I have table Customer:
Id Code Name
1 100 John
2 200 Jack
3 300 Mike
4 400 Betty
And table SaleType:
Id Code Name
1 1000 cash
2 2000 cheque
3 3000 free
And a table that describe which customer has which sale type named SaleType_Customer
Id SaleTypeID CustomerID
1 1 1
2 1 2
3 2 1
4 2 3
I want to write a query that takes the SaleTypes of a customer. But if the customer is not in table SaleType_Customer the query returns all of SaleTypes. How can I write this query?
My query:
SELECT SaleType.ID, SaleType.Code, SaleType.Name
FROM SaleType left outer join SaleType_Customer on SaleType.Id = SaleType_Customer.SaleTypeID
Where SaleType_Customer.CustomerID= 1
I want the result for John (id=1):
Id Code Name
1 1000 cash
2 2000 cheque
And for Betty (id=4) is complete because she is not in SaleType_Customer:
Id Code Name
1 1000 cash
2 2000 cheque
3 3000 free
How should I write my query?
SELECT distinct SaleType.ID, SaleType.Code, SaleType.Name
FROM Customer left join SaleType_Customer
on CustomerID = Customer.Id
,SaleType
where (SaleTypeID = SaleType.Id or SaleTypeID is NULL)
and Customer.ID= 4;
Here is the SQLFiddle
SELECT SaleType.ID, SaleType.Code, SaleType.Name
FROM SaleType
WHERE NOT EXISTS (SELECT *
FROM SaleType_Customer
WHERE SaleType_Customer.Customerid = 4)
UNION
SELECT SaleType.ID, SaleType.Code, SaleType.Name
FROM SaleType
INNER JOIN SaleType_Customer
ON SaleType_Customer.Saletypeid = SaleType.Id
WHERE SaleType_Customer.Customerid = 4
Sqlfiddle sample (oracle)
Related
Input=[Buyers.Name], get other [Buyers.Name]s who have the same [Stores.StoreID]s.
Example: Input "Sten" (BuyerID 1), get "Patrick"(BuyerID 3) because both have StoreID 13.
TABLES
Buyers
BuyerID
Name
1
Sten
2
Henry
3
Patrick
Stores
BuyerID
StoreID
1
7
1
13
2
5
3
1
3
2
3
13
As I am a new user, I can't add images to the post.
Simplified view of the tables.
You can use in with a subquery:
select distinct s.buyerid
from sellers s
where s.storeid in (select s2.storeid
from sellers s2 join
buyers b2
on s2.buyerId = b2.buyerId
where b2.name = 'Sten'
);
Here is a db<>fiddle.
accounts table
----------------
id name
10 ABC Company
11 XYZ Company
12 LMN Company
13 EFG Company
14 JKL Company
.. ...........
.. ...........
accounts_opportunities table
-----------------------
id opportunity_id account_id deleted
1 1 11 0
2 2 11 0
3 3 12 0
4 4 12 0
5 5 13 0
6 6 14 0
. . .. .
. . .. .
opportunities table
-----------------
id name amount
1 Opp 1 100
2 Opp 2 50
3 Opp 3 500
4 Opp 4 600
5 Opp 5 200
6 Opp 6 1000
I am trying to select top 20 accounts from above tables. And I written following query for
that,
SELECT TOP 20 COUNT(*) as number_of_opportunities,
(
SELECT accounts.name
FROM accounts
WHERE accounts.id=accounts_opportunities.account_id
) as account_name
FROM accounts_opportunities
JOIN opportunities ON opportunities.id = accounts_opportunities.opportunity_id
WHERE accounts_opportunities.deleted != '1'
GROUP BY accounts_opportunities.account_id
ORDER BY number_of_opportunities DESC
And above query gives following output;
Account name Number of Opportunities
------------ -----------------------
ABC Company 3
XYZ Company 2
LMN Company 2
EFG Company 1
JKL Company 1
XYZ and LMN have same numbers opportunities, but if I calculate total amount of XYZ opportunities are less than LMN total amount. Also JKL has higher amount than EFG.
My question is how to order this query from number_of_opportunities and then total opportunity amount. can someone please give me a guide..
Expected Output
Account name Number of Opportunities
------------ -----------------------
ABC Company 3
LMN Company 2
EFG Company 1
JKL Company 1
XYZ Company 2
Try this:
SELECT TOP 20 a.name, COUNT(*) AS [Number of Opportunities]
FROM accounts AS a
INNER JOIN accounts_opportunities AS ao ON a.id = ao.account_id
INNER JOIN opportunities AS o ON o.id = ao.opportunity_id
WHERE ao.deleted != 1
GROUP BY a.id, a.name
ORDER BY COUNT(*) DESC, SUM(amount) DESC
So, you can add SUM(amount) in the ORDER BY clause with DESC. This will place accounts with higher amount sums on top of other accounts, in case of a tie in COUNT(*).
I have 4 tables here, I need to multiply newly entered row value in a table with another row and find the total sum using CustomerId:
CustomerTable:
CustomerId Name EmailId
-------------------------
1 Paul r#r.com
2 John J#j.com
LoyaltyPointTable:
LoyaltyPointsId LoyaltyType Points
---------------------------------------
1 Registration 10
2 Loginstatus 1
3 Downloading 10
4 Redemming 1
5 Sharing 20
6 Refer 10
LoyaltyDetailsTable:
LoyaltyDetailsId LoyaltyPointsId CustomerId Dates
-------------------------------------------------
1 1 1 2015-01-22
2 2 1 2015-01-22
3 3 2 2015-01-22
4 3 1 2015-01-22
5 4 1 2015-01-22
6 4 1 2015-01-24
7 5 1 2015-01-24
This query works fine for the total sum for each LoyaltyType
SELECT
LoayaltyPointsTable.LoyaltyType,
COUNT(CustomerTable.CustomerId) AS UserActions,
SUM(LoayaltyPointsTable.Points) AS TotalPoints
FROM
LoayaltyPointsTable
JOIN
LoyaltyDetailsTable ON LoayaltyPointsTable.LoyaltyPointsId = LoyaltyDetailsTable.LoyaltyPointsId
JOIN
CustomerTable ON CustomerTable.CustomerId = LoyaltyDetailsTable.CustomerId
WHERE
CustomerTable.CustomerId = 1
GROUP BY
LoyaltyDetailsTable.CustomerId ,LoayaltyPointsTable.LoyaltyType
below RedeemPointsTable is created with relation to row redeeming in LoyaltyPointTable:
RedeemPointsTable:
RedeemPointsId CustomerId ShopName BillNo Amount
------------------------------------------------
1 1 Mall x 4757 100
3 1 Mall y SH43 50
4 1 Mall x 7743 10
6 1 Mall x s34a 60
What I am expecting is before calculating the total sum, I want column Amount sum (100+50+10+60) * 1 in Redeeming in LoyaltyPointTable to be added with total points for each CustomerId
Expected output
LoyaltyType UserActions TotalPoints
-------------------------------------
Downloading 1 10
Loginstatus 1 1
Redemming 4 (100+50+10+60)*1(here using Amount in RedeemPointsTable)
Refer 1 10
Registration 1 10
Sharing 1 20
User actions count is 4, it is based on the Amount he entered in RedeemPointsTable
Should I need to make changes in adding a foreign key column in RedeemPointsTable or can you point out my mistake?
Any help would be great.
This is the query which returns desired result:
SELECT
LoyaltyPointTable.LoyaltyType,
CASE
WHEN LoyaltyPointTable.LoyaltyPointsId=4 THEN (SELECT COUNT(amount) FROM RedeemPointsTable where CustomerId=1)
ELSE COUNT(CustomerTable.CustomerId)
END as UserActions,
CASE
WHEN LoyaltyPointTable.LoyaltyPointsId=4 THEN (SELECT SUM(amount) FROM RedeemPointsTable where CustomerId=1)*Points
ELSE SUM(LoyaltyPointTable.Points)
END as TotalPoints
FROM
LoyaltyPointTable
JOIN
LoyaltyDetailsTable ON LoyaltyPointTable.LoyaltyPointsId = LoyaltyDetailsTable.LoyaltyPointsId
JOIN
CustomerTable ON CustomerTable.CustomerId = LoyaltyDetailsTable.CustomerId
WHERE
CustomerTable.CustomerId = 1
GROUP BY
LoyaltyDetailsTable.CustomerId ,LoyaltyPointTable.LoyaltyType
You can check it here
These are the tables in the query. Want to compare the ID_Skills in the following 2 tables. And in the returning table from the select query, display ID_Skills with condition saying whether or not TrainingRequired (Yes/No)
tblEmployeeCurrentSkills
ID_EmployeeCurrentSkills ID_Employee ID_Skills
1 1 1
2 1 2
3 2 1
tblSkillsRequired
ID_SkillsRequired ID_Employee ID_Skills ID_Position
1 1 1 1
2 1 2 1
3 1 3 1
4 2 3 2
tblSkills
ID_Skills Skill
1 Reading
2 Wiring
3 Stapling
tblPosition
ID_Position Position
1 Tech1
2 Stapler
tblEmployee
ID_Employee EmployeeName
1 Hannah
2 Bob
SQL for qrySkillsGap table - determines whether training is necessary
SELECT tblEmployee.[Employee Name],
tblSkillsRequired.ID_Skills,
tblSkills.Skill,
IIf([tblEmployeeCurrentSkills].[ID_Skills]
Like [tblSkillsRequired].[ID_Skills],"No","Yes") AS TrainingRequired
FROM (tblSkills
INNER JOIN tblSkillsRequired
ON tblSkills.ID_Skills = tblSkillsRequired.ID_Skills)
INNER JOIN (tblEmployee INNER JOIN tblEmployeeCurrentSkills
ON tblEmployee.ID_Employee = tblEmployeeCurrentSkills.ID_Employee)
ON tblSkills.ID_Skills = tblEmployeeCurrentSkills.ID_Skills;
This is the current output:
EmployeeName ID_Skill TrainingRequired
Hannah 1 No
Hannah 1 No
Hannah 2 No
Bob 1 No
Bob 1 No
I want it to display this:
EmployeeName ID_Skill TrainingRequired
Hannah 1 No
Hannah 2 No
Hannah 3 Yes
Bob 1 No
Bob 3 Yes
Thanks for any help!
I was able to create the tables you provided and used a union to bring together the employee skills and required skills.
SELECT te.EmployeeName
, emp.ID_Skills
, CASE WHEN MIN(emp.TrainingRequired) = 0 THEN 'No'
ELSE 'Yes'
END AS TrainingRequired
FROM dbo.tblEmployee AS te
JOIN (SELECT tecs.ID_Employee
, tecs.ID_Skills
, 0 AS TrainingRequired
FROM dbo.tblEmployeeCurrentSkills AS tecs
UNION
SELECT tsr.ID_Employee
, tsr.ID_Skills
, 1 AS TrainingRequired
FROM dbo.tblSkillsRequired AS tsr
) emp
ON te.ID_Employee = emp.ID_Employee
GROUP BY te.ID_Employee
, te.EmployeeName
, emp.ID_Skills
ORDER BY te.ID_Employee
, emp.ID_Skills
I have following tables:
UserMaster:
UserId Int, UserName Varchar(200),AddedBy Int
UserId EmpName AddedBy
1 admin 0
2 SubAdmin1 1
3 SubAdmin2 1
4 Vikas 2
5 Mohit 4
6 Atul 5
7 Vishal 6
8 Mani 3
9 Sunny 8
SalesMaster:
SalesId Int, UserId Int (FK_UserMaster_UserId) , Price Int
SalesId UserId Price
1 1 100
2 2 200
3 3 300
4 4 500
5 5 100
6 6 200
7 7 111
8 8 222
9 9 333
Case 1: Now I want the price total of all the users who are under the one particular user and its own price also.
Means If i consider UserId=1 , Then the price will be calculated for all users where Column value in AddedBy=1
and their lower level employees.
Means the total Price of users will be calulated for the users having UserId are: 1,2,3,4,5,6,7,8,9.
Case 2: Similarly, If i want to calculate the total price under UserId=3(SubAdmin2) then the total price from the salesMaster will be calculated for the Users having UserId are: 3,8,9
The Result of first Case should be:
UserId Price
1 2066
The Result of Second Case should be:
UserId Price
3 300+222+333
Please Help
Thanks & Regards
Nitin
with cte as (
select #UserId as UserId
union all
select um.UserId
from UserMaster as um
inner join cte as c on c.UserId = um.AddedBy
)
select sum(s.Price)
from cte as c
inner join SalesMaster as s on s.UserId = c.UserId
sql fiddle demo