Split data from 2 symbols - sql

Question

have table
CREATE TABLE #tbl
(
id int identity(1,1),
obj_type int ,
obj_id nvarchar(50)
)
have data like : 153:0|114:0|147:0|148:0|152:0|155:0
want insert which data ise before " : " to obj_id , which data is next to " : " insert tu obj_type. it's must be like
id obj_type obj_id
1 0 153
2 0 114
3 0 147
4 0 148
5 0 152
6 0 155
How do it in stored procedure ? not function

Answer 1

declare #S varchar(100) = '153:0|114:0|147:0|148:0|152:0|155:0'
declare #xml xml
select #xml = '<item><value>'+replace(replace(#s, ':','</value><value>'), '|','</value></item><item><value>')+'</value></item>'
select N.value('value[1]', 'int') as obj_id,
N.value('value[2]', 'int') as obj_type
from #xml.nodes('item') as T(N)
SQL Fiddle

Answer 2

You can wait for some experts answer
till then you can give it one chance
insert into #tbl
SELECT LEFT(splitdata, CHARINDEX(':', splitdata) - 1) AS obj_id,
RIGHT(splitdata, CHARINDEX(':', REVERSE(splitdata)) - 1) AS obj_type from (select splitdatafrom fnSplitString(parameterName,'|')
now you can write stringsplit function like this
CREATE FUNCTION [dbo].[fnSplitString]
(
#string NVARCHAR(MAX),
#delimiter CHAR(1)
)
RETURNS #output TABLE(splitdata NVARCHAR(MAX)
)
BEGIN
DECLARE #start INT, #end INT
SELECT #start = 1, #end = CHARINDEX(#delimiter, #string)
WHILE #start < LEN(#string) + 1 BEGIN
IF #end = 0
SET #end = LEN(#string) + 1
INSERT INTO #output (splitdata)
VALUES(SUBSTRING(#string, #start, #end - #start))
SET #start = #end + 1
SET #end = CHARINDEX(#delimiter, #string, #start)
END
RETURN
END

Answer 3

Another Solution :
Create FUNCTION [dbo].[SplitString]
(
#List NVARCHAR(MAX),
#Delim VARCHAR(255)
)
RETURNS TABLE
AS
RETURN ( SELECT [Value] FROM
(
SELECT
[Value] = LTRIM(RTRIM(SUBSTRING(#List, [Number],
CHARINDEX(#Delim, #List + #Delim, [Number]) - [Number])))
FROM (SELECT Number = ROW_NUMBER() OVER (ORDER BY name)
FROM sys.all_objects) AS x
WHERE Number <= LEN(#List)
AND SUBSTRING(#Delim + #List, [Number], LEN(#Delim)) = #Delim
) AS y
);
taken form: T-SQL split string
And then select the values:
Declare
#Text varchar (100) = '153:0|114:0|147:0|148:0|152:0|155:0',
#Delim varchar(50) = ':0|'
select case when CHARINDEX(':0', Value) > 0 then Left(Value, Len(Value)-2) else Value End AS Result from dbo.SplitString(#Text, #Delim)

Answer 4

CREATE procedure [dbo].[Insert_procedure]
#inputString varchar(max)
AS
BEGIN
set #inputString ='2153:770|114:0|147:0|148:0|152:0|155:0' Declare #delimiter char(1) = '|' Declare #delimiter_Colon char(1) = ':'
DECLARE #chIndex int DECLARE #chIndex1 int DECLARE #item varchar(100)Declare #ReverseString varchar(max)
SELECT #ReverseString = Reverse(substring(reverse(#inputString), 1, 1))
IF(#ReverseString <> '|')
set #inputString = #inputString +'|'
WHILE CHARINDEX(#delimiter, #inputString, 0) <> 0
BEGIN
SET #chIndex = CHARINDEX(#delimiter, #inputString, 0)
SELECT #item = SUBSTRING(#inputString, 1, #chIndex - 1)
IF LEN(#item) > 0
BEGIN
set #chIndex1 = CHARINDEX(#delimiter_Colon, #item, 0)
Declare #obj_type int Declare #obj_id varchar(50)
SELECT #obj_id = SUBSTRING(#item, #chIndex1+1,len(#item)) SELECT #obj_type = SUBSTRING(#item,1,#chIndex1-1)
Insert into TEST(obj_type,obj_id) values (#obj_type,#obj_id)
END
SELECT #inputString = SUBSTRING(#inputString, #chIndex + 1, LEN(#inputString))
END
END