I would like to separate numbers with more then 3 digits with another character then a comma or a dot in Open Flash Chart 2.
In my region/country we format a big amount like this: 1'234'567.95
I only found the way to choose between a comma or a dot as a thousand separator here:
http://teethgrinder.co.uk/open-flash-chart-2/doxygen/html/classopen__flash__chart.html
How can I define the apostrophe character ' as number format separator like in #'###.00
Related
I'm currently trying to read from a CSV files ( separated with semicolon ';') with decimal numbers formatted with a comma(,) as a decimal separator instead of a dot (.).
i.e: the number 12356.12 is stored as 12356,12.
In the source's projection, what would be the correct format to read the value correctly?
The format should in Java Decimal Format
If your CSV file's columnDelimiter is a comma (','), your first concern is how to avoid your number data won't be treated as different columns. Since your number data is stored as 12356,12, so my suggests as below :
Change the columnDelimiter as | or other special characters.
2.Set escape char. Please see this description:
In addition, 12356,12 can't be identified as Decimal format in ADF automatically. And no such mechanism o turn , into .. So I think you need to transfer data as string temporary. Then convert it into Decimal in your destination with java code.
True answer is in the comments: In the copy job the culture can be defined, which influences the decimal separator. Go to "mapping" > "Type conversion settings" > "culture" and chose en-us, de-de or whatever works for you. Be aware that this will also influence other types like dates.
Can anyone help with a query on how to replace special/non-numeric/hidden characters from a phone number column.
I've tried
LTRIM(RTRIM(REGEXP_REPLACE(
PHONE_NBR,
'[^[:digit:]][:cntrl:][:alpha:][:graph:][:blank:][:print:][:punct:][:space:]~',
'')))
but no luck, there are still a few records which contain non-numeric values.
Your regex is saying to ONLY replace a string consisting of: a non-numeric character followed by a control character, an alpha, a graph, a blank, a print, a punct, a space, and then a tilde.
You should be able to just use '[^[:digit:]]' as your regex, to remove all non-numeric characters.
I would like to replace all pipes and line breaks with space in a free text field in my data base.
My current approach looks like the following:
SELECT
ID,
REGEXP_REPLACE(REGEXP_REPLACE(FREETEXT,'|',‘ ‘),‘\n',' ')
FROM TABLE
My idea is to replace the pipes | with a space and then the results get checked again and all linebreaks are replaced. Problem now is that there are still pipes in there which messes up the CSV since my delimter for that is |.
Hope anyone can help me out here.
PS: I am not able to change the delimter to something else.
The pipe symbol is a special character in a Regular Expression, splitting it into multiple alternatives, thus you must escape it.
If you want to replace all pipe and line break characters you don't have to nest:
RegExp_Replace(FREETEXT,'[\|\n\r]',' ')
\| pipe 0x7C
\n line feed 0x0A
\r carriage return 0x0D
But as those are single characters you can simply use
OTranslate(FREETEXT, '7C0A0D'xc,' ')
Only if you want to replace consecutive occurences of those characters with a single space you need a RegEx:
RegExp_Replace(FREETEXT,'[\|\n\r]+',' ')
I would like to have a regular expression to make an Oracle SQL REGEXP_LIKE query that checks
if a string starts with one alphanumeric character
if the string ends with one alphanumeric character
if the "body" of the string contains only alphanumeric character OR these authorized characters (written) : hyphen (dash), dot, apostrophe, space
if the authorised characters are NOT adjacent (to avoid something like "he--'''l..'-lo")
I started with this :
^[a-zA-Z0-9]+(a-zA-Z0-9\-\.'|([^\-\.'])\1)*[a-zA-Z0-9]$
I used backslash to escape assuming that dot and hyphen are metacharacters
I think this is what you want:
^[a-zA-Z0-9]+([-.' ][a-zA-Z0-9]|[a-zA-Z0-9])*\w?$
It looks for
at least 1 alphanumeric (alnum),
followed by
either an authorized character followed by an alphanumeric or just an alphanumeric, repeated any number of times (including 0).
optionally followed by
an alnum
This meets your specification. I'm not sure if starts with one alnum and ends with one alnum means that there must be at least 2 alnums, or if they can be the same. If there must be at least 2 of them, remove the last ? (which make the last alnum optional).
Regards
assuming you meant "authorised characters are NOT adjacent to each other"
try something along these lines
^[a-zA-Z0-9]+([a-zA-Z0-9]+[\-\.' ]?)*[a-zA-Z0-9]$
so that the repeating middle part always has one alphanumeric character followed by zero to one special characters.
I am trying to write a query which will tell me if certain record is having only the special characters. e.g- "%^&%&^%&" will error however "%HH678*(*))" is fine (as it's having alphanumeric values as well. I have written following query however, it's working fine only for English alphabets and numbers, if column is having some other characters like mandarin then also it's not giving expected value.Any help is highly appreciated.
SELECT * FROM test WHERE REGEXP_LIKE(sampletext, '[^]^A-Z^a-z^0-9^[^.^{^}^ ]' );
You may try this,
regexp_like(text, '^[^A-Za-z0-9]+$')
This would match the text only if the input text contains special chars ie, only chars which are not of letters or digits.
To detect strings containing only characters other than unaccented alphabetic, numeric, or white space characters try this:
regexp_like(text,'^[^a-zA-Z0-9[:space:]]+$')
If you don't think punctuation characters are special than add [:punct:] to the class of characters to ignore.
If you are looking for a specific set of characters you can use a character class of just those characters of interest, for example some common accented characters (note the lack of a leading ^ in the character class []:
regexp_like(text,'^[àèìòùÀÈÌÒÙáéíóúýÁÉÍÓÚÝâêîôûÂÊÎÔÛãñõÃÑÕäëïöüÿÄËÏÖÜŸçÇßØøÅåÆæœ]+$')