I am trying to append all lines that begin with > to the previous line that did not begin with >
cat tmp
ATAAACGGAAAAACACTACTTTAGCTTACGGGATCCGGT
>Aa_816
>Aa_817
>Aa_818
CCAAACGGAAAAACACTACTTGAGCTTACGGGATCCGGT
>Aa_940
>Aa_941
CTAAAAGGAAAAACACTACTTTAGCTTTTGGGATCCGGT
What I want is this:
ATAAACGGAAAAACACTACTTTAGCTTACGGGATCCGGT >Aa_816 >Aa_817 >Aa_818
CCAAACGGAAAAACACTACTTGAGCTTACGGGATCCGGT >Aa_940 >Aa_941
CTAAAAGGAAAAACACTACTTTAGCTTTTGGGATCCGGT
This almost gets me there:
cat tmp |awk '!/>/ {sub(/\\$/,""); getline t; print $0 t; next}; 1'
With awk:
awk '!/^>/{printf "%s%s", (NR==1)?"":RS,$0;next}{printf "%s", FS $0}END{print ""}' file
Using awk
awk '!/>/{printf (NR==1)?$0:RS $0;next}{printf FS $0}' file
If you don't care the output has new line generated on the first line, here is the shorter one.
awk '{printf (/>/?FS $0:RS $0)}' file
I think all you need is a little sed:
sed ':a; N; $!ba; s/\n>/ >/g' file
Results:
ATAAACGGAAAAACACTACTTTAGCTTACGGGATCCGGT >Aa_816 >Aa_817 >Aa_818
CCAAACGGAAAAACACTACTTGAGCTTACGGGATCCGGT >Aa_940 >Aa_941
CTAAAAGGAAAAACACTACTTTAGCTTTTGGGATCCGGT
awk '/^[^>]/ { if (length(old) > 0) print old; old = $0 }
/^>/ { old = old " " $0 }
END { if (length(old) > 0) print old }'
Related
I have a file.file content is:
20210126000880000003|3|33.00|20210126|15:30
1|20210126000000000000000000002207|1220210126080109|1000|100000000000000319|100058110000000325|402041000012|402041000012|PT07|621067000000123645|收款方户名|2021-01-26|2021-01-26|10.00|TN|NCS|12|875466
2|20210126000000000000000000002208|1220210126080110|1000|100000000000000319|100058110000000325|402041000012|402041000012|PT06|621067000000123645|收款方户名|2021-01-26|2021-01-26|20.00|TN|NCS|12|875466
3|20210126000000000000000000002209|1220210126080111|1000|100000000000000319|100058110000000325|402041000012|402041000012|PT08|621067000000123645|收款方户名|2021-01-26|2021-01-26|3.00|TN|NCS|12|875466
I use awk command:
awk -F"|" 'NR==1{print $1};FNR==2{print $2,$3}' testfile
Get the following result：
20210126000880000003
20210126000000000000000000002207 1220210126080109
I want the number to auto-increase:
awk -F"|" 'NR==1{print $1+1};FNR==2{print $2+1,$3+1}' testfile
But get follow result:
20210126000880001024
20210126000000000944237587726336 1220210126080110
have question:
I want to the numer is auto-increase: hope the result is：
20210126000880000003
20210126000000000000000000002207|1220210126080109
-------------------------------------------------
20210126000880000004
20210126000000000000000000002208|1220210126080110
--------------------------------------------------
20210126000880000005
20210126000000000000000000002209|1220210126080111
How to auto_increase?
Thanks!
You may try this gnu awk command:
awk -M 'BEGIN {FS=OFS="|"} NR == 1 {hdr = $1; next} NF>2 {print ++hdr; print $2, $3; print "-------------------"}' file
20210126000880000004
20210126000000000000000000002207|1220210126080109
-------------------
20210126000880000005
20210126000000000000000000002208|1220210126080110
-------------------
20210126000880000006
20210126000000000000000000002209|1220210126080111
-------------------
A more readable version:
awk -M 'BEGIN {
FS=OFS="|"
}
NR == 1 {
hdr = $1
next
}
NF > 2 {
print ++hdr
print $2, $3
print "-------------------"
}' file
Here is a POSIX awk solution that doesn't need -M:
awk 'BEGIN {FS=OFS="|"} NR == 1 {hdr = $1; next} NF>2 {"echo " hdr " + 1 | bc" | getline hdr; print hdr; print $2, $3; print "-------------------"}' file
20210126000880000004
20210126000000000000000000002207|1220210126080109
-------------------
20210126000880000005
20210126000000000000000000002208|1220210126080110
-------------------
20210126000880000006
20210126000000000000000000002209|1220210126080111
-------------------
Anubhava has the best solution but for older versions of GNU awk that don't support -M (big numbers) you can try the following:
awk -F\| 'NR==1 { print $1;hed=$1;hed1=substr($1,(length($1)-1));next; } !/^$/ {print $2" "$3 } /^$/ { print "--------------------------------------------------";printf "%s%s\n",substr(hed,1,((length(hed))-(length(hed1)+1))),++hed1 }' testfile
Explanation:
awk -F\| 'NR==1 { # Set field delimiter to | and process the first line
print $1; # Print the first field
hed=$1; # Set the variable hed to the first field
hed1=substr($1,(length($1)-1)); # Set a counter variable hed1 to the last digit in hed ($1)
next;
}
!/^$/ {
print $2" "$3 # Where there is no blank line, print the second field, a space and the third field
}
/^$/ {
print "--------------------------------------------------"; # Where there is a blank field, process
printf "%s%s\n",substr(hed,1,((length(hed))-(length(hed1)+1))),++hed1 # print the header extract before the counter, followed by the incremented counter
}' testfile
I need to merge all the lines that have the same value on the first column.
The input file is the following:
34600000031|(1|1|0|1|1|20190114180000|20191027185959)
34600000031|(2|2|0|2|2|20190114180000|20191027185959)
34600000031|(3|3|0|3|3|20190114180000|20191027185959)
34600000031|(4|4|0|4|4|20190114180000|20191027185959)
34600000015|(1|1|100|1|8|20190114180000|20191027185959)
34600000015|(2|2|100|2|9|20190114180000|20191027185959)
34600000015|(3|3|100|3|10|20190114180000|20191027185959)
34600000015|(4|4|100|4|11|20190114180000|20191027185959)
I was able to partially achieve it using the following:
awk -F'|' '$1!=p{if(p)print s; p=$1; s=$0; next}{sub(p,x); s=s $0} END{print s}' INPUT
The output is the following:
34600000031|(1|1|0|1|1|20190114180000|20191027185959)|(2|2|0|2|2|20190114180000|20191027185959)|(3|3|0|3|3|20190114180000|20191027185959)|(4|4|0|4|4|20190114180000|20191027185959)
34600000015|(1|1|100|1|8|20190114180000|20191027185959)|(2|2|100|2|9|20190114180000|20191027185959)|(3|3|100|3|10|20190114180000|20191027185959)|(4|4|100|4|11|20190114180000|20191027185959)
What I need (and i cannot find how) is the following:
34600000031|(1|1|0|1|1|20190114180000|20191027185959)(2|2|0|2|2|20190114180000|20191027185959)(3|3|0|3|3|20190114180000|20191027185959)(4|4|0|4|4|20190114180000|20191027185959)
34600000015|(1|1|100|1|8|20190114180000|20191027185959)(2|2|100|2|9|20190114180000|20191027185959)(3|3|100|3|10|20190114180000|20191027185959)(4|4|100|4|11|20190114180000|20191027185959)
I could do a sed after the initial awk but I don't believe that this is the proper way to do it.
You need to substitute the separator in the values too. Your fixes awk would look like this:
awk -F'|' '$1!=p{if(p)print s; p=$1; s=$0; next}{sub(p "\\|",x); s=s $0} END{print s}'
but it's also good to match beginning of the string:
awk -F'|' '$1!=p{if(p)print s; p=$1; s=$0; next}{sub("^" p "\\|",x); s=s $0} END{print s}'
I would do it somewhat simpler, which uses more memory (as it stores everything in an array) but doesn't need the file to be sorted:
awk -F'|' '{ k=$1; sub("^" $1 "\\|", ""); a[k] = a[k] $0 } END{ for (i in a) print i "|" a[i] }'
For each line, remember the first field, substitute the first field with | for nothing, then add it to an array indexed by the first field. On the end, print each element in the array with the key, separator and value.
$ awk -F'|' '
{
curr = $1
sub(/^[^|]+\|/,"")
printf "%s%s", (curr==prev ? "" : ors curr FS), $0
ors = ORS
prev = curr
}
END { print "" }
' file
34600000031|(1|1|0|1|1|20190114180000|20191027185959)(2|2|0|2|2|20190114180000|20191027185959)(3|3|0|3|3|20190114180000|20191027185959)(4|4|0|4|4|20190114180000|20191027185959)
34600000015|(1|1|100|1|8|20190114180000|20191027185959)(2|2|100|2|9|20190114180000|20191027185959)(3|3|100|3|10|20190114180000|20191027185959)(4|4|100|4|11|20190114180000|20191027185959)
I have two files. I need to print information like the example, when the first field exist and is equal, in two files.
file 1
20;"aaaaaa";99292929
24;"fsfdfa";42933294
30;"fsdsff";23832299
38;"fjsdjl";62673777
file 2
13;"fsdffsdfs";2272777
20;"ffuiiii";23728877
30;"wdwfsdh";8882817
40;"sfjslll";82371111
expect result:
file1;20;"aaaaaa";99292929;file2;20;"ffuiiii";23728877
file1,30;"fsdsff";23832299;file2;30;"wdwfsdh";8882817
I tried with:
awk 'FNR==NR{a[$1]=$1;next} $1 in a' file2 file1 > newfile
logical it's ok, but I can't show fields that I want.
awk will help:
awk -F ';' 'NR==FNR{rec[$1]=FILENAME FS $0}
NR>FNR{
if($1 in rec){
print rec[$1] FS FILENAME FS $0
}
}' file{1..2}
should do.
$ cat tst.awk
BEGIN { FS=OFS=";" }
{ $0 = FILENAME FS $0 }
NR==FNR { a[$2] = $0; next }
$2 in a { print a[$2], $0 }
$ awk -f tst.awk file1 file2
file1;20;"aaaaaa";99292929;file2;20;"ffuiiii";23728877
file1;30;"fsdsff";23832299;file2;30;"wdwfsdh";8882817
I want to compare two files delimited with
;
with the same field1,
output field2 of file1 and field2 field1 of file2.
File1:
16003-Z/VG043;204352
16003/C3;100947
16003/C3;172973
16003/PAB4L;62245
16003;100530
16003;101691
16003;144786
File2:
16003-Z/VG043;568E;0540575;2.59
16003/C3;568E;0000340;2.53
16003/PAB4L;568H;0606738;9.74
16003;568E;0000339;0.71
16003TN9/C3;568E;0042261;3.29
Desired output:
204352;568E;16003-Z/VG043
100947;568E;16003/C3
172973;568E;16003/C3
62245;568H;16003/PAB4L
100530;568E;16003
101691;568E;16003
144786;568E;16003
My try:
awk -F\, '{FS=";"} NR==FNR {a[$1]; next} ($1) in a{ print a[$2]";"$2";"$3}' File1 File2 > Output
The above is not working probably because awk is still obscure to me.
The problem is what is driving the output? what $1, $2, etc are referred to what?
The a[$2] in my intention is the field2 of file 1....but it is not...
What I get is:
;204352;16003-Z/VG043
;100947;16003/C3
;172973;16003/C3
;62245;16003/PAB4L
;100530;16003
;101691;16003
;144786;16003
thanks for helping
This might be what you are after:
awk -F";" '(NR==FNR) { a[$1] = ($1 in a ? a[$1] FS : "") $2; next }
($1 in a) { split(a[$1],b); for(i in b) print b[i] FS $2 FS $1 }' file1 file2
This outputs:
204352;568E;16003-Z/VG043
100947;568E;16003/C3
172973;568E;16003/C3
62245;568H;16003/PAB4L
100530;568E;16003
101691;568E;16003
144786;568E;16003
This approach reads a file file_1.txt by first into an associative array table. (This is done to associate ids / values across files.) Then, looping over the 2nd file file_2.txt, I print the values in table that match the id field of this file along with the current value:
BEGIN {
FS=OFS=";"
while (getline < first)
table[$1] = $2 FS table[$1]
}
$1 in table {
len = split(table[$1], parts)
for (i=1; i<len; i++)
print parts[i], $2, $1
}
$ awk -v first=file_1.txt -f script.awk file_2.txt
204352;568E;16003-Z/VG043
172973;568E;16003/C3
100947;568E;16003/C3
62245;568H;16003/PAB4L
144786;568E;16003
101691;568E;16003
100530;568E;16003
Would like to print unique lines based on first field , keep the first occurrence of that line and remove duplicate other occurrences.
Input.csv
10,15-10-2014,abc
20,12-10-2014,bcd
10,09-10-2014,def
40,06-10-2014,ghi
10,15-10-2014,abc
Desired Output:
10,15-10-2014,abc
20,12-10-2014,bcd
40,06-10-2014,ghi
Have tried below command and in-complete
awk 'BEGIN { FS = OFS = "," } { !seen[$1]++ } END { for ( i in seen) print $0}' Input.csv
Looking for your suggestions ...
You put your test for "seen" in the action part of the script instead of the condition part. Change it to:
awk -F, '!seen[$1]++' Input.csv
Yes, that's the whole script:
$ cat Input.csv
10,15-10-2014,abc
20,12-10-2014,bcd
10,09-10-2014,def
40,06-10-2014,ghi
10,15-10-2014,abc
$
$ awk -F, '!seen[$1]++' Input.csv
10,15-10-2014,abc
20,12-10-2014,bcd
40,06-10-2014,ghi
This should give you what you want:
awk -F, '{ if (!($1 in a)) a[$1] = $0; } END '{ for (i in a) print a[i]}' input.csv
typo there in syntax.
awk '{ if (!($1 in a)) a[$1] = $0; } END { for (i in a) print a[i]}'