I have a column named quantity with values 1.00,2.00,1.5,2.5,etc. If I want to retrieve the values 1.5,2.5 along with all other similar values how can I write the query?
in SQL in have tried:
SELECT quantity_billed FROM invoice_line_item WHERE quantity_billed != ROUND(quantity_billed)
and
with like operator it is giving the values like 1.00 also.
You can use a MODULO function, too:
SELECT quantity_billed
FROM invoice_line_item
WHERE quantity_billed MOD 1 <> 0
%LIKE% only works for Character string,so you should convert to varchar.if ur data in float or decimal.
SELECT quantity_billed
FROM invoice_line_item WHERE convert (varchar,quantity_billed )
like '%.5%'
How about using NOT LIKE('%.00') to get fractional amounts. Not sure which database you are using so you may need to modify slightly but this works in MySql and SQL Server
Related
I need for a SQL query to transform an int with a value between 1 to 300000 to a number which has this pattern : always 8 number.
For example:
1 becomes 00000001,
123 becomes 00000123,
123456 becomes 00123456.
I have no idea how to do that... How can I do it?
In Standard SQL, you can use this trick:
select substring(cast( (num + 100000000) as varchar(255)) from 2)
Few databases actually support this syntax. Any given database can do what you want, but the method depends on the database you are using.
For MS SQL Server
You could use FORMAT function, like this:
SELECT FORMAT(123,'00000000')
https://database.guide/how-to-format-numbers-in-sql-server/#:~:text=Starting%20from%20SQL%20Server%202012,the%20output%20should%20be%20formatted.
Read at the link Leading Zeroes
For MySql/Oracle
You could use LPAD, like this:
SELECT LPAD('123',8,'0')
https://database.guide/how-to-add-leading-zeros-to-a-number-in-mysql/
I am trying to extract only the numeric values from a column that contains cells that are exclusively numbers, and cells that are exclusively letter values, so that I can multiply the column with another that contains only numeric values. I have tried
SELECT trim(INTENT_VOLUME)
from A
WHERE ISNUMERIC(INTENTVOLUME)
and also
SELECT trim(INTENT_VOLUME)
from A
WHERE ISNUMERIC(INTENTVOLUME) = 1
and neither works. I get the error Function ISNUMERIC(VARCHAR) does not exist. Can someone advise? Thank you!
It highly depends on DBMS.
in SqlServer you have a limited built-in features to do it, so the next query may not work with all variants of your data:
select CAST(INTENT_VOLUME AS DECIMAL(10, 4))
from A
where INTENT_VOLUME LIKE '%[0-9.-]%'
and INTENT_VOLUME NOT LIKE '%[^0-9.-]%';
In Oracle you can use regex in a normal way:
select to_number(INTENT_VOLUME)
from A
where REGEXP_LIKE(INTENT_VOLUME,'^[-+]?[0-9]+(\.[0-9]+)?$');
MySQL DBMS has also built-in regex
Try this, which tests if that text value can be cast as numeric...
select intent_volume
from a
where (intent_volume ~ '^([0-9]+[.]?[0-9]*|[.][0-9]+)$') = 't'
I am trying to take an average of a column in my database. The column is AMOUNT and it is stored as NVARCHAR(300),null.
When I try to convert it to a numeric value I get the following error:
Msg 8114, Level 16, State 5, Line 1
Error converting datatype NVARCHAR to NUMBER
Here is what I have right now.
SELECT AVG(CAST(Reimbursement AS DECIMAL(18,2)) AS Amount
FROM Database
WHERE ISNUMERIC(Reimbursement) = 1
AND Reimbursement IS NOT NULL
You would think that your code would work. However, SQL Server does not guarantee that the WHERE clause filters the database before the conversion for the SELECT takes place. In my opinion this is a bug. In Microsoft's opinion, this is an optimization feature.
Hence, your WHERE is not guaranteed to work. Even using a CTE doesn't fix the problem.
The best solution is TRY_CONVERT() available in SQL Server 2012+:
SELECT AVG(TRY_CONVERT(DECIMAL(18,2), Reimbursement)) AS Amount
FROM Database
WHERE ISNUMERIC(Reimbursement) = 1 AND Reimbursement IS NOT NULL;
In earlier versions, you can use CASE. The CASE does guarantee the sequential ordering of the clauses, so:
SELECT AVG(CASE WHEN ISNUMERIC(Reimbursement) = 1 AND Reimbursement IS NOT NULL
THEN CONVERT(DECIMAL(18,2), Reimbursement))
END)
FROM Database;
Because AVG() ignores NULL values, the WHERE is not necessary, but you can include it if you like.
Finally, you could simplify your code by using a computed column:
alter database add Reimbursement_Value as
(CASE WHEN ISNUMERIC(Reimbursement) = 1 AND Reimbursement IS NOT NULL
THEN CONVERT(DECIMAL(18,2), Reimbursement))
END);
Then you could write the code as:
select avg(Reimbursement_Value)
from database
where Reimbursement_Value is not null;
Quote from MSDN...
ISNUMERIC returns 1 for some characters that are not numbers, such as plus (+), minus (-), and valid currency symbols such as the dollar sign ($). For a complete list of currency symbols, see money and smallmoney
select isnumeric('+')---1
select isnumeric('$')---1
so try to add to avoid non numeric numbers messing with your ouput..
WHERE Reimbursement NOT LIKE '%[^0-9]%'
If you are on SQLServer 2012,you could try using TRY_Convert which outputs null for conversion failures..
SELECT AVG(try_convert( DECIMAL(18,2),Reimbursement))
from
table
I am guessing that since it is Nvarchar you are going to find some values in there with a '$','.', or a (,). I would run a query likt this:
SELECT Amount
FROM database
WHERE Amount LIKE '%$%' OR
Amount LIKE '%.%' OR
Amount LIKE '%,%'
See what you get and my guess you will get some rows returned and then update those rows and try it again.
Currently your query would pull all numbers that are not all numeric which is a reason why it is failing too. Instead try running this:
SELECT AVG(CAST(Reimbursement AS DECIMAL(18,2)) AS Amount
FROM Database
--Changed ISNUMERIC() = to 0 for true so it will only pull numeric numbers.
WHERE ISNUMERIC(Reimbursement) = 0 and Reimbursement IS NOT NULL
I'm trying to figure out a way, using SQL, to query for values that go out to, say, 5 or more decimal places. In other words, I want to see only results that have 5+ decimal places (e.g. 45.324754) - the numbers before the decimal are irrelevant, however, I still need to see the full number. Is this possible? Any help if appreciated.
Assuming your DBMS supports FLOOR and your datatype conversion model supports this multiplication, you can do this:
SELECT *
FROM Table
WHERE FLOOR(Num*100000)!=Num*100000
This has the advantage of not requiring a conversion to a string datatype.
On SQL Server, you can specify:
SELECT *
FROM Table
WHERE Value <> ROUND(Value,4,1);
For an ANSI method, you can use:
SELECT *
FROM Table
WHERE Value <> CAST(Value*100000.0 AS INT) / 100000.0;
Although this method might cause an overflow if you're working with large numbers.
I imagine most DBMSs have a round function
SELECT *
FROM YourTable
WHERE YourCol <> ROUND(YourCol,4)
This worked for me in SQL Server:
SELECT *
FROM YourTable
WHERE YourValue LIKE '%._____%';
select val
from tablename
where length(substr(val,instr(val, '.')+1)) > 5
This is a way to do it in oracle using substr and instr
You can use below decode statement to identify maximum decimal present in database table
SELECT max(decode(INSTR(val,'.'), 0, 0, LENGTH(SUBSTR(val,INSTR(val,'.')+1)))) max_decimal
FROM tablename A;
I'm having trouble finding a way to write a query that will return all non-integers in a float column in SQL Server 2005/8.
I have a float field where the majority of the data in it is actually integers, but I'd like to take a look at the rows where the values actually contain a decimal value. The first thing I tried was modulus 1, but the % operator doesn't work on float values.
Thanks for your help!
I don't know exact syntax of MSSQL, however you could try something like that (pseudo-code)
SELECT ... FROM tbl_name WHERE col_name != CAST(col_name AS INTEGER)
are you just wanting the rows with a decimal in it?
select field
from table
where field like '%.%'
Try something like:
SELECT *
FROM MyTable
WHERE (CONVERT(INT, floatField) - floatField) <> 0
You may also try this:
SELECT * FROM tbl WHERE col != ROUND(col)