I have a substring which pulls the data I need but I need to add a leading zero to the front of the result. I've searched and found several samples of pulling data with leading zeros but none using a substring. I can add the zero to the end of the result but do not know how to add it to the front. The substring I am using is shown below.
"substring((substring(convert(char(6),Convert(int,a.nor_ppd_hrs_no*100) + 100000),3,4) + space(16)),1,16) as 'ApprovedHrs',"
This produces a result like this 7500 and I need it to look like this 07500.
Thanks
One of most simple solution for adding leading zeros in order to get a number with a desired width (ex. 16 digits) is to concatenate a string of zeros (REPLICATE('0', 15) or '000000000000000') with the source number (ex. 123) converted to VARCHAR ('123'). Then, the result '000000000000000123' is truncated to desired length (ex. 16 digits) using the RIGHT function:
DECLARE #Num INT;
SET #Num = 123;
SELECT RIGHT(REPLICATE('0', 15) + CONVERT(VARCHAR(11), #Num), 16) AS NumWithLeadingZeros1
SELECT RIGHT('000000000000000' + CONVERT(VARCHAR(11), #Num), 16) AS NumWithLeadingZeros2
Output:
NumWithLeadingZeros1
--------------------
0000000000000123
NumWithLeadingZeros2
--------------------
0000000000000123
Assuming you need the resulting string to be 5 characters length,
stuff(substring((substring(convert(char(6),Convert(int,a.nor_ppd_hrs_no*100) + 100000),3,4) + space(16)),1,16), 1, 0, replicate('0', 5 - len(substring((substring(convert(char(6),Convert(int,a.nor_ppd_hrs_no*100) + 100000),3,4) + space(16)),1,16)))) as 'ApprovedHrs
Use the STR() function to convert a number to a fixed-length, right-justified string. By default, it pads with spaces, so replace ' ' with '0' to get a zero-padded output.
SELECT REPLACE(STR(a.nor_ppd_hrs_no*100,5),' ','0') FROM MyTable
Related
I have a column with the given values
MRN
1946
456
27
557
The column values length is fixed.
If at all any value is less than 6characters,then it should concate 0's to the left and make it 6characters length.
The desired output is
MRN
001946
000456
000027
000557
This is called left paddings. In SQL Server, this is typically done with more basic string operations:
select right(replicate('0', 6) + mrn, 6)
If mrn is a number, then use the concat() function:
select right(concat(replicate('0', 6), mrn), 6)
You can also use the FORMAT function for this. (Demo)
SELECT FORMAT(MRN ,'D6')
FROM YourTable
Change the number 6 to whatever your total length needs to be:
SELECT REPLICATE('0',6-LEN(EmployeeId)) + EmployeeId
If the column is an INT, you can use RTRIM to implicitly convert it to a VARCHAR
SELECT REPLICATE('0',6-LEN(RTRIM(EmployeeId))) + RTRIM(EmployeeId)
And the code to remove these 0s and get back the 'real' number:
SELECT RIGHT(EmployeeId,(LEN(EmployeeId) - PATINDEX('%[^0]%',EmployeeId)) + 1)
We can achieve this by adding leading zero's
select RIGHT('0000'+CAST(MRN AS VARCHAR(10)),6)
I'm trying to link two tables, one has an 'EntityRef' that's made of four alpha characters and a sequential number...
EntityRef
=========
SWIT1
LIVE32
KIRB48
MEHM38
BRAD192
The table that I'm trying to link to stores the reference in a 15 character field where the 4 alphas are at the start and the numbers are at the end but with zeros in between to make up the 15 characters...
EntityRef
=========
SWIT00000000001
LIVE00000000032
So, to get theses to link, my options are to either remove the zeros on one field or add the zeros on the other.
I've gone for the later as it seems to be a simpler approach and eliminates the risk of getting into problems if the numeric element contains a zero.
So, the alpha is always 4 characters at the beginning and the number is the remainder and 15 minus the LEN() of the EntityRef is the number of zeros that I need to insert...
left(entityref,4) as 'Alpha',
right(entityref,len(EntityRef)-4) as 'Numeric',
15-len(EntityRef) as 'No.of Zeros'
Alpha Numeric No.of Zeros
===== ======= ===========
SWIT 1 10
LIVE 32 9
KIRB 48 9
MEHM 38 9
MALL 36 9
So, I need to concatenate the three elements but I don't know how to create the string of zeros to the specified length...how do I do that??
Concat(Alpha, '0'*[No. of Zeros], Numeric)
What is the correct way to repeat a character a specified number of times?
You can use string manipulation. In this case:
LEFT() to get the alpha portion.
REPLICATE() to get the zeros.
STUFF() to get the number.
The query:
select left(val, 4) + replicate('0', 15 - len(val)) + stuff(val, 1, 4, '')
from (values ('SWIT1'), ('ABC12345')) v(val)
You may try left padding with zeroes:
SELECT
LEFT(EntityRef, 4) +
RIGHT('00000000000' + SUBSTRING(ISNULL(EntityRef,''), 5, 30), 11) AS EntityRef
FROM yourTable;
Demo
With casting to integer the numeric part:
select *
from t1 inner join t2
on concat(left(t2.EntityRef, 4), cast(right(t2.EntityRef, 11) as bigint)) = t1.EntityRef
See the demo.
I found the answer as soon as I posted the question (sometimes it helps you think it through!).
(left(entityref,4) + replicate('0',15-len(EntityRef)) +
right(entityref,len(EntityRef)-4)),
I have the following code in a stored procedure and am trying to conditionally format a calculated number based on its length (if the number is less than 4 digits, pad with leading zeros). However, my case statement is not working. The "formattedNumber2" result is the one I'm looking for.
I'm assuming the case statement treats the variable strangely, but I also don't know of a way around this.
DECLARE #Number int = 5
SELECT
CASE
WHEN (LEN(CONVERT(VARCHAR, #Number)) > 4)
THEN #Number
ELSE RIGHT('0000' + CAST(#Number AS VARCHAR(4)), 4)
END AS formattedNumber,
LEN(CONVERT(VARCHAR, #Number)) AS numberLength,
RIGHT('0000' + CAST(#Number AS VARCHAR(4)), 4) AS formattedNumber2
I get the following results when I run the query:
formattedNumber numberLength formattedNumber2
-------------------------------------------------
5 1 0005
SQL DEMO
The problem is you are using different data type on your case , integer and string. So the CASE stay with the first type he find and convert the rest.
CASE WHEN (LEN(convert(VARCHAR, #Number)) > 4) THEN convert(VARCHAR, #Number)
This can be done a lot easier with format() since version 2012.
format(n,
'0000')
And that would also handle negative values, which your current approach apparently doesn't.
Prior 2012 it can be handled with basically replicate() and + (string concatenation).
isnull(replicate('-',
-sign(n)), '')
+
isnull(replicate('0',
4
-
len(cast(abs(n) AS varchar(10)))
),
'')
+
cast(abs(n) AS varchar(10))
(It targets integer values, choose a larger length for the varchar casts for bigint.)
db<>fiddle
So if I have a data (varchar) like say 10.1
I need the value as 0000101000000.
means (000010) whole number and (1000000) decimal value.
Its a 13 character string ,numbers coming before decimal point should be in first 6 characters and numbers coming after decimal point should be in last 7 characters
Maybe..?
DECLARE #d decimal(13,7) = 10.1;
SELECT RIGHT('0000000000000' + CONVERT(varchar(13),CONVERT(bigint,(#d * 10000000))),13);
Using my crystal ball here though.
Edit: As, for some reason, the OP is storing a decimal as a varchar (this is a really bad bad idea on it's own), I have added further logic to attempt to convert the value to a decimal first.
As experience has taught many of us, give a user a non-numeric column to store a numeric value in and they're more than happily store a non-numeric value in it, so i have used TRY_CONVERT and assumed you are using SQL Server 2012+:
DECLARE #d varchar(13) = 10.1;
SELECT RIGHT('0000000000000' + CONVERT(varchar(13),CONVERT(bigint,(TRY_CONVERT(decimal(13,7),#d) * 10000000))),13);
SELECT REPLICATE('0',6-LEN(SUBSTRING(CAST([data] AS VARCHAR), 1,
CHARINDEX('.',CAST([data] AS VARCHAR)) -1)))+SUBSTRING(CAST([data] AS VARCHAR), 1,
CHARINDEX('.',CAST([data] AS VARCHAR)) -1)+
SUBSTRING(CAST([data] AS VARCHAR), CHARINDEX('.',CAST([data] AS VARCHAR)) + 1,
LEN(CAST([data] AS VARCHAR)))+REPLICATE('0',7-LEN(SUBSTRING(CAST([data] AS VARCHAR), CHARINDEX('.',CAST([data] AS VARCHAR)) + 1,
LEN(CAST([data] AS VARCHAR))))) AS Whole
FROM Table1
Output
Whole
0000101000000
Demo
http://sqlfiddle.com/#!18/8649d/16
You can use some math and string operations to do it like below
see live demo
declare #var decimal(10,4)
set #var=10.1
select #var,
right(cast(cast(( floor(#var)+ power(10,7)) as int) as varchar(13)),6)
+
cast(cast(((#var- floor(#var)) * power(10,7)) as int) as varchar(13))
There's a fair amount of string manipulation to be done here. I'll step through what I did.
I used a variable for the base number so I could verify different results:
declare #n decimal(9,3) = 10.1
You need 6 spaces left of the decimal and 7 spaces to the right, so I'm doing all the manipulation on a VARCHAR(13). I didn't create a new variable as a VARCHAR because I'm assuming you want to be able to do this conversion in line on the fly, so I'm using that CAST over and over again.
Start by finding the decimal place.
SELECT CHARINDEX('.',CAST(#n as VARCHAR(13)))
In the sample number, that's a 3, but it could obviously change.
Now, get the portion of the number to the left of the decimal place.
SELECT SUBSTRING(CAST(#n as VARCHAR(13)),1,CHARINDEX('.',CAST(#n as VARCHAR(13)))-1)
Then get the portion to the right of the decimal.
SELECT SUBSTRING(CAST(#n as VARCHAR(13)),CHARINDEX('.',CAST(#n as VARCHAR(13)))+1,LEN(CAST(#n as VARCHAR(13))))
Pad the leading zeroes. Put 6 on, concatenate, and take a RIGHT 6. Accounts for no digits to the left of the decimal.
SELECT RIGHT(REPLICATE(0,6) + SUBSTRING(CAST(#n as VARCHAR(13)),1,CHARINDEX('.',CAST(#n as VARCHAR(13)))-1), 6)
Pad the trailing zeroes. Same idea, but in the other direction.
SELECT LEFT(SUBSTRING(CAST(#n as VARCHAR(13)),CHARINDEX('.',CAST(#n as VARCHAR(13)))+1,LEN(CAST(#n as VARCHAR(13)))) + REPLICATE(0,7),7)
Then put it all together.
SELECT RIGHT(REPLICATE(0,6) + SUBSTRING(CAST(#n as VARCHAR(13)),1,CHARINDEX('.',CAST(#n as VARCHAR(13)))-1), 6)
+
LEFT(SUBSTRING(CAST(#n as VARCHAR(13)),CHARINDEX('.',CAST(#n as VARCHAR(13)))+1,LEN(CAST(#n as VARCHAR(13)))) + REPLICATE(0,7),7)
Results.
0000101000000
declare #var varchar(20) = '10000.112'
SELECT FORMAT (FLOOR(#var), '000000') + left((PARSENAME(#var,1)) + replicate('0',7),7)
I have a database with a list of old ItemID's that need updating to a new format.
The old format is of the form 8046Y and the new format moves the 4th digit to the end and prepends a hyphen and adds a 0 if it's a single digit. The old format also uses alpha characters when the number goes over 9 for example 464HB where the H represents 17. I also need to add a 1 to the beginning of the new format. All this can be done with string manipulation in SQL I hope.
Some examples:
8046Y becomes 1804Y-06
464HB becomes 1464B-17 (H = 17)
Can anyone give me some pointers as to how to go about this in SQL?
I got as far as:
select '1' + LEFT(ItemID, 3) + RIGHT(ItemID,1) + '-' + '0' + SUBSTRING(ItemID,3,1) from items
But the conversion from a=10 to z=36 stumped me
Try this:
select
'1'
+ left(#str,3)
+ right(#str,1)
+ '-'
+ case
when substring(#str,4,1) like '%[0-9]%' 1 then right('00' + substring(#str,4,1),2)
else cast(10 + ascii(substring(#str,4,1))-ascii('A') as varchar(2))
end
Explanation: If the 4th character is a digit, then do not change the value and append it after padding with a zero. Otherwise, use ASCII to get the ASCII value for that character, get it's difference with the value for 'A' and add the offset of 10.
Demo
Since I don't know if there are any other special character to consider except 'H' only included this single character.
DECLARE #val CHAR(5) = '464HB'
SELECT #val, '1' + LEFT(#val,3)+SUBSTRING(#val,5,1)+'-'+CASE WHEN +SUBSTRING(#val,4,1)='H' THEN '17' ELSE '0'+SUBSTRING(#val,4,1) END
select '1' + LEFT(ItemID, 3) + RIGHT(ItemID,1) + '-'
+CASE RIGHT(LEFT(ItemID,1),2)
WHEN 'a' then 10
WHEN 'b' THEN 11
etc...
END [NewItemID]
from items
Just add the appropriate cases in that format.
I do it only for the challenge, i dont recommend to use
DECLARE #id varchar(5) = '8046Y'
--SET #id = '464HB'
SELECT
'1' +
LEFT(#id, 3) +
RIGHT(#id, 1) +
'-' +
CASE WHEN ISNUMERIC(RIGHT(LEFT(#id, 4), 1)) = 1 THEN
RIGHT(LEFT(#id, 4), 1)
ELSE
RIGHT('00' + CONVERT(VARCHAR, ASCII(RIGHT(LEFT(#id, 4), 1)) - 64 + 9), 2)
END
-64 for the Start of ASCII A and +9 for your convention
Personally, I'd create a function for it.
Create a variable to handle the new value.
Manipulate the positions through SUBSTRING, you can also use RIGHT or LEFT
When adding zeros in single digit numbers, just do conditional statement
Regarding the conversion of letters to numbers(e.g. letter H), the converted value of the first letter is 65 assuming it's all capital. So, A=65, B=66, H=72 and so on. Use this data in manipulating the values. Uhm, I'll give you my thoughts but you can optimize it (since I don't have lots of time).
Taking your example of H=17, so A=10. Just subtract 55 in the conversions. So H=72(-55) becomes 17. This is applicable to all letters (in uppercase only).
I think this much is more than enough to guide you. Hope this would help.