IF statement with RC in vba gives compile error, why? - vba

Question

I am currently working on a small VBA code that needs to compare a piece of string. If I would type this directly into excel I would do following:
=IF(C14 = "ABC",1,0)
Now, since this is a VBA code, it needs to do this as a relative reference. Instead it would look something like this:
=IF(RC[-5] = "ABC",1,0)
Problem: Now, the latter IF statement gives a compile error - why so?
If I where to type in
=IF(RC[-5] = 2,1,0)
This does not give any compile error. So it appears that the String comparisment gives me problems.

Answer 1

For vba code try this
ActiveCell.FormulaR1C1 = "=IF(RC[-5]=""ABC"",1,0)"
Followup from comments.
Howcome the double "" is needed? – SteewDK 3 mins ago
We need the extra " to encompass the double quotes to pass it as a string. You could use Chr(34) as well. For example
ActiveCell.FormulaR1C1 = "=IF(RC[-5]=" & Chr(34) & "ABC" & Chr(34) & ",1,0)"
BTW if you do not want to use a formula then you can use OFFSET as well
For example
If ActiveCell.Offset(0,-5).Value = "ABC" Then _
ActiveCell.Value = 1 Else ActiveCell.Value = 0