I want to select entries from first table that have no entries in second table
I tried this:
SELECT
first.clientid
FROM
table1 AS first,
table2 AS second
WHERE
first.clientid NOT IN second.clientid
but i have realize problem
any tips?
Wrong Syntax.
Either use IN:
SELECT clientid FROM table1
WHERE clientid NOT IN (SELECT clientid FROM table2);
Or use EXISTS:
SELECT clientid FROM table1
WHERE NOT EXISTS (SELECT * FROM table2 where table2.clientid = table1.clientid);
Or use MINUS (not avaliable in every DBMS):
SELECT clientid FROM table1
MINUS
SELECT clientid FROM table2;
You can use NOT EXISTS to do that:
SELECT first.clientid
FROM table1 AS first
WHERE NOT EXISTS
(SELECT * FROM table2 AS second WHERE first.clientid = second.clientid)
Related
I used the search function which brought me to the following solution.
Starting Point is the following: I have one table A which stores all data.
From that table I select a certain amount of records and store it in table B.
In a new statement I want to select new records from table A that do not appear in table B and store them in table c. I tried to solve this with a AND ... NOT IN statement.
But I still receive records in table C that are in table B.
Important: I can only work with select statements, each statement needs to start with select as well.
Does anybody have an idea where the problem in the following statement could be:
Select *
From
(Select TOP 10000 *
FROM [table_A]
WHERE Email like '%#domain_A%'
AND Id NOT IN (SELECT Id
FROM [table_B]))
Union
(Select TOP 7500 *
FROM table_A]
WHERE Email like '%#domain_B%'
AND Id NOT IN (SELECT Id
FROM [table_B]))
Union
(SELECT TOP 5000 *
FROM [table_A]
WHERE Email like '%#domain_C%'
AND Id NOT IN (SELECT Id
FROM [table_B]))
Try NOT EXISTS instead of NOT IN
SELECT
*
FROM TableA A
WHERE NOT EXISTS
(
SELECT 1 FROM TableB WHERE Id = A.Id
)
So Basically the idea here is to select everything from table A that doesnt exists in table B and Insert all that into Table C?
INSERT INTO Table_C
SELECT a.colum1, a.column2,......
FROM [table_A]
LEFT JOIN [table_B] ON a.id = b.ID
WHERE a.Email like '%#domain_A%' AND b.id IS NULL
Thank you guys all for your feedback, from which I learned a lot.
I was able to fix the statement with your help. Above is the statement which is working now with the desired results:
Select Id
From
(Select TOP 10000 * FROM Table_A
WHERE Email like '%#domain_a%'
AND Id NOT IN (SELECT Id
FROM Table_B)
order by No desc) t1
Union
Select Id
From
(Select TOP 7500 * FROM Table_A
WHERE Email like '%#domain_b%'
AND Id NOT IN (SELECT Id
FROM Table_B)
order by No desc) t2
Union
Select Id
From
(SELECT TOP 5000 * FROM Table_A
WHERE Email like '%#domain_c%'
AND Id NOT IN (SELECT Id
FROM Table_B)
order by No desc) t3
How to make query like this:
SELECT column1 FROM table1 WHERE ppp=$parameter
AND (SELECT * FROM table2 WHERE parameter=$parameter AND qweqwe=$parameter2)
PS: '$' not from PHP, I just show that this values are variable.
Actually, I need AND qweqwe<650 in the second query
Maybe something like this:
SELECT
column1
FROM
table1
WHERE
ppp=$parameter
AND EXISTS
(
SELECT
NULL
FROM
table2
WHERE
table1.ppp=table2.parameter
AND qweqwe<$parameter2
)
SELECT column1 FROM table1 WHERE parameter=$parameter
AND exists
(SELECT 1 FROM table2 WHERE table2.parameter=table1.parameter AND table2.qweqwe=$parameter2)
It depends on you data.
You can either use exists as shown in previous answers or use join.
SELECT column1 FROM table1
join table2 on table1.ppp=table2.parameter and table2.qweqwe=$parameter2
where table1.ppp=$parameter
In most cases join will be much faster then exists. But it can turn out that you have to use distinct if there's more then one recotd in table2 for each record in table1
what exactly are you trying to do?
the thing after first AND should be logical, for example
... AND 650<(SELECT qweqwe FROM table2 WHERE parameter=$parameter2)
Suppose I have two tables, which both have user ids. I want to perform an operation that would return all user IDS in table 1 that are not in table 2. I know there has to be some easy way to do this - can anyone offer some assistance?
Its slow, but you can normally accomplish this with something like 'not in'. (There are other functions in various RDBMS systems to do this in better ways, Oracle for instance has a 'exists' clause that can be used for this.
But you could say:
select id from table1 where id not in (select id from table2)
There are a few ways to do it. Here's one approach using NOT EXISTS:
SELECT userid
FROM table1
WHERE NOT EXISTS
(
SELECT *
FROM table2
WHERE table1.userid = table2.userid
)
And here's another approach using a join:
SELECT table1.userid
FROM table1
LEFT JOIN table2
ON table1.userid = table2.userid
WHERE table2.userid IS NULL
The fastest approach depends on the database.
One way is to use EXCEPT if your TSQL dialect supports it. It is equivalent to performing a left join and null test
SELECT user_id FROM table1 LEFT JOIN table2 ON table1.user_id = table2.user_id WHERE table2.user_id IS NULL;
If it is
SQL Server:
SELECT id FROM table1
EXCEPT
SELECT id FROM table2
Oracle:
SELECT id FROM table1
MINUS
SELECT id FROM table2
Rest: Am not sure....
Try this:
SELECT id FROM table1 WHERE id NOT IN
(
SELECT id FROM table2
)
select ID from table1
where ID not in (select ID from table2)
I would like to make an SQL query to compare two tables with identical columns, both names and types. Each table has a unique key. I want the query to return any rows that contain unequal values. I know could do something like this
select *
from table_1, table_2
where
table_1.key = table_2.key
and (
table_1.col1 != table_2.col1 OR
table_1.col2 != table_2.col2 OR
...
)
but this would be tedious since there are a large and potentially variable number of columns.
edit
If it helps, I'm using a tsql system.
Not sure what type of DB you are using but if you are using SQL Server 2005 or higher try this:
select 'table1' as tblName, * from
(select * from table1
except
select * from table2) x
union all
select 'table2' as tblName, * from
(select * from table2
except select *
from table1) x
How abt this..
select * from table1 where not exists (select * from table2)
union all
select * from table2 where not exists (select * from table1)
Verified with SQL Server:
(select * from table1 except select * from table2)
union
(select * from table2 except select * from table1);
Verified with Oracle:
(select * from table1 minus (select * from table2))
union
(select * from table2 minus (select * from table1))
I have a table containing a unique ID field. Another field (REF) contains a reference to another dataset's ID field.
Now I have to select all datasets where REF points to a dataset that doesn't exist.
SELECT * FROM table WHERE ("no dataset with ID=REF exists")
How can I do this?
3 ways
SELECT * FROM YourTable y WHERE NOT EXISTS
(SELECT * FROM OtherTable o WHERE y.Ref = o.Ref)
SELECT * FROM YourTable WHERE Ref NOT IN
(SELECT Ref FROM OtherTable WHERE Ref IS NOT NULL)
SELECT y.* FROM YourTable y
LEFT OUTER JOIN OtherTable o ON y.Ref = o.Ref
WHERE o.Ref IS NULL
See also Five ways to return all rows from one table which are not in another table
Try this:
SELECT * FROM TABLE WHERE NOT EXISTS
(SELECT * FROM OtherTable WHERE TABLE.Ref = OtherTable.ID)
I think this should work
SELECT * FROM table WHERE id NOT IN (SELECT ref_id FROM ref_table)
or with JOIN
SELECT table.*
FROM table LEFT JOIN ref_table ON table.id = ref_table.ref_id
WHERE ref_table.ref_id IS NULL
SELECT
table1.*
FROM
table1
LEFT JOIN table2 ON table1.id = table2.ref
WHERE
table2.ref IS NULL
You can do a subquery like:
select * from table where somefield not in (select otherfield from sometable where ID=REF)
SELECT *
FROM table
WHERE ((SELECT COUNT(*) FROM table2 WHERE table2.id = table.ref) = 0)
Something like that :
SELECT * FROM table WHERE ID NOT IN(SELECT REF FROM Table2 )
Yes you can use
select * from x where not exist ( select * from y )