Can anyone tell me how I can identify and switch to the iframe which has only a title?
<iframe frameborder="0" style="border: 0px none; width: 100%; height: 356px; min-width: 0px; min-height: 0px; overflow: auto;" dojoattachpoint="frame" title="Fill Quote" src="https://tssstrpms501.corp.trelleborg.com:12001/teamworks/process.lsw?zWorkflowState=1&zTaskId=4581&zResetContext=true&coachDebugTrace=none">
I have tried by below code but it is not working
driver.switchTo().frame(driver.findElement(By.tagName("iframe")));
driver.switchTo().frame() has multiple overloads.
driver.switchTo().frame(name_or_id)
Here your iframe doesn't have id or name, so not for you.
driver.switchTo().frame(index)
This is the last option to choose, because using index is not stable enough as you could imagine. If this is your only iframe in the page, try driver.switchTo().frame(0)
driver.switchTo().frame(iframe_element)
The most common one. You locate your iframe like other elements, then pass it into the method.
Here locating it by title attributes seems to be the best.
driver.switchTo().frame(driver.findElement(By.cssSelector("iframe[title='Fill Quote']")));
// driver.switchTo().frame(driver.findElement(By.xpath(".//iframe[#title='Fill Quote']")));
you can use cssSelector,
driver.switchTo().frame(driver.findElement(By.cssSelector("iframe[title='Fill Quote']")));
You also can use src to switch to frame, here is what you can use:
driver.switchTo().frame(driver.findElement(By.xpath(".//iframe[#src='https://tssstrpms501.corp.trelleborg.com:12001/teamworks/process.lsw?zWorkflowState=1&zTaskId=4581&zResetContext=true&coachDebugTrace=none']")));
Make sure you switch to default content before switching to frame:
driver.switchTo().defaultContent();
driver.switchTo().frame(x);
x can be the frame number or you can do a driver.findlement and use any of the options you have available eg: driver.findElementByName("Name").
1) goto html view
2) type iframe and find your required frame and count the value and switch to it using
oASelFW.driver.switchTo().frame(2);
if it is first frame then use oASelFW.driver.switchTo().frame(0);
if it is second frame then use oASelFW.driver.switchTo().frame(1); respectively
You can use Css Selector or Xpath:
Approach 1 : CSS Selector
driver.switchTo().frame(driver.findElement(By.cssSelector("iframe[title='Fill Quote']")));
Approach 2 : Xpath
driver.switchTo().frame(driver.findElement(By.xpath("//iframe[#title='Fill Quote']")));
https://seleniumatfingertips.wordpress.com/2016/07/05/handling-frames-in-selenium-webdriver-with-java/
Easiest way of doing this is like this. If its a frame you can right click on the field and if you see the choice of "open frame in a tab" do it.
Then take the URL of the frame and that is what you put in your Python script using "driver.get (http://blah blah..)
Then Selenium can find your named element. This saved me hours of trying all the suggestions here which was learning about but didn't work. Problem with mine was it was in a frame.
I'm using Linux which gives me the right-click option of opening the frame, on its own, in another tab. I don't use Windows so don't know if you would get that option in you right-click menu.
Ganzarola
I struggled with this for a while; a particularly frustrating website had several nested frames throughout the site. I couldn't find any way to identify the frames- no name, id, xpath, css selector- nothing.
Eventually I realised that frames are numbered with the top level being frame(0) the second frame(1) etc.
As I still didn't know which frame the element I needed was sitting in, I wrote a for loop to start from 0 and cycle to 50 continually moving to the next frame and attempting to access my required element; if it failed I got it to print a message and continue.
Spent too much time on this problem for such a simple solution -_-
driver.switch_to.default_content()
for x in range(50):
try:
driver.switch_to.frame(x)
driver.find_element_by_xpath("//*[#id='23']").click()
driver.find_element_by_xpath("/html/body/form/table/tbody/tr[1]/td/ul/li[49]/a").click()
except:
print("It's not: ", x)
continue
There are three ways to switch to the frame
1)Can use id
2)Can use name of the frame
3)Can use WebElement of the frame
2->driver.switchTo().frame("name of the frame");
I think I can add something here.
Situation I faced
I cannot or not easily use the debug tools or inspection tools like firebug to see which frame I am currently at and want to go to.
The XPATH/CSS selector etc. that the inspection tool told me doesn't work since the current frame is not the target one. e.g. I need to first switch to a sub-frame to be able to access/locate the element from XPATH or any other reference.
In short, the find_element() or find_elements() method doesn't apply in my case.
Wait Wait! not exactly
unless we use some fazzy search method.
use find_elements() with contains(#id,"frame") to filter out the potential frames.
e.g.
driver.find_elements(By.XPATH,'//*[contains(#id,"frame")]')
Then use switchTo() to switch to that frame and hopefully the underlying XPATH for your target element can be accessed this time.
If you're similar unlucky like me, iteration might need to be done for the found frames and even iterate deeper in more layers.
e.g.
This is the piece I use.
try:
elf1 = mydriver.find_elements(By.XPATH,'//*[contains(#id,"rame")]')
mydriver.switch_to_frame(elf1[1])
elf2 = mydriver.find_elements(By.XPATH,'//*[contains(#id,"rame")]')
mydriver.switch_to_frame(elf2[2])
len(mydriver.page_source) ## size of source tell whether I am in the right frame
I try out different switch_to_frame(elf1[x])/switch_to_frame(elf2[x]) combinations and finally found the wanted element by the XPATH I found from the inspection tool in browser.
try:
element = WebDriverWait(mydriver, 10).until(
EC.presence_of_element_located((By.XPATH, '//*[#id="C4_W16_V17_ZSRV-HOME"]'))
)
#Click the link
element.click()
I could solve that with the following code
browser.switch_to.frame(browser.find_element_by_tag_name('iframe'))
Related
Below in my code
driver.switchTo().frame(driver.findElement(By.id("file")));
Above line is not running
There is various way to switch to frame. Please share the HTML code if you need a exact code to switch to your respective application. you can try with below method. Better use index if your frame do not any name etc
driver.switchTo().frame(index)
replace index with 0 first and if it not work then try with 1 and then 2 etc one by one
More details
driver.switchTo().frame() has multiple overloads.
driver.switchTo().frame(name or id)
Here your iframe doesn't have id or name, so not for you.
driver.switchTo().frame(index)
This is the last option to choose, because using index is not stable enough as you could imagine. If this is your only iframe in the page, try
driver.switchTo().frame(0)
driver.switchTo().frame(iframe_element)
The most common one. You locate your iframe like other elements, then pass it into the method.
Here locating it by title attributes seems to be the best.
driver.switchTo().frame(driver.findElement(By.cssSelector("iframe[title='Fill Quote']")));
// driver.switchTo().frame(driver.findElement(By.xpath(".//iframe[#title='Fill Quote']")));
most probably, your iframe is not visible or your window is not active.
in Python:
driver.switch_to_default_content()
wait.until(EC.frame_to_be_available_and_switch_to_it("yourFrame"))
in Java:
driver.switchTo().defaultContent();
wait.until(ExpectedConditions.frameToBeAvailableAndSwitchToIt(By.tagName("yourFrame")));
I have a td element with ID like "a:2:3:d:", and when i want to select it by id, my webdriver can not find it. Is there a way to search by part of ID, because I think, that the problem is at last ":" in the identifier.
First, you need to confirm that this really is the problem, and it's not just that the page isn't fully loaded, or is loaded asynchronously. I don't see any particular reason why Selenium should care about the trailing ":".
Update: From the comments, it's much more likely that the dynamic id that is the problem, but the solution is the same either way:
To find an element by partial id, you can use xpath. If you were trying to find a div by partial id, for example:
//div[contains(#id, 'a:2:3')]
You don't say what language you are using, but in python, this would be used as follows:
driver.find_element_by_xpath("//div[contains(#id, 'a:2:3')]")
and in Java:
driver.findElement(By.xpath("//div[contains(#id, 'a:2:3')]"))
Assuming you are using Java
WebElement el = driver.findElement(By.cssSelector("td[id*='a:2:3']"));
The above code gets the element of TD which starts with a:2:3 as we use * in the css Selector.
XPath is more powerful and can be sometimes difficult to understand. CSS Selector is easy.
I am using the selenium getAttribute("style") method on the following id element:-
<div id="ntsDiv_1" style="width: 250px; text-align: left; white-space: normal; top: 1090px; left: 131px; visibility: hidden;" class="mlt-pop-container">
but the API is returning only the half of the value. It is returning width: 250px; text-align: left; white-space: normal; and the remaning portion of the style is clipped.
I'm trying to extract the value of the visibility, but the method is not returning the complete value of style. Hence, i am unable to determine the correct value of visibility.
I executed System.out.println("Style is:- "+super.getElement(NEXTAG_STORES_DIV).getAttribute("style"));
NEXTAG_STORES_DIV corresponds to the xpath of the id element, and super.getElement extracts element by xpath
Please help me out!!
I just tried this with Selenium 2.30.0 and it works fine, the whole attribute is returned.
Try the following things (all the examples assume element is the WebElement you need to test):
Make really sure only a part of the attribute is returned. Aren't you just printing it into console? Many consoles have a limited line length. Try setting your console to show long lines. Check programatically the length of the returned value, or try evaluating
element.getAttribute("style").contains("visibility")
Try upgrading your Selenium library, if you can. I am not aware of any bug related to attribute getting, but there might have been some which is now (with version 2.30.0) solved.
Try it in a different browser / OS / architecture. If it works somewhere, you'll know it's an issue of a particular browser / driver / OS / architecture / whatever and you might be able to focus it down and either fix it or file a bug.
If you simply want to know whether an element is visible or not, the correct and generally preferred way is to call
element.isDisplayed()
This method takes care of all the rules you might need to inspect in order to determine whether it actually is visible or not.
If the style value changes dynamically on the page (i.e. it's not statically written in the source code of the page), WebDriver can't really see it as it doesn't pick up dynamic changes. Try accessing the value via JavaScript:
if (!driver instanceof JavascriptExecutor) {
throw new IllegalStateException("JavaScript not enabled for this driver!");
}
JavascriptExecutor js = (JavascriptExecutor)driver;
String styleAttribute = (String)js.executeScript("return arguments[0].style", element);
If you actually need to get the computed value of the CSS visibility attribute that is actually used by the browser and not the one in the style atribute (if there either isn't any or is somehow overridden), you need to use the JavaScript's getComputedStyle() method. One way (described by this article on quirksmode.org) is this:
var elem = arguments[0];
if (elem.currentStyle) {
var vis = elem.currentStyle['visibility'];
} else {
var vis = document.defaultView.getComputedStyle(elem, null).getPropertyValue('visibility');
}
return vis;
Again, this should be invoked via
String visibility = (String)js.executeScript(here_goes_the_whole_script, element);
I am getting different results for the same locator. For example
//table[#id='foo']
returns true when testing ElementPresent, but returns 0 for XpathCount. In Selenium v1.0.10 IDE the Find button highlights the correct element for both functions. Any ideas on what could be causing this?
Notes:
We have frames on the page EDIT: This is probably the problem. Bounty to verification.
There are many tables on the page, but only one with #id of "foo"
Firefox 3.6
Happens in both IDE and Java RC
Well, this is not a verification more of a non-verification.
I use Selenium to test a GUI with frames. To make isElementPresent and getXpathCount to work I always have to select a frame first with selectFrame (even to get isElementPresent to work correctly). By just opening an URL no frame at all seems to be selected.
This is what the HTML and corresponding selectFrame code looks like:
<frameset id="mainframeset"><frame name="nav" id="nav" src....
selenium.selectFrame("nav");
Use these XPath expressions:
boolean(//table[#id='foo'])
and
count(//table[#id='foo'])
In case there is a table element whose id attribute's value is "foo", then the first expression above should evalute to true() and the second expression above should evalute to a positive integer.
Not really a direct answer to the question, but a workaround if you are reading this and want to loop over the elements. Use isElementPresent in the for loop like this:
for(int i = 2; selenium.isElementPresent("//table[#id='foo']//tr["+i+"]"); i++)
{
selenium.getText("//table[#id='foo']//tr["+i+"]//td["+columnNum+"]");
}
Note that we start i at 2 since XPath is indexed from 1 and we want to skip the header
I'm doing some drag and drop js testing with selenium-client. It works (taking screengrabs before and after clearly show the elements to switch places), but I'm having trouble programatically asserting the change happened.
Am I mental, or can I not do something like:
selenium.assert_equal("css locator", "expected id of element")
which, in this case, would look something like:
selenium.assert_equal("css=li:nth-child(1)", "li#list_item_2")
Any tips on how to implement this would be great.
Thanks,
Adam
Edit: if I had selenium.get_element that would take a selector and return what it was, I could then perform the assertion in the next step.
i.e.
element = selenium.get_element("css=li:nth-child(1)")
assert_equal(element, "li#list_item_2")
(I think).
Your example won't work because you're comparing two strings that aren't equal. One way to assert that your element has moved would be to use isElementPreset as demonstrated below:
//before drag and drop
assertTrue(selenium.isElementPresent("css=#source li:nth-child(1)"));
assertFalse(selenium.isElementPresent("css=#target li:nth-child(1)"));
//drag and drop code here
...
//after drag and drop
assertTrue(selenium.isElementPresent("css=#target li:nth-child(1)"));
assertFalse(selenium.isElementPresent("css=#source li:nth-child(1)"));
This example uses the Java client API, but it should be easy to work out how to do it in your preferred client API. It will also depend heavily on your application, as the above will check that the element with id of 'target' has one child li element before the drag and drop, and none afterwards. If you have a snippet of your HTML source I might be able to prove a more robust example.