Running the WLST interpreter silently - weblogic

I am trying to figure out a way to make the weblogic WLST terminal run in silent mode.
When i start the terminal with the java weblogic.WLST command, it prints the lines:
Initializing WebLogic Scripting Tool (WLST) ...
Welcome to WebLogic Server Administration Scripting Shell
Type help() for help on available commands
Is there a command line flag or some unknown witchcraft to make the interpreter not write these lines?
I wishfully tried -s for silent, to no avail.
And all my googling lead me to an -i flag that does something completely different.
EDIT:
To clarify my purpose:
I need the interpreter to run a python script, and i do need the output from that. The welcome message is useless clutter however, that i would like to be rid of.
Limited to:
The only problem i have is the first lines written by the interpreter itself. Once inside the python script i have no problem handling what send to the output. My only problem is the welcome lines written above. These are written by the interpreter itself, and not the python code.

To solve the problem, I did something little differente..
I put a grep -v in the output .. like this:
java weblogic.WLST script.py $ARGS | grep -v "Initializing WebLogic
Scripting Tool (WLST) ..." | grep -v "Welcome to WebLogic Server
Administration Scripting Shell" | grep -v "Type help() for help on
available commands" | grep -v "Successfully connected to Admin Server
\"AdminServer\" that belongs to domain \"domain\"." | grep -v
"Warning: An insecure protocol was used to connect to the server." |
grep -v "To ensure on-the-wire security, the SSL port or Admin port
should be used instead." | grep -v "Location changed to domainRuntime
tree. This is a read-only tree" | grep -v "with DomainMBean as the
root MBean." | grep -v "For more help, use help('domainRuntime')" |
grep -v "Successfully connected to Admin Server" | grep -v "Connecting
to t3://"

Try this:
Like you said "it's a hack", but it's a fairly elegant hack.
Create the file runwlst.sh:
#!/bin/bash
. ${WLS_HOME}/server/bin/setWLSEnv.sh >/dev/null 2>&1
FILENAME=$1
shift
java weblogic.WLST ${FILENAME} "$#" | sed -e "1,7 d"
WLS_HOME needs to be set, or use the absolute path to setWLSEnv.sh.
Then create your WLST scripts as "shell" scripts like so (I like to use the ".wlsh" extension for my scripts):
#!/bin/bash /absolute_path_to_runwlst.sh/runwlst.sh
# your WLST Python code starts here
import ...
This obviously the sed script used in runwlst.sh only works if the "Initializing" banner is 7 lines long, which could change with new releases or patches of WLS.
The benefit of this solution is that now you can just run your WLST scripts from the command line like so:
$ createManagedServer.wlsh domain servername
Or use WLST scripts is other shell scipts like so:
#!/bin/bash
PORT=`./getPortForManagedServer.wlsh domain server`
echo ${PORT}
you get the picture

I wanted for it to only show me lines that I print inside the script, so I did it simple - prepended special char sequence to all lines I wanted to see in logs (it was print('--> ...') in my case) and launched it like that:
wlst.sh changePassword.wlst.py "$#" | grep -- "-->"
Sample output:
Executing WLST script for domain SampleDomain
--> Executing credential change for SampleDomain
--> Changing DB password for DSTYPE1
--> Changing password for DataSource SampleDS1
--> Successfully changed DB credentials!
--> Changing password for DataSource SampleDS2
--> No JDBC resource with name SampleDS2 found, skipping...
--> Changing password for DataSource SampleDS3
--> No JDBC resource with name SampleDS3 found, skipping...
--> Changing password for DataSource SampleDS4
--> Successfully changed DB credentials!
Completed execution for domain SampleDomain

Bit of a long shot but you could also silence the entire JVM output by capturing stdout and stderr into a different stream and then print values captured from the weblogic mbeans to the console streams. I had to do something similar a while back after writing an ansible module which required me to return pure JSON to stdout without any message banners or other stuff printed to the terminal.
A possible solution for your needs would involve writing a python script that first changes the OutputStreams as in this example and then starts a WSLT session. Just remember to keep a "copy" of the console out streams and use these to write your results to.

Related

How to create a Linux GUI app short cut for WSL2 on Windows10?

I have properly installed and setup WSL2. It works fine.
I also setup X11 forwarding and X server (VcXsrv). I can launch GUI apps such like konsole or gvim or even google-chrome from a bash shell.
Now I want to launch konsole by simply double clicking a short cut on the desktop without launching the bash command mode terminal. How should I do it?
I tried running this in cmd:
> wsl /usr/bin/konsole
and it reports:
qt.qpa.xcb: could not connect to display
qt.qpa.plugin: Could not load the Qt platform plugin "xcb" in "" even though it was found.
This application failed to start because no Qt platform plugin could be initialized. Reinstalling the application may fix this problem.
Available platform plugins are: eglfs, linuxfb, minimal, minimalegl, offscreen, vnc, wayland-egl, wayland, wayland-xcomposite-egl, wayland-xcomposite-glx, xcb.
I'm guessing it is because some X11 forwarding configurations were not properly setup, so I created a k.sh as follows:
#!/usr/bin/bash
export DISPLAY=$(cat /etc/resolv.conf | grep nameserver | awk '{print $2; exit;}'):0.0
export LIBGL_ALWAYS_INDIRECT=1
/usr/bin/konsole &
The first two lines were the X11 settings in my .bashrc, the last line launches konsole.
It works fine under bash environment; but when I ran
wsl k.sh
from windows cmd environment, it silently quitted without launching the konsole.
I'm out of ideas. What should I do to directly launch konsole or other Linux GUI apps under windows without having to getting into bash?
Thanks in advance.
You are asking about two different command-lines, and while the failures in running them via the wsl command have the same root-cause, the underlying failures are likely slightly different.
In both cases, the wsl <command> invocation results in a non-login, non-interactive shell where the command simply "runs and exits".
Since the shell is non-login/non-interactive, your startup files (such as ~/.bashrc and ~/.bash_profile, among others) are not being processed.
When you run:
wsl /usr/bin/konsole
... the DISPLAY variable is not set, since, as you said, you normally set it in your ~/.bashrc.
Try using:
wsl -e bash -lic "/usr/bin/konsole"
That will force bash to run as a login (-l), interactive (-i) shell. The DISPLAY should be set correctly, and it should run konsole.
Note that the quotes probably aren't necessary in this case, but are useful for delineating the commands you are passing to bash. More complicated command-lines can be passed in via the quotes.
As for:
wsl k.sh
That's likely a similar problem. You are doing the right thing by setting DISPLAY in your script, but I notice that you aren't using a fully-qualified path it. This would normally work, of course, if your script is in a directory on the $PATH.
But I'm guessing that you might add that directory to the $PATH in your startup config, which means (again) that it isn't being set in this non-login, non-interactive shell.
As before, try:
wsl -e bash -lic "k.sh"`
You could also use a fully-qualified path, of course.
And, I'm fairly sure you are going to run into an issue with trying to put konsole in the background via the script. When WSL exits, and the bash shell process ends, the child konsole process will terminate as well.
You could get around this with a nohup in the script, but then you also need to redirect the stderr. It's probably easiest just to move the & from the script itself to the command-line. Change your k.sh to:
#!/usr/bin/bash
export DISPLAY=$(cat /etc/resolv.conf | grep nameserver | awk '{print $2; exit;}'):0.0
export LIBGL_ALWAYS_INDIRECT=1
/usr/bin/konsole
Then run it with:
wsl -e bash -lic "k.sh &"`
Finally, a side note that when and if you can upgrade to Windows 11, it will automatically create Windows Start Menu entries for any Linux GUI app you install that creates a .desktop file. You can manually create .desktop files to have WSL create Start menu items for most applications.
For reference, in Windows 11 it's easier. To run a GUI application without a terminal window popping up, you just need to call wslg.exe instead of wsl.exe.
So, for example:
target: C:\Windows\System32\wslg.exe konsole
start in: C:\WINDOWS\system32
shortcut key: None
comment: Konsole
This tutorial shows how to install VcXsrv and and edit .bashrc to ensure that the "DISPLAY env var is updated on every restart".
DISPLAY env var needs to be dynamic setting.
I've used it successfully with WSL2 on Windows10 Version 21H2 (OS build 19044.2130) to run Chrome, Edge, and thunar. I'm using the Ubuntu 20.04 Linux distro.
To edit .bashrc follow these instructions.

Cypress unable to open X Display in WSL2

I have followed every single step in this tutorial. Double Checked. Double Installed.
https://nickymeuleman.netlify.app/blog/gui-on-wsl2-cypress
But I get the error :
[3974:0912/194522.792278:ERROR:browser_main_loop.cc(1402)] Unable to open X display.
The futex facility returned an unexpected error code.
The Test Runner unexpectedly exited via a exit event with signal SIGABRT
I had a similar issue, but there was a line before that same error message about Authentication. For me, I had to Disable Access Control after first ensuring all other running instances of VcXsrv were terminated:
If you've configured an external nameserver, then following the steps of Nicky Meuleman's tutorial, the DISPLAY variable will be set wrong. The tutorial says to add this to your .bashrc:
export DISPLAY=$(cat /etc/resolv.conf | grep nameserver | awk '{print $2; exit;}'):0.0
... but if you've configured an external nameserver, DISPLAY will end up pointing to that server, and it won't work. Instead, you should do this:
export DISPLAY=$( cmd.exe /C netsh interface ip show addresses "vEthernet (WSL)" | grep "IP Address" | sed -e "s/\sIP Address:\s//g; s/\r//" ):0.0
This will set DISPLAY to (e.g.) 172.24.0.1:0.0 instead of 8.8.4.4:0.0.

Cant start linux "screen" with logging to specific output file

I have the problem that I want to enable logging of a screen session at the start of it which then saves the log to a specific file.
What I have until now was:
screen -AmdSL cod2war /home/cod2server/scripts/service_28969.sh
while service_28969.sh is a shell script that will call other scripts which produce output.
I started multiple of those screen-sessions with different names, for example
screen -AmdSL cod2sd /home/cod2server/scripts/service_28962.sh
-L enables logging as the screen's man say, and will safe the ouput in a file called 'screenlog.0', now since I have multiple of those screens only one of it produces output saved in that log file (I can't find other 'screenlog.*' files in that folder).
I thought to use the -Logfile "file" option from the same man page, but it doesn't work for me and I can't find out what I'm doing wrong..
screen -Logfile cod2sd.log -AmdS cod2sd /home/u268450/cod2server/scripts/service_28962.sh
will produce the following error:
Use: screen [-opts] [cmd [args]]
or: screen -r [host.tty]
Options:
[...]
Error: Unknown option Logfile
and
screen -AmdS cod2sd /home/u268450/cod2server/scripts/service_28962.sh -Logfile cod2sd.log
will run without any error and start the screen but without the logging at all..
You can specify a logfile from within the default startup ~/.screenrc file using a line like
logfile mylog.log
To do this from the command line you can create a file mystartup to hold the above line, then use option -c mystartup to tell screen to read this file for setup instead of the default. If you also need to have ~/.screenrc read, you can add the source command to your startup file. The final result would look something like:
echo 'logfile mylog.log
source ~/.screenrc' >mystartup
screen -AmdSL cod2war -c mystartup /home/cod2server/scripts/service_28969.sh
This works for me:
screen -L -Logfile /Logs/Screen/`date +%Y%m%d`_screen.log
The configs I checked:
screen version 4.08.00 (GNU) 05-Feb-20 on FreeBSD 12.2
and
version 4.06.02 (GNU) 23-Oct-17 on Debian GNU/Linux 10 (buster)
and
version 4.00.03 (FAU) 23-Oct-06 on Mac OS X 10.9.5.
I just ran into this error myself and found this solution that worked with my python file, wanted to share for anyone else who might run into this issue:
screen -L -Logfile LOGFILENAME.LOG -dmS SCREENNAME python3 ./FILENAME.PY
I have no idea if this is the 'correct' way but it works.
-L enables logging
-Logfile LOGFILENAME.LOG declares what to call the log file and file format
-dmS SCREENNAME, dm runs in detached mode and S allows you to name the session
python3 ./FILENAME.PY in this case is my script but I assume that any other script here functions
I have tried a different ordering of these commands and this was the only way I managed to have them all run without issues. Hopes this helps.

Teradata client on Unix Solaris

I deploy some .bteq and .sql scripts on a TERADATA database. For doing this, I use a client on my desktop called BTEQWin version 13.10.0.03.
I get the .bteq/.sql from a version control like pvcs/svn etc and all I do once the files are in my workspace folder (from Version control tool), to just drag and drop the files from Windows browser to BTEQWin client (which I connect to a database prior to drag/drop for running those scripts).
Now, I have to automate this whole process in UNIX.
I have written a SHELL KSH/BASH script which is getting all the .bteq/.sql from a TAG/LABEL in the version control tool to a given UNIX folder. Now, all I need to do is the pass these files one by one (i'll take care of the order) to Teradata client.
My ?
- what client do I need to tell Unix admin team to install on Unix server - so that I can run something like below:
someTeraDataCommand -u username -p password -h hostname -d database -f filenametoexectue | tee output_filename.log
Where, someTeraDataCommand is the client / executable - which will let me run Teradata scripts (like I was doing using BTEQWin on my desktop - GUI session). Other parameters can be username, password, which database to connect on what server and which file to run or make that file passed to the command using "<" operator at command line.
Any idea?
- What client ?
Assuming the complete Teradata Tools and Utilities package is installed on your UNIX server (which will have the connectivity tools to talk to Teradata), you should have access to bteq from the command line. Something like this:
bteq < script_file > output_file
Your script file should contain a .LOGON statement to establish the connection:
.LOGON yourTDPID/your_account,your_pw
You might also need to use other commands to set your default database or non-default session values.
Another option would be to combine the SQL and call to BTEQ in a Korn shell script:
#!/usr/bin/ksh
##############
SHELL_NAME=`basename $0`
PRG_NAME=`basename $(SHELL_NAME} .ksh`
LOG_FILE=${PRG_NAME}.log
OUT_FILE=${PRG_NAME}.out
#
bteq <<EOBTQ > ${LOG_FILE} 2>$1
.LOGON {TDPID}/{USERID},{PWD};
--.RUN file=${LOGON}
/* Add your SQL/BTEQ commands here */
.QUIT 0;
EOBTQ
Edit
The double hyphen indicates a single line comment. Typically in a UNIX script you do not leave your password in plain text of a KSH script. The .RUN command would reference a text file in a barely sufficient secure location containing the .LOGON {TPDID}/{USERID},{PWD}; command.
The .RUN command in BTEQ allows you to reference another text file containing a series of valid BTEQ commands that you want to run in the current BTEQ script.
Easiest way is to setup the Solaris TTU, is to request root sudo, and run an interactive installation into defaults as a root. That would cure all client issues.

Cron Job - Could not open input file:

I have set up a php file to run that just echos hello.
<?php
echo hello;
?>
My cron job looks like this:
/usr/local/bin/php -f “/home/username/public_html/mls/test.php”
when my script runs i get a confirmation email that says:
Could not open input file: /home/username/public_html/mls/test.php
I don't know what is causing this. I am using godaddy's virtual private server with cpanel x installed. I have used the ssh to set permissions 777 on folder and file and still can not get it to run.
Any advice would be helpful. Thanks.
For some reason PHP cannot open the file. Try replacing /usr/local/bin/php -f with "ls -la" to try to crib some more information. Remember to NOT quote the file name in the crontab: php -f filename.php, not php -f "filename.php", unless it contains spaces -- and then it's better to use single quotes.
Possibly, try "ls -la /home", "ls -la /home/username", "ls -la ~/public_html" and so on.
Also try appending
2>&1
to the command line, in case only stdout is mailed to you (I don't really think so, but being sure costs little).
One other possibility
The crontab as it is refers /home/username/public_html/mls/test.php - that is, a public HTML directory inside username's commonest value for a home directory.
It is possible that the cron job is either not running with the appropriate user and privileges, or that the user it "sees" is actually a virtual user - there is no "/home/username" at all - and the "home directory" is elsewhere, possibly even existing just as long as the cron job runs. In this case the solution might be to refer to
~/public_html/mls/test.php
or, as described above, to first run a command such as pwd or ls -la to determine exactly where the cron job's current working directory is.
If this, too, fails, then another workaround could be to invoke the PHP HTTP handler via curl or lynx:
/usr/bin/curl http://www.thishostname.com/mls/test.php
Possibly using either some environment variable or curl header or _GET option to authenticate to the script as the cron job, and avoid it being accessible from the outside.