I'm writing a unit test for a method with the following sql
WITH temptab(
i__id , i__name, i__effective, i__expires, i__lefttag, i__righttag,
hier_id, hier_dim_id, parent_item_id, parent_hier_id, parent_dim_id,
ancestor, h__id, h__name, h__level, h__effective, h__expires, rec_lvl)
AS (
SELECT
item.id as i__id,
item.name as i__name,
item.effectivets as i__effective,
item.expirests as i__expires,
item.lefttag as i__lefttag,
item.righttag as i__righttag,
hier_id, hier_dim_id,
parent_item_id,
parent_hier_id,
parent_dim_id, 1 as ancestor,
hier.id as h__id, hier.name as h__name,
hier.level as h__level, hier.effectivets as h__effective,
hier.expirests as h__expires, 1 as rec_lvl FROM metro.item item,
metro.hierarchy hier WHERE item.id = 'DI' AND hier_id = '69' AND hier_dim_id= '36' AND hier.id =item.hier_id
)
SELECT
i__id, i__name, i__effective, i__expires, i__lefttag,
i__righttag, hier_id, hier_dim_id, parent_item_id,
parent_hier_id, parent_dim_id, ancestor,
h__id, h__name, h__level, h__effective, h__expires
FROM temptab
This query returns empty dataset, but I expect 1 row.
The data are correct, as similar simple query without with clause works fine.
I investigated the problem and I've found the
Sub Query with WITH-CLAUSE in H2DB
but that solution did not help.
So, does anyone know how H2 supports with clause?
Thanks in advance for your time.
According to the following :h2 database grammar
Looks like WITH clause is not supported in H2 database, except of experimental support for recursive queries: h2 recursive queries
Its supported now http://www.h2database.com/html/grammar.html
For non-recursive queries also.
Related
Is there a way to do this in HiveQL :
SELECT ......
from
default.thm_renta_produits_jour rpj
WHERE
rpj.co_societe = '${hiveconf:in_co_societe}'
AND rpj.dt_jour >= (SELECT MIN(dt_jour) FROM default.calendrier WHERE co_an_semaine = '${hiveconf:in_co_an_sem}')
Because when i do this, i get this error :
FAILED: ParseException line 51:26 cannot recognize input near 'SELECT' 'MIN' '(' in expression specification
Thanks,
Hive does not support sub queries in where clause it supports sub queries in from clause only.
Hive does not support sub queries in the WHERE clause. Perhaps you can work around this by moving your sub query to a JOIN clause like so:
SELECT
rpj.*
FROM
default.thm_renta_produits_jour rpj
JOIN
( SELECT MIN(dt_jour) AS min_dt_jour
FROM default.calendrier
WHERE co_an_semaine = '${hiveconf:in_co_an_sem}'
) m
WHERE
rpj.co_societe = '${hiveconf:in_co_societe}'
AND rpj.dt_jour >= m.min_dt_jour;
Hope that helps.
I know that this is an old post, but the previous answers are now outdated. Newer versions of Hive (0.13+) support subqueries of where clauses, so your query should run.
https://cwiki.apache.org/confluence/display/Hive/LanguageManual+SubQueries#LanguageManualSubQueries-SubqueriesintheWHEREClause
I'm looking to add a conditional IIf or CASE to a WHERE clause in Access SQL to add an either/or condition based upon a passed value. I've seen a couple of examples on the site, but they were a little different and I have struggled to get the code to work in my case. The code:
SELECT * FROM incHC
WHERE
incHC.repdte=(SELECT Max(repdte) AS maxDt FROM bYrs) AND
incHC.asset>0 AND
incHC.eq2<>0 AND
(
CASE WHEN recType="inst" THEN
incHC.orphan=0
ELSE
incHC.orphan<=1
END
)
Any help is much appreciated.
Unless I am missing something with your query, you should be able to do this without a CASE:
SELECT *
FROM incHC
WHERE incHC.repdte=(SELECT Max(repdte) AS maxDt FROM bYrs)
AND incHC.asset>0
AND incHC.eq2<>0
AND
(
(
recType="inst"
AND incHC.orphan=0
)
OR
(
recType<>"inst"
AND incHC.orphan<=1
)
)
I have the following sql syntax that I used in my database query (SQL Server)
SELECT Nieuwsbrief.ID
, Nieuwsbrief.Titel
, Nieuwsbrief.Brief
, Nieuwsbrief.NieuwsbriefTypeCode
, (SELECT COUNT(*) AS Expr1
FROM NieuwsbriefCommentaar
WHERE (Nieuwsbrief.ID = NieuwsbriefCommentaar.NieuwsbriefID
AND NieuwsbriefCommentaar.Goedgekeurd = 1)) AS AantalCommentaren
FROM Nieuwsbrief
I'm changing now to sql-server-ce (compact edition) which won't allow me to have subqueries like this. Proposed solution : inner join. But as I only need a count of the subtable 'NieuwsbriefCommentaar', I have to use a 'group by' clause on my base table attributes to avoid doubles in the result set.
However the 'Nieuwbrief.Brief' attribute is of datatype 'text'. Group by clauses are not allowed on 'text' datatype in sql-server-ce. 'Text' datatype is deprecated, but sql-server-ce doesn't support 'nvarchar(max)' yet...
Any idea how to solve this? Thx for your help.
I think that the solution could be easier. I don't know exactly how is your metadata but I think that this code could fit your requirements by simply using LEFT JOIN.
SELECT Nieuwsbrief.ID
, Nieuwsbrief.Titel
, Nieuwsbrief.Brief
, Nieuwsbrief.NieuwsbriefTypeCode
, COUNT(NieuwsbriefCommentaar.NieuwsbriefID) AS AantalCommentaren
FROM Nieuwsbrief
LEFT JOIN NieuwsbriefCommentaar ON (Nieuwsbrief.ID = NieuwsbriefCommentaar.NieuwsbriefID)
WHERE NieuwsbriefCommentaar.Goedgekeurd = 1
Edited: 2ndOption
SELECT N.ID, N.Titel, N.Brief, N.NieuwsbriefTypeCode, G.AantalCommentaren FROM Nieuwsbrief as N LEFT JOIN (SELECT NieuwsbriefID, COUNT(*) AS AantalCommentaren FROM NieuwsbriefCommentaar GROUP BY NieuwsbriefID) AS G ON (N.ID = G.NieuwsbriefID)
Please, let me know if this code works in order to find out another workaround..
regards,
suppose we have a model in django defined as follows:
class Literal:
name = models.CharField(...)
...
Name field is not unique, and thus can have duplicate values. I need to accomplish the following task:
Select all rows from the model that have at least one duplicate value of the name field.
I know how to do it using plain SQL (may be not the best solution):
select * from literal where name IN (
select name from literal group by name having count((name)) > 1
);
So, is it possible to select this using django ORM? Or better SQL solution?
Try:
from django.db.models import Count
Literal.objects.values('name')
.annotate(Count('id'))
.order_by()
.filter(id__count__gt=1)
This is as close as you can get with Django. The problem is that this will return a ValuesQuerySet with only name and count. However, you can then use this to construct a regular QuerySet by feeding it back into another query:
dupes = Literal.objects.values('name')
.annotate(Count('id'))
.order_by()
.filter(id__count__gt=1)
Literal.objects.filter(name__in=[item['name'] for item in dupes])
This was rejected as an edit. So here it is as a better answer
dups = (
Literal.objects.values('name')
.annotate(count=Count('id'))
.values('name')
.order_by()
.filter(count__gt=1)
)
This will return a ValuesQuerySet with all of the duplicate names. However, you can then use this to construct a regular QuerySet by feeding it back into another query. The django ORM is smart enough to combine these into a single query:
Literal.objects.filter(name__in=dups)
The extra call to .values('name') after the annotate call looks a little strange. Without this, the subquery fails. The extra values tricks the ORM into only selecting the name column for the subquery.
try using aggregation
Literal.objects.values('name').annotate(name_count=Count('name')).exclude(name_count=1)
In case you use PostgreSQL, you can do something like this:
from django.contrib.postgres.aggregates import ArrayAgg
from django.db.models import Func, Value
duplicate_ids = (Literal.objects.values('name')
.annotate(ids=ArrayAgg('id'))
.annotate(c=Func('ids', Value(1), function='array_length'))
.filter(c__gt=1)
.annotate(ids=Func('ids', function='unnest'))
.values_list('ids', flat=True))
It results in this rather simple SQL query:
SELECT unnest(ARRAY_AGG("app_literal"."id")) AS "ids"
FROM "app_literal"
GROUP BY "app_literal"."name"
HAVING array_length(ARRAY_AGG("app_literal"."id"), 1) > 1
Ok, so for some reason none of the above worked for, it always returned <MultilingualQuerySet []>. I use the following, much easier to understand but not so elegant solution:
dupes = []
uniques = []
dupes_query = MyModel.objects.values_list('field', flat=True)
for dupe in set(dupes_query):
if not dupe in uniques:
uniques.append(dupe)
else:
dupes.append(dupe)
print(set(dupes))
If you want to result only names list but not objects, you can use the following query
repeated_names = Literal.objects.values('name').annotate(Count('id')).order_by().filter(id__count__gt=1).values_list('name', flat='true')
EDIT: Specifically talking about querying against no table. Yes I can use exists, but I'd have to do
select case when exists (blah) then 1 else 0 end as conditionTrue
from ARealTableReturningMultipleRows
In T-SQL I can do:
select case when exists(blah) then 1 else 0 end as conditionTrue
In Oracle I can do:
select case when exists(blah) then 1 else 0 end as conditionTrue from DUAL
How can I achieve the same thing in HQL?
select count() seems like the second-best alternative, but I don't want to have to process every row in the table if I don't need to.
Short answer: I believe it's NOT possible.
My reasoning:
According to Where can I find a list of all HQL keywords? Hibernate project doesn't publish HQL grammar on their website, it's available in the Hibernate full distribution as a .g ANTLR file though.
I don't have much experience with .g files from ANTLR, but you can find this in the file (hibernate-distribution-3.6.1.Final/project/core/src/main/antlr/hql.g):
selectFrom!
: (s:selectClause)? (f:fromClause)? {
// If there was no FROM clause and this is a filter query, create a from clause. Otherwise, throw
// an exception because non-filter queries must have a FROM clause.
if (#f == null) {
if (filter) {
#f = #([FROM,"{filter-implied FROM}"]);
}
else
throw new SemanticException("FROM expected (non-filter queries must contain a FROM clause)");
}
which clearly states there are some HQL queries having no FROM clause, but that's acceptable if that's a filter query. Now again, I am not an expert in HQL/Hibernate, but I believe a filter query is not a full query but something you define using session.createFilter (see How do I turn item ordering HQL into a filter query?), so that makes me think there's no way to omit the FROM clause.
I'm use fake table with one row for example MyDual.
select case when exists(blah) then 1 else 0 end as conditionTrue from MyDual
According to http://docs.jboss.org/hibernate/core/3.3/reference/en/html/queryhql.html#queryhql-expressions it looks like they support both case and exists statements.