I have an output from my query:
Item Type Qty
1 A 2
2 A 3
3 B 1
4 B 2
5 C 1
6 D 3
Type to be grouped: A, B
I need my output to look like this:(after sum the qty and group by)
Type Qty
A 5
B 3
OTHERS 4
when the Type is not defined, it will group in 'OTHERS'. Is this possible to be done using analytic function or do I need to create my own function for this?
Assuming your table / view name is x, this gives exactly the desired output:
SELECT CASE WHEN type IN ('A', 'B') THEN type ELSE 'OTHERS' END AS type,
SUM(qty) AS qty
FROM x
GROUP BY CASE WHEN type IN ('A', 'B') THEN type ELSE 'OTHERS' END
ORDER BY 1
select type,sum(qty) from (select decode(type,c,'OTHERS',d,'OTHERS') type,qty from your_table) group by type;
(or)
select type,sum(qty) from (select (case when type in ('A','B') then type else 'others' end) type,qty from your_table) group by type;
Related
I would like to transpose rows into columns in Snowflake.
Suppose I have the following table BASE
ID
value
type
1
100
'A'
1
200
'B'
1
300
'B'
2
400
'A'
The output should be as follows:
ID
A
B
1
100
200
1
100
300
2
400
NULL
Currently I am pivoting the table with
SELECT ID,
CASE WHEN TYPE = 'A' THEN VALUE ELSE NULL AS A,
CASE WHEN TYPE = 'B' THEN VALUE ELSE NULL AS B
FROM BASE
For now the GROUP BY statement is missing. Typically I would GROUP BY ID, but that does not account for keeping one row per each value on the same TYPE and ID.
Any ideas how to achieve this?
Cheers,
P
You can use conditional aggregation. You can use row_number() to get multiple rows:
SELECT ID,
MAX(CASE WHEN TYPE = 'A' THEN VALUE END) AS A,
MAX(CASE WHEN TYPE = 'B' THEN VALUE END) AS B
FROM (SELECT B.*,
ROW_NUMBER() OVER (PARTITION BY ID, TYPE ORDER BY VALUE) as seqnum
FROM BASE B
) B
GROUP BY ID, seqnum;
This would work, too:
select *
from base_table
pivot(sum(value) for type in ('A','B')) as p
order by id;
I have a question regarding pivoting data in SQL.
Input data:
TABLE NAME temp
id cat value
1 A 22
1 B 33
1 C 44
1 C 55
My ideal output would be:
id A B C
1 22 33 44
1 22 33 55
Can someone provide some hints on this?
Thanks!
select * from
(
select
id,cat,value
from tablename
)
as tablo
pivot
(
sum(value)
for cat in ([A],[B],[C])
) as p
order by id
use case when, assuming you did a mistake in output format in 2nd rows
select id, max( case when cat='A' then value end) as A,
max(case when cat='B' then value end) as B,
max(case when cat='C' then value end)as C from table
group by id
You need row_number() function with conditional aggregation :
select id, max(case when cat = 'a' then value end) a,
max(case when cat = 'b' then value end) b,
max(case when cat = 'c' then value end) c
from (select t.*, row_number() over (partition by id, cat order by value) as seq
from table t
) t
group by id, seq;
However, it doesn't produce your actual output (it leaves null value where the cat has only one value compare to other cats) but it will give the idea of how to do that.
Use CASE WHEN and MAX aggregation:
select id, max(case when cat='A' then value end) as A,max(case when cat='B' then value end) as B,
max(case when cat='C' then value end) as C from temp
group by id
I want to get the "max" character value for a column using a group by statement, except instead of the default alphabetical order, I want to set up a custom ordering that the max will use.
Table1:
ID | TYPE
-----+-------
1 | A
1 | B
1 | C
2 | A
2 | B
I want to group by ID and get max(type) in the order of C, A, B. Expected result:
ID | MAX_TYPE
-----+-----------
1 | C
2 | A
select
id,
case
max(
case max_type
when 'C' then 3 when 'A' then 2 when 'B' then 1
end
)
when 3 then 'C' when 2 then 'A' when 1 then 'B'
end as max_type
from T
group by id
Translate to a value that an be ranked by max() and then translate back to the original value.
If you also want to order the result by that value then you could add:
order by
max(
case max_type
when 'C' then 3 when 'A' then 2 when 'B' then 1
end
) desc
Some platforms require the sorting column to be included in the output. I'm not sure if PostgreSql is one of those. And no objection to Gordon's answer but you'd have to use another window function to calculate the sort order if you need that too.
Instead of translating back and forth, use window functions:
select t.*
from (select t.*,
row_number() over (partition by id
order by (case when type = 'C' then 1
when type = 'A' then 2
when type = 'B' then 3
end) as seqnum
from t
) t
where seqnum = 1;
Depending on what the values look like, you can also simplify this using string functions:
select t.*
from (select t.*,
row_number() over (partition by id
order by position(type, 'CAB')) as seqnum
from t
) t
where seqnum = 1;
I have the following table
Type SubType value
A 1 1
A 2 2
A 3 3
A 4 4
B 1 1
B 2 2
B 3 3
C 1 1
C 2 2
C 3 3
C 4 4
I want to group by all rows except where Type=A and the output should like below
Type Sum
A1 1
A2 2
A3 3
A4 4
B 6
C 10
Is it possible to group by few rows on one condition and others on a different condition?
Yes, you have to write an expression that creates the group definition:
Select case When Type = 'A' then type + ltrim(str(subtype, 9))
Else Type End Type, Sum(Value) Sum
From table
Group By case When Type = 'A' then type + ltrim(str(subtype, 9))
Else Type End
Yes, you can GROUP BY a CASE expression;
SELECT CASE WHEN type='A'
THEN type+CAST(subtype AS VARCHAR(MAX))
ELSE type END [Type],
SUM(value) [Sum]
FROM mytable
GROUP BY CASE WHEN type='A'
THEN type+CAST(subtype AS VARCHAR(MAX))
ELSE type END
ORDER BY [Type]
An SQLfiddle to test with.
In SQL Server 2012, you can use CONCAT without the cast, which simplifies the query somewhat.
Another option. Split the logic into the 2 cases:
SELECT Type + CAST(subtype AS VARCHAR(MAX)) AS Type,
SUM(Value) AS Sum
FROM mytable
WHERE Type = 'A'
GROUP BY Type, Subtype
UNION ALL
SELECT Type,
SUM(Value)
FROM mytable
WHERE Type <> 'A'
GROUP BY Type
ORDER BY Type ;
Tested at SQL-Fiddle (thnx to #Joachim Isakkson)
In the example table below, I'm trying to figure out a way to sum amount over id for all marks where mark 'C' doesn't exist within an id. When mark 'C' does exist in an id, I want the sum of amounts over that id, excluding the amount against mark 'A'. As illustration, my desired output is at the bottom. I've considered using partitions and the EXISTS command, but I'm having trouble conceptualizing the solution. If any of you could take a look and point me in the right direction, it would be greatly appreciated :)
sample table:
id mark amount
------------------
1 A 1
2 A 3
2 B 2
3 A 2
4 A 1
4 B 3
5 A 1
5 C 3
6 A 2
6 C 2
desired output:
id sum(amount)
-----------------
1 1
2 5
3 2
4 4
5 3
6 2
select
id,
case
when count(case mark when 'C' then 1 else null end) = 0
then
sum(amount)
else
sum(case when mark <> 'A' then amount else 0 end)
end
from sampletable
group by id
Here is my effort:
select id, sum(amount) from table t where not t.id = 'A' group by id
having id in (select id from table t where mark = 'C')
union
select id, sum(amount) from table t where t.id group by id
having id not in (select id from table t where mark = 'C')
SELECT
id,
sum(amount) AS sum_amount
FROM atable t
WHERE mark <> 'A'
OR NOT EXISTS (
SELECT *
FROM atable
WHERE id = t.id
AND mark = 'C'
)
GROUP BY
id
;