I understand that id is for any Object type even objects that do not inherit NSObject such as things from Cocoa. I have been told to almost always use id but what if I were making an API and had a method that I wanted to make it clear that it should only take a certain type of object such an object called Animal, would I still use
(id) animal
or would I do
(Animal) animal
Thanks so much!
id is a generic pointer to an object -- it's like void *, except that the pointer must point to an Objective-C object. So yes, you could use id in most situations where a more specific object pointer type would work, but it's usually better to use the more specific type:
- (id)animal; // OK if 'animal' could be any type of object
- (Animal*)animal; // much better if you know that 'animal' points to an object of type 'Animal'
You'll find plenty of examples if you look at any Cocoa or Cocoa Touch class. Let's look at a little bit of UIView:
- (BOOL)isDescendantOfView:(UIView *)view; // returns YES for self.
- (UIView *)viewWithTag:(NSInteger)tag; // recursive search. includes self
As you can see, the first method takes a UIView* as a parameter. If you try to pass something other than a pointer to an instance of UIView, the compiler will complain.
The second method returns a UIView*, and you can use the result directly as the receiver of other messages that UIView understands:
[[topView viewWithTag:someTag] removeFromSuperview];
Being specific about the types of parameters and return values lets the compiler help you make sure that you're sending appropriate messages to your objects and getting appropriate values back.
You can use any type starting from Animal and then up through inheritance chain to NSObject and id. Any would be valid. But in most cases you need to use just Animal because this is the very type you need to work with
Related
In Objective-C, is it possible to restrict id to just a few types? I want to write a method having an id parameter, but this method applies only to some ObjC types: using id could lead to runtime errors. Is there any LLVM convention or something like that?
id is a generic Objective-C object pointer, ie it means any object.
The only way you could restrict the type would be using protocols:
id <myProtocol>
Therefore, in this way, you point to any object which adopts the myProtocol protocol.
As long as you're dealing with objects, you can ask for it's class:
id anId;
if ([anId isKindOfClass:[NSNumber class]]) {
...
}
"restricting" id is not something Objective-C has. Anyways, if you pass an object of which the type doesn't match the type specified in the method declaration, you would only get a warning and not a compiler error (unless you compile using -Werror), so the compiler can't really prevent you from doing this.
Yes, this is runtime-error-prone, but that's how Objective-C works. One thing you should do is documenting which types are accepted.
One thing you can do is checking the type at runtime, either by using the isKindOfClass: or isMemeberOfClass: methods of NSObject. Also, if there are a common set of messages the object should respond to, you can wrap them into a protocol and require an expression of type id <MyProtocol>.
When you retrieve the ID of a selector with #selector(), is the selector value different depending on the types of the arguments?
Here's what I mean. I have a method that takes an object reference and a selector, then calls it with a parameter:
-(void)CallLater:(NSObject*) Obj Sel: (SEL)Sel
{
//Some stuff, then:
[Obj performSelector: Sel withObject: SomeOtherObject];
}
I'm using this method with a selector to a function that takes a typed object reference, not an id:
-(void)MyMethod: (MyObject*) a
{
}
[self CallLater: self Sel:#selector(MyMethod:)];
It seems to work, but my senses are tingling. In a statically typed language like C# this would be a foul, an upcast - CallLater is expecting a selector for a function that takes an id and I'm giving it a function that takes a MyObject.
On the other hand, the compiler does not complain, and both id and concrete object references seems to be mere pointers deep down, trivially castable to one another. Then again, there are many fouls that Objective C compiler does not complain about.
So the real question is - is it safe? Language lawyers welcome.
It's safe; objects are objects. A selector parameter for an NSObject * is exactly the same as a selector parameter for a MyObject *.
If you want MyMethod to verify that it's being called with an object of a particular type, it should do a NSParameterAssert on it:
NSParameterAssert([obj isKindOfClass: [MyObject class]]);
Personally, I rarely do this check. It's enough that the actual object acts like the type I want it to be, and if it doesn't I'll get a runtime error (usually unrecognized selector). You'll get a compiler warning in the simple cases, and it's worth paying attention to this warning (and silencing it with an id cast when necessary).
I'm a bit confused here about your use of id in your question, so I want to make sure you understand this: An NSObject * is exactly as much an id as a MyObject * is. id is a generic instance pointer class, whereas NSObject * is a NSObject instance (or a subclass of NSObject). You can have objects that don't descend from NSObject. But you're unlikely to ever have to know this.
Other notes, re: convention:
Selectors (both the name and parameters) start with lowercase letters, so CallLater:Sel: should be callLater:sel:.
Variable and parameter names start with lowercase letters; Obj above should be obj.
Class names do start with an uppercase letter. :)
is it possible to specify that a NSMutableArray can only contain a certain type of objects.
For example, if I want to store only this kind of objects :
#interface MyObject : NSObject {
UInt8 value;
}
In order to be able to use the instance variable like this :
- (void)myMethod:(NSMutableArray *)myArray{
for (id myObject in myArray){
[self otherMethod:myObject.value];
}
}
because I'm getting this error :
request for member 'value' in something not a structure or union
Thank you for your help
It sounds like you're coming from a Java/C# type background where limits can be imposed on collections.
Collections in Cocoa don't follow that pattern. There is no way to set a restriction on what type of objects can be inserted (unless you write a wrapper class that enforces this).
Objective-C, by design, follows the "if it walks like a duck and it quacks like a duck, then it most probably is a duck" philosophy. That is to say that rather than checking whether an object is a particular type, you should be checking whether it can do what you want it to do regardless of its type.
You can do this using respondsToSelector:.
Finally, your problem isn't actually related to the fact that the array has no restrictions. Your object doesn't appear to declare the instance variable value as a property, or expose any accessor methods for it.
This is why you're seeing the error when you try myObject.value. That syntax in Objective-C is how you access properties.
The default scope for instance variables in Objective-C is #protected, which means anything outside your class can't access them without going through an accessor method of some kind.
You need to declare and define the methods - (UInt8)value and - (void)setValue:(UInt8)aValue and use them.
Alternatively, you could declare it as a property.
You are getting that error, because for as far as Objective-C is concerned, myObject is of the non-type id, which doesn't support the value property. To make Objective-C aware of the fact it's always dealing with a MyObject in this loop, you'll have to tell it the myObject object is an instance of MyObject.
for (MyObject *myObject in myArray) {
Also, you have to make sure the value ivar is accessible using dot-notation by implementing getter and setter methods for it. You can do this yourself by implementing -value and -setValue:, or you can use #property and #synthesize to let Objective-C do this.
Objective-C doesn't work like that. You need to use [myObject value] (which will work irrespective of the kind of object, as long as it responds to -[value]. If you only want one type of objects in it, insert only that type of objects.
You would have to write a wrapper-class for the NSMutableArray, see for example this question.
Subclass NSMutableArray and override methods that mediate the addition of objects to the array. You would check the object type in these overridden methods, only calling [super addObject:xyz] if the type is accepted.
maybe you can use protocol:
#protocol Person <NSObject>
#end
#interface Person : NSObject <Person>
#end
to use:
NSArray<Person>* personArray;
I have a function that I want to operate on two different custom objects. My first thought was to accept the argument as an (id) and operate on the id object. I can't quite seem to figure out how to do that, however.
Both classes (say apples and oranges) have interface variables:
NSDecimalNumber *count;
I want to do something similar to this:
-(NSDecimalNumber*)addCount:(id)addObject{
return [count decimalNumberByAdding:addObject.count];
}
I can't seem to figure out the syntax to make that happen. Is this the proper approach, or would it be better to subclass (from say a fruit class) and operate on the parent class?
-(NSDecimalNumber*)addCount:(Fruit*)addFruit{
return [count decimalNumberByAdding:addFruit.count];
}
While you can send a message to any object (id) - property accessors require that the compiler be aware of the type you are dealing with - this is because property accessors are syntactic sugar around calling specific getter and setter methods.
You have a few of ways of working around this:
Instead of accessing the count property, call the corresponding [getCount] methods.
If the different classes have different versions of this method, you can use a runtime type check:
Provide a base class for both types so that you can pass in something more specific than (id).
Define and implement a Protocol that both objects implement that defines a count property (or method).
Example of a dynamic type check:
if( [object isKindOfClass:[Apple Class] )
// call one overload of getCount
else if( [object isKindOfClass:[Orange Class] )
// call another overload of getCount
Personally, I favor strong typing in my code because it makes it easier to understand the intent. It also allows the IDE to support your coding effort with intellisense, static analysis, and refactoring features. So, in your case, I would use either #3 or #4 as an approach - depending on whether inheritance is really appropriate for the problem.
You should try not to access instance variables from another class.
In Objective-C it's enough that the two objects respond to the same selector (say count), however that would give you a compiler warning.
There are two ways you can get rid of this warning: either by subclassing from a common Fruit class or by having your two classes conform to a protocol. I'd go with the protocol:
#protocol FruitProtocol
- (NSDecimalNumber *)count;
#end
#interface Orange : NSObject<FruitProtocol>
#end
#interface Apple : NSObject<FruitProtocol>
#end
Then your method can look like this:
-(NSDecimalNumber*)addCount:(id<FruitProtocol>)addFruit {
return [count decimalNumberByAdding:[addFruit count]];
}
Here you are saying that your addCount expects any object that conforms to the FruitProtocol protocol, and hence can respond to the count selector, so the compiler will accept it.
The fact that you are trying to access 'addFruit.count' is the problem. The dot syntax is only for properties declared with #property (or for structs). If you change it to
[addFruit count]
and add
-(NSDecimalNumber*)count
{
return [[count retain] autorelease];
}
to each class, then it would work. However, you will notice you'll get a warning saying 'id' may not respond to the 'count' message, and unless you can be absolutely sure the items sent to this method implement a 'count' method, this is a problematic approach.
I agree with pgb's approach. You should define a protocol, and declare both classes to implement that protocol. This eliminates the problem of not knowing whether the object will respond to 'count' or not, as you now have a 'contract' of sorts.
If you want to keep the dot syntax with a property, you can declare it in the protocol:
#protocol FruitProtocol
#property(readonly) NSDecimalNumber * count;
- (NSDecimalNumber *)count
#end
and then, your function would be:
-(NSDecimalNumber*)addCount:(id<FruitProtocol>)addObject{
return [count decimalNumberByAdding:addObject.count];
}
You're sending the message to count, what is count? id is a pointer to any type of object. If you expect the object to have a count property, then you should only be able to pass in an Array (or some other type restriction).
-(NSDecimalNumber*)addCount:(NSArray*) Object{
return [count decimalNumberByAdding: [Object count]];
}
As I understand it, id does not have any methods or variables associated with it because it is a generic pointer that does not refer to any specific class. This page has some good info on ids if you scroll down a bit.
anObject this will not have a count variable, which is why your first attempt won't work. Creating a base class and using that as a parameter to the method seems like the best idea to me.
In Objective-C, what's the difference between declaring a variable id versus declaring it NSObject *?
With a variable typed id, you can send it any known message and the compiler will not complain. With a variable typed NSObject *, you can only send it messages declared by NSObject (not methods of any subclass) or else it will generate a warning. In general, id is what you want.
Further explanation: All objects are essentially of type id. The point of declaring a static type is to tell the compiler, "Assume that this object is a member of this class." So if you send it a message that the class doesn't declare, the compiler can tell you, "Wait, that object isn't supposed to get that message!" Also, if two classes have methods with the same name but different signatures (that is, argument or return types), it can guess which method you mean by the class you've declared for the variable. If it's declared as id, the compiler will just throw its hands up and tell you, "OK, I don't have enough information here. I'm picking a method signature at random." (This generally won't be helped by declaring NSObject*, though. Usually the conflict is between two more specific classes.)
id means "an object", NSObject * means "an instance of NSObject or one of its subclasses". There are objects in Objective-C which are not NSObjects (the ones you'll meet in Cocoa at the moment are NSProxy, Protocol and Class). If some code expects an object of a particular class, declaring that helps the compiler check that you're using it properly. If you really can take "any object" - for instance you are declaring a delegate and will test all method sends with respondsToSelector: calls - you can use an id.
Another way to declare an object variable is like "id <NSObject>", which means "any object which implements the NSObject protocol.
From my limited understanding of Objective-C, not all objects are derived from NSObject (unlike Java where all objects derive from Object). You can theoretically have other root objects. id could apply to any of those non-NSObject derived objects.
I would like to add another difference. When you add a protocol to id, it does not longer mean that it will be of type NSObject *, it just means that it will be any class that confirms to that protocol.
So, for example, this code will not throw any error, since NSObject's category NSDelayedPerforming has that method:
id testId;
[testId performSelector:#selector(isKindOfClass:) withObject:[NSObject class] afterDelay:.5];
However, this code will show the error No known instance method for selector "performSelector:withObject:afterDelay:":
id<NSMutableCopying> testId;
[testId performSelector:#selector(isKindOfClass:) withObject:[NSObject class] afterDelay:.5];