How to find 4th Saturday of month? [closed] - sql

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Please let me know that how to find fourth Saturday of month in oracle. suppose we put "03/02/1999" then write a sql query to find out fourth saturday of month.

Answer 1

In Oracle you can use this:
NEXT_DAY(TRUNC(TO_DATE('1999-02-03','yyyy-mm-dd'), 'MM')-1, 'Saturday')+3*7

Answer 2

TRUNC( date, [fmt] ) takes an optional second argument which determines what time portion you are truncating to; so:
TRUNC( your_date, 'mm' )
Will truncate to the first day of the month and if you subtract a day from it then you get the last day of the previous month:
TRUNC( your_date, 'mm' ) - INTERVAL '1' DAY
or, more simply,
TRUNC( your_date, 'mm' ) - 1
NEXT_DAY( date, char) will get the next day, as specified by the second argument, from the given date. Combining the two functions will give you the first specified day of the month:
NEXT_DAY( TRUNC( your_date, 'mm' ) - 1, day_of_week )
Adding two weeks to it will give you the fourth day-of-the-week of the month:
NEXT_DAY( TRUNC( your_date, 'mm' ) - 1, 'Saturday' ) + INTERVAL '21' DAY
As an example:
SQL Fiddle
Oracle 11g R2 Schema Setup:
CREATE TABLE dates ( your_date ) AS
SELECT TO_DATE( '2014-' || LPAD( LEVEL, 2, '0' ) || '-01', 'YYYY-MM-DD' )
FROM DUAL
CONNECT BY LEVEL < 12
/
Query 1:
SELECT NEXT_DAY( TRUNC( your_date, 'mm') - INTERVAL '1' DAY, 'Saturday') + INTERVAL '21' DAY AS fourth_saturday
FROM dates
Results:
| FOURTH_SATURDAY |
|----------------------------------|
| January, 25 2014 00:00:00+0000 |
| February, 22 2014 00:00:00+0000 |
| March, 22 2014 00:00:00+0000 |
| April, 26 2014 00:00:00+0000 |
| May, 24 2014 00:00:00+0000 |
| June, 28 2014 00:00:00+0000 |
| July, 26 2014 00:00:00+0000 |
| August, 23 2014 00:00:00+0000 |
| September, 27 2014 00:00:00+0000 |
| October, 25 2014 00:00:00+0000 |
| November, 22 2014 00:00:00+0000 |
You could also wrap the code in a (more generic) function:
CREATE FUNCTION nth_day_of_month (
month DATE,
day_of_week VARCHAR2,
nth NUMBER
) RETURN DATE DETERMINISTIC
IS
BEGIN
RETURN NEXT_DAY( TRUNC( month, 'mm' ) - INTERVAL '1' DAY, day_of_week ) + (nth - 1) * 7;
END nth_day_of_month;
/
Query 2:
SELECT TO_CHAR( nth_day_of_month( your_date, 'Monday', 1 ), 'DAY YYYY-MM-DD' ) AS first_monday,
TO_CHAR( nth_day_of_month( your_date, 'Saturday', 4 ), 'DAY YYYY-MM-DD' ) AS fourth_saturday
FROM dates
Results:
| FIRST_MONDAY | FOURTH_SATURDAY |
|-------------------|---------------------|
| MONDAY 2014-01-06 | SATURDAY 2014-01-25 |
| MONDAY 2014-02-03 | SATURDAY 2014-02-22 |
| MONDAY 2014-03-03 | SATURDAY 2014-03-22 |
| MONDAY 2014-04-07 | SATURDAY 2014-04-26 |
| MONDAY 2014-05-05 | SATURDAY 2014-05-24 |
| MONDAY 2014-06-02 | SATURDAY 2014-06-28 |
| MONDAY 2014-07-07 | SATURDAY 2014-07-26 |
| MONDAY 2014-08-04 | SATURDAY 2014-08-23 |
| MONDAY 2014-09-01 | SATURDAY 2014-09-27 |
| MONDAY 2014-10-06 | SATURDAY 2014-10-25 |
| MONDAY 2014-11-03 | SATURDAY 2014-11-22 |

Answer 3

select next_day(trunc(to_date('1999-02- 03','yyyy-mm-dd'),'mm')-1,'saturday')+21
from dual;

Answer 4

Try this
DECLARE #StartDate DATETIME;
SELECT #StartDate = DATEADD(year, DATEDIFF(year,0,GETDATE()), 0);
-- This clause is just to get some numbers: a Tally table, for joining to get a range of dates
WITH NumDays AS (
SELECT TOP 365 -- one year of days
ROW_NUMBER() OVER (ORDER BY sc1.ID) AS N
FROM Master.dbo.SysColumns sc1,
Master.dbo.SysColumns sc2
UNION SELECT 0 -- just to get a zero in the results
), DateRange AS (
SELECT N,
DATEADD(day, N, #StartDate) AS [Date],
DATEPART(dw,DATEADD(day, N, #StartDate)) AS [Day],
DATENAME(dw,DATEADD(day, N, #StartDate)) AS [DayName],
DATENAME(week,DATEADD(day, N, #StartDate)) AS [WeekNo]
FROM NumDays
)
SELECT *
FROM DateRange
WHERE [DayName] = 'Saturday'
AND WeekNo in (4)
Here you can give weekNo comma separated. Suppose you want find 2nd and 4th Saturday then add this WeekNo in (2,4) instead of WeekNo in (4)