I need to order my results by int column ascending, but I want to get only rows with numbers (0...10000) but default ordering gives me rows with null values for this column before numbers. I googled solution which set rows with null into the end of ordering (after all numbers) it looks like
SELECT ProductName
FROM Products
ORDER BY
CASE WHEN Position is null THEN 1 ELSE 0 END,
Position
So I my query looks like:
SELECT c.CompanyId, c.CompanyName, c.CompanyCategoryId, cc.CompanyCategoryName, c.HQCountryISO, c.CrunchBaseUrl,c.AngelListUrl,
(SELECT MAX(mf.NumLikes) FROM MeasurementFacebook mf
JOIN FacebookAccount f ON f.CompanyId = c.CompanyId
WHERE f.FacebookAccountId in (mf.FacebookAccountId)) as Likes,
(SELECT MAX(mt.NumFollowers) FROM MeasurementTwitter mt
JOIN TwitterAccount t ON t.CompanyId = c.CompanyId
WHERE t.TwitterAccountId in (mt.TwitterAccountId)) as Followers,
(SELECT MAX(ma.AlexaRanking) FROM MeasurementAlexa ma
JOIN Website w ON w.CompanyId = c.CompanyId
WHERE w.WebsiteId in (ma.WebsiteId)) as AlexaRank
FROM Company c
JOIN CompanyCategory cc ON c.CompanyCategoryId = cc.CompanyCategoryId
WHERE c.HQCountryISO = 'FRA'
ORDER BY CASE WHEN AlexaRank IS NULL THEN 1 ELSE 0 END, AlexaRank
OFFSET 0 ROWS FETCH NEXT 10 ROWS ONLY
As you can see, AlexaRank is the result of third subquery, and I want to order result by this column. But I have an error which says:
Msg 207, Level 16, State 1, Line 14
Invalid column name 'AlexaRank'.
What I'm doing wrong? Thanks
While you can use an alias in the ORDER BY clause, you can't use an alias in an expression, easiest solution is to plop it in a cte/subquery:
;WITH cte AS (SELECT c.CompanyId
, c.CompanyName
, c.CompanyCategoryId
, cc.CompanyCategoryName
, c.HQCountryISO
, c.CrunchBaseUrl
,c.AngelListUrl
,(SELECT MAX(mf.NumLikes)
FROM MeasurementFacebook mf
JOIN FacebookAccount f ON f.CompanyId = c.CompanyId
WHERE f.FacebookAccountId in (mf.FacebookAccountId)) as Likes
,(SELECT MAX(mt.NumFollowers)
FROM MeasurementTwitter mt
JOIN TwitterAccount t ON t.CompanyId = c.CompanyId
WHERE t.TwitterAccountId in (mt.TwitterAccountId)) as Followers
,(SELECT MAX(ma.AlexaRanking)
FROM MeasurementAlexa ma
JOIN Website w ON w.CompanyId = c.CompanyId
WHERE w.WebsiteId in (ma.WebsiteId)) as AlexaRank
FROM Company c
JOIN CompanyCategory cc ON c.CompanyCategoryId = cc.CompanyCategoryId
WHERE c.HQCountryISO = 'FRA')
SELECT *
FROM cte
ORDER BY CASE WHEN AlexaRank IS NULL THEN 1 ELSE 0 END, AlexaRank
OFFSET 0 ROWS FETCH NEXT 10 ROWS ONLY
Very inefficient code but you could do something like the following. Basically wrap your initial query in a common table expression so you don't need to rewrite your 3rd sub-select in your order by.
SELECT * FROM (
SELECT c.companyid,
c.companyname,
c.companycategoryid,
cc.companycategoryname,
c.hqcountryiso,
c.crunchbaseurl,
c.angellisturl,
(SELECT Max(mf.numlikes)
FROM measurementfacebook mf
JOIN facebookaccount f
ON f.companyid = c.companyid
WHERE f.facebookaccountid IN ( mf.facebookaccountid )) AS Likes,
(SELECT Max(mt.numfollowers)
FROM measurementtwitter mt
JOIN twitteraccount t
ON t.companyid = c.companyid
WHERE t.twitteraccountid IN ( mt.twitteraccountid )) AS Followers,
(SELECT Max(ma.alexaranking)
FROM measurementalexa ma
JOIN website w
ON w.companyid = c.companyid
WHERE w.websiteid IN ( ma.websiteid )) AS AlexaRank
FROM company c
JOIN companycategory cc
ON c.companycategoryid = cc.companycategoryid
WHERE c.hqcountryiso = 'FRA' ) Q
ORDER BY CASE
WHEN Q.AlexaRank IS NULL THEN 1
ELSE 0
END,
Q.AlexaRank
Related
Why is this query not returning the count of the results? How do I get it to show the count
SELECT COUNT (*) AS MWith
FROM member m
JOIN Channel mc ON mc.MemberID = m.id
JOIN Client c ON c.id = m.clientid
JOIN packages p ON p.id = m.packageid
WHERE Enroll > '2018'
AND EXISTS (
SELECT * FROM
activity a
WHERE a.memberid = m.id
AND a.code IN ('785', 'a599')
)
GROUP BY m.id;
OUTPUT
MWith
1
1
1
The empty set is because of the clause group by .
The workarounds are:
Remove a GROUP BY, because m.id anyway is not part of the output
Use GROUP BY ALL
An original example:
SELECT COUNT(*) AS MWith
FROM member m
JOIN Channel mc
ON mc.MemberID = m.id
JOIN Client c
ON c.id = m.clientid
JOIN packages p
ON p.id = m.packageid
WHERE Enroll > '2018'
AND EXISTS
(
SELECT *
FROM activity a
WHERE a.memberid = m.id
AND a.code IN ( '785', 'a599' )
)
-- GROUP BY m.id;
Other, simpler examples to show a difference:
-- returns an empty resultset
SELECT COUNT(*) FROM sys.databases
WHERE 1=0
GROUP BY name
-- returns: a single row with 0
SELECT COUNT(*) FROM sys.databases
WHERE 1=0
-- Another example with GROUP BY ALL
-- it returns one row per grouped value, with expected count = 0
SELECT COUNT(*) FROM sys.databases
WHERE 1=0
GROUP BY ALL name
I have the following SQL query and need to know the count of companyid as I can see repeating data. How do I find the count of it. Following is the query
SELECT a.companyId 'companyId'
, i.orgDebtType 'orgDebtType'
, d.ratingTypeName 'ratingTypeName'
, c.currentRatingSymbol 'currentRatingSymbol'
, c.ratingStatusIndicator 'ratingStatusIndicator'
, g.qualifierValue 'qualifierValue'
, c.ratingdate 'ratingDate'
, h.value 'outlook'
FROM ciqRatingEntity a
JOIN ciqcompany com
on com.companyId = a.companyId
JOIN ciqratingobjectdetail b ON a.entitySymbolValue = b.objectSymbolValue
JOIN ciqRatingData c ON b.ratingObjectKey = c.ratingObjectKey
JOIN ciqRatingType d ON b.ratingTypeId = d.ratingTypeId
JOIN ciqRatingOrgDebtType i ON i.orgDebtTypeId=b.orgDebtTypeId
JOIN ciqRatingEntityData red ON red.entitySymbolValue=a.entitySymbolValue
AND red.ratingDataItemId='1' ---CoName
LEFT JOIN ciqRatingDataToQualifier f ON f.ratingDataId = c.ratingDataId
LEFT JOIN ciqRatingQualifiervalueType g ON g.qualifiervalueid = f.qualifierValueId
LEFT JOIN ciqRatingValueType h ON h.ratingValueId = c.outlookValueId
WHERE 1=1
AND b.ratingTypeId IN ( '130', '131', '126', '254' )
-- and a.companyId = #companyId
AND a.companyId IN
(SELECT distinct TOP 2000000
c.companyId
FROM ciqCompany c
inner join ciqCompanyStatusType cst on cst.companystatustypeid = c.companystatustypeid
inner join ciqCompanyType ct on ct.companyTypeId = c.companyTypeId
inner join refReportingTemplateType rep on rep.templateTypeId = c.reportingtemplateTypeId
inner join refCountryGeo rcg on c.countryId = rcg.countryId
inner join refState rs on rs.stateId = c.stateId
inner join ciqSimpleIndustry sc on sc.simpleIndustryId = c.simpleIndustryId
ORDER BY companyid desc)
ORDER BY companyId DESC, c.ratingdate, b.ratingTypeId, c.ratingStatusIndicator
This will list where there are duplicate companyID's
SELECT companyId, count(*) as Recs
FROM ciqCompany
GROUP BY ciqCompany
HAVING count(*) > 1
I understand that you wish to add a column to the query with the count of each companyId, you can use COUNT() OVER():
select count(a.companyId) over (partition by a.companyId) as companyCount,
<rest of the columns>
from ciqRatingEntity a
join <rest of the query>
This would return in each row the count of the companyId of that row without grouping the results.
given these relationships, how could you query the following:
The tourists (name and email) that booked at least a pension whose rating is greater than 9, but didn't book any 3 star hotel with a rating less than 9.
Is the following correct?
SELECT Tourists.name, Tourists.email
FROM Tourists
WHERE EXISTS (
SELECT id FROM Bookings
INNER JOIN Tourists ON Bookings.touristId=Tourists.id
INNER JOIN AccomodationEstablishments ON Bookings.accEstId=AccomodationEstablishments.id
INNER JOIN AccomodationTypes ON AccomodationEstablishments.accType=AccomodationTypes.id
WHERE AccomodationTypes.name = 'Pension' AND
AccomodationEstablishments.rating > 9
) AND NOT EXISTS (
SELECT id FROM Bookings
INNER JOIN Tourists ON Bookings.touristId=Tourists.id
INNER JOIN AccomodationEstablishments ON Bookings.accEstId=AccomodationEstablishments.id
INNER JOIN AccomodationTypes ON AccomodationEstablishments.accType=AccomodationTypes.id
WHERE AccomodationTypes.name = 'Hotel' AND
AccomodationEstablishments.noOfStars = 3 AND
AccomodationEstablishments.rating < 9
)
I would do this using aggregation and having:
SELECT t.name, t.email
FROM Bookings b INNER JOIN
Tourists t
ON b.touristId = t.id INNER JOIN
AccomodationEstablishments ae
ON b.accEstId = ae.id INNER JOIN
AccomodationTypes a
ON ae.accType = a.id
GROUP BY t.name, t.email
HAVING SUM(CASE WHEN a.name = 'Pension' AND ae.rating > 9 THEN 1 ELSE 0 END) > 0 AND
SUM(a.name = 'Hotel' AND ae.noOfStars = 3 AND ae.rating < 9 THEN 1 ELSE 0 END)= 0;
Your method also works, but you probably need t.id in the subqueries.
I'm struggling with left joining the earliest row in this left join.
The results are showing a 2011 date, but i know for a fact this particular row should be returning 2008.
SELECT TOP 1000
f.name as [Franchisee]
,p.paid_date as paid_date
FROM franchisees_franchisee f
OUTER APPLY (SELECT TOP 1 *
FROM era_project_invoice_payment p
WHERE f.franchiseeid = p.franchiseeid
and p.deleted = 0 and p.payment_confirmed = 1
ORDER BY p.eraprojectinvoicepaymentid ASC) p
where
f.deleted = 0
and f.name LIKE '%VKlinkosch%'
Below returns the correct, 2008 date.
SELECT TOP 1000
f.name as [Franchisee]
,min(p.paid_date) as paid_date
from [era_uat_shared].[dbo].[franchisees_franchisee] f
left join era_project_invoice_payment p
on f.franchiseeid = p.franchiseeid
where f.deleted = 0
and f.name LIKE '%VKlinkosch%'
GROUP BY f.name
Problem is, I need more than just the Paid Date from the payments table! :(
SELECT
f.name as [Franchisee]
, p.*
FROM franchisees_franchisee f
INNER JOIN
(
SELECT
ROW_NUMBER() OVER (PARTITION BY franchiseeid ORDER BY paid_date ASC) rn
, p.*
FROM
era_project_invoice_payment p
WHERE
deleted = 0
AND payment_confirmed = 1
) p
ON
f.franchiseeid = p.franchiseeid
AND f.deleted = 0
AND f.name LIKE '%VKlinkosch%'
AND p.rn = 1
I try to export my order total by customers group in prestashop
This is my REQUEST for the group N° 3 for example:
SELECT ROUND(SUM(IFNULL(o.`total_paid_real`, 0 ) / cu.conversion_rate), 2) as totalMoneySpent
FROM `ps_orders` o
LEFT JOIN `ps_currency` cu ON o.id_currency = cu.id_currency
LEFT JOIN `ps_customer` c ON c.id_default_group= 3
WHERE o.valid = 1;
OTHER VERSION (SAME RESULT, the total of all group)
SELECT ROUND( SUM( IFNULL(o.`total_paid_real`, 0 ) / cu.conversion_rate), 2 ) as totalMoneySpent
FROM `ps_orders` o
LEFT JOIN `ps_currency` cu ON o.id_currency = cu.id_currency
#LEFT JOIN `ps_customer` c ON c.id_default_group=3
WHERE o.valid = 1
AND o.id_customer IN( SELECT c.id_customer FROM `ps_customer` c WHERE c.id_default_group=3 )
;
My problem is that c.id_default_group never change the results,
Thanks for your help
SELECT c.group_id, ROUND(SUM(IFNULL(o.`total_paid_real`, 0 ) / cu.conversion_rate), 2) as totalMoneySpent
FROM `ps_orders` o
LEFT JOIN `ps_currency` cu ON o.id_currency = cu.id_currency
Once you apply the aggregate function SUM you have to GROUP BY in order to get the aggregate result for a number of rows (otherwise the aggregate is applied individually for each row, defeating its own purpose).
SELECT c.group_id, ROUND(SUM(IFNULL(o.`total_paid_real`, 0 ) / cu.conversion_rate), 2) as totalMoneySpent
FROM `ps_orders` o
LEFT JOIN `ps_currency` cu ON o.id_currency = cu.id_currency
LEFT JOIN `ps_customer` c ON c.id_default_group= 3
WHERE o.valid = 1
GROUP BY c.group
ORDER BY c.group
assuming group_id identifies the customer group you refer to in the question.