Say, I have an organizational structure that is 5 levels deep:
CEO -> DeptHead -> Supervisor -> Foreman -> Worker
The hierarchy is stored in a table Position like this:
PositionId | PositionCode | ManagerId
1 | CEO | NULL
2 | DEPT01 | 1
3 | DEPT02 | 1
4 | SPRV01 | 2
5 | SPRV02 | 2
6 | SPRV03 | 3
7 | SPRV04 | 3
... | ... | ...
PositionId is uniqueidentifier. ManagerId is the ID of employee's manager, referring PositionId from the same table.
I need a SQL query to get the hierarchy tree going down from a position, provided as parameter, including the position itself. I managed to develop this:
-- Select the original position itself
SELECT
'Rank' = 0,
Position.PositionCode
FROM Position
WHERE Position.PositionCode = 'CEO' -- Parameter
-- Select the subordinates
UNION
SELECT DISTINCT
'Rank' =
CASE WHEN Pos2.PositionCode IS NULL THEN 0 ELSE 1+
CASE WHEN Pos3.PositionCode IS NULL THEN 0 ELSE 1+
CASE WHEN Pos4.PositionCode IS NULL THEN 0 ELSE 1+
CASE WHEN Pos5.PositionCode IS NULL THEN 0 ELSE 1
END
END
END
END,
'PositionCode' = RTRIM(ISNULL(Pos5.PositionCode, ISNULL(Pos4.PositionCode, ISNULL(Pos3.PositionCode, Pos2.PositionCode)))),
FROM Position Pos1
LEFT JOIN Position Pos2
ON Pos1.PositionId = Pos2.ManagerId
LEFT JOIN Position Pos3
ON Pos2.PositionId = Pos3.ManagerId
LEFT JOIN Position Pos4
ON Pos3.PositionId = Pos4.ManagerId
LEFT JOIN Position Pos5
ON Pos4.PositionId = Pos5.ManagerId
WHERE Pos1.PositionCode = 'CEO' -- Parameter
ORDER BY Rank ASC
It works not only for 'CEO' but for any position, displaying its subordinates. Which gives me the following output:
Rank | PositionCode
0 | CEO
... | ...
2 | SPRV55
2 | SPRV68
... | ...
3 | FRMN10
3 | FRMN12
... | ...
4 | WRKR01
4 | WRKR02
4 | WRKR03
4 | WRKR04
My problems are:
The output does not include intermediate nodes - it will only output end nodes, i.e. workers and intermediate managers which have no subordinates. I need all intermediate managers as well.
I have to manually UNION the row with original position on top of the output. I there any more elegant way to do this?
I want the output to be sorted in hieararchical tree order. Not all DeptHeads, then all Supervisors, then all Foremen then all workers, but like this:
Rank | PositionCode
0 | CEO
1 | DEPT01
2 | SPRV01
3 | FRMN01
4 | WRKR01
4 | WRKR02
... | ...
3 | FRMN02
4 | WRKR03
4 | WRKR04
... | ...
Any help would be greatly appreciated.
Try a recursive CTE, the example on TechNet is almost identical to your problem I believe:
http://technet.microsoft.com/en-us/library/ms186243(v=sql.105).aspx
Thx, everyone suggesting CTE. I got the following code and it's working okay:
WITH HierarchyTree (PositionId, PositionCode, Rank)
AS
(
-- Anchor member definition
SELECT PositionId, PositionCode,
0 AS Rank
FROM Position AS e
WHERE PositionCode = 'CEO'
UNION ALL
-- Recursive member definition
SELECT e.PositionId, e.PositionCode,
Rank + 1
FROM Position AS e
INNER JOIN HierarchyTree AS d
ON e.ManagerId = d.PositionId
)
SELECT Rank, PositionCode
FROM HierarchyTree
GO
I had a similar problem to yours on a recent project but with a variable recursion length - typically between 1 and 10 levels.
I wanted to simplify the SQL side of things so I put some extra work into the logic of storing the recursive elements by storing a "hierarchical path" in addition to the direct manager Id.
So a very contrived example:
Employee
Id | JobDescription | Hierarchy | ManagerId
1 | DIRECTOR | 1\ | NULL
2 | MANAGER 1 | 1\2\ | 1
3 | MANAGER 2 | 1\3\ | 1
4 | SUPERVISOR 1 | 1\2\4 | 2
5 | SUPERVISOR 2 | 1\3\5 | 3
6 | EMPLOYEE 1 | 1\2\4\6 | 4
7 | EMPLOYEE 2 | 1\3\5\7 | 5
This means you have the power to very quickly query any level of the tree and get all descendants by using a LIKE query on the Hierarchy column
For example
SELECT * FROM dbo.Employee WHERE Hierarchy LIKE '\1\2\%'
would return
MANAGER 1
SUPERVISOR 1
EMPLOYEE 1
Additionally you can also easily get one level of the tree by using the ManagerId column.
The downside to this approach is you have to construct the hierarchy when inserting or updating records but believe me when I say this storage structure saved me a lot of pain later on without the need for unnecessary query complexity.
One thing to note is that my approach gives you the raw data - I then parse the result set into a recursive strongly typed structure in my services layer. As a rule I don't tend to format output in SQL.
Related
*I apologize, my tables displayed correctly when I was writing this question and after publishing the formatting looks off. trying to fix that now
I am trying to write a query in postgresql that would return, for any given child value, the nearest parent value that has reached a certain rank. Currently, I have this query, which displays the entire hierarchical path for any given child value-
WITH RECURSIVE tree AS (
SELECT "ChildDisplayID",
"ParentID",
"Rank",
1 as level
FROM table1
WHERE "ChildDisplayID" = {{some ChildID}}
UNION ALL
SELECT t1."ChildDisplayID",
t1."ParentID",
t1."Rank",
t.level + 1
FROM table1 t1
JOIN tree t ON t."ParentID" = t1."ChildDisplayID"
)
SELECT *
FROM tree
What I want to do is have in a single row that displays the child ID and the parent ID of the nearest parent whose rank is "Partner". For example, here is the output I am currently getting:
| ChildID | ParentID | Rank | Level |
|---------|----------|------|-------|
| 6 | 5 |Associate Manager| 1 |
| 5 | 4 |Manager| 2 |
| 4 | 3 |Associate Partner| 3 |
| 3 | 2 |Partner| 4 |
| 2 | 1 |Partner| 5 |
| 1 | |CEO| 6 |
Here is the output I want:
|ChildID | Nearest Partner | Rank |
|--------|----------|------|
|6 |3 | Partner |
What is the best way to do this?
You can put a stop condition on the first matching partner in the recursion, then filter the result:
WITH RECURSIVE tree AS (
SELECT "ChildDisplayID" as initialid, "ChildDisplayID", "ParentID", "Rank", 1 as level
FROM table1
WHERE "ChildDisplayID" = {{some ChildID}}
UNION ALL
SELECT t.initialid, t1."ChildDisplayID", t1."ParentID", t1."Rank", t.level + 1
FROM table1 t1
INNER JOIN tree t ON t."ParentID" = t1."ChildDisplayID"
WHERE t."Rank" <> 'Partner'
)
SELECT *
FROM tree
WHERE "Rank" = 'Partner'
It seems like you have a hierarchy where each child has just one parent, so there should be only one match, or no match at all.
I have a structure / tree that looks similar to this.
CostType is mandatory and can exist by itself, but it can have a parent ProfitType or Unit and other CostTypes as children.
There can only be duplicate Units. Other cannot appear multiple times in the structure.
| ID | name | parent_id | ProfitType | CostType | Unit |
| -: | ------------- | --------: |
| 1 | Root | (NULL) |
| 2 | 1 | 1 | 300 | | |
| 3 | 1-1 | 2 | | 111 | |
| 4 | 1-1-1 | 3 | | | 8 |
| 5 | 1-2 | 2 | | 222 | |
| 6 | 1-2-1 | 5 | | 333 | |
| 7 | 1-2-1-1 | 6 | | | 8 |
| 8 | 1-2-1-2 | 6 | | | 9 |
Parameters | should RETURN |
(300,111,8) | 4 |
(null,111,8) | 4 |
(null,null,8) | first match, 4 |
(null,222,8) | best match, 5 |
(null,333,null) | 6 |
I am at a loss on how I could create a function that receives (ProfitType, CostType, Unit) and return the best matching ID from the structure.
This isn't giving exactly the answers you provided as example, but see my comment above - if (null,222,8) should be 7 to match how (null,333,8) returns 4 then this is correct.
Also note that I formatted this using temp tables instead of as a function, I don't want to trip a schema change audit so I posted what I have as temp tables, I can rewrite it as a function Monday when my DBA is available, but I thought you might need it before the weekend. Just edit the "DECLARE #ProfitType int = ..." lines to the values you want to test
I also put in quite a few comments because the logic is tricky, but if they aren't enough leave a comment and I can expand my explanation
/*
ASSUMPTIONS:
A tree can be of arbitrary depth, but will not exceed the recursion limit (defaults to 100)
All trees will include at least 1 CostType
All trees will have at most 1 ProfitType
CostType can appear multiple times in a traversal from root to leaf (can units?)
*/
SELECT *
INTO #Temp
FROM (VALUES (1,'Root',NULL, NULL, NULL, NULL)
, (2,'1', 1, 300, NULL, NULL)
, (3,'1-1', 2, NULL, 111, NULL)
, (4,'1-1-1', 3, NULL, NULL, 8)
, (5,'1-2', 2, NULL, 222, NULL)
, (6,'1-2-1', 5, NULL, 333, NULL)
, (7,'1-2-1-1', 6, NULL, NULL, 8)
, (8,'1-2-1-2', 6, NULL, NULL, 9)
) as TempTable(ID, RName, Parent_ID, ProfitType, CostType, UnitID)
--SELECT * FROM #Temp
DECLARE #ProfitType int = NULL--300
DECLARE #CostType INT = 333 --NULL --111
DECLARE #UnitID INT = NULL--8
--SELECT * FROM #Temp
;WITH cteMatches as (
--Start with all nodes that match one criteria, default a score of 100
SELECT N.ID as ReportID, *, 100 as Score, 1 as Depth
FROM #Temp AS N
WHERE N.CostType= #CostType OR N.ProfitType=#ProfitType OR N.UnitID = #UnitID
), cteEval as (
--This is a recursive CTE, it has a (default) limit of 100 recursions
--, but that can be raised if your trees are deeper than 100 nodes
--Start with the base case
SELECT M.ReportID, M.RName, M.ID ,M.Parent_ID, M.Score
, M.Depth, M.ProfitType , M.CostType , M.UnitID
FROM cteMatches as M
UNION ALL
--This is the recursive part, add to the list of matches the match when
--its immediate parent is also considered. For that match increase the score
--if the parent contributes another match. Also update the ID of the match
--to the parent's IDs so recursion can keep adding if more matches are found
SELECT M.ReportID, M.RName, N.ID ,N.Parent_ID
, M.Score + CASE WHEN N.CostType= #CostType
OR N.ProfitType=#ProfitType
OR N.UnitID = #UnitID THEN 100 ELSE 0 END as Score
, M.Depth + 1, N.ProfitType , N.CostType , N.UnitID
FROM cteEval as M INNER JOIN #Temp AS N on M.Parent_ID = N.ID
)SELECT TOP 1 * --Drop the "TOP 1 *" to see debugging info (runners up)
FROM cteEval
ORDER BY SCORE DESC, DEPTH
DROP TABLE #Temp
I'm sorry I don't have enough rep to comment.
You'll have to define "best answer" (for example, why isn't the answer to null,222,8 7 or null instead of 5?), but here's the approach I'd use:
Derive a new table where ProfitType and CostType are listed explicitly instead of only by inheritance. I would approach that by using a cursor (how awful, I know) and following the parent_id until a ProfitType and CostType is found -- or the root is reached. This presumes an unlimited amount of child/grandchild levels for parent_id. If there is a limit, then you can instead use N self joins where N is the number of parent_id levels allowed.
Then you run multiple queries against the derived table. The first query would be for an exact match (and then exit if found). Then next query would be for the "best" partial match (then exit if found), followed by queries for 2nd best, 3rd best, etc. until you've exhausted your "best" match criteria.
If you need nested parent CostTypes to be part of the "best match" criteria, then I would make duplicate entries in the derived table for each row that has multiple CostTypes with a CostType "level". level 1 is the actual CostType. level 2 is that CostType's parent, level 3 etc. Then your best match queries would return multiple rows and you'd need to pick the row with the lowest level (which is the closest parent/grandparent).
I got the following question at a job interview and it completely stumped me, so I'm wondering if anybody out there can help explain it to me. Say I have the following table:
employees
--------------------------
id | name | reportsTo
--------------------------
1 | Alex | 2
2 | Bob | NULL
3 | Charlie | 5
4 | David | 2
5 | Edward | 8
6 | Frank | 2
7 | Gary | 8
8 | Harry | 2
9 | Ian | 8
The question was to write a SQL query that returned a table with a column for each employee's name and a column showing how many people are above that employee in the organization: i.e.,
hierarchy
--------------------------
name | hierarchyLevel
--------------------------
Alex | 1
Bob | 0
Charlie | 3
David | 1
Edward | 2
Frank | 1
Gary | 2
Harry | 1
Ian | 2
I can't even figure out where to begin writing this as a SQL query (a cursor, maybe?). Can anyone help me out in case I get asked a similar question to this again? Thanks.
The simplest example would be to use a (real or temporary) table, and add one level at a time (fiddle):
INSERT INTO hierarchy
SELECT id, name, 0
FROM employees
WHERE reportsTo IS NULL;
WHILE ((SELECT COUNT(1) FROM employees) <> (SELECT COUNT(1) FROM hierarchy))
BEGIN
INSERT INTO hierarchy
SELECT e.id, e.name, h.hierarchylevel + 1
FROM employees e
INNER JOIN hierarchy h ON e.reportsTo = h.id
AND NOT EXISTS(SELECT 1 FROM hierarchy hh WHERE hh.id = e.id)
END
Other solutions will be slightly different for each RDBMS. As one example, in SQL Server, you can use a recursive CTE to expand it (fiddle):
;WITH expanded AS
(
SELECT id, name, 0 AS level
FROM employees
WHERE reportsTo IS NULL
UNION ALL
SELECT e.id, e.name, level + 1 AS level
FROM expanded x
INNER JOIN employees e ON e.reportsTo = x.id
)
SELECT *
FROM expanded
ORDER BY id
Other solutions include recursive stored procedures, or even using dynamic SQL to iteratively increase the number of joins until everybody is accounted for.
Of course all these examples assume there are no cycles and everyone can be traced up the chain to a head honcho (reportsTo = NULL).
I have a table that is a list of paths between points. I want to create a query to return a list with pointID and range(number of point) from a given point. But have spent a day trying to figure this out and haven't go any where, does any one know how this should be done? ( I am writing this for MS-SQL 2005)
example
-- fromPointID | toPointID |
---------------|-----------|
-- 1 | 2 |
-- 2 | 1 |
-- 1 | 3 |
-- 3 | 1 |
-- 2 | 3 |
-- 3 | 2 |
-- 4 | 2 |
-- 2 | 4 |
with PointRanges ([fromPointID], [toPointID], [Range])
AS
(
-- anchor member
SELECT [fromPointID],
[toPointID],
0 AS [Range]
FROM dbo.[Paths]
WHERE [toPointID] = 1
UNION ALL
-- recursive members
SELECT P.[fromPointID],
P.[toPointID],
[Range] + 1 AS [Range]
FROM dbo.[Paths] AS P
INNER JOIN PointRanges AS PR ON PR.[toPointID] = P.[fromPointID]
WHERE [Range] < 5 -- This part is just added to limit the size of the table being returned
--WHERE P.[fromPointID] NOT IN (SELECT [toPointID] FROM PointRanges)
--Cant do the where statment I want to because it wont allow recurssion in the sub query
)
SELECT * FROM PointRanges
--Want this returned
-- PointID | Range |
-----------|-------|
-- 1 | 0 |
-- 2 | 1 |
-- 3 | 1 |
-- 4 | 2 |
Markus Jarderot's link gives a good answer for this. I end tried using his answer and also tried rewriting my problem in C# and linq but it ended up being more of a mathematical problem than a coding problem because I had a table with several thousands of point that interlinked. This is still something I am interested in and trying to get a better understanding of by reading books on mathematics and graph theory but if anyone else runs into this problem I think Markus Jarderot's link is the best answer you will find.
I have a database table structured like this (irrelevant fields omitted for brevity):
rankings
------------------
(PK) indicator_id
(PK) alternative_id
(PK) analysis_id
rank
All fields are integers; the first three (labeled "(PK)") are a composite primary key. A given "analysis" has multiple "alternatives", each of which will have a "rank" for each of many "indicators".
I'm looking for an efficient way to compare an arbitrary number of analyses whose ranks for any alternative/indicator combination differ. So, for example, if we have this data:
analysis_id | alternative_id | indicator_id | rank
----------------------------------------------------
1 | 1 | 1 | 4
1 | 1 | 2 | 6
1 | 2 | 1 | 3
1 | 2 | 2 | 9
2 | 1 | 1 | 4
2 | 1 | 2 | 7
2 | 2 | 1 | 4
2 | 2 | 2 | 9
...then the ideal method would identify the following differences:
analysis_id | alternative_id | indicator_id | rank
----------------------------------------------------
1 | 1 | 2 | 6
2 | 1 | 2 | 7
1 | 2 | 1 | 3
2 | 2 | 1 | 4
I came up with a query that does what I want for 2 analysis IDs, but I'm having trouble generalizing it to find differences between an arbitrary number of analysis IDs (i.e. the user might want to compare 2, or 5, or 9, or whatever, and find any rows where at least one analysis differs from any of the others). My query is:
declare #analysisId1 int, #analysisId2 int;
select #analysisId1 = 1, #analysisId2 = 2;
select
r1.indicator_id,
r1.alternative_id,
r1.[rank] as Analysis1Rank,
r2.[rank] as Analysis2Rank
from rankings r1
inner join rankings r2
on r1.indicator_id = r2.indicator_id
and r1.alternative_id = r2.alternative_id
and r2.analysis_id = #analysisId2
where
r1.analysis_id = #analysisId1
and r1.[rank] != r2.[rank]
(It puts the analysis values into additional fields instead of rows. I think either way would work.)
How can I generalize this query to handle many analysis ids? (Or, alternatively, come up with a different, better query to do the job?) I'm using SQL Server 2005, in case it matters.
If necessary, I can always pull all the data out of the table and look for differences in code, but a SQL solution would be preferable since often I'll only care about a few rows out of thousands and there's no point in transferring them all if I can avoid it. (However, if you have a compelling reason not to do this in SQL, say so--I'd consider that a good answer too!)
This will return your desired data set - Now you just need a way to pass the required analysis ids to the query. Or potentially just filter this data inside your application.
select r.* from rankings r
inner join
(
select alternative_id, indicator_id
from rankings
group by alternative_id, indicator_id
having count(distinct rank) > 1
) differ on r.alternative_id = differ.alternative_id
and r.indicator_id = differ.indicator_id
order by r.alternative_id, r.indicator_id, r.analysis_id, r.rank
I don't know wich database you are using, in SQL Server I would go like this:
-- STEP 1, create temporary table with all the alternative_id , indicator_id combinations with more than one rank:
select alternative_id , indicator_id
into #results
from rankings
group by alternative_id , indicator_id
having count (distinct rank)>1
-- STEP 2, retreive the data
select a.* from rankings a, #results b
where a.alternative_id = b.alternative_id
and a.indicator_id = b. indicator_id
order by alternative_id , indicator_id, analysis_id
BTW, THe other answers given here need the count(distinct rank) !!!!!
I think this is what you're trying to do:
select
r.analysis_id,
r.alternative_id,
rm.indicator_id_max,
rm.rank_max
from rankings rm
join (
select
analysis_id,
alternative_id,
max(indicator_id) as indicator_id_max,
max(rank) as rank_max
from rankings
group by analysis_id,
alternative_id
having count(*) > 1
) as rm
on r.analysis_id = rm.analysis_id
and r.alternative_id = rm.alternative_id
You example differences seems wrong. You say you want analyses whose ranks for any alternative/indicator combination differ but the example rows 3 and 4 don't satisfy this criteria. A correct result according to your requirement is:
analysis_id | alternative_id | indicator_id | rank
----------------------------------------------------
1 | 1 | 2 | 6
2 | 1 | 2 | 7
1 | 2 | 1 | 3
2 | 2 | 1 | 4
On query you could try is this:
with distinct_ranks as (
select alternative_id
, indicator_id
, rank
, count (*) as count
from rankings
group by alternative_id
, indicator_id
, rank
having count(*) = 1)
select r.analysis_id
, r.alternative_id
, r.indicator_id
, r.rank
from rankings r
join distinct_ranks d on r.alternative_id = d.alternative_id
and r.indicator_id = d.indicator_id
and r.rank = d.rank
You have to realize that on multiple analysis the criteria you have is ambiguous. What if analysis 1,2 and 3 have rank 1 and 4,5 and 6 have rank 2 for alternative/indicator 1/1? The set (1,2,3) is 'different' from the set (4,5,6) but inside each set there is no difference. what is the behavior you desire in that case, should they show up or not? My query finds all records that have a different rank for the same alternative/indicator *from all other analysis' but is not clear if this is correct in your requirement.