I have two tables that are exactly the same. I want to join them together into one large dataset. I tried simply SELECT-INTO query but got an error...
SELECT * INTO dbo.ParkingBay
FROM (SELECT * FROM dbo.ParkingBay_Old
UNION
SELECT * FROM dbo.ParkingBay_New) AS PARKING_BAY;
The error is:
The geometry data type cannot be selected as DISTINCT because it is
not comparable.
The UNION performs a DISTINCT on the combined result set.
UNION ALL eliminates this DISTINCT step, but would create the possibility of dupes in the result.
If you are OK with dupe possibility, then try this
SELECT * INTO dbo.ParkingBay
FROM (SELECT * FROM dbo.ParkingBay_Old
UNION ALL
SELECT * FROM dbo.ParkingBay_New) AS PARKING_BAY;
It looks like ALL solves everything:
SELECT * INTO dbo.ParkingBay
FROM (SELECT * FROM dbo.ParkingBay_Old
UNION ALL
SELECT * FROM dbo.ParkingBay_New) AS PARKING_BAY;
Related
I've got some SQL code working at the moment but I need to do another union. I want to ensure what I do is correct. Currently, this is what I have:
select * from (select * from stametadata
union select * from stajjmetadata)
I want to union on another table. Would this be correct?
select * from (select * from stametadata
union select * from stajjmetadata
union select * from staggmetadata)
Is this the neatest way to do it?
You can chain unions. To be honest, you don't even need the outer query:
SELECT * FROM stametadata
UNION
SELECT * FROM stajjmetadata
UNION
SELECT * FROM staggmetadata
I am trying to create a union with 3 tables that have the same column names. However, the queries tested seems not to be working.
The first query that I have used is the following:
Select * FROM table1
UNION ALL
SELECT * FROM table2
SELECT * FROM table3
UNION ALL
The second query used is the following:
SELECT *
FROM
(select * from table_1),
(select * from table_2),
(select * from table_3)
Both of them are not working for me. Please someone can help me with this?
This should work if columns are identical:
SELECT * FROM table1 UNION ALL
SELECT * FROM table2 UNION ALL
SELECT * FROM table3
Thanks in advance !!
I want to get below data in separate table with column how can we achieved this.
From my reading of your question, you would like the results of that SELECT statement put into a new table?
Firstly, I'm assuming your original SQL works as a SELECT statement - e.g., all those tables have the same structure. Note that you can simplify the unions, but I haven't done so here, to keep the key part of the answer (saving the data) as the main focus.
To save the data into another table, you can either create a table first and make that into an insert, or just use 'SELECT INTO' within the main SELECT.
If you are happy with the columns being automatically created, the 'SELECT INTO' version will create columns (e.g., you do not need to specify the columns in a CREATE TABLE statement). However, when you run the SELECT INTO, it does create the table. Therefore if you want to insert further values, you need to specify the column list (or have matching column lists).
SELECT INTO version
select *
INTO #Temp -- Added This row
from
( select * from #OneyearExpiry
union all
select * from #OtherYearExpiry
) A
except
select * from
( select * from #ONEYRCON
union all
select * from #OTHERYRCON
) B
INSERT INTO version
CREATE TABLE #Temp (<your fields here to match the SELECT statement>)
INSERT INTO #Temp
select * from
( select * from #OneyearExpiry
union all
select * from #OtherYearExpiry
) A
except
select * from
( select * from #ONEYRCON
union all
select * from #OTHERYRCON
) B
Set operators are evaluated from top to bottom so there only needs to be 1 subquery. Something like this
select ab.* into #Temp
from (select * from #OneyearExpiry
union all
select * from #OtherYearExpiry
except
select * from #ONEYRCON
except
select * from #OTHERYRCON) ab;
I was recently asked this question and was a little stumped so I want to ask the experts...
Given two tables A & B, I want to return all the values from A and B that do not overlap. Think of two overlapping circles; how do we return all the data that is NOT in the overlapping center section? And, I had to use ANSI Standard SQL rather than Oracle syntax.
Assuming we want everything exclusive to both A & B, my answer was
select *
from A
cross join B
minus
(select a.common_column from a
intersect
select b.common_column)
Does this look correct, or even close? If it is correct, is there a more efficient way to do this?
BTW - my solution was soundly rejected....
Thank you!
Given the tables A and B, you are looking for (A U B) - (A & B). In other words, you need A union B minus their intersection. Remember A and B must be union-compatible for this query to work. I would do:
(select * from A
union
select * from B
)
minus
(select * from A
intersect
select * from B
)
May be full outer join?
select coalesce(A.col, B.col)
from A full outer join B on A.col = B.col
where A.col is null or B.col is null;
For computing a set symmetric difference, you can use a combination of MINUS and UNION ALL:
select * from (
(select * from A
minus
select * from B)
union all
(select * from B
minus
select * from A)
)
Your query was rejected because it is syntactically incorrect: the number of columns differ and it confuses cross join and union all. However, I think you have the right idea for solving this.
You can easily fix this:
(select *
from A
union all
select *
from B
) minus
(select *
from A
intersect
select *
from B
);
That is, combine everything using union all and then subtract the rows that occur in both tables.
Of course, if there is a single id, then you can use the id with join and other operations.
Just like Frank Schmitt answered in the meantime:
Here it is including a data example:
WITH
table_a(name) AS (
SELECT 'From_A_1'
UNION ALL SELECT 'From_A_2'
UNION ALL SELECT 'From_A_3'
UNION ALL SELECT 'From_A_4'
UNION ALL SELECT 'From_A_5'
UNION ALL SELECT 'From_BOTH_6'
UNION ALL SELECT 'From_BOTH_7'
UNION ALL SELECT 'From_BOTH_8'
)
,
table_b(name) AS (
SELECT 'From_B_1'
UNION ALL SELECT 'From_B_2'
UNION ALL SELECT 'From_B_3'
UNION ALL SELECT 'From_B_4'
UNION ALL SELECT 'From_B_5'
UNION ALL SELECT 'From_BOTH_6'
UNION ALL SELECT 'From_BOTH_7'
UNION ALL SELECT 'From_BOTH_8'
)
(SELECT * FROM table_a EXCEPT SELECT * FROM table_b)
UNION ALL
(SELECT * FROM table_b EXCEPT SELECT * FROM table_a)
ORDER BY name
;
name
From_A_1
From_A_2
From_A_3
From_A_4
From_A_5
From_B_1
From_B_2
From_B_3
From_B_4
From_B_5
You will need to select all the data from both tables, except where they overlap, and then combine the data with a union. The code provided should work for your example.
SELECT *
FROM
(
SELECT * FROM Table1
EXCEPT SELECT * FROM Table2
)
UNION
SELECT *
FROM
(
SELECT * FROM Table2
EXCEPT SELECT * FROM Table1
)
Hope this helps.
I am trying to get the diff between two nearly identical tables in postgresql. The current query I am running is:
SELECT * FROM tableA EXCEPT SELECT * FROM tableB;
and
SELECT * FROM tableB EXCEPT SELECT * FROM tableA;
Each of the above queries takes about 2 minutes to run (Its a large table)
I wanted to combine the two queries in hopes to save time, so I tried:
SELECT * FROM tableA EXCEPT SELECT * FROM tableB
UNION
SELECT * FROM tableB EXCEPT SELECT * FROM tableA;
And while it works, it takes 20 minutes to run!!! I would guess that it would at most take 4 minutes, the amount of time to run each query individually.
Is there some extra work UNION is doing that is making it take so long? Or is there any way I can speed this up (with or without the UNION)?
UPDATE: Running the query with UNION ALL takes 15 minutes, almost 4 times as long as running each one on its own, Am I correct in saying that UNION (all) is not going to speed this up at all?
With regards to your "extra work" question. Yes. Union not only combines the two queries but also goes through and removes duplicates. It's the same as using a distinct statement.
For this reason, especially combined with your except statements "union all" would likely be faster.
Read more here:
http://www.postgresql.org/files/documentation/books/aw_pgsql/node80.html
In addition to combining the results of the first and second query, UNION by default also removes duplicate records. (see http://www.postgresql.org/docs/8.1/static/sql-select.html). The extra work involved in checking for duplicate records between the two queries is probably responsible for the extra time. In this situation there should not be any duplicate records so the extra work looking for duplicates can be avoided by specifying UNION ALL.
SELECT * FROM tableA EXCEPT SELECT * FROM tableB
UNION ALL
SELECT * FROM tableB EXCEPT SELECT * FROM tableA;
I don't think your code returns resultset you intend it to. I rather think you want to do this:
SELECT *
FROM (
SELECT * FROM tableA
EXCEPT
SELECT * FROM tableB
) AS T1
UNION
SELECT *
FROM (
SELECT * FROM tableB
EXCEPT
SELECT * FROM tableA
) AS T2;
In other words, you want the set of mutually exclusive members. If so, you need to read up on relational operator precedence in SQL ;) And when you have, you may realise the above can be rationalised to:
SELECT * FROM tableA
UNION
SELECT * FROM tableB
EXCEPT
SELECT * FROM tableA
INTERSECT
SELECT * FROM tableB;
FWIW, using subqueries (derived tables T1 and T2) to explicitly show (what would otherwise be implicit) relational operator precedence, your original query is this:
SELECT *
FROM (
SELECT *
FROM (
SELECT *
FROM tableA
EXCEPT
SELECT *
FROM tableB
) AS T2
UNION
SELECT *
FROM tableB
) AS T1
EXCEPT
SELECT *
FROM tableA;
The above can be relationalised to:
SELECT *
FROM tableB
EXCEPT
SELECT *
FROM tableA;
...and I think not what is intended.
You could use tableA FULL OUTER JOIN tableB, which would give what you want (with a propre join condition) with only 1 table scan, it probably would be faster than the 2 queries above.
Post more info please.