Get id of max value in group - sql

Question

I have a table and i would like to gather the id of the items from each group with the max value on a column but i have a problem.
SELECT group_id, MAX(time)
FROM mytable
GROUP BY group_id
This way i get the correct rows but i need the id:
SELECT id,group_id,MAX(time)
FROM mytable
GROUP BY id,group_id
This way i got all the rows. How could i achieve to get the ID of max value row for time from each group?
Sample Data
id = 1, group_id = 1, time = 2014.01.03
id = 2, group_id = 1, time = 2014.01.04
id = 3, group_id = 2, time = 2014.01.04
id = 4, group_id = 2, time = 2014.01.02
id = 5, group_id = 3, time = 2014.01.01
and from that i should get id: 2,3,5
Thanks!

Answer 1

Use your working query as a sub-query, like this:
SELECT `id`
FROM `mytable`
WHERE (`group_id`, `time`) IN (
SELECT `group_id`, MAX(`time`) as `time`
FROM `mytable`
GROUP BY `group_id`
)

Answer 2

Have a look at the below demo
DROP TABLE IF EXISTS mytable;
CREATE TABLE mytable(id INT , group_id INT , time_st DATE);
INSERT INTO mytable VALUES(1, 1, '2014-01-03'),(2, 1, '2014-01-04'),(3, 2, '2014-01-04'),(4, 2, '2014-01-02'),(5, 3, '2014-01-01');
/** Check all data **/
SELECT * FROM mytable;
+------+----------+------------+
| id | group_id | time_st |
+------+----------+------------+
| 1 | 1 | 2014-01-03 |
| 2 | 1 | 2014-01-04 |
| 3 | 2 | 2014-01-04 |
| 4 | 2 | 2014-01-02 |
| 5 | 3 | 2014-01-01 |
+------+----------+------------+
/** Query for Actual output**/
SELECT
id
FROM
mytable
JOIN
(
SELECT group_id, MAX(time_st) as max_time
FROM mytable GROUP BY group_id
) max_time_table
ON mytable.group_id = max_time_table.group_id AND mytable.time_st = max_time_table.max_time;
+------+
| id |
+------+
| 2 |
| 3 |
| 5 |
+------+

Answer 3

When multiple groups may contain the same value, you could use
SELECT subq.id
FROM (SELECT id,
value,
MAX(time) OVER (PARTITION BY group_id) as max_time
FROM mytable) as subq
WHERE subq.time = subq.max_time
The subquery here generates a new column (max_time) that contains the maximum time per group. We can then filter on time and max_time being identical. Note that this still returns multiple rows per group if the maximum value occurs multiple time within the same group.
Full example:
CREATE TABLE test (
id INT,
group_id INT,
value INT
);
INSERT INTO test (id, group_id, value) VALUES (1, 1, 100);
INSERT INTO test (id, group_id, value) VALUES (2, 1, 200);
INSERT INTO test (id, group_id, value) VALUES (3, 1, 300);
INSERT INTO test (id, group_id, value) VALUES (4, 2, 100);
INSERT INTO test (id, group_id, value) VALUES (5, 2, 300);
INSERT INTO test (id, group_id, value) VALUES (6, 2, 200);
INSERT INTO test (id, group_id, value) VALUES (7, 3, 300);
INSERT INTO test (id, group_id, value) VALUES (8, 3, 200);
INSERT INTO test (id, group_id, value) VALUES (9, 3, 100);
select * from test;
id | group_id | value
----+----------+-------
1 | 1 | 100
2 | 1 | 200
3 | 1 | 300
4 | 2 | 100
5 | 2 | 300
6 | 2 | 200
7 | 3 | 300
8 | 3 | 200
9 | 3 | 100
(9 rows)
SELECT subq.id
FROM (SELECT id,
value,
MAX(value) OVER (partition by group_id) as max_value
FROM test) as subq
WHERE subq.value = subq.max_value;
id
----
3
5
7
(3 rows)