[i]){var temp_data={date:dating(twt[i].created_at),tweet:linking(twt[i].text),avatar:'<img src="'+twt[i].user.profile_image_url+'" />'};that.find('ul').append('<li>'+templating(temp_data)+'</li>')}else{break}}})})}})(jQuery);
Does anyone know how to use or get the absolute URL of tweet.php? I've tried researching or doing a google search on it but none seem to work.
The location of the tweet.php is
http://exampledomain.com/api/tweet.php
EDIT:
This is the thread discussion that I posted on their support website. I didn't share the link since it requires visitors to open an account with them just to view responses
Support Thread Picture
According to the Tweetie jQuery plugin documentation, you have to use the apiPath option:
$('.foo').twittie({
'apiPath': 'http://exampledomain.com/api/tweet.php',
});
But specifying the domain is discouraged and unnecessary. So :
$('.foo').twittie({
'apiPath': '/api/tweet.php',
});
I am using google image search API. Till yesterday it was working, but today morning it says "This API is no longer available"
Is it officially closed, Or any error at my side
Request
https://ajax.googleapis.com/ajax/services/search/images?v=1.0&rsz=8&q=cute+kittens
Response
{"responseData": null, "responseDetails": "This API is no longer available.", "responseStatus": 403}
The answer I found was using Google's Custom Search Engine (CSE) API. Note that this is limited to 100 free requests per day.
Creating cx and modifying it to search for images
Create custom search engine at https://cse.google.com/cse/create/new based on your search criteria.
Choose sites to search (leave this blank if you want to search the entire web, otherwise you can enter a site to search in one particular site)
Enter a name and a language for your search engine.
Click "create." You can now find cx in your browser URL.
Under "Modify your search engine," click the "Control Panel" button. In the "edit" section you will find an "Image Search" label with an ON/OFF button, change it to ON. Click "update" to save your changes.
Conducting a search with the API
The API endpoint url is https://www.googleapis.com/customsearch/v1
The following JSON parameters are used for this API:
q: specifies search text
num: specifies number of results. Requires an integer value between 1 and 10 (inclusive)
start: the "offset" for the results, which result the search should start at. Requires an integer value between 1 and 101.
imgSize: the size of the image. I used "medium"
searchType: must be set to "image"
filetype: specifies the file type for the image. I used `"jpg", but you can leave this out if file extension doesn't matter to you.
key: an API key, obtained from https://console.developers.google.com/
cx: the custom search engine ID from the previous section
Simply make a GET request by passing above parameters as JSON to the API endpoint (also listed above).
Note: If you set a list of referrers in the search engine settings, visiting the URL via your browser will likely not work. You will need to make an AJAX call (or the equivalent from another language) from a server specified in this list. It will work for only the referrers which were specified in the configuration settings.
Reference:
https://developers.google.com/custom-search/json-api/v1/reference/cse/list
Now You can search images with Custom image search API.
You can do this with two steps:
Get CUSTOM_SEARCH_ID
Go to - https://cse.google.ru/cse/all
Here you must create new Search Engine. Do this and enable Image Search at there.
Screen(i am Russian... sorry)
then get this search engine ID. To do this press at Get Code button:
And there find line with cx = "here will be your CUSTOM_SEARCH_ID":
Ok. It's done, now second step:
Get SERVER_KEY
Go to google Console - https://console.developers.google.com/project
Press to Create project button, enter the name and other required information.
Pick this project and go to Enable Apis
Now find Custom Search Engine.
And Enable it.
Now we must go to Credentials and create new Server Key:
Ok. Now we can use Image Search.
Query:
https://www.googleapis.com/customsearch/v1?key=SERVER_KEY&cx=CUSTOM_SEARCH_ID&q=flower&searchType=image&fileType=jpg&imgSize=xlarge&alt=json
Replace the SERVER_KEY and CUSTOM_SEARCH_ID and call this request.
Limit: for free you can search only 100 images per day.
If this is just for your own purposes (not for production) and you're not planning to abuse Google Image Search, you can simply extract first image URL from Google search results using JSOUP.
For example:
Code to retrieve image URL of the first thumbnail:
public static String FindImage(String question, String ua) {
String finRes = "";
try {
String googleUrl = "https://www.google.com/search?tbm=isch&q=" + question.replace(",", "");
Document doc1 = Jsoup.connect(googleUrl).userAgent(ua).timeout(10 * 1000).get();
Element media = doc1.select("[data-src]").first();
String finUrl = media.attr("abs:data-src");
finRes= "<img src=\"" + finUrl.replace(""", "") + "\" border=1/>";
} catch (Exception e) {
System.out.println(e);
}
return finRes;
}
Guide:
question - image search term
ua - user agent of the browser
After I read several responses I compiled a response with images:
Access the website: https://developers.google.com/custom-search/v1/introduction, on the page you will find this part, so click in the button Get a Key:
Create or select a project, and then NEXT:
Copy the API KEY:
Access the website to create your CX: https://cse.google.com/cse/create/new, write some random domain like “www.anypage.com”, (after we will delete), select a language, and define some name for your search engine. Click on the Button CREATE.
Will see this page, then click in Control Panel:
Copy the Search engine ID for later (this is your CX). After you can set to search in all websites (active Search the entire web, select on the random website www.anypage.com then click on the button Delete) and you can active Image search. So will see like this:
And Using REST you can get the results, using this example code (searching for flower):
<html lang="pt">
<head>
<title>JSON Custom Search API Example</title>
</head>
<body>
<div id="content"></div>
<script>
function hndlr(response) {
console.log(response);
for (var i = 0; i < response.items.length; i++) {
var item = response.items[i];
// in production code, item.htmlTitle should have the HTML entities escaped.
document.getElementById("content").innerHTML += "<br>" + item.htmlTitle;
}
}
</script>
<script src="https://www.googleapis.com/customsearch/v1?key=API_KEY&cx=SEARCH_ENGINE_KEY&q=flower&searchType=image&callback=hndlr"></script>
</body>
</html>
The base code is found here: https://developers.google.com/custom-search/v1/using_rest
After setting your API_KEY (key) and your SEARCH ENGINE KEY (cx), the result will see like this:
Thanks to #Vijay Shegokar, #aftamat4ik and #Alladinian
This is the full URL template to be used
We can eliminate unnecessary parameters.
https://www.googleapis.com/customsearch/v1?q={searchTerms}&num={count?}&start={startIndex?}&lr={language?}&safe={safe?}&cx={cx?}&cref={cref?}&sort={sort?}&filter={filter?}&gl={gl?}&cr={cr?}&googlehost={googleHost?}&c2coff={disableCnTwTranslation?}&hq={hq?}&hl={hl?}&siteSearch={siteSearch?}&siteSearchFilter={siteSearchFilter?}&exactTerms={exactTerms?}&excludeTerms={excludeTerms?}&linkSite={linkSite?}&orTerms={orTerms?}&relatedSite={relatedSite?}&dateRestrict={dateRestrict?}&lowRange={lowRange?}&highRange={highRange?}&searchType={searchType}&fileType={fileType?}&rights={rights?}&imgSize={imgSize?}&imgType={imgType?}&imgColorType={imgColorType?}&imgDominantColor={imgDominantColor?}&alt=json
I am using
https://www.googleapis.com/customsearch/v1?key=ap_key&cx=cx&q=hello&searchType=image&imgSize=xlarge&alt=json&num=10&start=1
Change the API url to
Google Custom Image search
Provide the same parameters along with with API KEY and CX.
More Info and Explorer
The Yahoo Boss API is a reasonable substitute, although it's not free and the results are not quite as good.
UPDATE: YAHOO BOSS JSON Search API will discontinue on March 31, 2016
SerpAPI enables to search through Google Images and returns a clean json. it integrates with most of the programming languages: python, php, java, golang, nodejs...
https://serpapi.com/images-results
Google limit the number of search per day.
but this service provides unlimited searches...
looks like we need to implement google custom search API
https://developers.google.com/custom-search/
says so on top of the page you provided yourself
I'm using google CSE in my site. But I want to change the "No Result" string to a link, or redirect the page when no search result.
I tried noResultsString attribute but it accept String only. How can I use HTML Tag like<gcse:searchresults noResultsString="<a src='testSrc'>no-result link</a>"></gcse:searchresults>? Or can I redirect the result page when no-result?
Use JavaScript, then specify names or ids then the functions if there is no results.
Here is an intro tutorial that does not specify an id relating to your case, but is using timers for a redirect http://www.tutorialspoint.com/javascript/javascript_page_redirect.htm
I'm implementing a Compony newsfeed on a website and ran into the following problem. The LinkedIn API doesn't provide a direct URL to a company update. Looking at the LinkedIn site there are direct URL's and they're like this for example:
https://www.linkedin.com/company/1441/comments?topic=5849556347070205952&type=U&scope=1441&stype=C&a=5uHW&goback=%2Ebzo_*1_*1_*1_*1_*1_*1_*1_1441
Trying stuff out it seems that the parameters topic, type, scope, stype and a are mandatory for the URL to work.. (goback is the only one that isn't).
Using the LinkedIn API with the Company updates call I'm able to buid the direct url, except for the a parameter. The value is always 4 (for me unexplainable) characters long.
Has anyone ever successfully build a direct URL to a company update or can someone maybe explain the a parameter or how to generate its value?
Updated to new format
You can link directly to any update (company or user) using the following url:
https://www.linkedin.com/feed/update/urn:li:activity:[topic_id]
You can get [topic_id] by getting the last bit of the updateKey in the api response from Linkedin. When updateKey = UPDATE-c7352-6410848097894756353, your topic_id = 6410848097894756353.
In your example that would become https://www.linkedin.com/feed/update/urn:li:activity:5849556347070205952 which links directly to the specific update. The post is too old to work with the new link format
The url used to be
https://www.linkedin.com/nhome/updates/?topic=[topic_id]
Updated thanks to the comment from #sethpollack
For anyone trying to get the topic id from the API response object (as already commented on the OP question), the topic id is the value after the last hyphen of the updateKey property, which can be used with #Daan answer:
"updateKey": "UPDATE-cXXXX-YYYYYYYYYYYYYYYYYY"
Direct URL:
https://www.linkedin.com/nhome/updates?topic=[YYYYYYYYYYYYYYYYYY]
Using the URL format above, get the topic_id by opening the update in its own window/tab, look at the page source code in your browser and search for the string :activity: the long number after the string is the infamous topic_id