this is my first time posting here and I am a basic SQL user and need help.
I have a varchar column that stores data like below:
Year.Docid
2007.000000001
2007.000000002
2007.000000003
2007.000000004
2007.000000005
2007.000000006
I need to join this data to another table that does not have all the zeros after the decimal, can someone please show me how to get the data to look like below:
Year Docid
2007.1
2007.2
2007.3
2007.4
2007.5
2007.6
I am using MICROSOFT SQL SERVER 2012
If the format is fixed, i.e. YYYY.NNNNNNNNN, you could just get the last 9 characters, convert them to int, convert the result back to varchar and concatenate back to the first 5 characters:
LEFT([Year.Docid], 5) + CAST(CAST(RIGHT([Year.Docid], 9) AS int) AS varchar(10))
However, it would make more sense to store Year and Docid as two separate int columns, in both tables. It is much easier to assemble them just for the output than do this processing every time and join on the results of it.
In SQL Server, assuming both columns are varchar, something like this should do you:
select *
from table_1 t1
join table_2 t2 on t2.docid = left(t2.docid,4)
+ '.'
+ convert(varchar,convert(int,right( t2.docid, len(t2.docid)-5 )))
You should bear in mind that making the one table's column an expression means that for that table/column, the query optimizer cannot use any indexes in the query plan.
This is a bit of work, but accomplishes the task of removing the zeros from the right of the dot:
SELECT SUBSTRING(YearDocid, 0, CHARINDEX('.', yearDocId)) +
REPLACE(SUBSTRING(yearDocId,
CHARINDEX('.', yearDocId),
LEN(yearDocID)),
'0', '')
FROM tab1;
sqlfiddle demo
To turn the long format into the short format:
SELECT LEFT('2007.000000001',5) + CAST(CAST(RIGHT('2007.000000001',LEN('2007.000000001')-5) AS int)AS VARCHAR)
...
To use that in a join:
SELECT
...
FROM
TABLE_1 T1
INNER JOIN TABLE_2 T2
ON LEFT(T1.pk,5) + CAST(CAST(RIGHT(T1.pk,LEN(T1.pk)-5) AS int)AS VARCHAR) = T2.pk
SELECT CONCAT(PARSENAME([Col_Varchar],2),'.',CONVERT(INT,PARSENAME([Col_Varchar],1))) FROM Tbl_sample
Related
I have a column which has inconsistent data. The column named ID and it can have values such as
0897546321
ABC,0876455321
ABC,XYZ,0873647773
ABC,
99756
test only
The SQL query should fetch only Ids which are of 10 digit in length, should begin with a 08 , should be not null and should not contain all characters. And for those values, which have both digits and characters such as ABC,XYZ,0873647773, it should only fetch the 0873647773 . In these kind of values, nothing is fixed, in place of ABC, XYZ , it can be anything and can be of any length.
The column Id is of varchar type.
My try: I tried the following query
select id
from table
where id is not null
and id not like '%[^0-9]%'
and id like '[08]%[0-9]'
and len(id)=10
I am still not sure how should I deal with values like ABC,XYZ,0873647773
P.S - I have no control over the database. I can't change its values.
SQL Server generally has poor support regular expressions, but in this case a judicious use of PATINDEX is viable:
SELECT SUBSTRING(id, PATINDEX('%,08[0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9],%', ',' + id + ','), 10) AS number
FROM yourTable
WHERE ',' + id + ',' LIKE '%,08[0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9],%';
Demo
If you normalise your data, and split the delimited data into parts, you can achieve this some what more easily:
SELECT SS.value
FROM dbo.YourTable YT
CROSS APPLY STRING_SPLIT(YT.YourColumn,',') SS
WHERE LEN(SS.value) = 10
AND SS.value NOT LIKE '%[^0-9]%';
If you're on an older version of SQL Server, you'll have to use an alternative String Splitter method (such as a XML splitter or user defined inline table-value function); there are plenty of examples on these already on Stack Overflow.
db<>fiddle
select rptName
from RptTable
where rpt_id in (
select LEFT(Reports, NULLIF(LEN(Reports)-1,-1))
from repoAccess1
where uid = 'VIKRAM'
)
this is my sql query In which i have use the sub query to access selected field
in this sub query returns
select LEFT(Reports, NULLIF(LEN(Reports)-1,-1))
from repoAccess1
where uid = 'VIKRAM'
Returns
1,2
that means the query should be like
select rptName
from RptTable where rpt_id in (1,2)
But i m getting this error
Msg 8114, Level 16, State 5, Line 1
Error converting data type nvarchar to numeric.
could anyone tell me ow to modify to get exact ans
It's a little hard to tell without the concrete table definitions, but I'm pretty sure you're trying to compare different data types to each other. If this is the case you can make use of the CAST or the CONVERT function, for example:
SELECT
[rptName]
FROM [RptTable]
WHERE [rpt_id] IN
(
SELECT
CONVERT(int, LEFT([Reports], NULLIF(LEN([Reports]) - 1, -1)))
FROM [repoAccess1]
WHERE [uid] = 'VIKRAM'
)
UPDATE: Since you have updated your question: The LEFT function returns results of either varchar or nvarchar data type. So the resulting query would be
SELECT
[rptName]
FROM [RptTable]
WHERE [rpt_id] IN('1', '2')
Please note the apostrophes (is this the correct term?) around the values. Since [rpt_id] seems to be of data type int the values cannot implicitly be converted. And that's where the aforementioned CAST or CONVERT come into play.
If I understand correctly, the subquery is returning a single row with a value of '1,2'. This is not a number, hence the error.
Before continuing, let me emphasize that storing values in comma delimited string is not the SQL-way of doing things. You should have one row per id, with proper types and foreign keys defined.
That said, sometimes we are stuck with other people's really bad design decisions. If this is the case, you can use LIKE:
select rptName
from RptTable r
where exists (select 1
from repoAccess1 a
where a.uid = 'VIKRAM' and
',' + a.reports + ',' like '%,' + cast(r.rpt_id as varchar(255)) + ',%'
);
select rptName
from RptTable
where rpt_id in (
select CAST(LEFT(Reports, NULLIF(LEN(Reports)-1,-1)) AS INT) as Val
from repoAccess1
where uid = 'VIKRAM'
)
Your query would work fine when (LEFT(Reports, NULLIF(LEN(Reports)-1,-1)) ) returns either 1 or 2 since SQL Server implicitly converts the varchar value to numeric.
It seems there might be a data issue. One of the data returned by LEFT function is non-numeric. In order to find that particular record you can use isnumeric function. Try like this,
SELECT rptName
FROM RptTable
WHERE rpt_id IN (
SELECT LEFT(Reports, NULLIF(LEN(Reports) - 1, - 1))
FROM repoAccess1
WHERE uid = 'VIKRAM'
AND ISNUMERIC(LEFT(Reports, NULLIF(LEN(Reports) - 1, - 1))) = 1
)
I have the following query to select record but i wan to format the column on the result set.
SELECT
COALESCE(dbo.tblMitchellLandscapeID.PatchSize,0) as PatchSize,
dbo.tblMitchellLandscape.MitchellLandscapeName
FROM tblMitchellLandscapeID
INNER JOIN dbo.tblMitchellLandscape
ON dbo.tblMitchellLandscapeID.MitchellLandscapeID=dbo.tblMitchellLandscape.MitchellLandscapeID
WHERE AssessmentVersionID = #AssessmentVersionID
"PatchSize" is a decimal value so it stored always like two decimals "15.10". All i trying to format to one decimal when the select statement is executed i wan to populate the result set like "15.1" rather than 15.10.
You can just cast it to the format you want:
SELECT CAST(COALESCE(li.PatchSize, 0) as decimal(5, 1)) as PatchSize,
l.MitchellLandscapeName
FROM tblMitchellLandscapeID li INNER JOIN
dbo.tblMitchellLandscape l
ON li.MitchellLandscapeID = l.MitchellLandscapeID
WHERE AssessmentVersionID = #AssessmentVersionID;
Notice the query is also easier to read (and write) if you use table aliases.
I need to identify repeated numbers( Eg: 1111, 33333333, 5555555555,777777777 etc.) in a column.
How can I do this in sql server without having to hard code every scenario. The max length is 10 of the column. Any help is appreciated.
This will check if the column has all the same value in it.
SELECT *
FROM tablename
WHERE columnname = REPLICATE(LEFT(columnname,1),LEN(columnname))
As Nicholas Cary notes, if the column is numbers you'd need to cast as varchar first:
SELECT *
FROM tablename
WHERE CAST(columnname AS VARCHAR(10)) = REPLICATE(LEFT(CAST(columnname AS VARCHAR(10)),1),LEN(CAST(columnname AS VARCHAR(10))))
Riffing on #Dave.Gugg's excellent answer, here's another way, using patindex() to look for a character different than the first.
select *
from some_table t
where 0 = patindex( '[^' + left(t.some_column,1) + ']' , t.some_column )
Again, this only works for string types (char,varchar, etc.). Numeric types such as int will need to be converted first.
SQL SERVER 2005
SQL Sorting :
Datatype varchar
Should sort by
1.aaaa
5.xx
11.bbbbbb
12
15.
how can i get this sorting order
Wrong
1.aaaa
11.bbbbbb
12
15.
5.xx
On Oracle, this would work.
SELECT
*
FROM
table
ORDER BY
to_number(regexp_substr(COLUMN,'^[0-9]+')),
regexp_substr(column,'\..*');
You could do this by calculating a column based on what's on the left hand side of the period('.').
However this method will be very difficult to make robust enough to use in a production system, unless you can make a lot of assertions about the content of the strings.
Also handling strings without periods could cause some grief
with r as (
select '1.aaaa' as string
union select '5.xx'
union select '11.bbbbbb'
union select '12'
union select '15.' )
select *
from r
order by
CONVERT(int, left(r.string, case when ( CHARINDEX('.', r.string)-1 < 1)
then LEN(r.string)
else CHARINDEX('.', r.string)-1 end )),
r.string
If all the entries have this form, you could split them into two parts and sort be these, for example like this:
ORDER BY
CONVERT(INT, SUBSTRING(fieldname, 1, CHARINDEX('.', fieldname))),
SUBSTRING(fieldname, CHARINDEX('.', fieldname) + 1, LEN(fieldname))
This should do a numeric sort on the part before the . and an alphanumeric sort for the part after the ., but may need some tuning, as I haven't actually tried it.
Another way (and faster) might be to create computed columns that contain the part before the . and after the . and sort by them.
A third way (if you can't create computed columns) could be to create a view over the table that has two additional columns with the respective parts of the field and then do the select on that view.