count of Balance installments - sql

Question

i got a requirement to write a MS-SQL stored procedure, the requirement is
Table 1
It consists total student fee to be paid in installments
EX:
SID SNAME INST.Date Amount
123 XYZ 01-01-2013 3500
123 XYZ 01-05-2013 3500
123 XYZ 01-10-2013 3500
123 XYZ 01-04-2014 3500
123 XYZ 01-06-2014 3500
`
Table 2
It consists Payment recd details
SID SNAME Paydate amoount
123 XYZ 01-01-2013 1167
123 XYZ 01-02-2013 1167
123 XYZ 01-03-2013 1167
123 XYZ 01-05-2013 1750
123 XYZ 01-05-2013 1750
123 XYZ 01-10-2013 1167
123 XYZ 01-10-2013 1167
now the requirement is as on jan2014,how many installment to paid,what is the Recd amount, no of balance installments to be paid as on jan-14.
Expected output
SID Sname Total Inst.Amt as on01.01.2014 Paid.amount Balance amt Balance.Installments
123 XYZ 10500 9335 1165 1
For reference I gave one student data.
The stored procedure should run for 36000 students.

Answer 1

Here's a query that will give you what you want, expect Balance.Installments I don't know what it means :
SELECT distinct t1.SID
, t1.SNAME
, t1.Total_Inst
, t2.Paid_amount AS 'Paid.Amount'
, t1.Total_Inst - t2.Paid_amount as 'Balance amt'
, CEILING( (t1.Total_Inst - t2.Paid_amount) / t.Amount ) as 'Balance.Installments'
FROM
table_1 as t
JOIN
( SELECT SID, SNAME, SUM(Amount) as Total_Inst
FROM table_1
WHERE Date < STR_TO_DATE('01/01/2014', '%m/%d/%Y') group by SID, SNAME
)
ON ( t1.SID = t.SID AND t1.SNAME = t.SNAME )
AS t1
LEFT JOIN
( SELECT SID, SNAME, SUM(Amount) as Paid_amount
FROM table_2
WHERE Paydate < STR_TO_DATE('01/01/2014', '%m/%d/%Y') group by SID, SNAME
) AS t2
ON ( t1.SID = t2.SID AND t1.SNAME = t2.SNAME )

Answer 2

why you will need to run for 36000 record at one time.Also what is actially installment.There is only one instalment for any student no several.So i think database is lil wrong.
There should only one instalment amount and time interval(due date) per student in table.
Check the latest change.It is only for one student .
Declare #student table(SID int,SNAME varchar(50),INST Date ,Amount int)
insert into #student
select 123,'XYZ','01-01-2013',3500 union all
select 123, 'XYZ', '01-05-2013', 3500 union all
select 123, 'XYZ', '01-10-2013', 3500 union all
select 123, 'XYZ', '01-04-2014', 3500 union all
select 123, 'XYZ', '01-06-2014', 3500
Declare #instalmentamount float
select #instalmentamount=amount from #student where sid=123
--select #instalmentamount
Declare #Table2 table(SID int,Paydate date,amoount int)
insert into #Table2
select 123, '01-01-2013', 1167 union all
select 123, '01-02-2013', 1167 union all
select 123, '01-03-2013', 1167 union all
select 123, '01-05-2013', 1750 union all
select 123, '01-05-2013', 1750 union all
select 123, '01-10-2013', 1167 union all
select 123, '01-10-2013', 1167
declare #input date='01-01-2014'
;With CTE as
(select s.SID, sum(s.amount) as [Total Inst.Amt ] from #student s
where s.INST<=#input
group by s.SID),
cte1 as
(
select t.SID, sum(t.amoount) as [Paid.amount] from #Table2 t
where t.Paydate<=#input
group by t.SID
)
select c.sid,
(select top 1 s.SNAME from #student s where s.SID=c.SID) [Name],
c.[Total Inst.Amt ],c1.[Paid.amount],
c.[Total Inst.Amt ]-c1.[Paid.amount] [BalanceAmount],cast(((c.[Total Inst.Amt ]-c1.[Paid.amount])/#instalmentamount) as int)+1 [Balance.Installments]
from CTE c inner join cte1 c1 on c.SID=c1.SID

Answer 3

TRY THIS...
SELECT t.ID,
T.SNAME,
T.AMT 'Total Inst.Amt as on01.01.2014',
ISNULL(SUM(amoount),0) AS 'PAID AMT',
T.AMT - ISNULL(SUM(amoount),0) AS 'BALANCE AMT' ,
CEILING((T.AMT- ISNULL(SUM(amoount),0) )/( T.InstAmt*1.)) 'Balance.Installments'
FROM
(
SELECT ID,SNAME,SUM(AMT)AMT,MAX(AMT) AS InstAmt FROM #Table1 WHERE DT_ < '01-31-2014' GROUP BY ID,SNAME
) T
LEFT JOIN #Table2 P ON P.ID = T.id AND P.Paydate < '01-31-2014'
GROUP BY t.ID,SNAME,t.InstAmt,T.AMT