I have two table
Table_A
ID PostId Item Stock Price
1 1 A 30 10
2 1 B 40 20
3 2 A 50 5
4 3 A 50 25
Table_B
ID PostId Item_ID Sold Price
1 1 1 2 20
2 1 2 2 40
3 1 1 1 10
4 2 3 3 15
5 2 3 1 5
I want to queries from above two table that have same 'PostID' and COUNT and SUM some field group by 'PostID', expected output would be like this
Output
ID PostId Total Item Total Stock Total Buyer(s) Total Sold Total Price
1 1 2 70 3 5 70
I've try to JOIN it, but result still miss calculate
SELECT Table_A.PostId AS PostId, COUNT(Table_A.Item) AS Total_Item, SUM(Table_A.stock) AS Total_Stock, COUNT(Table_B.Item_ID) AS total_buyer, SUM( Table_B.Sold ) AS TotalSold, SUM( Table_B.Price ) AS Total_Price
FROM Table_A
LEFT JOIN Table_B
ON Table_A.PostId = Table_B.PostId
WHERE Table_A.PostId = '1'
GROUP BY Table_A.PostId
LIMIT 0 , 30
Any suggestion for this query problem?? Thank you
SELECT Table_B.PostId AS PostId,
MIN(Table_A.Total_Item) AS Total_Item,
MIN(Table_A.Total_Stock) AS Total_Stock,
COUNT(Table_B.Item_ID) AS total_buyer,
SUM( Table_B.Sold ) AS TotalSold,
SUM( Table_B.Price ) AS Total_Price
FROM Table_B
LEFT JOIN
(
SELECT PostId,
COUNT(Item) AS Total_Item,
SUM(stock) AS Total_Stock
FROM
Table_A
GROUP BY PostId
) Table_A
ON Table_B.PostId=Table_A.PostId
WHERE Table_B.PostId = '1'
GROUP BY Table_B.PostId
LIMIT 0 , 30
Related
Table 1
ID
Grp
Qty
1
A
5
2
A
4
3
B
5
4
B
3
5
B
2
6
C
14
7
D
1
8
D
1
9
E
2
10
E
2
11
E
1
12
E
1
Table 2
ID
Grp
Qty
1
A
7
2
B
9
3
C
13
4
D
1
5
E
4
Select/Output
ID
Grp
Qty
1
A
0
2
A
2
3
B
0
4
B
0
5
B
1
6
C
1
7
D
0
8
D
1
9
E
0
10
E
0
11
E
1
12
E
1
I want to select a row on a 1st table with a specific quantity based on the total quantity of the 2nd table. The result is on the 3rd table. Please see sample tables above, I really appreciate a help, thank you so much and sorry it was my first time asking a question here.
I have tried this code on both 2 tables
WITH tbl AS(
SELECT ID,
Qty,
Grp,
ROW_NUMBER() OVER (PARTITION BY Grp)AS Rown,
SUM(Qty) OVER (PARTITION BY Grp)AS Total
FROM Table1
)
SELECT * FROM tbl WHERE Rown = 1
But I am not able to select the specific rows on Table 1 because it only select the 1st row and total the quantity. Every row on table 1 has its own quantity.
You could use a cumulative windowed aggregates and then a CASE expression to achieve this:
--Saple Data
WITH Table1 AS(
SELECT *
FROM (VALUES(1,'A',5),
(2,'A',4),
(3,'B',5),
(4,'B',3),
(5,'B',2),
(6,'C',14))V(ID,Grp,Qty)),
Table2 AS(
SELECT *
FROM (VALUES(1,'A',7),
(2,'B',9),
(3,'C',13))V(ID,Grp,Qty)),
--Solution
CTE AS(
SELECT T1.ID,
T1.Grp,
T1.Qty,
SUM(T1.Qty) OVER (PARTITION BY T1.Grp ORDER BY T1.Id
ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW) AS RunningQty,
T2.Qty AS T2Qty
FROM Table1 T1
JOIN Table2 T2 ON T1.Grp = T2.Grp)
SELECT C.ID,
C.Grp,
CASE WHEN C.RunningQty <= C.T2Qty THEN C.Qty
ELSE C.T2Qty - LAG(C.RunningQty,1,0) OVER (PARTITION BY C.Grp ORDER BY C.ID)
END AS Qty
FROM CTE C;
I have a table which stores purchase info from sellers and table contains rating to every purchase out of 5 stars. I want to have output Group By sellers and Each sellers good(Above 3) and bad(Below 4) ratings count
PurchaseId SellerId PurchaseRating
1 ABC 2
2 ABC 5
3 DEF 1
4 XYZ 2
5 DEF 4
7 ABC 3
OUTPUT
SellerId TotalOrders AvgRating Above3*(4&5) Below4*(1 to 3)
ABC 3 3.3 1 2
DEF 2 2.5 1 1
XYZ 1 2 0 1
For first 3 columns I am getting result using this
Select SellerId, Count(P.Id) TotalOrders, Avg(PurchaseRating) AvgRating,
CASE WHEN P.PurchaseRating >= 4 THEN 1 ELSE 0 END AS Above3*(4&5)
from
[dbo].[AmazonAbeOrdersPurchaseInfo] P
Where PurchaseRating is not null
Group by P.SellerId
order by TotalOrders desc
Unable to identify how to include case in group by clause.
You are trying to do conditional aggreation. The important thing is that you want the conditional expression inside the aggregate function:
select
sellerId,
count(*) totalOrders,
avg(purchaseRating) avgRating,
sum(case when purchaseRating > 3 then 1 else 0 end) above3,
sum(case when purchaseRating < 4 then 1 else 0 end) below4
from [dbo].[AmazonAbeOrdersPurchaseInfo]
where purchaseRating is not null
group by sellerId
order by totalOrders desc
I'm working with SQL Server, and I have 2 tables: Invoice and InvoiceService.
Invoice:
InvoiceID InvoiceDate InvoicePrice InvoicePaidAmount PatientID
----------------------------------------------------------------------------
1 01-01-2016 50 30 1
2 01-02-2016 100 100 2
InvoiceService:
ID InvoiceID ServiceName ServicePrice
-------------------------------------------------
1 1 Dermato 20
2 1 ophthalmo 30
3 2 General 100
My query:
select
ServiceName, ServicePrice, InvoiceID, InvoicePrice,
InvoicePaidAmount, PatientID
from
InvoiceService
inner join
Invoice on Invoice.InvoiceID = InvoiceService.InvoiceID
Result:
ServiceName ServicePrice InvoiceID InvoicePrice InvoicePaidAmount PatientID
Dermato 20 1 50 30 1
ophthalmo 30 1 50 30 1
General 100 2 100 100 2
I need to get non duplicate values from the left table :
when an invoice has more than 1 service I want that the invoice price and InvoicePaidAmount don't be repeated like this example:
ServiceName ServicePrice InvoiceID InvoicePrice InvoicePaidAmount PatientID
Dermato 20 1 50 30 1
ophthalmo 30 1 0 0 1
General 100 2 100 100 2
If I understand correctly, you want one invoice service to "really" match.
select s.ServiceName, s.ServicePrice, i.InvoiceID,
(case when seqnum = 1 then i.InvoicePrice else 0 end) as InvoicePrice,
(case when seqnum = 1 then i.InvoicePaidAmount else 0 end) as InvoicePaidAmount,
i.PatientID
from Invoice i join
(select s.*,
row_number() over (partition by s.InvoiceID order by s.id) as seqnum
from InvoiceService s
) s
on i.InvoiceID = s.InvoiceID
I need to get the sum of all TOTAL fields where the ID, RECNO and DRCR fields have the same value, while also displaying these fields in the result set.
eg
ID RECNO SECRECNO DRCR TOTAL
1 9 5 D 25
1 9 12 D 22
1 9 6 C 33
1 9 5 D 50
1 8 2 D 12
1 8 2 C 23
2 9 5 D 100
So the results of the query should be
ID RECNO SECRECNO DRCR SUM(TOTAL)
1 9 5 D 75
1 9 12 D 22
1 9 6 C 33
1 8 2 D 12
1 8 2 C 23
2 9 5 D 100
This query will give the results set, without the TOTAL:
select distinct t1.recno, t1.secrecno
from table t1, table t2
where t1.recno = t2.recno and t.id = '1' and t1.drcr = 'D'
But I can't see how to SUM the TOTAL of these results.
How to do this?
select t1.id,
t1.recno,
t1.secrecno,
t1.drcr,
SUM( TOTAL )
from table t1
INNER JOIN
table t2
ON ( t1.recno = t2.recno )
WHERE t1.id = '1'
AND t1.drcr = 'D'
GROUP BY
t1.id,
t1.recno,
t1.secrecno,
t1.drcr
I need to GROUP BY item_id and check if user_id in any of those matches a variable. If so, I want it to = 1, if not 0.
for example, imagine table like this:
item_id, user_id
1 1
1 3
2 4
2 1
2 7
2 3
3 4
3 6
4 8
4 1
5 3
IF (user_id = 3,1,0) AS match,
Want my Query to come back as
item_id, match
1 1
2 1
3 0
4 0
5 1
Where "1" all occurrences of user_id 3 in an item_id group.
You need the right aggregation function:
select item_id,
max(case when user_id = 3 then 1 else 0 end) as hasmatch
from t
group by item_id
order by item_id
In MySQL, true is 1 and false is 0, so you can just do:
SELECT item_id, MAX(user_id = 3) AS has_match
FROM table
GROUP BY 1
You can even count the number of matches:
SELECT item_id, SUM(user_id = 3) AS matches
FROM table
GROUP BY 1
GROUP BY 1 is short for GROUP BY item_id, as item_id is the first select expression.
I would do it as follows:
SELECT
A.item_id, ISNULL(B.count, 0)
FROM
(SELECT DISTINCT item_id 'item_id' FROM myTable) AS A
LEFT JOIN
(
SELECT item_id, count(*) 'count'
FROM myTable WHERE user_id IN (3, 1, 0)
GROUP BY item_id
) AS B
ON A.item_id = B.item_id