How can I add a sequential row number to a query that is using order by?
Let say I have a request in this form :
SELECT row_number() over(), data
FROM myTable
ORDER BY data
This will produce the desired result as rows are ordered by "data", but the row numbers are also ordered by data. I understand this is normal as my row number is generated before the order by, but how can I generate this row number after the order by?
I did try to use a subquery like this :
SELECT row_number() over(ORDER BY data), *
FROM
(
SELECT data
FROM myTable
ORDER BY data
) As t1
As shown here, but DB2 doesn't seem to support this syntax SELECT ..., * FROM
Thanks !
You also need to use alaias name before '*'
SELECT row_number() over(ORDER BY data), t1.*
FROM
(
SELECT data
FROM myTable
ORDER BY data
) As t1
You don't need a subquery to do this,
SELECT data , row_number() over(ORDER BY data) as rn
FROM myTable
ORDER BY data
Related
I have a table as shown in the image.In Number column, the values are appeared more than once (for example 63 appeared twice). I would like to keep only one value. Please see my code:
delete from t1 where
(SELECT *,row_number() OVER (
PARTITION BY
Number
ORDER BY
Date) as rn from t1 where rn > 1)
It shows error. Can anyone please assist.
enter image description here
The column created by row_number() was not accessed by your main query, in order to enable that, you can create a quick sub query and use the desired filter
SELECT *
FROM
(
SELECT *,
row_number() OVER (PARTITION BY Number ORDER BY Date) as rn
FROM t1 ) T
where rn = 1;
The partition by determines how row numbers repeat. The row numbers are assigned per group of partition by keys. So, you can get duplicates.
If you want a unique row number over all rows, just leave out the partition by:
select t1.*
from (select t1.*,
row_number() over (order by date) as rn
from t1
) t1
where rn > 1
if you want to keep only one value, rn = 1 instead of "> 1"
I have a table with multiple rows of the same member id. I need only distinct rows based on 2 unique columns
Ex: there are 100 different customers, the table has 1000 rows because every customer has multiple cities and segments assigned to him.
I need 100 distinct rows for these customers depending on a unique segment and city combination. There is no specific requirement for this combination, just the first from the table is fine.
So, currently the table is somewhat like this,
Hope this helps.
use row_number()
select * from (select *,row_number() over(partition by memberid order by sales) rn
from table_name
) a where a.rn=1
Handy sql-server top(1) with ties syntax for that
select top(1) with ties t.*
from table_name t
order by row_number() over(partition by memberid order by sales)
As you have no paticular requirement for which exactly row to select, any column will do at order by, it can be null as well
select top(1) with ties t.*
from table_name t
order by row_number() over(partition by memberid order by (select null))
The simplest way to do this is to use the ROW_NUMBER() OVER(GROUP BY...) syntax. You have no need to use an order by, since you want an arbitrary row, but only one, for each member.
Since you need only the expected data, and not the Row_Number value, make sure that you detail the fields returned, like below:
SELECT
MemberId,
city,
segment,
sales
FROM (
SELECT *
ROW_NUMBER() OVER (GROUP BY MemberId) as Seq
FROM [Status]
) src
WHERE Seq = 1
how to add to the query max(o.Acct)-1 rows. I need to visualize the last two o.Acct rows. My query is currently showing only the max(o.Acct)
SELECT Max(o.Acct) AS [MaxAcct],o.ObjectID,o.Opertype
FROM Operations o
GROUP By o.ObjectID,o.Opertype
If you want to see the last two rows (per group), you're better off using ROW_NUMBER() rather than GROUP BY.
SELECT
*
FROM
(
SELECT
*,
ROW_NUMBER() OVER (PARTITION BY ObjectID,
Opertype
ORDER BY Acct DESC
)
AS sequence_id
FROM
Operations
)
sortedOperations
WHERE
sequence_id <= 2
ORDER BY
ObjectID,
Opertype,
Acct
If you want the last two of something, I'm thinking order by and top. Something like this:
select top (2) o.*
from Operations o
order by o.acct desc;
I have a set of SQL Stored procedure to use partitioning for my ranking to get percentile. by doing the below partitioning I am able to get my percentiles data right. However my problem is there are duplicates in each row. E.g for each DESC there are multiple duplicates when it is suppose to be only 1 row. Why is this so?
row_nums AS
(
SELECT DATE, DESC, NUM, ROW_NUMBER() OVER (PARTITION BY DATE, DESC ORDER BY NUM ASC) AS Row_Num
FROM ******
)
SELECT .................
This is the output I get currently: (Where there are duplicate rows being returned - Refer to Row 6 to 8)
http://i.stack.imgur.com/foe7g.png[^]
This is the output I want to achieve: http://i.stack.imgur.com/GkrHP.png[^]
You can remove duplicate by adding one more INNER query in FROM clause like below:
;WTIH row_nums AS
(
SELECT DATE, DESC, NUM, ROW_NUMBER() OVER (PARTITION BY DATE, DESC ORDER BY NUM ASC) AS Row_Num
FROM (
SELECT your required columns, COUNT(duplicated_rows_columnsname)
FROM ***
GROUP BY columnnames
HAVING COUNT(duplicated_rows_columnsname) = 1
)
)
SELECT .................
However, You can also remove duplicate row using DISTINCT clause in INNER. query.
I am having a select statement that generates the following output.
If you look the output there are few rows that generates duplicate AdjusterIds.
What i need is to get the FIRST ROW ONLY for repeated ids along with other rows.
I tried several Group By, Distinct etc but no luck.
Please note that there are several columns that i just omitted for simplicity.
You can use a CTE + ROW_NUMBER:
WITH CTE AS
(
SELECT t.*, RN = ROW_NUMBER() OVER (PARTITION BY AdjusterIds
ORDER BY AdjusterIds)
FROM dbo.TableName t
)
SELECT * FROM CTE WHERE RN = 1