FOR XML multiple control by attribute in tree concept - sql

Question

I want to figure out one issue.
I already had question about simple ordering issue but I want to order more detail.
check below this link :
SQL Server : FOR XML sorting control by attribute
I made a example case.
SQL Query.
select (
select '123' AS '#id', (
select
(
select 'test' AS '#testid' , '20' AS '#order'
FOR XML path ('tree') , TYPE
),
(
select 'test2' AS '#testid' , '30' AS '#order'
FOR XML path ('tree-order') , TYPE
),
(
select 'test' AS '#testid' , '10' AS '#order'
FOR XML path ('tree') , TYPE
)
FOR XML path ('Node') , TYPE
)
FOR XML path ('Sample') , TYPE
),
(select '456' AS '#id', (
select
(
select 'test' AS '#testid' , '20' AS '#order'
FOR XML path ('tree') , TYPE
),
(
select 'test2' AS '#testid' , '30' AS '#order'
FOR XML path ('tree-order') , TYPE
),
(
select 'test' AS '#testid' , '10' AS '#order'
FOR XML path ('tree') , TYPE
)
FOR XML path ('Node') , TYPE
)
FOR XML path ('Sample') , TYPE)
FOR XML path ('Main') , TYPE
Result :
<Main>
<Sample id="123">
<Node>
<tree testid="test" order="20" />
<tree-order testid="test2" order="30" />
<tree testid="test" order="10" />
</Node>
</Sample>
<Sample id="456">
<Node>
<tree testid="test" order="20" />
<tree-order testid="test2" order="30" />
<tree testid="test" order="10" />
</Node>
</Sample>
</Main>
Expected result :
<Main>
<Sample id="123">
<Node>
<tree testid="test" order="10" />
<tree testid="test" order="20" />
<tree-order testid="test2" order="30" />
</Node>
</Sample>
<Sample id="456">
<Node>
<tree testid="test" order="10" />
<tree testid="test" order="20" />
<tree-order testid="test2" order="30" />
</Node>
</Sample>
</Main>
final result :
<Main>
<Sample id="123">
<Node>
<tree testid="test" />
<tree testid="test" />
<tree-order testid="test2" />
</Node>
</Sample>
<Sample id="456">
<Node>
<tree testid="test" />
<tree testid="test" />
<tree-order testid="test2" />
</Node>
</Sample>
</Main>
That's order by tree-order.
finally I don't want to show order information in attribute
Any one has great Idea?
Thank you for everybody who interesting to this.
Updated ----------------------------------------
Thank you every body finally I solved problem as below about order by and remove attribute issue :
declare #resultData xml = (select #data.query('
element Main {
for $s in Main/Sample
return element Sample {
$s/#*,
for $n in $s/Node
return element Node {
for $i in $n/*
order by $i/#order
return $i
}
}
}'));
SET #resultData.modify('delete (Main/Sample/Node/tree/#order)');
SET #resultData.modify('delete (Main/Sample/Node/tree-order/#order)');
select #resultData

Answer 1

select #data.query('
element Main {
for $s in Main/Sample
return element Sample {
$s/#*,
for $n in $s/Node
return element Node {
for $i in Node/*
order by $i/#order
return
if ($i/self::tree)
then element tree { $i/#testid }
else element tree-order { $i/#testid }
}
}
}
}')

Answer 2

What's interesting to me is that in your original post, you're stating that you're generating the XML as the result of a SQL query. If it were me, I'd control the ordering at that level.