I have 2 columns from a table and i want to add a third column to output the result of a calculation
select statement at the moment is:
select revenue, cost
from costdata
my 2 columns are revenue and cost
table name: costdata
my formula is: = ((revenue - cost)/ revenue)*100
I want the third column to be named 'result'
any idea on how to do this in a select statement?
SELECT revenue
, cost
, ((revenue - cost) / revenue) * 100 As result
FROM costdata
You mentioned in the comments that you get a divide by zero error. This wll occur when revenue equals zero.
What you want to happen in this scenario is up to you but this should get you started
SELECT revenue
, cost
, CASE WHEN revenue = 0 THEN
0
ELSE
((revenue - cost) / revenue) * 100
END As result
FROM costdata
Query:
SELECT revenue,
cost,
CASE WHEN revenue <> 0
THEN ((revenue - cost) / revenue) * 100
ELSE 0 END As result
FROM costdata
Try,
select revenue, cost,((revenue - cost)/ revenue)*100 AS result
from costdata
SELECT revenue, cost, ((revenue - cost)/ revenue)*100 AS result FROM costdata
Related
I have a table in GBQ in the following format :
UserId Orders Month
XDT 23 1
XDT 0 4
FKR 3 6
GHR 23 4
... ... ...
It shows the number of orders per user and month.
I want to calculate the percentage of users who have orders, I did it as following :
SELECT
HasOrders,
ROUND(COUNT(*) * 100 / CAST( SUM(COUNT(*)) OVER () AS float64), 2) Parts
FROM (
SELECT
*,
CASE WHEN Orders = 0 THEN 0 ELSE 1 END AS HasOrders
FROM `Table` )
GROUP BY
HasOrders
ORDER BY
Parts
It gives me the following result:
HasOrders Parts
0 35
1 65
I need to calculate the percentage of users who have orders, by month, in a way that every month = 100%
Currently to do this I execute the query once per month, which is not practical :
SELECT
HasOrders,
ROUND(COUNT(*) * 100 / CAST( SUM(COUNT(*)) OVER () AS float64), 2) Parts
FROM (
SELECT
*,
CASE WHEN Orders = 0 THEN 0 ELSE 1 END AS HasOrders
FROM `Table` )
WHERE Month = 1
GROUP BY
HasOrders
ORDER BY
Parts
Is there a way execute a query once and have this result ?
HasOrders Parts Month
0 25 1
1 75 1
0 45 2
1 55 2
... ... ...
SELECT
SIGN(Orders),
ROUND(COUNT(*) * 100.000 / SUM(COUNT(*), 2) OVER (PARTITION BY Month)) AS Parts,
Month
FROM T
GROUP BY Month, SIGN(Orders)
ORDER BY Month, SIGN(Orders)
Demo on Postgres:
https://dbfiddle.uk/?rdbms=postgres_10&fiddle=4cd2d1455673469c2dfc060eccea8020
You've stated that it's important for the total to be 100% so you might consider rounding down in the case of no orders and rounding up in the case of has orders for those scenarios where the percentages falls precisely on an odd multiple of 0.5%. Or perhaps rounding toward even or round smallest down would be better options:
WITH DATA AS (
SELECT SIGN(Orders) AS HasOrders, Month,
COUNT(*) * 10000.000 / SUM(COUNT(*)) OVER (PARTITION BY Month) AS PartsPercent
FROM T
GROUP BY Month, SIGN(Orders)
ORDER BY Month, SIGN(Orders)
)
select HasOrders, Month, PartsPercent,
PartsPercent - TRUNCATE(PartsPercent) AS Fraction,
CASE WHEN HasOrders = 0
THEN FLOOR(PartsPercent) ELSE CEILING(PartsPercent)
END AS PartsRound0Down,
CASE WHEN PartsPercent - TRUNCATE(PartsPercent) = 0.5
AND MOD(TRUNCATE(PartsPercent), 2) = 0
THEN FLOOR(PartsPercent) ELSE ROUND(PartsPercent) -- halfway up
END AS PartsRoundTowardEven,
CASE WHEN PartsPercent - TRUNCATE(PartsPercent) = 0.5 AND PartsPercent < 50
THEN FLOOR(PartsPercent) ELSE ROUND(PartsPercent) -- halfway up
END AS PartsSmallestTowardZero
from DATA
It's usually not advisable to test floating-point values for equality and I don't know how BigQuery's float64 will work with the comparison against 0.5. One half is nevertheless representable in binary. See these in a case where the breakout is 101 vs 99. I don't have immediate access to BigQuery so be aware that Postgres's rounding behavior is different:
https://dbfiddle.uk/?rdbms=postgres_10&fiddle=c8237e272427a0d1114c3d8056a01a09
Consider below approach
select hasOrders, round(100 * parts, 2) as parts, month from (
select month,
countif(orders = 0) / count(*) `0`,
countif(orders > 0) / count(*) `1`,
from your_table
group by month
)
unpivot (parts for hasOrders in (`0`, `1`))
with output like below
Hello i have a sql query and it does not count my one row. which is called Spend, you can see it in the fiddle. what is wrong with my code?
I just need basic table
Month ID GOT SPEND
1 1 100 50
2 1 500 200
1 2 200 50
I have created the fiddle http://sqlfiddle.com/#!9/3623b1/2
Could you please help me?
Here is the query:
select
keliones_lapas.Vairuot_Id,
MONTH(keliones_lapas.Data_darbo),
sum(keliones_lapas.uzdarbis) as Got,
coalesce(Suma, 0) AS Spend,
(sum(keliones_lapas.uzdarbis) - coalesce(Suma, 0)) Total
from keliones_lapas
left join (
select Vairuotas,
MONTH(Data_islaidu) as Data_islaidu,
sum(Suma) as Suma
from islaidos
group by Vairuotas, MONTH(Data_islaidu)) islaidos
on keliones_lapas.Vairuot_Id = islaidos.Vairuotas
and MONTH(keliones_lapas.Data_darbo) = MONTH(islaidos.Data_islaidu)
group by keliones_lapas.Vairuot_Id, MONTH(keliones_lapas.Data_darbo), Suma
order by keliones_lapas.Vairuot_Id, MONTH(keliones_lapas.Data_darbo);
TRY THIS: You are taking already month in your subquery then again using MONTH to retrieve from month in the join so it's returning NULL and not matching with any month of keliones_lapas
SELECT
keliones_lapas.Vairuot_Id,
MONTH(keliones_lapas.Data_darbo),
SUM(keliones_lapas.uzdarbis) AS Got,
COALESCE(Suma, 0) AS Spend,
(SUM(keliones_lapas.uzdarbis) - COALESCE(Suma, 0)) Total
FROM keliones_lapas
LEFT JOIN (
SELECT Vairuotas,
MONTH(Data_islaidu) AS Data_islaidu, --It's already in MONTH
SUM(Suma) AS Suma
FROM islaidos
GROUP BY Vairuotas, MONTH(Data_islaidu)) islaidos
ON keliones_lapas.Vairuot_Id = islaidos.Vairuotas
AND MONTH(keliones_lapas.Data_darbo) = Data_islaidu --No need to use MONTH or `vice versa`
GROUP BY keliones_lapas.Vairuot_Id, MONTH(keliones_lapas.Data_darbo), Suma
ORDER BY keliones_lapas.Vairuot_Id, MONTH(keliones_lapas.Data_darbo)
I'm trying to write a Select statement that increments a column value by 50, but the range can end up being 200,000 so I can't do it all in a case statement manually.
Something similar to this, but instead of manually writing the increments
Select count(order_id) as order_count,
case when revenue between 0 and 50 then ‘$50’
when order_value between 51 and 100 then ‘$100’
else ‘over $101’
end as revenue_bucket
from Orders
group by 2
Turn your revenue into the bucket value, then make string out of it:
SELECT count(order_id) AS order_count,
'$' || ((((revenue - 0.01)/50)::int + 1) * 50)::text AS revenue_bucket
FROM Orders
GROUP BY 2;
This obviously runs well past $200,000.
You can work with modulo to get this. Limit would be 101 in your example. All you have to do, is cast the result in a string and add the $ before it
Select count(order_id) as order_count,
case when revenue < limit then revenue - (revenue % 50) + 50
else ‘over $101’
end as revenue_bucket
from Orders
group by 2
You can round to the nearest 50 with div (integer division):
revenue div 50 * 50
To round up instead of down:
(revenue div 50 + 1) * 50
To include 50 in the next bracket (so 50 as $50 instead of $100):
((revenue-1) div 50 + 1) * 50
Example query:
select revenue
, concat('$', ((revenue-1) div 50 + 1) * 50) as revenue_bucket
from YourTable
See it working at SQL Fiddle.
figured out something similar
select floor((revenue+49)/50)*50 as revenue_bucket,
count(1) as order_count
from Orders
group by 1;
Say, you have a query like
SELECT COUNT(*), date FROM ORDERS GROUP BY date ORDER BY date
but you also want to have a third "phantom/dummy field", where it basically tells you the fraction of orders each day that are of a particular type (lets say "Utensils" and "Perishables").
I should say that there is an additional column in the ORDERS table that has the type of the order:
order_type
The third dummy column should do something like take the count of orders on a date that have the "Utensils" or the "Perishables" type (not XOR), then divide by the total count of orders of that day, and then round to 2 decimal points, and append a percentage sign.
The last few formatting things, aren't really important...all I really need to know is how to apply the logic in valid PLSQL syntax.
Example output
4030 2012-02-02 34.43%
4953 2012-02-03 16.66%
You can do something like
SELECT COUNT(*),
dt,
round( SUM( CASE WHEN order_type = 'Utensils'
THEN 1
ELSE 0
END) * 100 / COUNT(*),2) fraction_of_utensils_orders
FROM ORDERS
GROUP BY dt
ORDER BY st
If you find it easier to follow, you could also
SELECT COUNT(*),
dt,
round( COUNT( CASE WHEN order_type = 'Utensils'
THEN 1
ELSE NULL
END) * 100/ COUNT(*), 2) fraction_of_utensils_orders
FROM ORDERS
GROUP BY dt
ORDER BY st
To Add sum of orders of same type to query:
select
o.*,
(
select count(o2.OrderType)
from ORDERS o2
where o2.OrderType = o.OrderType
) as NumberOfOrdersOfThisType
from ORDERS o
To Add fraction of orders of same type to query:
(Check variable definition to make sure it is PL/SQL)
declare totalCount number
select count(*)
into totalCount
from ORDERS
select
o.*,
(
select count(o2.OrderType)
from ORDERS o2
where o2.OrderType = o.OrderType
) / totalCount as FractionOfOrdersOfThisType
from ORDERS o
I have a table with these columns: ID, Price, IsMonthlyPrice
How can I select all and sort by weekly price, taking into account that:
if (IsMonthlyPrice = false) then Price is weekly
EDIT:
I need to sort by weekly price
weekly price of a monthly price would be: Price*12/52
You don't need to include the calculation twice. You can order on the column number
SELECT
ID,
Price,
IsMonthlyPrice,
CASE IsMonthlyPrice
WHEN 1 THEN Price * 12 / 52
ELSE price
END
FROM [TABLE]
order by
4
Not sure if this is what you look for but maybe try:
select
id,
case isMonthlyPrice when 'false' then (price*52/12) else price end normalizedPrice
from
yourTable
order by
normalizedPrice
You can sort calculated columns using two approaches. The more verbal approach (untested pseudocode) is:
select ID, CASE WHEN IsMonthlyPrice = 0 THEN Price * 52 / 12 ELSE Price END AS Price
ORDER BY CASE WHEN IsMonthlyPrice = 0 THEN Price * 52 / 12 ELSE Price END
The more concise approach is:
select * from
(
select ID, CASE WHEN IsMonthlyPrice = 0 THEN Price * 52 / 12 ELSE Price END AS Price
) as derived
ORDER BY derived.Price
You can use a case to calculate different values depending on whether the price is weekly or monthly.
This will calculate an approximate (assuming 31 days per month) price per day to sort on:
select ID, Price, IsMonthlyPrice
from TheTable
order by Price / case IsMonthlyPrice when 1 then 31.0 else 7.0 end
I generally wrap the select in a another one. then the column is no longer "calculated"
select
Price,
ID
from
(select
ID,
Price,
[calculate the IsMonthly Price] as 'IsMonthlyPrice'
from table
) order by IsMonthlyPrice