Accessing field in related table through Foreign Key in Yii - yii

Question

I have three tables
1. tbl_employee: id(PK), name, position_id(FK), type_id(FK)
2. tbl_position: id, position
3. tbl_type : id, type
I want to display records in field position like what sql does below.
SELECT tbl_employee.name, tbl_position.position
FROM tbl_employee, tbl_position
WHERE tbl_employee.position_id = tbl_position.id AND tbl_position.position LIKE '%Designer';
In my EmployeeController
public function actionIndex(){
$dataProvider=new CActiveDataProvider('Employee', array(
'criteria'=>array(
'select'=>'t.name, tbl_position',
'with'=>array(
'position'=>array('select'=>'position'),
'type'=>array('select'=>'type'),
),
'condition'=>"tbl_position.position LIKE '%Designer'",
),
));
$this->render('index',array('dataProvider'=>$dataProvider,));
}
and in my models
public function relations(){
// NOTE: you may need to adjust the relation name and the related
// class name for the relations automatically generated below.
return array(
'position' => array(self::BELONGS_TO, 'Position', 'position_id'),
'type' => array(self::BELONGS_TO, 'Type', 'type_id'),
);
}
and this is my view
<?php $this->widget('zii.widgets.CDetailView', array(
'data'=>$model,
'attributes'=>array(
'id',
'name',
array(
'name'=>'position_id',
'value'=>CHtml::encode($model->position->position),
),
array(
'name'=>'type_id',
'value'=>CHtml::encode($model->type->type),
)
),
)); ?>
The error I've got is:
Active record "Employee" is trying to select an invalid column "tbl_position".
Note, the column must exist in the table or be an expression with alias.
How can I access position field in tbl_position by using join?What is the correct syntax for achieving that purpose.
Many thanks

Answer 1

'select'=>'t.name, position.position',
'condition'=>"position.position LIKE '%Designer'",
or
$model = TblEmployee::model()->with('position','type')->findall(array("condition"=>"position.position LIKE '%Designer'"));

Answer 2

Here I find the solution, but actually your answer was very close
public function actionIndex(){
$dataProvider=new CActiveDataProvider('Employee', array(
'criteria'=>array(
'select'=>'t.name',
'with'=>array(
'position'=>array('select'=>'position'),
'type'=>array('select'=>'type'),
),
'condition'=>"position.position LIKE '%Designer'",
),
));
$this->render('index',array('dataProvider'=>$dataProvider,));
}