i have two tables:
create table saller(
id_saller int IDENTITY PRIMARY KEY,
name varchar(50),
branch varchar(10)
);
create table sale(
id_sale int IDENTITY PRIMARY KEY,
amount float,
id_saller int,
CONSTRAINT fk_saller FOREIGN KEY (id_saller)REFERENCES saller(id_saller)
);
i wanna get the biggest selling value of the amount for each branch
and get the name and id of the saller in charge for the biggest selling
i tried this:
SELECT saller.name, saller.id_saller,maxv.branch, maxv.maxbranch
FROM saller
INNER JOIN sale
ON saller.id_saller = sale.id_saller
INNER JOIN (
SELECT saller.branch,saller.id_saller,MAX(sale.amount) AS maxbranch
FROM saller
INNER JOIN sale
ON saller.id_saller = sale.id_saller
GROUP BY saller.branch,saller.id_saller
) AS maxv ON(sale.id_saller = maxv.id_saller)
One way to do it if you want to return exactly one row per branch even if you have ties
SELECT branch, id_saller, name, amount
FROM
(
SELECT r.branch, s.id_saller, r.name, s.amount,
ROW_NUMBER() OVER (PARTITION BY r.branch ORDER BY s.amount DESC) rnum
FROM sale s JOIN saller r
ON s.id_saller = r.id_saller
) q
WHERE q.rnum = 1
or if you want the highest value with ties
SELECT branch, id_saller, name, amount
FROM
(
SELECT r.branch, s.id_saller, r.name, s.amount,
RANK() OVER (PARTITION BY r.branch ORDER BY s.amount DESC) rank
FROM sale s JOIN saller r
ON s.id_saller = r.id_saller
) q
WHERE q.rank = 1
Here is SQLFiddle demo
According to your question, I don't understand the presence of branch, maybe a table that has not been mentionned. But to retrieve the seller id and name, you can try this;
SELECT saller.name, saller.id_saller
FROM saller
INNER JOIN sale
ON saller.id_saller = sale.id_saller
WHERE sale.Amount = (Select Max(Amount) from sale)
Related
I have three tables and want a join where only 1 row per priority shows.
table Role (AgreementId int, CustomerId int, AgreementRoleId int);
table AgreementRoleGroup (RoleGroupId int, AgreementRoleId int);
table RoleGroup (RoleGroupid int, priority int)
Current query gives all rows
select * from role r
left join agreementRoleGroup as arg on r.agreementRoleId = arg.agreementRoleId
I made a db fiddle, where I want the result to be two rows, the first and one of the two next.
https://dbfiddle.uk/?rdbms=sqlserver_2019&fiddle=fea96bb551657bfcce18f9af7f3f2947
Your criteria for which row isn't defined, but I assume you want the unique set of AgreementID, CustomerID and RoleGroupID, in which case use:
select distinct r.AgreementID, r.CustomerID, arg.RoleGroupID
from role r
inner join agreementRoleGroup as arg on r.agreementRoleId = arg.agreementRoleId
You can use analytical function ROW_NUMBER as follows:
select * from
(select r.*, arg.RoleGroupId,
row_number() over (partition by rg.priority order by r.AgreementId) as rn
from role r
join agreementRoleGroup as arg on r.agreementRoleId = arg.agreementRoleId
join rolegroup rg on rg.RoleGroupid = arg.RoleGroupId) t
where rn = 1
db<>fiddle
I have a table with a list of Client No's, ID etc & there are many Clients with different ID's. I need to pull out the MAX ID No. for each Client, e.g.
ClientNo: 1500 has 3 ID's - the maximum in the ID field is the one I need!
UPDATE: This works:
SELECT MP.ClientID, MP.SequenceID
FROM TABLENAME MP
INNER JOIN (
SELECT ClientID, MAX(SequenceID) SequenceID
FROM TABLENAME
GROUP BY ClientID
) b on MP.ClientID = b.ClientID AND MP.SequenceID = b.SequenceID
BUT....
I need to link the table to many others to pull in other data, where do I insert the left joins to these tables please?
I am assuming you have multiple same client (numbers) with different IDs and for each client (number) you have to get the maximum ID. You may do the following:
select client_number, max(ID) from client group by client_number;
Depending on your need tweak this query.
You may want to do this:
SELECT MP.ClientID, b.DesiredValue
FROM TABLENAME MP
INNER JOIN (
SELECT ClientID, DesiredValue, ROW_NUMBER () OVER (PARTITION BY ClientID order by SequenceID desc) As RecentRN
FROM TABLENAME
) b
on MP.ClientID = b.ClientID AND b.RecentRN = 1
or
SELECT MP.ClientID, b.DesiredValue
FROM TABLENAME MP
INNER JOIN (
SELECT ClientID, DesiredValue,ROW_NUMBER () OVER (PARTITION BY ClientID order by SequenceID desc) As RecentRN
FROM TABLENAME
) b
on MP.ClientID = b.ClientID
Where b.RecentRN = 1
I created this simple database in SQL Server:
create database product_test
go
use product_test
go
create table product
(
id int identity primary key,
label varchar(255),
description text,
price money,
);
create table picture
(
id int identity primary key,
p_path text,
product int foreign key references product(id)
);
insert into product
values ('flip phone 100', 'back 2 the future stuff.', 950),
('flip phone 200', 's;g material', 1400)
insert into picture
values ('1.jpg', 1), ('2.jpg', 1), ('3.jpg', 2)
What I want is to select all products and only one picture for each product. Any help is greatly appreciated.
I'm a fan of outer apply for this purpose:
select p.*, pi.id, pi.path
from product p outer apply
(select top 1 pi.*
from picture pi
where pi.product = p.id
) pi;
You can include an order by to get one particular picture (say, the one with the lowest or highest id). Or, order by newid() to get a random one.
Have you tried using a correlated sub-query?
SELECT *, (SELECT TOP 1 p_path FROM picture WHERE product = p.id ORDER BY id)
FROM picture p
Hope this helps,
SELECT
*,
(
SELECT TOP 1 p2.p_path
FROM dbo.picture p2
WHERE p.id = p2.product
) AS picture
FROM dbo.product p
Or with join:
SELECT
*
FROM dbo.product p
INNER JOIN
(
SELECT p2.product, MIN(p2.p_path) AS p_path
FROM dbo.picture p2
GROUP BY p2.product
) AS pt
ON p.id = pt.product
But you need to change p_path to varchar type
I would use a windowing function like this:
SELECT *
FROM product
JOIN (
SELECT id, product, p_path,
row_number() OVER (PARTITION BY product ORDER BY id ASC) as RN
FROM picture
) pic ON product.id = pic.product AND pic.RN = 1
As you can see here I am selecting the picture with the lowest id (ORDER BY id ASC) -- you can change this order by to your requirements.
just group by and take min or max
left join in case there is no picture
select pr.ID, pr.label, pr.text, pr.price
, min(pic.p_path)
from product pr
left join picture pic
on pic.product = pr.ID
group by pr.ID, pr.label, pr.text, pr.price
I have 4 tables with the following structure:
Table artist:
artistID lastname firstname nationality dateofbirth datedcease
Table work:
workId title copy medium description artist ID
Table Trans:
TransactionID Date Acquired Acquistionprice datesold askingprice salesprice customerID workID
Table Customer:
customerID lastname Firstname street city state zippostalcode country areacode phonenumber email
First question is which artist has the most works of artsold and how many of the artist works have been sold.
My SQL query is this:
SELECT * From dtoohey.artist A1
INNER JOIN
(
SELECT COUNT(W1.ArtistID) AS COUNTER, artistID FROM dtoohey.trans T1
INNER JOIN dtoohey.work W1
ON W1.workid = T1.Workid
GROUP BY W1.artistID
) TEMP1
ON TEMP1.artistID = A1.artistID
WHERE A1.artistID = TEMP1.artistId
ORDER BY COUNTER desc;
I am to get the whole table but I only want show only the first row which is the highest count how do I do that??
I have tried inserting WHERE ROWNUM <=1 but it shows artist ID with 1
qns 2 is sales of which artist's work have resulted in the highest average profit (i.e) the average of the profits made on each sale of worksby an artist), and what is that amount.
My SQL query is:
SELECT A1.artistid, A1.firstname FROM
(
SELECT
(salesPrice - AcquisitionPrice) as profit,
w1.artistid as ArtistID
FROM dtoohey.trans T1
INNER JOIN dtoohey.WORK W1
on W1.workid = T1.workid
) TEMP1
INNER JOIN dtoohey.artist A1
ON A1.artistID = TEMP1.artistID
GROUP BY A1.artistid
HAVING MAX(PROFIT) = AVG(PROFIT);
I'm not able to execute it
I have tried query below but still not able to get it keep getting the error missing right parenthesis
SELECT A1.artistid, A1.firstname, TEMP1.avgProfit
FROM
(
SELECT
AVG(salesPrice - AcquisitionPrice) as avgProfit,
W1.artistid as artistid
FROM dtoohey.trans T1
INNER JOIN dtoohey.WORK W1
ON W1.workid = T1.workid
GROUP BY artistid
ORDER BY avgProfit DESC
LIMIT 1
) TEMP1
INNER JOIN dtoohey.artist A1
ON A1.artisid = TEMP1.artistid
Sometimes ORA-00907: missing right parenthesis means exactly that: we have a left bracket without a matching right one. But it can also be thrown by a syntax error in a part of a statement bounded by parentheses.
It's that second cause here: LIMIT is a Mysql command which Oracle does not recognise. You can use an analytic function here:
SELECT A1.artistid, A1.firstname, TEMP1.avgProfit
FROM
(
select artistid
, avgProfit
, rank() over (order by avgProfit desc) as rnk
from (
SELECT
AVG(salesPrice - AcquisitionPrice) as avgProfit,
W1.artistid as artistid
FROM dtoohey.trans T1
INNER JOIN dtoohey.WORK W1
ON W1.workid = T1.workid
GROUP BY artistid
)
) TEMP1
INNER JOIN dtoohey.artist A1
ON A1.artisid = TEMP1.artistid
where TEMP1.rnk = 1
This uses the RANK() function which will return more than one row if several artists achieve the same average profit. You might want to use ROW_NUMBER() instead. Analytic functions can be very powerful. Find out more.
You can apply ROWN_NUMBER(), RANK() and DENSE_RANK() to any top-n problem. You can use one of them to solve your first problem too.
"however the avg profit is null."
That's probably a data issue. If one of the numbers in (salesPrice - AcquisitionPrice) is null the result will be null, and won't be included in the average. If all the rows for an artist are null the AVG() will be null.
As it happens the sort order will put NULL last. But as the PARTITION BY clause sorts by AvgProfit desc that puts the NULL results at rank 1. The solution is to use the NULLS LAST in the windowing clause:
, rank() over (order by avgProfit desc nulls last) as rnk
This will guarantee you a non-null result at the top (providing at least one of your artists has values in both columns).
1st question - Oracle does not guarantee the order by which rows are retrieved. Hence you must first order and then limit the ordered set.
SELECT * from (
SELECT A1.* From dtoohey.artist A1
INNER JOIN
(
SELECT COUNT(W1.ArtistID) AS COUNTER, artistID FROM dtoohey.trans T1
INNER JOIN dtoohey.work W1
ON W1.workid = T1.Workid
GROUP BY W1.artistID
) TEMP1
ON TEMP1.artistID = A1.artistID
WHERE A1.artistID = TEMP1.artistId
ORDER BY COUNTER desc
) WHERE ROWNUM = 1
2nd question: I believe (haven't tested) that you have that LIMIT 1 wrong. That keyword is for use with Bulk collecting.
I'm sure this is a common request but I wouldn't know how to ask for it formally.
I encountered this a long time ago when I was in the Army. A soldier has multiple physical fitness tests but the primary test that counts in the most recent. The soldier also has multiple marksmanship qualifications but only the most recent qualification to the weapon assigned is significant.
How do you create a view that itemizes the most significant child of the parent?
Use:
SELECT p.*, x.*
FROM PARENT p
JOIN CHILD x ON x.parent_id = p.id
JOIN (SELECT c.id,
c.parent_id,
MAX(c.date_column) AS max_date
FROM CHILD c
GROUP BY c.id, c.parent_id) y ON y.id = x.id
AND y.parent_id = x.parent_id
AND y.max_date = x.date
Assuming SQL Server 2005+:
WITH summary AS (
SELECT p.*,
c.*,
ROW_NUMBER() OVER (PARTITION BY p.id
ORDER BY c.date DESC) AS rank
FROM PARENT p
JOIN CHILD c ON c.parent_id = p.id)
SELECT s.*
FROM summary s
WHERE s.rank = 1
Although I'm not quite sure what you are implying by "itemizing", you can do something like so:
Select ..
From Soldier
Left Join FitnessTest
On FitnessTest.SoldierId = Soldier.Id
And FitnessTest.TestDate = (
Select Max(FT1.TestDate)
From FitnessTest As FT1
Where FT1.SoldierId = FitnessTest.SoldierId
)
Left Join MarksmanshipTest
On MarksmanshipTest.SoldierId = Soldier.Id
And MarksmanshipTest.TestDate = (
Select Max(MT1.TestDate)
From MarksmanshipTest As MT1
Where MT1.SoldierId = MarksmanshipTest.SoldierId
)
This assumes that a solider cannot have two test datetime values for a fitness test or a marksmanship test.
No significant differnce from previous two answer but a little more detail perhaps:
create table soldier ( soldierId int primary key,
name varchar(100) )
create table fitnessTest ( soldierId int foreign key references soldier,
occurred datetime, result int )
create table marksmanshipTest ( soldierId int foreign key references soldier,
occurred datetime, result int )
;with
mostRecentFitnessTest as
(
select
fitnessTest.soldierId,
fitnessTest.result,
row_number() over (order by occurred desc) as row
from fitnessTest
),
mostRecentMarksmanshipTest as
(
select
marksmanshipTest.soldierId,
marksmanshipTest.result,
row_number() over (order by occurred desc) as row
from marksmanshipTest
)
select
soldier.soldierId,
soldier.name,
mostRecentFitnessTest.result,
mostRecentMarksmanshipTest.result
from soldier
left outer join mostRecentFitnessTest on
mostRecentFitnessTest.soldierId = soldier.soldierId
and mostRecentFitnessTest.row = 1
left outer join mostRecentMarksmanshipTest on
mostRecentMarksmanshipTest.soldierId = soldier.soldierId
and mostRecentMarksmanshipTest.row = 1