I want to have an output like this
MM-DD-YYYY +5hours
Mine is Feb 24, 2014 4:05PM
Here's my code
SELECT CAST(DATEADD(hour,5,getdate()) AS nvarchar(30))
DATEADD (datepart , number , date )
Declare #myDate Datetime
Set #myDate = dateadd(HOUR, 5, getdate())
SELECT Left(Convert(varchar(10),#myDate,21),10) +
stuff(right(convert(varchar(26), #myDate, 109 ), 15 ), 7, 7, ' ')
Fiddle Demo
Use CONVERT passing the Style:
SELECT CONVERT(NVARCHAR(30), DATEADD(hour,5,getdate()), 101)
http://msdn.microsoft.com/en-us/library/ms187928.aspx
Related
I have searched far and wide, but I can't seem find a way to convert julian to yyyy-mm-dd.
Here is the format of my julian:
The Julian format consists of the year, the first two digits, and the day within the year, the last three digits.
For example, 95076 is March 17, 1995. The 95 indicates the year and the
076 indicates it is the 76th day of the year.
15260
I have tried this but it isn't working:
dateadd(d,(convert(int,LAST_CHANGED_DATE) % 1000)-1, convert(date,(convert(varchar,convert(int,LAST_CHANGED_DATE) /1000 + 1900) + '/1/1'))) as GrgDate
You can select each part of the date using datepart()
SELECT DATEPART(yy, 95076), DATEPART(dy, 95076)
+++EDIT: I misunderstood something. Here's my correction: +++++
SELECT DATEADD(day, CAST(RIGHT('95076',3) AS int) – 1, CONVERT(datetime,LEFT('95076',2) + '0101', 112))
Edit: leaving this answer for Oracle and MySQL users
This will not work in T-SQL.
Use this:
MAKEDATE(1900 + d / 1000, d % 1000)
For example:
SELECT MAKEDATE(1900 + 95076 / 1000, 95076 % 1000)
This returns March, 17 1995 00:00:00.
SQLFiddle
I concatenated 20 to my JD and then ran
DATEADD(YEAR, LAST_CHANGE_DATE / 1000 - 1900, LAST_CHANGE_DATE % 1000 - 1)
this got me the result. Thank you!!!
FOR SQL Users
DECLARE #jdate VARCHAR(10)
SET #jdate = 117338
SELECT dateadd(dd, (#jdate - ((#jdate/1000) * 1000)) - 1, dateadd(yy, #jdate/1000, 0))
This will definitely work in all case.
DECLARE #date int
SET #date = 21319
SELECT DATEADD(dd, RIGHT(#date,LEN(#date)-3)-1, DATEADD(yy,LEFT(#date,1)*100 +RIGHT(LEFT(#date,3),2),'1 Jan 1900'))
You need to specify 1 or 0 for century in first character. For example, SET #date = 21319 should be prefixed with 1 or 0. Below is an example that will work with all y2k use cases.
DECLARE #jdate INT
SET #jdate = 119150
SELECT DATEADD(dd, (#jdate - ((#jdate/1000) * 1000)) - 1, DATEADD(yy, #jdate/1000, 0))
Declare #Julian varchar(7)
Declare #date date
Set #Julian = 2020277
Set #Date = Dateadd(day,+ Cast(right(#Julian,3) as int)-1, Cast(left(#Julian,4) + '0101' as Date))
Select #Date
Standard SQL is simple (you can do similar for 2 digit year YYMMDD)
Declare #julDate int = 2020275
Select
DateAdd
(
day
, Right(#julDate,3)-1
, Cast((Left(#julDate,4)+'-01-01') as smalldatetime)
)
Try this out:
DECLARE #jdate int
SET #jdate = 21243
select dateadd(dd, (#jdate - ((#jdate/1000) * 1000)) - 1, dateadd(yy, #jdate/1000+100, 0))
I have a week number and year and i need to display "total for mm/dd/yy to mm/dd/yy in a row of my ssrs report. My week starts with Monday. For example if my week number is '2' and year is '2010' then I have to display "total for 01/04/2010 to 01/10/2010 in my ssrs column. how to do this?
Try this
declare #year char(4) = '2010'
declare #week int = 2
declare #fromdate datetime
declare #todate datetime
set #fromdate = DATEADD(wk, DATEDIFF(wk, 6, '1/1/' + #year) + (#week-1), 7);
set #todate = DATEADD(wk, DATEDIFF(wk, 5, '1/1/' + #year) + (#week-1), 6) ;
;WITH dates AS
(
SELECT CONVERT(datetime,#fromDate) as Date
UNION ALL
SELECT DATEADD(d,1,[Date])
FROM dates
WHERE DATE < #toDate
)
select * from dates
SQL Server has a DATEPART function which calculates the ordinal week number of a year. However, you have to call DATEFIRST before this to define which day of the week represents the start of the week. In your case, you have stated that the start of your week is Monday (i.e. 1).
SET DATEFIRST 1;
SELECT SUM([your data column])
FROM [your table]
WHERE DATEPART(WEEKNUM, [your date column])=[your week parameter]
AND DATEPART(YEAR, [your date column])=[your year parameter]
Your description is not american standard nor isoweek. Seems like a mix of those. I never heard of that as a standard. It is nearly isoweek. So that is what this answer is based on.
Calculating iso year is a bit tricky, you can read about it here:
This is the syntax you need:
DECLARE #year int = 2010
DECLARE #week int = 2
;WITH CTE AS
(
SELECT
dateadd(wk, datediff(wk, - #week * 7,
cast(cast(#year as char(4)) as datetime) - 5), 0) startofweek
)
SELECT
replace('total for ' + convert(char(10), startofweek, 110)
+ ' to ' + convert(char(10), dateadd(day, 6, startofweek) , 110), '-', '/')
FROM CTE
Result:
total for 01/11/2010 to 01/17/2010
Isoweek 2 in 2010 is 2010-01-11
Try setting DATEFIRST (https://msdn.microsoft.com/en-ie/library/ms181598.aspx)
SET DATEFIRST 7
declare #wk int
declare #yr int
declare #EndOfWeek as datetime
set #wk = 2
set #yr = 2010
SET #EndOfWeek = dateadd (week, #wk, dateadd (year, #yr-1900, 0)) + 1 - datepart(dw, dateadd (week, #wk, dateadd (year, #yr-1900, 0)) )
SELECT
replace('total for ' + convert(char(10), dateadd(day, -6, #EndOfWeek) , 110)
+ ' to ' + convert(char(10), #EndOfWeek, 110), '-', '/')
The result:
total for 01/04/2010 to 01/10/2010
I hope it helps:
declare #year char(4) = '2014'
declare #week int = 2
select dateadd(week,#week,convert(date,#year+'-01-01',121))
Change the date format appropriate for you from this list
i trying to build the following query to select * from table where the minDate is 03-02-2014 and the maxDate is 01-03-2014
but something i missing.
hope that someone can help me with this.
SELECT * From table Where
SUBSTRING(mydate, 1, 10) >= REPLACE('03-02-2014','-','/') AND
SUBSTRING(mydate, 1, 10) <= REPLACE('01-03-2014','-','/')
Note:
My Date column is of type varchar with a value like this --> 03/02/2014 18:13:16
im working in sql server management studio (t-sql)
From your comments, it seems that the mydate column of your table is in the British format.
Read this article about date conversion in SQL SERVER to understand more about date conversions.
Also updated my answer with the date conversions for this format.
Try something like
SELECT * FROM table
WHERE CONVERT(DATE, SUBSTRING(mydate, 1, 10), 103) >= CONVERT(DATE, '03/02/2014', 103)
AND CONVERT(DATE, SUBSTRING(mydate, 1, 10), 103) <= CONVERT(DATE, '01/03/2014', 103)
you can do something like:
Select * From Table
Where CONVERT( Datetime, mydate ,110 ) between CONVERT( Datetime, #min ,110 ) and between CONVERT( Datetime, #max ,110 )
I don't have SSMS available right now, but for a quick try you might try this
SELECT * From table Where
CAST( SUBSTRING(mydate, 1, 10) as date) BETWEEN CAST( SUBSTRING('START DATE', 1, 10) as date)
AND CAST( SUBSTRING('END DATE', 1, 10) as date)
i have a DB with a atribute "Date" which is a string ...
its format is:
"Jan 5 2014 6:26 PM"
and would like to get the number of rows where the date is this year.
already know how to convert the date:
SELECT convert(datetime, 'Oct 23 2012 11:01AM')
i found this code but I do not know how to join the two
select * from datetimes2
where dtm2 >= CAST(CURRENT_TIMESTAMP AS DATE)
and dtm2 < DATEADD(DD, 1, CAST(CURRENT_TIMESTAMP AS DATE))
;
Now I do not know how to do what I want :(
Is this what you looking for ?
DECLARE #datetime DATETIME = 'Jan 5 2014 6:26 PM'
SELECT
*
FROM datetimes2
WHERE [Date] >= CONVERT(DATETIME, CAST(DATEPART(YEAR, #datetime) AS VARCHAR) + '-01-01')
AND [Date] <= CONVERT(DATETIME, CAST(DATEPART(YEAR, #datetime) AS VARCHAR) + '-12-31')
This will get the records for complete year 2014. Hope this helps!
As simple as (assuming SQL server, given convert() )
select * from mytable where year( convert(datetime, date) ) = year( getDate() )
?
I have searched and i cannot seem to find the answer. I have tried using different styles, but none of them give me exactly what i want.
I am trying to convert a datetime, that I have calculated. However I need it to display the full month.
SELECT CONVERT(VARCHAR(25),DATEADD(dd, #codelife, getdate()),107)
the above line works fine, EXCEPT it displays the date like
Feb 27, 2014
I need it to display date like
February 27, 2014 etc.....
any suggestions?
Nathan's answer seems solid, however if you're using SQL Server 2012 you can make use of the FORMAT() function:
SELECT FORMAT(GETDATE(),'MMMM dd, yyyy')
Or in your case:
SELECT FORMAT(DATEADD(dd, #codelife, getdate()),'MMMM dd, yyyy')
I always use http://www.sql-server-helper.com/tips/date-formats.aspx as my reference
SELECT DATENAME(MM, GETDATE()) + RIGHT(CONVERT(VARCHAR(12), GETDATE(), 107), 9) AS [Month DD, YYYY]
I would declare your date as a variable and do something like:
DECLARE #myDate DATETIME
SET #myDate = DateAdd(dd, #codelife, getdate());
SELECT DATENAME(MM, #myDate) + RIGHT(CONVERT(VARCHAR(12), #myDate, 107), 9) AS [Month DD, YYYY]
You may have to do it in 2 steps.
DECLARE #codelife INT = 120
DECLARE #codedate DATETIME = (SELECT (DATEADD(D, #codelife, GETDATE())))
SELECT DATENAME(MM, #codedate) + SUBSTRING(CONVERT(VARCHAR(25), #codedate, 107), 4, 25)
SELECT DATENAME(MONTH, GETDATE())
+ RIGHT(CONVERT(VARCHAR(12), GETDATE(), 107), 9) AS [Month DD, YYYY]
OR Date without Comma Between date and year, you can use the following
SELECT DATENAME(MONTH, GETDATE()) + ' ' + CAST(DAY(GETDATE()) AS VARCHAR(2))
+ ' ' + CAST(YEAR(GETDATE()) AS VARCHAR(4)) AS [Month DD YYYY]
I answered the same question a couple of days ago have a look here sql server Get the FULL month name from a date