OOP inheritance memory initialization - oop

When you're instantiating an object of a class that inherits from a parent class the constructor calls the superclasses constructor in most langiages I know and my question is: when the superclasse's constructor is called there will effectively be an object of that type in memory, but we're creating an object of the subclass with(in this example) additional values to add to the object so how is that accomplished in memory? Is it added to the original object? Are the contents of the original object copied into a new object with space for all the variables? Or is it something completely different?
A different question that just occured to me, are class variables, like in java, kept in the data segment of the program in memory? How are classes, not the objects, stored in memory for that matter?
Thanks.

I don't really know how engine works, but I know how to test memory usage in PHP. Both scripts
class base {
public function __construct() {
}
}
$start_memory = memory_get_usage();
$object = new base;
echo memory_get_usage() - $start_memory;
and
class base {
public function __construct() {
}
}
class derived extends base {
public function __construct() {
}
}
$start_memory = memory_get_usage();
$object = new derived;
echo memory_get_usage() - $start_memory;
return the same value. It means there'is only one instance in memory, not parent + it's child, when class is extended
phpfiddles: 1st script, 2nd script

Classed are code that define its object, so they are in Code Segment of program. And all class variables are in data segment.
And when we create an object of subclass, first its parents' object are created and it is extended for subclass members. That's why subclass object has all members of its parent class.

Related

OO Design Issue related to subclassing

I have a parent bean having one instance variable like below :
public Class ParentBean {
protected boolean show; // this variable will be used to show some UI component
public void action() {
// update show variable here
}
public boolean isShow() {
return show;
}
}
Is it a good design if I want to reuse the "show" variable in a child bean (to show other UI component specific to child bean ) as shown below :
public Class ChildBean extends ParentBean {
// override the action method from parent bean
public void action() {
// update show variable here
show = true /false;
}
}
In effect , show variable is being updated by "childBean" by overriding action() method.
Is this a good design practice ? Otherwise same thing has to be repeated in ChildBean to get this work done.
If you use the show variable for the same purpose in the subclass, as you seem to be doing in this example, then obviously you should reuse it, because otherwise you just end up writing the same code twice, which is contrary to the point of OOP.
In general, in OOP, it is common to override superclass methods in subclasses, as well as modifying superclass instance variables, as long as you know what the variable you are modifying is being used for (you don't want to be randomly changing instance variables in classes that you don't completely understand, or don't have access to the source of, because you don't want any unfortunate side effects), so when it's your own code, this is absolutely fine.
As a general guideline, if your options are either to copy and paste a massive hunk of code and use it unchanged, or subclass and use the superclass' instance variables or functions, it's better to subclass. Otherwise, you're missing out on the point of OOP.
Changing the value in subclass will not affect superclass variable
This is fine with respect to the design. When a subclass object is instantiated, it will have a different copy of variable. and If superclass object is instantiated it will have different copy.
It is. Having a protected variable means you are allowed to modify it into parent or children classes (remember every single instance of each class has its own property values). So, if you have some generic functionality which is valuable for all the children:
Parent class:
public void action(){
//update show variable here
show = true;
}
Appart from that, if you want to add some extra functionality in a specifical child:
Child class:
#Override
public void action(){
super.action();
//Extra functionality goes here
//You can also access parent's 'protected' fields
if (show){
System.out.println("Shown");
}
}
An example of the use:
Parent p = new Parent();
p.action();//Prints nothing
Child c = new Child();
p.action();//Prints 'shown'

asp.net c# Automap a class from within that class

To best describe what I want to happen, i'll show what i'm doing, as to me it makes sense that this would work ...
public class foo()
{
public foo()
{
MyContext db = new MyContext();
foobar = db.foobar.first();
this = Mapper.Map<bar, foo>(foobar);
}
}
Basically, I want to use automapper within the destination class to map from the source class within the destination classes constructor.
Is there a way to do this?
You cannot do this because this is read only in C#. You cannot assign this a value in the constructor. Not cool to try to change the reference of an object in its constructor. You will have to do the mapping manually and assign each individual property. I would also question if it as a good practice to assign an object values from a database or service in a default constructor. It is not very transparent to the user of the object what is going on and you can get an exception in your constructor.

Can a class return an object of itself

Can a class return an object of itself.
In my example I have a class called "Change" which represents a change to the system, and I am wondering if it is in anyway against design principles to return an object of type Change or an ArrayList which is populated with all the recent Change objects.
Yes, a class can have a method that returns an instance of itself. This is quite a common scenario.
In C#, an example might be:
public class Change
{
public int ChangeID { get; set; }
private Change(int changeId)
{
ChangeID = changeId;
LoadFromDatabase();
}
private void LoadFromDatabase()
{
// TODO Perform Database load here.
}
public static Change GetChange(int changeId)
{
return new Change(changeId);
}
}
Yes it can. In fact, that's exactly what a singleton class does. The first time you call its class-level getInstance() method, it constructs an instance of itself and returns that. Then subsequent calls to getInstance() return the already-constructed instance.
Your particular case could use a similar method but you need some way of deciding the list of recent changes. As such it will need to maintain its own list of such changes. You could do this with a static array or list of the changes. Just be certain that the underlying information in the list doesn't disappear - this could happen in C++ (for example) if you maintained pointers to the objects and those objects were freed by your clients.
Less of an issue in an automatic garbage collection environment like Java since the object wouldn't disappear whilst there was still a reference to it.
However, you don't have to use this method. My preference with what you describe would be to have two clases, changelist and change. When you create an instance of the change class, pass a changelist object (null if you don't want it associated with a changelist) with the constructor and add the change to that list before returning it.
Alternatively, have a changelist method which creates a change itself and returns it, remembering the change for its own purposes.
Then you can query the changelist to get recent changes (however you define recent). That would be more flexible since it allows multiple lists.
You could even go overboard and allow a change to be associated with multiple changelists if so desired.
Another reason to return this is so that you can do function chaining:
class foo
{
private int x;
public foo()
{
this.x = 0;
}
public foo Add(int a)
{
this.x += a;
return this;
}
public foo Subtract(int a)
{
this.x -= a;
return this;
}
public int Value
{
get { return this.x; }
}
public static void Main()
{
foo f = new foo();
f.Add(10).Add(20).Subtract(1);
System.Console.WriteLine(f.Value);
}
}
$ ./foo.exe
29
There's a time and a place to do function chaining, and it's not "anytime and everywhere." But, LINQ is a good example of a place that hugely benefits from function chaining.
A class will often return an instance of itself from what is sometimes called a "factory" method. In Java or C++ (etc) this would usually be a public static method, e.g. you would call it directly on the class rather than on an instance of a class.
In your case, in Java, it might look something like this:
List<Change> changes = Change.getRecentChanges();
This assumes that the Change class itself knows how to track changes itself, rather than that job being the responsibility of some other object in the system.
A class can also return an instance of itself in the singleton pattern, where you want to ensure that only one instance of a class exists in the world:
Foo foo = Foo.getInstance();
The fluent interface methods work on the principal of returning an instance of itself, e.g.
StringBuilder sb = new StringBuilder("123");
sb.Append("456").Append("789");
You need to think about what you're trying to model. In your case, I would have a ChangeList class that contains one or more Change objects.
On the other hand, if you were modeling a hierarchical structure where a class can reference other instances of the class, then what you're doing makes sense. E.g. a tree node, which can contain other tree nodes.
Another common scenario is having the class implement a static method which returns an instance of it. That should be used when creating a new instance of the class.
I don't know of any design rule that says that's bad. So if in your model a single change can be composed of multiple changes go for it.

What is the use of making constructor private in a class?

Why should we make the constructor private in class? As we always need the constructor to be public.
Some reasons where you may need private constructor:
The constructor can only be accessed from static factory method inside the class itself. Singleton can also belong to this category.
A utility class, that only contains static methods.
By providing a private constructor you prevent class instances from being created in any place other than this very class. There are several use cases for providing such constructor.
A. Your class instances are created in a static method. The static method is then declared as public.
class MyClass()
{
private:
MyClass() { }
public:
static MyClass * CreateInstance() { return new MyClass(); }
};
B. Your class is a singleton. This means, not more than one instance of your class exists in the program.
class MyClass()
{
private:
MyClass() { }
public:
MyClass & Instance()
{
static MyClass * aGlobalInst = new MyClass();
return *aGlobalInst;
}
};
C. (Only applies to the upcoming C++0x standard) You have several constructors. Some of them are declared public, others private. For reducing code size, public constructors 'call' private constructors which in turn do all the work. Your public constructors are thus called delegating constructors:
class MyClass
{
public:
MyClass() : MyClass(2010, 1, 1) { }
private:
MyClass(int theYear, int theMonth, int theDay) { /* do real work */ }
};
D. You want to limit object copying (for example, because of using a shared resource):
class MyClass
{
SharedResource * myResource;
private:
MyClass(const MyClass & theOriginal) { }
};
E. Your class is a utility class. That means, it only contains static members. In this case, no object instance must ever be created in the program.
To leave a "back door" that allows another friend class/function to construct an object in a way forbidden to the user. An example that comes to mind would be a container constructing an iterator (C++):
Iterator Container::begin() { return Iterator(this->beginPtr_); }
// Iterator(pointer_type p) constructor is private,
// and Container is a friend of Iterator.
Everyone is stuck on the Singleton thing, wow.
Other things:
Stop people from creating your class on the stack; make private constructors and only hand back pointers via a factory method.
Preventing creating copys of the class (private copy constructor)
This can be very useful for a constructor that contains common code; private constructors can be called by other constructors, using the 'this(...);' notation. By making the common initialization code in a private (or protected) constructor, you are also making explicitly clear that it is called only during construction, which is not so if it were simply a method:
public class Point {
public Point() {
this(0,0); // call common constructor
}
private Point(int x,int y) {
m_x = x; m_y = y;
}
};
There are some instances where you might not want to use a public constructor; for example if you want a singleton class.
If you are writing an assembly used by 3rd parties there could be a number of internal classes that you only want created by your assembly and not to be instantiated by users of your assembly.
This ensures that you (the class with private constructor) control how the contructor is called.
An example : A static factory method on the class could return objects as the factory method choses to allocate them (like a singleton factory for example).
We can also have private constructor,
to enfore the object's creation by a specific class
only(For security reasons).
One way to do it is through having a friend class.
C++ example:
class ClientClass;
class SecureClass
{
private:
SecureClass(); // Constructor is private.
friend class ClientClass; // All methods in
//ClientClass have access to private
// & protected methods of SecureClass.
};
class ClientClass
{
public:
ClientClass();
SecureClass* CreateSecureClass()
{
return (new SecureClass()); // we can access
// constructor of
// SecureClass as
// ClientClass is friend
// of SecureClass.
}
};
Note: Note: Only ClientClass (since it is friend of SecureClass)
can call SecureClass's Constructor.
You shouldn't make the constructor private. Period. Make it protected, so you can extend the class if you need to.
Edit: I'm standing by that, no matter how many downvotes you throw at this.
You're cutting off the potential for future development on the code. If other users or programmers are really determined to extend the class, then they'll just change the constructor to protected in source or bytecode. You will have accomplished nothing besides to make their life a little harder. Include a warning in your constructor's comments, and leave it at that.
If it's a utility class, the simpler, more correct, and more elegant solution is to mark the whole class "static final" to prevent extension. It doesn't do any good to just mark the constructor private; a really determined user may always use reflection to obtain the constructor.
Valid uses:
One good use of a protected
constructor is to force use of static
factory methods, which allow you to
limit instantiation or pool & reuse
expensive resources (DB connections,
native resources).
Singletons (usually not good practice, but sometimes necessary)
when you do not want users to create instances of this class or create class that inherits this class, like the java.lang.math, all the function in this package is static, all the functions can be called without creating an instance of math, so the constructor is announce as static.
If it's private, then you can't call it ==> you can't instantiate the class. Useful in some cases, like a singleton.
There's a discussion and some more examples here.
I saw a question from you addressing the same issue.
Simply if you don't want to allow the others to create instances, then keep the constuctor within a limited scope. The practical application (An example) is the singleton pattern.
Constructor is private for some purpose like when you need to implement singleton or limit the number of object of a class.
For instance in singleton implementation we have to make the constructor private
#include<iostream>
using namespace std;
class singletonClass
{
static int i;
static singletonClass* instance;
public:
static singletonClass* createInstance()
{
if(i==0)
{
instance =new singletonClass;
i=1;
}
return instance;
}
void test()
{
cout<<"successfully created instance";
}
};
int singletonClass::i=0;
singletonClass* singletonClass::instance=NULL;
int main()
{
singletonClass *temp=singletonClass::createInstance();//////return instance!!!
temp->test();
}
Again if you want to limit the object creation upto 10 then use the following
#include<iostream>
using namespace std;
class singletonClass
{
static int i;
static singletonClass* instance;
public:
static singletonClass* createInstance()
{
if(i<10)
{
instance =new singletonClass;
i++;
cout<<"created";
}
return instance;
}
};
int singletonClass::i=0;
singletonClass* singletonClass::instance=NULL;
int main()
{
singletonClass *temp=singletonClass::createInstance();//return an instance
singletonClass *temp1=singletonClass::createInstance();///return another instance
}
Thanks
You can have more than one constructor. C++ provides a default constructor and a default copy constructor if you don't provide one explicitly. Suppose you have a class that can only be constructed using some parameterized constructor. Maybe it initialized variables. If a user then uses this class without that constructor, they can cause no end of problems. A good general rule: If the default implementation is not valid, make both the default and copy constructor private and don't provide an implementation:
class C
{
public:
C(int x);
private:
C();
C(const C &);
};
Use the compiler to prevent users from using the object with the default constructors that are not valid.
Quoting from Effective Java, you can have a class with private constructor to have a utility class that defines constants (as static final fields).
(EDIT: As per the comment this is something which might be applicable only with Java, I'm unaware if this construct is applicable/needed in other OO languages (say C++))
An example as below:
public class Constants {
private Contants():
public static final int ADDRESS_UNIT = 32;
...
}
EDIT_1:
Again, below explanation is applicable in Java : (and referring from the book, Effective Java)
An instantiation of utility class like the one below ,though not harmful, doesn't serve
any purpose since they are not designed to be instantiated.
For example, say there is no private Constructor for class Constants.
A code chunk like below is valid but doesn't better convey intention of
the user of Constants class
unit = (this.length)/new Constants().ADDRESS_UNIT;
in contrast with code like
unit = (this.length)/Constants.ADDRESS_UNIT;
Also I think a private constructor conveys the intention of the designer of the Constants
(say) class better.
Java provides a default parameterless public constructor if no constructor
is provided, and if your intention is to prevent instantiation then a private constructor is
needed.
One cannot mark a top level class static and even a final class can be instantiated.
Utility classes could have private constructors. Users of the classes should not be able to instantiate these classes:
public final class UtilityClass {
private UtilityClass() {}
public static utilityMethod1() {
...
}
}
You may want to prevent a class to be instantiated freely. See the singleton design pattern as an example. In order to guarantee the uniqueness, you can't let anyone create an instance of it :-)
One of the important use is in SingleTon class
class Person
{
private Person()
{
//Its private, Hense cannot be Instantiated
}
public static Person GetInstance()
{
//return new instance of Person
// In here I will be able to access private constructor
}
};
Its also suitable, If your class has only static methods. i.e nobody needs to instantiate your class
It's really one obvious reason: you want to build an object, but it's not practical to do it (in term of interface) within the constructor.
The Factory example is quite obvious, let me demonstrate the Named Constructor idiom.
Say I have a class Complex which can represent a complex number.
class Complex { public: Complex(double,double); .... };
The question is: does the constructor expects the real and imaginary parts, or does it expects the norm and angle (polar coordinates) ?
I can change the interface to make it easier:
class Complex
{
public:
static Complex Regular(double, double = 0.0f);
static Complex Polar(double, double = 0.0f);
private:
Complex(double, double);
}; // class Complex
This is called the Named Constructor idiom: the class can only be built from scratch by explicitly stating which constructor we wish to use.
It's a special case of many construction methods. The Design Patterns provide a good number of ways to build object: Builder, Factory, Abstract Factory, ... and a private constructor will ensure that the user is properly constrained.
In addition to the better-known uses…
To implement the Method Object pattern, which I’d summarize as:
“Private constructor, public static method”
“Object for implementation, function for interface”
If you want to implement a function using an object, and the object is not useful outside of doing a one-off computation (by a method call), then you have a Throwaway Object. You can encapsulate the object creation and method call in a static method, preventing this common anti-pattern:
z = new A(x,y).call();
…replacing it with a (namespaced) function call:
z = A.f(x,y);
The caller never needs to know or care that you’re using an object internally, yielding a cleaner interface, and preventing garbage from the object hanging around or incorrect use of the object.
For example, if you want to break up a computation across methods foo, bar, and zork, for example to share state without having to pass many values in and out of functions, you could implement it as follows:
class A {
public static Z f(x, y) {
A a = new A(x, y);
a.foo();
a.bar();
return a.zork();
}
private A(X x, Y y) { /* ... */ };
}
This Method Object pattern is given in Smalltalk Best Practice Patterns, Kent Beck, pages 34–37, where it is the last step of a refactoring pattern, ending:
Replace the original method with one that creates an instance of the new class, constructed with the parameters and receiver of the original method, and invokes “compute”.
This differs significantly from the other examples here: the class is instantiable (unlike a utility class), but the instances are private (unlike factory methods, including singletons etc.), and can live on the stack, since they never escape.
This pattern is very useful in bottoms-up OOP, where objects are used to simplify low-level implementation, but are not necessarily exposed externally, and contrasts with the top-down OOP that is often presented and begins with high-level interfaces.
Sometimes is useful if you want to control how and when (and how many) instances of an object are created.
Among others, used in patterns:
Singleton pattern
Builder pattern
On use of private constructors could also be to increase readability/maintainability in the face of domain-driven design.
From "Microsoft .NET - Architecing Applications for the Enterprise, 2nd Edition":
var request = new OrderRequest(1234);
Quote, "There are two problems here. First, when looking at the code, one can hardly guess what’s going
on. An instance of OrderRequest is being created, but why and using which data? What’s 1234? This
leads to the second problem: you are violating the ubiquitous language of the bounded context. The
language probably says something like this: a customer can issue an order request and is allowed to
specify a purchase ID. If that’s the case, here’s a better way to get a new OrderRequest instance:"
var request = OrderRequest.CreateForCustomer(1234);
where
private OrderRequest() { ... }
public OrderRequest CreateForCustomer (int customerId)
{
var request = new OrderRequest();
...
return request;
}
I'm not advocating this for every single class, but for the above DDD scenario I think it makes perfect sense to prevent a direct creation of a new object.
If you create a private constructor you need to create the object inside the class
enter code here#include<iostream>
//factory method
using namespace std;
class Test
{
private:
Test(){
cout<<"Object created"<<endl;
}
public:
static Test* m1(){
Test *t = new Test();
return t;
}
void m2(){
cout<<"m2-Test"<<endl;
}
};
int main(){
Test *t = Test::m1();
t->m2();
return 0;
}

Ensuring only factory can create instance

class XFactory {
private XFactory() {}
static void getX() {
if(...)
return new A(new XFactory());
else
return new B(new XFactory());
}
}
class A {
private A() {}
public A(XFactory xf) {}
}
class B {
private B() {}
public A(XFactory xf) {}
}
By this way I can ensure only Factory can create instances of it's belonging Classes.
Is this right approach or there is any other alternative/good approach?
The common approach (in C++) is to make the "belonging classes" constructors private, and have them declare the factory class as friend.
I would make classes A and B friends of XFactory, and keep all their constructors private. Therefore, only XFactory has access to their constructors.
That is, in C++. In Java or C#, I don't see any clean way of enforcing that at compile-time. Your example is far from fool-proof and even a bit confusing, since as long as one has an instance of XFactory, he can pass it to the constructor of A or B and instantiate them directly like that.
If you were up for hacks and could not make your constructors private, you could:
Make your factory a global singleton and to create an object:
Create a random key
Add that key to a private list in the factory object of keys in use
Pass the key to the constructor
Have the constructor retrieve the global factory object and call it to validate the key.
If they key validation fails, scuttle your program (call exit, die, ... whatever is appropriate). Or possibly email a stack tract to an admin. This is the kind of thing that should be caught quickly.
(Do I get hack points?)
Jacob
In Java you can make the constructors private and provide the factory in the form of a public nested class, since nested classes have access to the private members of the class in which they are declared.
public class ExampleClass {
private ExampleClass() {
}
public class NestedFactory {
public ExampleClass createExample() {
return new ExampleClass();
}
}
Anyone who wanted to could create an instance of ExampleClass.NestedFactory and through it instantiate ExampleClasses.
I haven't been able to figure out a way to do this that lets you then inherit from ExampleClass since the Java compiler demands that you specify a constructor for the superclass... so that's a disadvantage.