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I am calculating how many zeros appear in a series of columns based on a ID.
Example Table:
ID hour1 hour2 hour3
1 2 10 0
2 0 0 0
3 0 24 0
I think it would look something like this, but obviously it doesn't work
SELECT ID, COUNT(CASE WHEN(
FROM (VALUES (hour1) , (hour2) , (hour3))
AS VALUE (v)) AS ZERO_HOURS
Desired output:
ID ZERO_HOURS
1 1
2 3
3 2
One method is:
select t.id, h.num_zeros
from t cross apply
(select count(*) as num_zeros
from (values (hour1), (hour2), (hour3)) v(h)
where h = 0
) h;
Of course a case expression is not so hard either:
select t.id,
(case when hour1 = 0 then 1 else 0 end +
case when hour2 = 0 then 1 else 0 end
case when hour3 = 0 then 1 else 0 end
) as num_zeros
Or, if there are no negative or NULL values:
select t.id,
(1 - sign(hour1)) + (1 - sign(hour2)) + (1 - sign(hour3)) as num_zeros
Please try the following solution.
SQL
-- DDL and sample data population, start
DECLARE #tbl TABLE (ID INT IDENTITY PRIMARY KEY, hour1 INT, hour2 INT, hour3 INT);
INSERT INTO #tbl (hour1, hour2, hour3) VALUES
(2, 10, 0),
(0, 0 , 0),
(0, 24, 0);
-- DDL and sample data population, end
SELECT ID
, c.value('count(/root/*[./text()="0"])','INT') AS ZERO_HOURS
FROM #tbl
CROSS APPLY (
SELECT hour1, hour2, hour3
FOR XML PATH(''), TYPE, ROOT('root')) AS t(c);
Output
+----+------------+
| ID | ZERO_HOURS |
+----+------------+
| 1 | 1 |
| 2 | 3 |
| 3 | 2 |
+----+------------+
I have the following data:
ID Days
----------------------- --------
1 5
1 10
1 15
2 5
2 13
2 15
I am trying to build out a range of numbers based on the days while grouping by their ID.
For ID Group 1: The range would start at 5 and end at 9. The next range would be 10-14, and then the final range would be 15-9999
For ID Group 2: The range would start at 5 and end at 12. The next range would be 13-14, and then the final range would be 15-9999
The resulting table would look something like this:
RangeStart RangeEnd RangeText ID
----------- ----------- --------- ----
5 9 5 - 9 1
10 14 10 - 14 1
15 9999 15 - 9999 1
5 12 5 - 12 2
13 14 13 - 14 2
15 9999 15 - 9999 2
I have attempted to use a CTE which works but only when I am not grouping by ID's.
Declare #RangeTable Table
(
ID Int,
RangeStart INT,
RangeEnd INT,
RangeText Varchar(50),
);with CTE as (
SELECT temp.Days,
rn = ROW_NUMBER() over(order by temp.Days asc),
temp.ID
FROM #TableWithDays temp)
INSERT #RangeTable
SELECT
ID= d1.ID,
RangeStart= ISNULL(d1.Days, 0),
RangeEnd = ISNULL(d2.Days- 1, 9999),
RangeText =
CASE WHEN (d1.Days = d2.Days - 1)
THEN CAST(d1.Days AS VARCHAR(100))
ELSE
ISNULL(CAST(d1.Days AS VARCHAR(100)),'0') + ISNULL(' - '+
CAST(d2.Days - 1 AS VARCHAR(100)),' - 9999')END
FROM
CTE d1 LEFT JOIN
CTE d2
ON d1.rn = d2.rn - 1
You can use a recursive CTE. This would be simpler with lead(), but that is not available. So:
with t as (
select t.*, t2.days as next_days
from #TableWithDays t outer apply
(select top (1) t2.*
from #TableWithDays t2
where t2.id = t.id and t2.days > t.days
order by t2.days desc
) t2
),
cte as (
select t.id, t.days, t.next_days
from t
union all
select cte.id, cte.days + 1, cte.next_days
from cte
where cte.days < cte.next_days or
(cte.days < 9999 and cte.next_days is null)
)
select *
from cte
with option (maxrecursion 0);
I want to split a string at each character and display each of them in a separate row. I also need an extra column (Col2) which should display whether the character is a number or not (if number, then 1 else 0).
Example:
If the data is 'October 11, 2017', I should get
Col1 Col2
O 0
c 0
t 0
o 0
b 0
e 0
r 0
0
1 1
1 1
, 0
0
2 1
0 1
1 1
7 1
You can use this.
DECLARE #data VARCHAR(100) = 'October 11, 2017'
;WITH CTE AS
(
SELECT STUFF(#data,1,1,'') TXT, LEFT(#data,1) Col1
UNION ALL
SELECT STUFF(TXT,1,1,'') TXT, LEFT(TXT,1) Col1 FROM CTE
WHERE LEN(TXT) > 0
)
select Col1, ISNUMERIC(Col1) from CTE
Result:
Col1 Col2
---- -----------
O 0
c 0
t 0
o 0
b 0
e 0
r 0
0
1 1
1 1
, 1
0
2 1
0 1
1 1
7 1
Try this:
CREATE TABLE tbSeperate (Data NVARCHAR(100))
INSERT INTO tbSeperate SELECT 'October 11, 2017'
SELECT SUBSTRING(Data,Number,1) rt , CASE WHEN TRY_CAST(SUBSTRING(Data,Number,1) AS INT) IS NULL THEN 0
WHEN SUBSTRING(Data,Number,1) = ' ' THEN 0 ELSE 1 END c FROM tbSeperate
CROSS APPLY (SELECT DISTINCT number FROM master..spt_values WHERE number > 0 AND number <= LEN(Data))V
One method uses a recursive CTE:
with cte as (
select cast('October 11, 2017' as varchar(max)) as str,
cast(NULL as varchar(max)) as letter, 0 as lev
union all
select substring(str, 2, len(str)), left(str, 1), lev + 1
from cte
where str <> ''
)
select letter,
(case when letter between '0' and '9' then 1 else 0 end) as is_digit
from cte
where lev > 0;
If the string can have more than 99 characters, then you would want to use the maximum recursion option.
Here is a Rextester.
Using recursive CTE in MySQL we can achieve this.
following query will print the character of each string in different rows.
replace your table name and column name as per requirement.
WITH RECURSIVE cte
as
(
select 1 as n,1 as f,first_name ,'Temporary Variable' as name1 from customer
union
select (n+1) as n,f,first_name,substr(first_name,n,f) as name1 from cte
where substr(first_name,n,n)<>""
)
select n,name1,first_name from cte where n<>1 and first_name='KAREN'
Screenshot
I have results like this
TimeDiffMin | OrdersCount
10 | 2
12 | 5
09 | 6
20 | 15
27 | 11
I would like the following
TimeDiffMin | OrdersCount
05 | 0
10 | 8
15 | 5
20 | 15
25 | 0
30 | 11
So you can see that i want the grouping of every 5 minutes and show the total order count in those 5 minutes. eg. 0-5 minutes 0 orders, 5-10 minutes 8 orders
any help would be appreciated.
current query:
SELECT TimeDifferenceInMinutes, count(OrderId) NumberOfOrders FROM (
SELECT AO.OrderID, AO.OrderDate, AON.CreatedDate AS CancelledDate, DATEDIFF(minute, AO.OrderDate, AON.CreatedDate) AS TimeDifferenceInMinutes
FROM
(SELECT OrderID, OrderDate FROM AC_Orders) AO
JOIN
(SELECT OrderID, CreatedDate FROM AC_OrderNotes WHERE Comment LIKE '%has been cancelled.') AON
ON AO.OrderID = AON.OrderID
WHERE DATEDIFF(minute, AO.OrderDate, AON.CreatedDate) <= 100 AND AO.OrderDate >= '2016-12-01'
) AS Temp1
GROUP BY TimeDifferenceInMinutes
Now, if you are open to a TVF.
I use this UDF to create dynamic Date/Time Ranges. You supply the range and increment
Declare #YourTable table (TimeDiffMin int,OrdersCount int)
Insert Into #YourTable values
(10, 2),
(12, 5),
(09, 6),
(20,15),
(27,11)
Select TimeDiffMin = cast(R2 as int)
,OrdersCount = isnull(sum(OrdersCount),0)
From (Select R1=RetVal,R2=RetVal+5 From [dbo].[udf-Range-Number](0,25,5)) A
Left Join (
-- Your Complicated Query
Select * From #YourTable
) B on TimeDiffMin >= R1 and TimeDiffMin<R2
Group By R1,R2
Order By 1
Returns
TimeDiffMin OrdersCount
5 0
10 6
15 7
20 0
25 15
30 11
The UDF if interested
CREATE FUNCTION [dbo].[udf-Range-Number] (#R1 money,#R2 money,#Incr money)
Returns Table
Return (
with cte0(M) As (Select cast((#R2-#R1)/#Incr as int)),
cte1(N) As (Select 1 From (Values(1),(1),(1),(1),(1),(1),(1),(1),(1),(1)) N(N)),
cte2(N) As (Select Top (Select M from cte0) Row_Number() over (Order By (Select NULL)) From cte1 a,cte1 b,cte1 c,cte1 d,cte1 e,cte1 f,cte1 g,cte1 h )
Select RetSeq=1,RetVal=#R1 Union All Select N+1,(N*#Incr)+#R1
From cte2
)
-- Max 100 million observations
-- Select * from [dbo].[udf-Range-Number](0,4,0.25)
You can do this using a derived table to first build up your time difference windows and then joining from that to sum up all the Orders that fall within that window.
declare #t table(TimeDiffMin int
,OrdersCount int
);
insert into #t values
(10, 2)
,(12, 5)
,(09, 6)
,(20,15)
,(27,11);
declare #Increment int = 5; -- Set your desired time windows here.
with n(n)
as
( -- Select 10 rows to start with:
select n from(values(1),(1),(1),(1),(1),(1),(1),(1),(1),(1)) as n(n)
),n2 as
( -- CROSS APPLY these 10 rows to get 10*10=100 rows we can use to generate incrementing ROW_NUMBERs. Use more CROSS APPLYs to get more rows:
select (row_number() over (order by (select 1))-1) * #Increment as StartMin
,(row_number() over (order by (select 1))) * #Increment as EndMin
from n -- 10 rows
cross apply n n2 -- 100 rows
--cross apply n n3 -- 1000 rows
--cross apply n n4 -- 10000 rows
)
select m.EndMin as TimeDiffMin
,isnull(sum(t.OrdersCount),0) as OrdersCount
from n2 as m
left join #t t
on(t.TimeDiffMin >= m.StartMin
and t.TimeDiffMin < m.EndMin
)
where m.EndMin <= 30 -- Filter as required
group by m.EndMin
order by m.EndMin
Query result:
TimeDiffMin OrdersCount
5 0
10 6
15 7
20 0
25 15
30 11
Consider I have the following table.
ID value
1 100
2 200
3 200
5 250
6 1
I have the following query which gives the result as follows. I want to exclude the value 200 from rank function, but still that row has to be returned.
SELECT
CASE WHEN Value = 200 THEN 0
ELSE DENSE_RANK() OVER ( ORDER BY VALUE DESC)
END AS RANK,
ID,
VALUE
FROM #table
RANK ID VALUE
1 5 250
0 2 200
0 3 200
4 1 100
5 6 1
But I want the result as follows. How to achieve it?
RANK ID VALUE
1 5 250
0 2 200
0 3 200
2 1 100
3 6 1
If VAL column is not nullable, taking into account NULL is the last value in ORDER BY .. DESC
select *, dense_rank() over (order by nullif(val,200) desc) * case val when 200 then 0 else 1 end
from myTable
order by val desc;
There is no way to exclude Val in Dense Rank currently ,unless you filter in where clause..that is the reason ,you get below result
RANK ID VALUE
1 5 250
0 2 200
0 3 200
4 1 100
5 6 1
You will need to filter once and then do a union all
;with cte(id,val)
as
(
select 1, 100 union all
select 2, 200 union all
select 3, 200 union all
select 5, 250 union all
select 6, 1 )
select *, dense_rank() over (order by val desc)
from cte
where val<>200
union all
select 0,id,val from cte where val=200
You could split the ranking in to separate queries for the values you want to include/exclude from the ranking and UNION ALL the results like so:
Standalone executable example:
CREATE TABLE #temp ( [ID] INT, [value] INT );
INSERT INTO #temp
( [ID], [value] )
VALUES ( 1, 100 ),
( 2, 200 ),
( 3, 200 ),
( 5, 250 ),
( 6, 1 );
SELECT *
FROM ( SELECT 0 RANK ,
ID ,
value
FROM #temp
WHERE value = 200 -- set rank to 0 for value = 200
UNION ALL
SELECT DENSE_RANK() OVER ( ORDER BY value DESC ) AS RANK ,
ID ,
value
FROM #temp
WHERE value != 200 -- perform ranking on records != 200
) t
ORDER BY value DESC ,
t.ID
DROP TABLE #temp
Produces:
RANK ID value
1 5 250
0 2 200
0 3 200
2 1 100
3 6 1
You can modify the ordering at the end of the statement if required, I set it to produce your desired results.
You can also try this, too:
SELECT ISNULL(R, 0) AS Rank ,t.id ,t.value
FROM tbl1 AS t
LEFT JOIN ( SELECT id ,DENSE_RANK() OVER ( ORDER BY value DESC ) AS R
FROM dbo.tbl1 WHERE value <> 200
) AS K
ON t.id = K.id
ORDER BY t.value DESC
The solution in the original question was actually pretty close. Just adding a partition clause to the dense_rank can do the trick.
SELECT CASE
WHEN VALUE = 200 THEN 0
ELSE DENSE_RANK() OVER(
PARTITION BY CASE WHEN VALUE = 200 THEN 0 ELSE 1 END
ORDER BY VALUE DESC
)
END AS RANK
,ID
,VALUE
FROM #table
ORDER BY VALUE DESC;
The 'partition by' creates separate groups for the dense_rank such that the order is performed on these groups individually. This essentially means you create two ranks at the same time, one for the group without the 200 value and one for the group with only the 200 value. The latter one to be set to 0 in the 'case when'.
Standalone executable example:
DECLARE #table TABLE
(
ID INT NOT NULL PRIMARY KEY
,VALUE INT NULL
)
INSERT INTO #table
(
ID
,VALUE
)
SELECT 1, 100
UNION SELECT 2, 200
UNION SELECT 3, 200
UNION SELECT 5, 250
UNION SELECT 6, 1;
SELECT CASE
WHEN VALUE = 200 THEN 0
ELSE DENSE_RANK() OVER(
PARTITION BY CASE WHEN VALUE = 200 THEN 0 ELSE 1 END
ORDER BY VALUE DESC
)
END AS RANK
,ID
,VALUE
FROM #table
ORDER BY VALUE DESC;
RANK ID VALUE
1 5 250
0 2 200
0 3 200
2 1 100
3 6 1