Excel show degree symbol incorrectly - vba

I have a worksheet which allows user to change the temperature unit, there is a dropdown box containing "° C" and "° F" and then I use VBA to do the rest.
The problem is, I have this code:
Dim UnitString As String
Set UnitRange = Worksheets("Units of Measure").Cells
UnitString = UnitRange(1, 1)
MsgBox UnitString
and it gives me "? C" or "? F"
The next problem, when I call:
UnitRange(1, 1) = "° C"
I got "ฐ C" in that cell. (ฐ is one of Thai's characters)
These problems broke my sheet's logic, can anyone help me?
Regards,
Sarun

You might want to use Unicode within your VBA routines. For example, here is a simple routine that formats cells to degrees Centigrade :
Sub centigrade()
Const g = "General"
dq = Chr(34)
cent = " " & ChrW(8451)
s = g & dq & cent & dq
Selection.NumberFormat = s
Selection.Font.Name = "Arial Unicode MS"
End Sub

Related

Modify matrix column spacing in equation through Word VBA

I would like to automate vertically stacked math problems (sums, products, etc.).
By using matrices I can align the numbers to the right so the digits align.
However, the column spacing default is too wide:
I can manually right click the matrix, select matrix spacing and set the minimum distance between columns to exactly 1, achieving my goal:
I cannot get the syntax of the matrix manipulation in VBA. The documentation seems very sparse (no examples). I tried recording a macro, but the right-click menu does not appear for the matrix in the equation when recording. I am not sure how to "set" the OMathMat object, since it is not a property of OMath.
I would settle for code that looped through all the equation objects in the document, all the matrix objects in those equations, and updated the OMathMat.ColSpacing property.
I tried something like:
For Each equation In ActiveDocument.OMaths
For Each Func In equation.Functions
Func.Mat.ColSpacing = 1
Next
Next
But the requested member (Mat) of the collection (Functions) did not exist. Also, there seems to be OMathFunction.Mat and OMathMat. I think I need the second option.
I agree that there isn't an obvious place to find documentation about accessing the OMath objects, so started trying to put something together.
But then you answered your own question - at this point it's probably more useful to publish what I already have, despite the fact that there are many unanswered questions.
So here are a few pieces of code that may help shed some light. They aren't well-tested.
I may well try to improve this question in future, but it will take time.
The first set of code should be able to deal with the situation where your Matrix objects could be anywhere in an OMath object.
The second set of code implements an "explorer" that reports the structure of the OMath objects in the main body of the document via Debug.Print statements.
Then there are a few more notes at the end.
Here's the code that should do what you needed, but slightly more generalised. You can copy the code into a single Module and run it.
' Keep some running totals
Dim OMathCount As Integer
Dim FunctionCount As Long
Dim MatCount As Long
Sub processOMaths()
Dim i As Long
FunctionCount = 0
MatCount = 0
' Just process the document body
With ActiveDocument
For i = 1 To .OMaths.Count
With .OMaths(i)
Call processOMathFunctions(.Functions)
End With
OMathCount = i
Next
End With
MsgBox "Processed " & CStr(OMathCount) & " Equation(s), " & _
CStr(FunctionCount) & " Function(s), " & _
CStr(MatCount) & " Matrix object(s)"
End Sub
Sub processOMathFunctions(oFunctions As OMathFunctions)
' There does not seem to be a way to return the entire collection of Functions
' in an OMath object. So it looks as if we have to recurse. But because the
' Object names for different Functions are different, we can't easily drill down
' to the next level using exactly the same code for multiple object types...
Dim i As Integer
For i = 1 To oFunctions.Count
Call processSingleOMathFunction(oFunctions, i)
Next
End Sub
Sub processSingleOMathFunction(oFunctions As OMathFunctions, index As Integer)
' ...so unless someone has a better idea, we'll just use a Select Case
' statement and deal with all the possible Function types
FunctionCount = FunctionCount + 1
With oFunctions(index)
Select Case .Type
Case WdOMathFunctionType.wdOMathFunctionAcc
Call processOMathFunctions(.Acc.E.Functions)
Case WdOMathFunctionType.wdOMathFunctionBar
Call processOMathFunctions(.Bar.E.Functions)
Case WdOMathFunctionType.wdOMathFunctionBorderBox
Call processOMathFunctions(.BorderBox.E.Functions)
Case WdOMathFunctionType.wdOMathFunctionBox
Call processOMathFunctions(.Box.E.Functions)
Case WdOMathFunctionType.wdOMathFunctionDelim
Dim delimCount As Integer
For delimCount = 1 To .Delim.E.Count
Call processOMathFunctions(.Delim.E(1).Functions)
Next
Case WdOMathFunctionType.wdOMathFunctionEqArray
Dim eqCount As Integer
For eqCount = 1 To .EqArray.E.Count
Call processOMathFunctions(.EqArray.E(eqCount).Functions)
Next
Case WdOMathFunctionType.wdOMathFunctionFrac
Call processOMathFunctions(.Frac.Num.Functions)
Call processOMathFunctions(.Frac.Den.Functions)
Case WdOMathFunctionType.wdOMathFunctionFunc
Call processOMathFunctions(.Func.E.Functions)
Call processOMathFunctions(.Func.FName.Functions)
Case WdOMathFunctionType.wdOMathFunctionGroupChar
Call processOMathFunctions(.GroupChar.E.Functions)
Case WdOMathFunctionType.wdOMathFunctionLimLow
Call processOMathFunctions(.LimLow.E.Functions)
Call processOMathFunctions(.LimLow.Lim.Functions)
Case WdOMathFunctionType.wdOMathFunctionLimUpp
Call processOMathFunctions(.LimUpp.E.Functions)
Call processOMathFunctions(.LimUpp.Lim.Functions)
Case WdOMathFunctionType.wdOMathFunctionLiteralText
' as far as I know, this cannot contain further Functions
' Do nothing.
Case WdOMathFunctionType.wdOMathFunctionMat
MatCount = MatCount + 1
Dim i As Integer
.Mat.ColGapRule = wdOMathSpacingExactly
' Hardcode this bit
.Mat.ColGap = 1 ' I think these are Twips, i.e. 1/20 pt
' We could iterate the columns and rows, but
' we'll iterate the Args instead.
For i = 1 To .Args.Count
Call processOMathFunctions(.Args(i).Functions)
Next
Case WdOMathFunctionType.wdOMathFunctionNary
Call processOMathFunctions(.Nary.Sub.Functions)
Call processOMathFunctions(.Nary.Sup.Functions)
Call processOMathFunctions(.Nary.E.Functions)
Case WdOMathFunctionType.wdOMathFunctionNormalText
' Used for 'Non-Math text'
' Do nothing
Case WdOMathFunctionType.wdOMathFunctionPhantom
Call processOMathFunctions(.Phantom.E.Functions)
Case WdOMathFunctionType.wdOMathFunctionRad
Call processOMathFunctions(.Rad.Deg.Functions)
Call processOMathFunctions(.Rad.E.Functions)
Case WdOMathFunctionType.wdOMathFunctionScrPre
Call processOMathFunctions(.ScrPre.Sub.Functions)
Call processOMathFunctions(.ScrPre.Sup.Functions)
Call processOMathFunctions(.ScrPre.E.Functions)
Case WdOMathFunctionType.wdOMathFunctionScrSub
Call processOMathFunctions(.ScrSub.E.Functions)
Call processOMathFunctions(.ScrSub.Sub.Functions)
Case WdOMathFunctionType.wdOMathFunctionScrSubSup
Call processOMathFunctions(.ScrSubSup.E.Functions)
Call processOMathFunctions(.ScrSubSup.Sub.Functions)
Call processOMathFunctions(.ScrSubSup.Sup.Functions)
Case WdOMathFunctionType.wdOMathFunctionScrSup
Call processOMathFunctions(.ScrSup.E.Functions)
Call processOMathFunctions(.ScrSup.Sup.Functions)
Case WdOMathFunctionType.wdOMathFunctionText
' Text - do nothing
Case Else
MsgBox "OMath Function type " & CStr(.Type) & " not recognized. Ignoring."
End Select
End With
End Sub
The second lot of code is the Explorer. It's incomplete, in various ways. All the code could go in a single Module but as it stands it is divided into three Modules:
One module contains the main Explorer code, which is structured in a similar way to the code I posted above. I haven't completed the code for all the function types so you will see some TBD (To Be Done) comments.
' indentation increment for each level of oMath object nesting
Const incindent As String = " "
Sub exploremath()
' This code explores the structure of 'modern' equations in Word
' i.e. the sort that have neen in Word since around Word 2007, not the older
' types inserted using an ActiveX object or an EQ field.
' Note to English speakers: some places use "Math" to refer to Mathematics
' e.g. the US. Others, e.g. the UK, use "Maths". This can cause a bit of confusion
' for UK English speakers but the trick is to realise that the oMaths object
' is just a collection of oMath objects. i.e. the naming convention is exactly the same as
' e.g. Paragraphs/Paragraph and so on.
' The overview is that
' - each Equation is represented by an OMath object
' - an oMath object contains an oMathFunctions collection
' with 0 (?1) or more oMathFunction objects
' - an oMathFunction object can represent several different
' types of structure, not just those with familiar function names
' such as Sin, Cos etc. but structures such as Matrices,
' Equation Arrays and so on.
Dim eqn As oMath
Dim fn As OMathFunction
Dim i As Long
Dim j As Long
Dim indent As String
With ActiveDocument
For i = 1 To .OMaths.Count
With .OMaths(i)
Debug.Print "Equation " & CStr(i) & ":-"
indent = ""
Call documentOMathFunctions(.Functions, indent)
End With
Debug.Print
Next
End With
End Sub
Sub documentOMathFunctions(fns As OMathFunctions, currentindent As String)
Dim i As Integer
Dim indent As String
indent = currentindent & incindent
Debug.Print indent & "Function count: " & CStr(fns.Count)
For i = 1 To fns.Count
Call documentOMathFunction(fns, i, indent)
Debug.Print
Next
End Sub
Sub documentOMathFunction(fns As OMathFunctions, index As Integer, currentindent As String)
Dim indent As String
indent = currentindent & incindent
With fns(index)
Debug.Print indent & "Function " & CStr(index) & ", Type: " & OMathFunctionTypeName(.Type) & " :-"
Select Case .Type
Case WdOMathFunctionType.wdOMathFunctionAcc
' Accented object
Debug.Print indent & "Accent: " & debugPrintString(ChrW(.Acc.Char))
Call documentOMathFunctions(.Acc.E.Functions, indent)
Case WdOMathFunctionType.wdOMathFunctionBar
' object with an overbar
Debug.Print indent & "Bar " & AB(.Bar.BarTop) & ":-"
Call documentOMathFunctions(.Bar.E.Functions, indent)
Case WdOMathFunctionType.wdOMathFunctionBorderBox
' TBD
Case WdOMathFunctionType.wdOMathFunctionBox
Debug.Print indent & "Box: IsDifferential? " & YN(.Box.Diff) & _
", Breaks Allowed? " & YN(Not .Box.NoBreak) & _
", TreatAsSingleOp? " & YN(.Box.OpEmu)
Call documentOMathFunctions(.Box.E.Functions, indent)
Case WdOMathFunctionType.wdOMathFunctionDelim
' Brackets etc.
Debug.Print indent & "Delim: BeginningChar: " & _
debugPrintString(ChrW(.Delim.BegChar)) & _
", EndChar: " & debugPrintString(ChrW(.Delim.EndChar)) & _
", SeparatorChar: " & debugPrintString(ChrW(.Delim.SepChar))
Debug.Print indent & incindent & "Grow? " & _
YN(.Delim.Grow) & ", LeftChar Hidden? " & _
YN(.Delim.NoLeftChar) & ", RightChar Hidden? " & _
YN(.Delim.NoRightChar) & ", Appearance: " & OMathShapeTypeName(.Delim.Shape)
Dim delimCount As Integer
For delimCount = 1 To .Delim.E.Count
Debug.Print indent & "Part " & CStr(delimCount) & ":-"
Call documentOMathFunctions(.Delim.E(1).Functions, indent)
Next
Case WdOMathFunctionType.wdOMathFunctionEqArray
' Array of aligned equations
Debug.Print indent & "Equation Array: Vertical Alignment : " & OMathVertAlignTypeName(.EqArray.Align) & _
", Expand to page column width? " & YN(.EqArray.MaxDist)
Debug.Print "Expand to object width? " & YN(.EqArray.ObjDist) & _
", Row Spacing Rule: " & oMathSpacingRuleName(.EqArray.RowSpacingRule);
If .EqArray.RowSpacingRule = WdOMathSpacingRule.wdOMathSpacingExactly Then
Debug.Print ", Row Spacing: " & CStr(.EqArray.RowSpacing) & " twips"
ElseIf .EqArray.RowSpacingRule = WdOMathSpacingRule.wdOMathSpacingMultiple Then
' Don't know what the .rowspacing Unit is in this case
Debug.Print ", Row Spacing: " & CStr(.EqArray.RowSpacing) & " half-lines";
End If
Debug.Print
Dim eqCount As Integer
For eqCount = 1 To .EqArray.E.Count
Debug.Print indent & "Equation " & CStr(eqCount) & ":-"
Call documentOMathFunctions(.EqArray.E(eqCount).Functions, indent)
Next
Case WdOMathFunctionType.wdOMathFunctionFrac
' Fraction
Debug.Print indent & "Fraction numerator:-"
Call documentOMathFunctions(.Frac.Num.Functions, indent)
Debug.Print indent & "Fraction denominator:-"
Call documentOMathFunctions(.Frac.Den.Functions, indent)
Case WdOMathFunctionType.wdOMathFunctionFunc
' Function (not sure yet whether a 'Func' can
' only have a single argument (possibly blank))
Debug.Print indent & "Func name: " & debugPrintString(.Func.FName.Range.Text)
Call documentOMathFunctions(.Func.E.Functions, indent)
Call documentOMathFunctions(.Func.FName.Functions, indent)
Case WdOMathFunctionType.wdOMathFunctionGroupChar
' A character such as a brace over or under another Function.
Debug.Print indent & "Group Char: " & UHex(.GroupChar.Char) & ", Position: " & AB(.GroupChar.CharTop); ""
Call documentOMathFunctions(.GroupChar.E.Functions, indent)
Case WdOMathFunctionType.wdOMathFunctionLimLow
' A Limit with the small text under the 'Lim word'
Debug.Print indent & "'LimLow':-"
Debug.Print indent & "Base:-"
Call documentOMathFunctions(.LimLow.E.Functions, indent)
Debug.Print indent & "Lim:-"
Call documentOMathFunctions(.LimLow.Lim.Functions, indent)
Case WdOMathFunctionType.wdOMathFunctionLimUpp
' A limit with the small text over the 'Lim word'
Debug.Print indent & "'LimUpp':-"
Debug.Print indent & "Base:-"
Call documentOMathFunctions(.LimUpp.E.Functions, indent)
Debug.Print indent & "Lim:-"
Call documentOMathFunctions(.LimUpp.Lim.Functions, indent)
Case WdOMathFunctionType.wdOMathFunctionLiteralText
' 'Literal Text' at first sight seems to be followed by
' a wdOMathFunctionText function with a Range
' containing the actual text.
' To be explored further
' But for now, do nothing.
Case WdOMathFunctionType.wdOMathFunctionMat
' A Matrix. AFAIK they have to be rectangular
Dim i As Integer
Debug.Print indent & ", Column count: " & CStr(.Mat.Cols.Count) & _
", Column gap rule: " & oMathSpacingRuleName(.Mat.ColGapRule);
If .Mat.ColGapRule = WdOMathSpacingRule.wdOMathSpacingExactly Then
Debug.Print ", Spacing: " & CStr(.Mat.ColGap) & " twips";
ElseIf .Mat.ColGapRule = WdOMathSpacingRule.wdOMathSpacingMultiple Then
Debug.Print ", Spacing: " & CStr(.Mat.ColGap);
End If
Debug.Print
Debug.Print indent & "Row count: " & CStr(.Mat.Rows.Count) & _
", Row gap rule: " & oMathSpacingRuleName(.Mat.RowSpacingRule);
If .Mat.RowSpacingRule = WdOMathSpacingRule.wdOMathSpacingExactly Then
Debug.Print ", Spacing: " & CStr(.Mat.RowSpacing) & " twips";
End If
Debug.Print
Debug.Print indent & "Args count: " & CStr(.Args.Count)
For i = 1 To .Args.Count
Debug.Print indent & " Arg " & CStr(i) & ":-"
Call documentOMathFunctions(.Args(i).Functions, indent)
Next
Case WdOMathFunctionType.wdOMathFunctionNary
' An N-Ary function, such as a summation operator, product operator
' various types of integral operator and so on.
' AFAICS all current N-Ary operators are in effect 3-Ary, i.e.
' The lower limit is the Sub, the upper limit is the Sup, and the
' thing being summed/integrated etc. is the 'Base'
' ignore .SubSupLim for now
.Nary.Char = &H2AFF
Debug.Print indent & "N-ary function, Type character: " & _
oMathNaryOpName(.Nary.Char) & ", Grow? " & YN(.Nary.Grow) & ":-"
Debug.Print indent & "N-ary Lower limit:- Hidden? " & YN(.Nary.HideSub)
Call documentOMathFunctions(.Nary.Sub.Functions, indent)
Debug.Print indent & "N-ary Upper limit:- Hidden? " & YN(.Nary.HideSup)
Call documentOMathFunctions(.Nary.Sup.Functions, indent)
Debug.Print indent & "N-ary body:-"
Call documentOMathFunctions(.Nary.E.Functions, indent)
Case WdOMathFunctionType.wdOMathFunctionNormalText
'Used for 'Non-Math text'
Debug.Print indent & "Literal Text: " & debugPrintString(.Range.Text)
Case WdOMathFunctionType.wdOMathFunctionPhantom
' TBD
Case WdOMathFunctionType.wdOMathFunctionRad
Debug.Print indent & "Degree:- (Hidden? " & YN(.Rad.HideDeg)
Call documentOMathFunctions(.Rad.Deg.Functions, indent)
Debug.Print indent & "Radical:-"
Call documentOMathFunctions(.Rad.E.Functions, indent)
Case WdOMathFunctionType.wdOMathFunctionScrPre
' base object with a superscript/subscript *before* the base
' Think this means an obect that has *both* (although one or both
' could be left blank)
' (TBR: Can OMath be used right-to-left, and if so, how
' are properties named/documented as 'to the left of',
' 'to the right of', 'before', 'after' to be interpreted?
' Or are math formulas etc. always expressed as LTR worldwide
' these days (I would guess so!)
Debug.Print indent & "ScrPre Subscript:-"
Call documentOMathFunctions(.ScrPre.Sub.Functions, indent)
Debug.Print indent & "ScrPre Superscript:-"
Call documentOMathFunctions(.ScrPre.Sup.Functions, indent)
Debug.Print indent & "ScrPre Base-"
Call documentOMathFunctions(.ScrPre.E.Functions, indent)
Case WdOMathFunctionType.wdOMathFunctionScrSub
' base object with a subscript after the base
Debug.Print indent & "Base:-"
Call documentOMathFunctions(.ScrSub.E.Functions, indent)
Debug.Print indent & "Superscript:-"
Call documentOMathFunctions(.ScrSub.Sub.Functions, indent)
Case WdOMathFunctionType.wdOMathFunctionScrSubSup
' base object with subscript and supersript after the base
Debug.Print indent & "ScrSubSup Base-"
Call documentOMathFunctions(.ScrSubSup.E.Functions, indent)
Debug.Print indent & "ScrSubSup Subscript:-"
Call documentOMathFunctions(.ScrSubSup.Sub.Functions, indent)
Debug.Print indent & "ScrSubSup Superscript:-"
Call documentOMathFunctions(.ScrSubSup.Sup.Functions, indent)
Case WdOMathFunctionType.wdOMathFunctionScrSup
' base object with supersript after the base
Debug.Print indent & "Base:-"
Call documentOMathFunctions(.ScrSup.E.Functions, indent)
Debug.Print indent & "Superscript:-"
Call documentOMathFunctions(.ScrSup.Sup.Functions, indent)
Case WdOMathFunctionType.wdOMathFunctionText
Debug.Print indent & "Text: " & debugPrintString(getRunTextFromXML(.Range))
Case Else
' we already printed an unknown type message before the select statement.
End Select
End With
End Sub
In Module "Common" there are some Helper routines
usly had Cstr
Function UHex(codepoint As Long) As String
' Form a 4-digit Unicode Hex string
' fix : had 'CStr' instead of 'Hex'
UHex = "U+" & Right("0000" & Hex(codepoint), 4)
End Function
Function debugPrintString(s As String) As String
' Form a string where 1-byte characters are output as is,
' others are output as Unicode Hex strings
' NB, at the moment we do not try to change stuff such as "&" to "&"
Dim i As Long
Dim t As String
t = ""
For i = 1 To Len(s)
If AscW(Mid(s, i, 1)) < 256 Then
t = t & Mid(s, i, 1)
Else
t = t & " " & UHex(AscW(Mid(s, i, 1))) & " "
End If
Next
debugPrintString = t
End Function
Function YN(b As Boolean) As String
If b Then YN = "Y" Else YN = "N"
End Function
Function AB(b As Boolean) As String
If b Then AB = "Above" Else AB = "Below"
End Function
Function getRunTextFromXML(r As Word.Range) As String
' We need a function like this to retrieve text in the Math Font, (e.g. Cambria Math Font,
' which appears to be encoded as ASCII rather than Unicode.
' So if the equation contains a Cambria Math "A", the .Range.Text is returned as "??"
' For later: if the text is *not* in Cambria Math, we probably *don't* want to do this!
' (Could end up inspecting character by character).
' For the moment, use a kludge to get the first run of text in the range.
Dim x As String
Dim i1 As Long
Dim i2 As Long
x = r.WordOpenXML
' FOr an oMath text, we look for m:t rather than w:t
i1 = InStr(1, x, "<m:t>")
i2 = InStr(i1, x, "</m:t>")
getRunTextFromXML = Mid(x, i1 + 5, i2 - i1 - 5)
End Function
In module Enums, there are some more Helper routines to return things such as Enum names as text (if only VBA had better facilities for Reflection!)
Function oMathIsAllowedNaryOp(codepoint As Long) As Boolean
' Perhaps can look up the unicode database rather than hardcode this list
Select Case codepoint
Case &H2140, &H220F To &H2211, &H222B To &H2233, &H22C0 To &H22C3, &H2A00 To &H2A06, &H2A09, &H2AFF
oMathIsAllowedNaryOp = True
Case Else
oMathIsAllowedNaryOp = False
End Select
End Function
Function oMathNaryOpName(codepoint As Long) As String
' Perhaps can look up the unicode database rather than hardcode this list
' and the standard Unicode character names
Select Case codepoint
Case &H2104
oMathNaryOpName = "Double-Struck N-Ary Summation"
Case &H220F
oMathNaryOpName = "N-Ary Product"
Case &H2210
oMathNaryOpName = "N-Ary Coproduct"
Case &H2211
oMathNaryOpName = "N-Ary Summation"
Case &H22C0
oMathNaryOpName = "N-Ary Logical And"
Case &H22C1
oMathNaryOpName = "N-Ary Logical Or"
Case &H22C2
oMathNaryOpName = "N-Ary Intersection"
Case &H22C3
oMathNaryOpName = "N-Ary Union"
Case &H22A0
oMathNaryOpName = "N-Ary Circled Dot Operator"
Case &H22A1
oMathNaryOpName = "N-Ary Circled Plus Operator"
Case &H22A2
oMathNaryOpName = "N-Ary Circled Times Operator"
Case &H22A3
oMathNaryOpName = "N-Ary Union Operator With Dot"
Case &H22A4
oMathNaryOpName = "N-Ary Union Operator With Plus"
Case &H22A5
oMathNaryOpName = "N-Ary Square Intersection Operator"
Case &H22A6
oMathNaryOpName = "N-Ary Square Union Operator"
Case &H22A9
oMathNaryOpName = "N-Ary Times Operator"
Case &H2AFF
oMathNaryOpName = "N-Ary White Vertical Bar"
Case Else
oMathNaryOpName = "(Possibly invalid N-ary opcode: " & UHex(codepoint) & ")"
End Select
End Function
Function OMathShapeTypeName(OMathShapeType As Integer) As String
Select Case OMathShapeType
Case WdOMathShapeType.wdOMathShapeCentered
OMathShapeTypeName = "wdOMathShapeCentered"
Case WdOMathShapeType.wdOMathShapeMatch
OMathShapeTypeName = "wdOMathShapeMatch"
Case Else
OMathShapeTypeName = "(Math Shape Type unknown: " & CStr(OMathShapeType) & ")"
End Select
End Function
Function oMathSpacingRuleName(oMathSpacingRule As Long) As String
Select Case oMathSpacingRule
Case WdOMathSpacingRule.wdOMathSpacing1pt5
oMathSpacingRuleName = "wdOMathSpacing1pt5"
Case WdOMathSpacingRule.wdOMathSpacingDouble
oMathSpacingRuleName = "wdOMathSpacingDouble"
Case WdOMathSpacingRule.wdOMathSpacingExactly
oMathSpacingRuleName = "wdOMathSpacingExactly"
Case WdOMathSpacingRule.wdOMathSpacingMultiple
oMathSpacingRuleName = "wdOMathSpacingMultiple"
Case WdOMathSpacingRule.wdOMathSpacingSingle
oMathSpacingRuleName = "wdOMathSpacingSingle"
Case Else
oMathSpacingRuleName = "(Math Spacing Rule unknown: " & CStr(oMathSpacingRule) & ")"
End Select
End Function
Function OMathVertAlignTypeName(OMathVertAlignType As Integer) As String
Select Case OMathVertAlignType
Case WdOMathVertAlignType.wdOMathVertAlignBottom
OMathVertAlignTypeName = "wdOMathVertAlignBottom"
Case WdOMathVertAlignType.wdOMathVertAlignCenter
OMathVertAlignTypeName = "wdOMathVertAlignCenter"
Case WdOMathVertAlignType.wdOMathVertAlignTop
OMathVertAlignTypeName = "wdOMathVertAlignTop"
Case Else
OMathVertAlignTypeName = "(Math Vertical Alignment Type unknown: " & CStr(OMathVertAlignType) & ")"
End Select
End Function
Notes.
AFAIK the author/designer of the OMath objects and User Interface
(and indeed other aspect of layout in Word) is Murray Sargent III.
His paper on UnicodeMath Describes how the system as a whole is
intended to use Build-Up. But take care, because not everything
mentioned in there is necessarily implemented in all versions of
OMath (which is used across a number of MS Office products). His
Math-in-Office blog can be quite enlightening too.
There are at least two versions of the OMath object documentation -
one for "VBA" and one for .NET. There are some differences (e.g. some
Properties and at least one Function Type enumeration name is missing
from the VBA version. The .NET version is near here and the VBA
version is near here.
At the moment, none of the code I've posted provides anything that would help you modify the Function structure of an Equation, e.g. insert a new function. That's mainly because I haven't got to grips with it yet. Even writing code to insert a piece of Text throws up a number of problems, not least the question of why Math Font text is not encoded as Unicode and what that means when it comes to modifying it. It may in fact be easier to work with the Linear ("not built up" text version rather than the Object model. TBD!
I solved my problem, looping through the equations (OMaths collection), and then, using the WdOMathFunctionType enumeration to find fraction type functions that contained a matrix in their numerator, I could properly set the matrix properties:
For Each eq In ActiveDocument.OMaths
For Each Func In eq.Functions
If Func.Type = 7 Then 'a fraction function
If Func.Args(1).Functions(1).Type = 12 Then 'a matrix function in the numerator
With Func.Args(1).Functions(1).Mat
.ColGapRule = wdOMathSpacingExactly
.ColGap = 1
.PlcHoldHidden = True
End With
End If
End If
Next
Next
I knew the type of structured equations my document contained, so I didn't include many check conditions. (There probably a more elegant and robust way to search all 'child functions' of equations until the last node is reached.) Hopefully this can serve as a template for anyone trying to expose specific OMath Function properties.

Conditional Formatting in word vba

Greeting to all Members and Experts, I am trying to automate
the formatting process in word. The formatting is done by applying styles. But before applying styles I need to trim extra spaces between characters of serial numbers, for example, 1. a. i. and insert tabs after dot(.) and then apply the style. I have attached a sample document. Plz have a look. I have tried to get the desired result by using the following code but it doesn't get the work done
I am new here so i dont know how to attach sample files so, here is the link for sample file. https://docs.google.com/document/d/1Z1dB6tvPKVrxHlw7qV8VNyiy49c5lRZN/edit?usp=sharing&ouid=101706223056224820285&rtpof=true&sd=true
Any help or suggestion would be of great help. Thanks in advance...
Sub formatts()
Dim a As Integer
Dim i As Integer, n As Long, para As Paragraph, rng As Range, doc As Document
Set doc = ActiveDocument
With doc
For i = 1 To .Range.Paragraphs.Count
For n = 1 To doc.Paragraphs(i).Range.Characters.Count
If .Paragraphs(i).Range.Characters(n).Text = " " Or .Paragraphs(i).Range.Characters(n).Text = Chr(9) Or .Paragraphs(i).Range.Characters(n).Text = Chr(160) Then
.Paragraphs(i).Range.Characters(n).Select
'This line checks whether the first character is whitespace character or not and delete it.
doc.Paragraphs(i).Range.Characters(n).Delete
ElseIf .Paragraphs(i).Range.Characters(n).Text = "." Then
.Paragraphs(i).Range.Characters(n).InsertAfter (vbTab)
n = n + 1
a = a + 1
ElseIf .Paragraphs(i).Range.Characters(n).Text Like "[a-z]." And .Paragraphs(i).Range.Characters(n).Next.Next.Text <> "i" Then
Exit For
End If
If a >= 3 Then Exit For
Next
For n = 1 To doc.Paragraphs(i).Range.Characters.Count
If .Paragraphs(i).Range.Characters(n).Text = "i" And .Paragraphs(i).Range.Characters(n).Next.Text = "." And .Paragraphs(i).Range.Characters(n).Next.Next.Text = " " Then
doc.Range.Paragraphs(i).Style = "shh"
Exit For:
ElseIf .Paragraphs(i).Range.Characters(n).Text = "a" Or .Paragraphs(i).Range.Characters(n).Text = "b" Or .Paragraphs(i).Range.Characters(n).Text = "c" And .Paragraphs(i).Range.Characters(n).Next.Text = "." And .Paragraphs(i).Range.Characters(n).Next.Next.Text = " " Then
doc.Range.Paragraphs(i).Style = "sh"
Exit For
End If
Next
Next
End With
End Sub

Inputbox is not accepting double number VBA excel

I have a declaration like number= InputBox("Number for:", "Number:"), number is declared as Dim number As Double but when I enter a double number, for example 5.4, into the Inputbox and transmit it into a cell, the cell shows me 54, it deletes the point.
How can I fix this?
THX
If you want to detect which settings your Excel uses for the Decimal seperator, try the code below:
MsgBox "Excel uses " & Chr(34) & Application.DecimalSeparator & Chr(34) & " as a decimal seperator"
if you want to change it to ., then use the line below:
Application.DecimalSeparator = "."
Unfortunately, VBA is horrible at handling differences in decimal seprators. In your case, you should probably use a comma (,), instead of a punctuation/dot (.).
Edit: Using the Application.DecimalSeparator method, it now works regardless of regional settings. Be aware though, it seems to cause some issues if you change the comma separator settings for Excel (it seems that VBA somewhat ignores this setting). If you do not change that however, the example should work in all other cas
Sub GetNumberFromInputBox()
Dim val As String
Dim num As Double
'Get input
val = InputBox("Number for:", "Number:")
Debug.Print Application.DecimalSeparator
If IsNumeric(val) Then
'Try to convert to double as usual
num = CDbl(val)
'If the dot is removed automatically, then
'you will se a difference in the length. In
'those cases, replace the dot with a comma,
'before converting to double
If Len(val) <> Len(num) Then
If Application.DecimalSeparator = "," Then
num = CDbl(Replace(val, ".", ","))
Else
num = CDbl(Replace(val, ",", "."))
End If
End If
'Pring the number
Debug.Print "You selected number: " & num
Else
'If its not a number at all, throw an error
Debug.Print "You typed " & val & ", which is not a number"
End If
End Sub

Access 2013 - Dlookup with double

Hello i've a little problem with my VBA code i'm trying to select the right gps number (double) which matches to the string Name in table tblpersonal and the string in the textbox tabletbesitzerbox. The GPS number should be displayed in the textbox fkgps:
Private Sub SP_Besitzersuche_Click()
DoCmd.OpenForm "F-Tablet-Hinzufuegen-Neu"
Dim Sim As Double
Sim = Nz(DLookup("[GPS]", _
"tblPersonal", _
"Name = " & Forms![F-Tablet-Hinzufuegen-Neu]![tabletbesitzerbox]), "")
FKGPS.Value = Sim
End Sub
The error shows me: Syntaxerror (missing Operation) in query expression 'Name = XY'
I'm thankful for every help :)
String parameters must be enclosed in quotes. When building the criteria in VBA, it is easiest to use single quotes:
Sim = Nz(DLookup("[GPS]", _
"tblPersonal", _
"Name = '" & Forms![F-Tablet-Hinzufuegen-Neu]![tabletbesitzerbox] & "'"), 0)

VBA optimization robust code

So I'm completely new to VBA. I have a java-fetish so I'm not new to programming, however manipulating office documents just seemed easier with VBA.
Anyway, on topic:
I'm currently automating things in the company (This example is creating a contract). However, using Java, I always learned to make robust code and although the VBA code now works, I'm not happy with it because it requires a lot of 'friendliness' of the user. So my question is (I hope you don't mind), could you give me a nudge in the right direction to make my code way more robust?
Here's the code:
Function spaties(Name As String) As String
' Function used to ensure the length of a String (Working with Range)
Dim index As Integer
While (Len(Name) < 30)
Name = Name + " "
Wend
spaties = Name
End Function
Sub Macro3()
'
' Macro3 Macro
'
'
'ActiveDocument.Range(26101, 26102).Text = "d"
StartUndoSaver
Dim firma As String
firma = InputBox("Voor welke onderaannemer? (Zonder hoofdletters)" + Chr(10) + "(nicu, sorin of marius)")
Dim werf As String
werf = InputBox("Over welke Werf gaat het?")
Dim datum As String
datum = InputBox("Op welke datum spreekt het contract? (dd/mm/yyyy)")
With ActiveDocument
.Range(25882, 25899).Text = datum
ActiveDocument.Range(575, 605).Text = spaties(werf)
ActiveDocument.Range(1279, 1309).Text = spaties(werf)
End With
Select Case Len(firma)
Case 4
With ActiveDocument
.Range(26168, 26181).Text = "Nicu Dinita"
.Range(26062, 26088).Text = "Badi Woodconstruct SRL"
.Range(11359, 11371).Text = "Nicu Dinita"
End With
Case 5
With ActiveDocument
.Range(26168, 26181).Text = "Asavei Sorin"
.Range(26062, 26088).Text = "BELRO INTERIOR DESIGN SRL"
.Range(11359, 11371).Text = "Asavei Sorin"
End With
Case 6
With ActiveDocument
.Range(26168, 26181).Text = "Ivan Maricel"
.Range(26062, 26088).Text = "Solomon & Aaron Construct"
.Range(11359, 11371).Text = "Ivan Maricel"
End With
End Select
Dim prijs As String
Dim besch As String
Dim eenh As String
Dim hoev As Integer
hoev = InputBox("Hoeveel artikels zijn er?")
Dim index As Integer
index = 1
While (index <= hoev)
besch = InputBox("Beschrijving van het artikel (engels)")
prijs = InputBox("prijs van het artikel")
eenh = InputBox("Eenheid van het artikel")
With ActiveDocument
.Range(5701, 5702).Text = "" + vbTab + spaties2(besch, prijs, eenh) + Chr(10) + vbTab
End With
index = index + 1
Wend
With ActiveDocument.Sections(1)
.Headers(wdHeaderFooterPrimary).Range.Text = "Raes G. Schrijnwerken BVBA" + vbTab + vbTab + datum + Chr(10) + "Robert Klingstraat 5" + Chr(10) + "8940 Wervik"
.Footers(wdHeaderFooterPrimary).Range.Text = "Overeenkomst tot onderaanneming" + Chr(10) + "met betrekking tot:" + werf
.Footers(wdHeaderFooterPrimary).PageNumbers.Add PageNumberAlignment:=wdAlignPageNumberRight
End With
If firma = "sorin" Then
ActiveDocument.Range(254, 255).ImportFragment "Z:\Raes Netwerk DATA\professioneel\004 Sjablonen\belro.docx", False
Else
If firma = "nicu" Then
With ActiveDocument
.Range(254, 255).ImportFragment "Z:\Raes Netwerk DATA\professioneel\004 Sjablonen\Nicu.docx", False
End With
Else
If firma = "marius" Then
ActiveDocument.Range(254, 255).ImportFragment "Z:\Raes Netwerk DATA\professioneel\004 Sjablonen\Marius.docx", False
End If
End If
End If
ActiveDocument.PrintOut
ActiveDocument.PrintOut
End Sub
Function spaties2(artikel As String, prijs As String, eenh As String) As String
'Another function to ensure length of String
Dim index As Integer
Dim eind As String
eind = "" + artikel + vbTab + vbTab + prijs + "€/" + eenh
While (Len(eind) < 100)
eind = eind + " "
Wend
spaties2 = eind
End Function
As you can see, the code is very basic. And although it works, it's no good to deliver.
The two defined Functions are simply formatting the String of the user because obviously the name of something is not always the same length.
I'd like to cut out the Range properties, because in my opinion, that's what makes the program so sensitive to changes.
Any and all suggestions are welcome.
note: For the moment, the contract can have three different 'target parties' so that's why the Select Case statement is there. It's going to be completely useless if it should grow but for now it works.
Here's one:
sName = Left(sName & Space(30), 30)
And I think it's better to use bookmarks as placeholders instead of using Range(start, end)
How to change programmatically the text of a Word Bookmark
I think that your code needs some Trim's, in order to avoid mistaken spaces before and after the names (when you use some inputboxes, I mean).
And you need to verify input dates, too.
For string concatenation, use the ampersand (&) better than the plus sign (+), in order to avoid mistaken sums.
Instead of Chr(10) I have some recommendations in order to make your code more readable:
Chr(13) = vbCr
Chr(10) = vbLf
Chr(13) & Chr(10) = vbCrLf
Verify that the files you are indicating exist.
Using Range with numerical values is definitely not reliable. Bookmarks, as Tim suggests or content controls if this is Word 2007 or later. Content Controls are Microsoft's recommendation, going forward, but I don't see any particular advantage one way or the other for your purpose.
Looking at all the InputBox calls I have to wonder whether displaying a VBA UserForm for the input might not be better? All the input fields in one place, rather than flashing multiple prompts. You can validate for correct input before the UserForm is removed from the screen, etc.