Create custom Function or Stored Procedure - sql

I have a Hierarchy table with Master_id and Sub_id.
sub_id Master_id
2 1
3 2
4 1
5 3
6 7
I want to create an iterative function or stored procedure (I am not sure I never used any of them before) to create one more column which gives me the primary_master_Column (PMC)
sub_id Master_id PMC
2 1 1
3 2 1
4 1 1
5 3 1
6 7 7

select
Master_id, sub_id,
max(PMC) keep(dense_rank first order by lev desc) as PMC
from
(
select
sub_id as PMC, level lev,
connect_by_root(Master_id) as Master_id,
connect_by_root(sub_id) as sub_id
from your_table
connect by prior sub_id = Master_id
)
group by Master_id, sub_id
fiddle

SQL Fiddle
Oracle 11g R2 Schema Setup:
CREATE TABLE test (sub_id, Master_id) AS
SELECT 2, 1 FROM DUAL
UNION ALL SELECT 3, 2 FROM DUAL
UNION ALL SELECT 4, 1 FROM DUAL
UNION ALL SELECT 5, 3 FROM DUAL
UNION ALL SELECT 6, 7 FROM DUAL;
Query 1:
SELECT t.sub_id,
t.master_id,
CONNECT_BY_ROOT( t.master_id ) AS PMC
FROM test t
LEFT OUTER JOIN
test x
ON ( t.master_id = x.sub_id )
START WITH x.sub_id IS NULL
CONNECT BY PRIOR t.sub_id = t.master_id
Results:
| SUB_ID | MASTER_ID | PMC |
|--------|-----------|-----|
| 2 | 1 | 1 |
| 3 | 2 | 1 |
| 5 | 3 | 1 |
| 4 | 1 | 1 |
| 6 | 7 | 7 |
Query 2:
SELECT t.sub_id,
t.master_id,
CONNECT_BY_ROOT( t.master_id ) AS PMC
FROM test t
START WITH NOT EXISTS ( SELECT 'x' FROM test x WHERE t.master_id = x.sub_id )
CONNECT BY PRIOR t.sub_id = t.master_id
Results:
| SUB_ID | MASTER_ID | PMC |
|--------|-----------|-----|
| 2 | 1 | 1 |
| 3 | 2 | 1 |
| 5 | 3 | 1 |
| 4 | 1 | 1 |
| 6 | 7 | 7 |

Related

Filtering a table via another table's values

I have 2 tables:
Value
+----+-------+
| id | name |
+----+-------+
| 1 | Peter |
| 2 | Jane |
| 3 | Joe |
+----+-------+
Filter
+----+---------+------+
| id | valueid | type |
+----+---------+------+
| 1 | 1 | A |
| 2 | 1 | B |
| 3 | 1 | C |
| 4 | 1 | D |
| 5 | 2 | A |
| 6 | 2 | C |
| 7 | 2 | E |
| 8 | 3 | A |
| 9 | 3 | D |
+----+---------+------+
I need to retrieve the values from the Value table where the related Filter table does not contain the type 'B' or 'C'
So in this quick example this would be only Joe.
Please note this is a DB2 DB and i have limited permissions to run selects only.
Or also a NOT IN (<*fullselect*) predicate:
Only that my result is 'Joe', not 'Jane' - and the data constellation would point to that ...
WITH
-- your input, sans reserved words
val(id,nam) AS (
SELECT 1,'Peter' FROM sysibm.sysdummy1
UNION ALL SELECT 2,'Jane' FROM sysibm.sysdummy1
UNION ALL SELECT 3,'Joe' FROM sysibm.sysdummy1
)
,
filtr(id,valueid,typ) AS (
SELECT 1,1,'A' FROM sysibm.sysdummy1
UNION ALL SELECT 2,1,'B' FROM sysibm.sysdummy1
UNION ALL SELECT 3,1,'C' FROM sysibm.sysdummy1
UNION ALL SELECT 4,1,'D' FROM sysibm.sysdummy1
UNION ALL SELECT 5,2,'A' FROM sysibm.sysdummy1
UNION ALL SELECT 6,2,'C' FROM sysibm.sysdummy1
UNION ALL SELECT 7,2,'E' FROM sysibm.sysdummy1
UNION ALL SELECT 8,3,'A' FROM sysibm.sysdummy1
UNION ALL SELECT 9,3,'D' FROM sysibm.sysdummy1
)
-- real query starts here
SELECT
*
FROM val
WHERE id NOT IN (
SELECT valueid FROM filtr WHERE typ IN ('B','C')
)
;
-- out id | nam
-- out ----+-------
-- out 3 | Joe
Or also, a failing left join:
SELECT
val.*
FROM val
LEFT JOIN (
SELECT valueid FROM filtr WHERE typ IN ('B','C')
) filtr
ON filtr.valueid = val.id
WHERE valueid IS NULL
You can use EXISTS, as in:
select *
from value v
where not exists (
select null from filter f
where f.valueid = v.id and f.type in ('B', 'C')
);
Result:
ID NAME
--- -----
3 Joe
See running example at db<>fiddle.

Adding a row number respecting the order of each row

I have a table like this
id, period, tag
1 1 A
1 2 A
1 3 B
1 4 A
1 5 A
1 6 A
2 1 A
2 2 B
2 3 B
2 4 B
2 5 B
2 6 A
I would like to add a new column with a ranking, respecting the order of the row given my column 'period' to obtain something like this
id, period, tag rank
1 1 A 1
1 2 A 1
1 3 B 2
1 4 A 3
1 5 A 3
1 6 A 3
2 1 A 1
2 2 B 2
2 3 B 2
2 4 B 2
2 5 B 2
2 6 A 3
What can I do?
I try rank and dense_rank function without any success
And another candidate for CONDITIONAL_CHANGE_EVENT()
less code, and quite effective, too ...!
WITH
input(id,period,tag) AS (
SELECT 1,1,'A'
UNION ALL SELECT 1,2,'A'
UNION ALL SELECT 1,3,'B'
UNION ALL SELECT 1,4,'A'
UNION ALL SELECT 1,5,'A'
UNION ALL SELECT 1,6,'A'
UNION ALL SELECT 2,1,'A'
UNION ALL SELECT 2,2,'B'
UNION ALL SELECT 2,3,'B'
UNION ALL SELECT 2,4,'B'
UNION ALL SELECT 2,5,'B'
UNION ALL SELECT 2,6,'A'
)
SELECT
*
, CONDITIONAL_CHANGE_EVENT(tag) OVER(PARTITION BY id ORDER BY period) + 1 AS rank
FROM input;
-- out id | period | tag | rank
-- out ----+--------+-----+------
-- out 1 | 1 | A | 1
-- out 1 | 2 | A | 1
-- out 1 | 3 | B | 2
-- out 1 | 4 | A | 3
-- out 1 | 5 | A | 3
-- out 1 | 6 | A | 3
-- out 2 | 1 | A | 1
-- out 2 | 2 | B | 2
-- out 2 | 3 | B | 2
-- out 2 | 4 | B | 2
-- out 2 | 5 | B | 2
-- out 2 | 6 | A | 3
-- out (12 rows)
-- out
-- out Time: First fetch (12 rows): 14.823 ms. All rows formatted: 14.874 ms
One method is a cumulative sum based on a lag():
select t.*,
sum(case when prev_tag = tag then 0 else 1 end) over (partition by id order by period) as rank
from (select t.*, lag(tag) over (partition by id order by period) as prev_tag
from t
) t;

Oracle query for selecting sampling of number values from a table

I have a data field in my Oracle DB Table whose datatype is NUMBER. I have tried a query below using order by.
SELECT Value
FROM Table
ORDER BY value;
I am getting the result as
Value |
------|
1 |
1 |
2 |
2 |
3 |
3 |
4 |
4 |
5 |
5 |
6 |
6 |
Instead I want a result as
Value |
------|
1 |
2 |
3 |
4 |
5 |
6 |
1 |
2 |
3 |
4 |
5 |
6 |
You can use the row_number to evaluate if an occurrence of a value is the first one, the second, and so on; an order by based on this value and then for the value in the table will do the work.
For example:
/* a test case */
with someTable(value) as (
select 1 from dual union all
select 2 from dual union all
select 3 from dual union all
select 4 from dual union all
select 5 from dual union all
select 6 from dual union all
select 1 from dual union all
select 2 from dual union all
select 3 from dual union all
select 4 from dual union all
select 5 from dual union all
select 6 from dual
)
/* the query */
select value
from someTable
order by row_number() over ( partition by value order by null), value
How it works:
select value, row_number() over ( partition by value order by null) rowNumber
from someTable
order by row_number() over ( partition by value order by null), value
gives:
VALUE ROWNUMBER
---------- ----------
1 1
2 1
3 1
4 1
5 1
6 1
1 2
2 2
3 2
4 2
5 2
6 2
Please try this. I'm using ROW_NUMBER() to arrange the values based on their occurrences,
SELECT VALUE
FROM (
SELECT VALUE
, ROW_NUMBER() OVER (PARTITION BY VALUE ORDER BY VALUE ASC) RNK
FROM MY_TABLE
)
ORDER BY RNK
, VALUE;
1 Value | ------| 1 | 1 | 2 | 2 | 3 | 3 | 4 | 4 | 5 | 5 | 6 | 6 |
SELECT ROW_NUMBER() OVER (PARTITION BY VALUE ORDER BY VALUE) AS RN, TABLE .* FROM TABLE
2 Value | ------| 1 | 2 | 3 | 4 | 5 | 6 | 1 | 2 | 3 | 4 | 5 | 6 |
SELECT ROWNUM,TABLE.* FROM TABLE

Recursive Join with Order

I have a table with a list of pages, some with parent pages. These pages are in a very random order. I need to make a recursive join statement to select all pages ordered by Page_Order, where the parents are listed each followed by its child pages.
Table: Pages
Page_ID | Page_Name | Page_Parent | Page_Order
1 | User | 2 | 2
2 | Admin | NULL | 2
3 | Pages | 2 | 1
4 | Home | NULL | 1
5 | About | NULL | 3
6 | Contact | 5 | 1
I want to select them in the following order (order the parent pages, each followed by its child pages):
Page_ID | Page_Name | Page_Parent | Page_Order
4 | Home | NULL | 1
2 | Admin | NULL | 2
3 | Pages | 2 | 1
1 | User | 2 | 2
5 | About | NULL | 3
6 | Contact | 5 | 1
It's not specifically what you asked for but here is a way to achieve what you want. This does limit you too a finite number of child pages though and its not recursive.
; WITH cte AS (
SELECT 1 Page_Id, 'User' Page_Name, 2 Page_Parent, 2 Page_Order union
SELECT 2, 'Admin ', NULL, 2 union
SELECT 3, 'Pages ', 2 , 1 union
SELECT 4, 'Home ', NULL, 1 union
SELECT 5, 'About ', NULL, 3 union
SELECT 6, 'Contact ', 5 , 1
)
SELECT Page_Id, Page_Name, Page_Parent, Page_order, x = CAST(Page_order AS DECIMAL(18,2))
FROM cte
WHERE Page_Parent IS NULL
UNION
SELECT child.Page_Id, child.Page_Name, child.Page_Parent, child.Page_order, X = CAST(parent.Page_order AS DECIMAL(18,2)) + ISNULL(CAST(child.Page_order AS DECIMAL(18,2))/10000, 0)
FROM cte parent
LEFT OUTER JOIN cte child
ON child.Page_Parent = parent.Page_Id
WHERE child.Page_Id IS NOT NULL
ORDER BY x

Select a row X times

I have a very specific sql problem.
I have a table given with order positions (each position belongs to one order, but this isn't a problem):
| Article ID | Amount |
|--------------|----------|
| 5 | 3 |
| 12 | 4 |
For the customer, I need an export with every physical item that is ordered, e.g.
| Article ID | Position |
|--------------|------------|
| 5 | 1 |
| 5 | 2 |
| 5 | 3 |
| 12 | 1 |
| 12 | 2 |
| 12 | 3 |
| 12 | 4 |
How can I build my select statement to give me this results? I think there are two key tasks:
1) Select a row X times based on the amount
2) Set the position for each physical article
You can do it like this
SELECT ArticleID, n.n Position
FROM table1 t JOIN
(
SELECT a.N + b.N * 10 + 1 n
FROM
(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) a
,(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) b
) n
ON n.n <= t.amount
ORDER BY ArticleID, Position
Note: subquery n generates a sequence of numbers on the fly from 1 to 100. If you do a lot of such queries you may consider to create persisted tally(numbers) table and use it instead.
Here is SQLFiddle demo
or using a recursive CTE
WITH tally AS (
SELECT 1 n
UNION ALL
SELECT n + 1 FROM tally WHERE n < 100
)
SELECT ArticleID, n.n Position
FROM table1 t JOIN tally n
ON n.n <= t.amount
ORDER BY ArticleID, Position
Here is SQLFiddle demo
Output in both cases:
| ARTICLEID | POSITION |
|-----------|----------|
| 5 | 1 |
| 5 | 2 |
| 5 | 3 |
| 12 | 1 |
| 12 | 2 |
| 12 | 3 |
| 12 | 4 |
Query:
SQLFIDDLEExample
SELECT t1.[Article ID],
t2.number
FROM Table1 t1,
master..spt_values t2
WHERE t1.Amount >= t2.number
AND t2.type = 'P'
AND t2.number <= 255
AND t2.number <> 0
Result:
| ARTICLE ID | NUMBER |
|------------|--------|
| 5 | 1 |
| 5 | 2 |
| 5 | 3 |
| 12 | 1 |
| 12 | 2 |
| 12 | 3 |
| 12 | 4 |