GROUP BY in SPARQL? - sparql

Question

Assume that I uses the FOAF ontology. I want to return the name and the mbox for each person. I use the following query:
PREFIX foaf: <http://xmlns.com/foaf/0.1/>
SELECT DISTINCT ?name ?email
WHERE {
?person foaf:name ?name.
?person foaf:mbox ?email.
}
The result of the join is a set of rows: ?person, ?name, ?email. This query is returning the ?name and ?email. Note that in some of the ?person may have multiple mailboxes, so in the returned set, a ?name row may appear multiple times, once for each mailbox.
Is there a solution to make a GROUP BY person ?name?

Answer 1

You can group by person but then you need an aggregation for ?name and ?email
PREFIX foaf: <http://xmlns.com/foaf/0.1/>
SELECT (sample(?name) AS ?name2) (sample(?email) as ?email2)
WHERE {
?person foaf:name ?name.
?person foaf:mbox ?email.
} GROUP BY ?person
SAMPLE picks one possible from the group for each ?person.
or maybe
SELECT (group_concat(?name) AS ?names)
(except that's a string).
It may be easier work with
PREFIX foaf: <http://xmlns.com/foaf/0.1/>
SELECT ?name ?email
WHERE {
?person foaf:name ?name.
?person foaf:mbox ?email.
}
ORDER BY ?person ?name ?email
and process the results in your application where you know the incoming results have all the entries for one person is a single section of the results.