This question already has answers here:
How to get cumulative sum
(16 answers)
Closed 9 years ago.
i have the data in my table as follows,
+----+-----+
| ID | Qty |
+----+-----+
| 1 | 100 |
| 2 | 200 |
| 3 | 150 |
| 4 | 50 |
+----+-----+
i need the result as follows,
+----+-----+-------+
| ID | Qty | C.Qty |
+----+-----+-------+
| 1 | 100 | 100 |
| 2 | 200 | 300 |
| 3 | 150 | 450 |
| 4 | 50 | 500 |
+----+-----+-------+
the result of third column will be the sum of previous rows,
please any one help....
I would just use a subquery:
SELECT ID, Qty,
(SELECT SUM(Qty) FROM [My Table] b WHERE b.ID <= [My Table].ID) AS [Total Qty]
FROM [My Table]
Please try:
SELECT S1.ID, S1.Qty ,sum(S2.Qty) CUM_SUM
FROM YourTable S1 join YourTable S2
on S1.ID>=S2.ID
group by S1.ID, S1.Qty
ORDER BY S1.ID
SELECT ID, Qty,
SUM(Qty) OVER(ORDER BY ID
ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW)
AS C.QTY
FROM Table
try this:
select a.id,a.qty,sum(b.qty) as total_qty
from table a cross join table b
where b.id <= a.id
group by a.id,a.qty
order by a.id
demo
Related
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Join to only the "latest" record with t-sql
(7 answers)
Fetch the rows which have the Max value for a column for each distinct value of another column
(35 answers)
Closed 4 months ago.
I want to list all customer with the latest phone number and most recent customer type
the phone number and type of customers are changing periodically so I want the latest record only without getting old values based on the lastestupdate column
Customer:
+------------+--------------------+------------+
|latestUpdate| CustID | AddID | TypeID |
+------------+--------+-----------+-------------
| 2020-03-01 | 1 | 1 | 1 |
| 2020-04-07 | 2 | 2 | 2 |
| 2020-06-13 | 3 | 3 | 3 |
| 2020-03-29 | 4 | 4 | 4 |
| 2020-02-06 | 5 | 5 | 5 |
+------------+--------+------------+----------+
CustomerAddress:
+------------+--------+-----------+
|latestUpdate| AddID | Mobile |
+------------+--------+-----------+
| 2020-03-01 | 1 | 66666 |
| 2020-04-07 | 1 | 55555 |
| 2020-06-13 | 2 | 99999 |
| 2020-03-29 | 3 | 11111 |
| 2020-02-06 | 3 | 22222 |
+------------+--------+-----------+
CustomerType:
+------------+--------+-----------+
|latestUpdate| TypeId | TypeName |
+------------+--------+-----------+
| 2020-03-01 | 1 | First |
| 2020-04-07 | 1 | Second |
| 2020-06-13 | 3 | Third |
| 2020-03-29 | 4 | Fourth |
| 2020-02-06 | 5 | Fifth |
+------------+--------+-----------+
When I tried to join I am always getting duplicated customerID not only the latest record
I want to Display Customer.CustID and CustomerType.TypeName and CustomerAddress.Mobile
You need to make sub-queries for most recent customer type and latest phone number like this:
SELECT *
FROM (
SELECT latestUpdate, CustID, AddID, TypeID,
ROW_NUMBER() OVER (PARTITION BY CustID ORDER BY latestUpdate DESC) AS RowNumber
FROM Customer
) AS c
INNER JOIN (
SELECT latestUpdate, AddID, Mobile,
ROW_NUMBER() OVER (PARTITION BY AddId ORDER BU ltestUpdate DESC) AS RowNumber
FROM CustomerAddress
) AS t
ON c.AddId = t.AddId
INNER JOIN CustomerType ct
ON ct.TypeId = c.TypeId
WHERE c.RowNumber = 1
AND t.RowNumber = 1
A simpler way than using row_number would be using cross apply together with top 1 in an ordered subquery:
select c.CustId, p.Mobile
from Customer c
cross apply (
select top 1 Mobile
from CustomerAddress a
where c.CustId = a.AddId
order by a.latestUpdate
) p
You need to use some subqueries :
SELECT *
FROM Customer AS C
LETF OUTER JOIN (SELECT *, ROW_NUMBER() OVER(PARTITION BY CustID ORDER BY LastestUpdate DESC) AS N
FROM CustomerAddress) AS A
ON C.CustID = A.CustID AND N = 1
LETF OUTER JOIN (SELECT *, ROW_NUMBER() OVER(PARTITION BY CustID ORDER BY LastestUpdate DESC) AS N
FROM CustomerType) AS T
ON C.CustID = T.CustID AND N = 1
If you have had used Temporal table which is an ISO SQL Standard feature for data history of table, you will always have the lastest rows inside the main table, old rows stays into history table and can be queried with a time point or date interval restriction.
This is it:
select * from (select *,RANK() OVER (
PARTITION BY b.AddID
ORDER BY b.latestUpdate DESC,
) as rank1
from
Customer a
left join
CustomerAddress b
on
a.AddID=b.AddID
left join
CustomerType c
on
v.TypeId =c.TypeId
) where rank1=1;
You should join the tables using the "APPLY" operator.
See: Link
I have a sales table with the following columns. I want to select the rows where sale price is increasing and skip those decrease sale price in which the sale price of above row is increase.
e.g. in the following table, I would like to have all rows except row having saleid=4
+--------+--------+-----------+
| SaleId | ItemId | SalePrice |
+--------+--------+-----------+
| 1 | 987 | 12 |
+--------+--------+-----------+
| 2 | 678 | 13 |
+--------+--------+-----------+
| 3 | 987 | 15 |
+--------+--------+-----------+
| 4 | 542 | 11 |
+--------+--------+-----------+
| 5 | 678 | 16 |
+--------+--------+-----------+
I have tried using inner join. But it shows nothing.
Here is the query I have wrote:
select s1.* from saletable s1
join saletable s2 on s1.saleid = s2.saleid
where s1.saleprice<s2.saleprice
Consider the following solution using running max
select t.*
from
(
select *, max(SalePrice) over (order by SaleId) runningMaxSalePrice
from testdata
) t
where t.SalePrice >= t.runningMaxSalePrice
This solution skips more than one consecutive row with decreasing SalePrice.
DBFdiddle DEMO
Use lag():
select st.*
from (select st.*, lag(saleprice) over (order by saleid ) as prev_saleprice
from saletable st
) st
where prev_saleprice is null or saleprice > prev_saleprice
Given a table A has the following data:
+----------+-------+
| Supplier | buyer |
+----------+-------+
| A | 1 |
| A | 2 |
| B | 3 |
| B | 4 |
| B | 5 |
+----------+-------+
My question is, can I transpose the second column so the resultant table will be like:
+----------+--------+--------+--------+
| Supplier | buyer1 | buyer2 | buyer3 |
+----------+--------+--------+--------+
| A | 1 | 2 | |
| B | 3 | 4 | 5 |
+----------+--------+--------+--------+
Assuming the maximum number of buyers is known as three.
You could use a common table expression to give each buyer an order within the supplier, and then just do a regular case to put them in columns;
WITH cte AS (
SELECT supplier, buyer,
ROW_NUMBER() OVER (PARTITION BY supplier ORDER BY buyer) rn
FROM Table1
)
SELECT supplier,
MAX(CASE WHEN rn=1 THEN buyer END) buyer1,
MAX(CASE WHEN rn=2 THEN buyer END) buyer2,
MAX(CASE WHEN rn=3 THEN buyer END) buyer3
FROM cte
GROUP BY supplier;
An SQLfiddle to test with.
You may consider using PIVOT clause:
select *
from (
select supplier, buyer, row_number() over (partition by supplier order by buyer) as seq
from a
)
pivot (max(buyer) for seq in (1 as buyer1, 2 as buyer2, 3 as buyer3));
SQLFiddle here.
I have two tables , A and B
Table A contains:
OrderNo | StyleNo | Qty
O-20 | S-15 | 20
O-20 | S-18 | 40
O-25 | S-19 | 50
Table B contains:
OrderNo | StyleNo | Ship Qty
O-20 | S-15 | 5
O-20 | S-18 | 30
O-20 | S-15 | 12
O-20 | S-18 | 6
Result Requires
OrderNo | StyleNo | Qty | Ship Qty
O-20 | S-15 | 20 | 17
O-20 | S-18 | 40 | 36
O-25 | S-19 | 50 | 0
The following query is not working
select
B.Orderno, B.StyleNo, sum(A.Qty), sum(B.QtyShip)
from
A
inner join
B on A.OrderNo = B.OrderNo and A.StyleNo = B.StyleNo
group by
B.OrderNo, B.StyleNo
The issue you're having is that it's summing the qty field multiple times. Move the sums to subqueries and use a join on those:
select a.orderno, a.styleno, a.qty, b.qtyship
from (
select orderno, styleno, sum(qty) qty
from a
group by orderno, styleno
) a
join (
select orderno, styleno, sum(qtyship) qtyship
from b
group by orderno, styleno
) b on a.orderno = b.orderno and a.styleno = b.styleno
SQL Fiddle Demo
Here's a sample database table :
| ID | ProductID | DateChanged | Price
| 1 | 12 | 2011-11-11 | 93
| 2 | 2 | 2011-11-12 | 12
| 3 | 3 | 2011-11-13 | 25
| 4 | 4 | 2011-11-14 | 17
| 5 | 12 | 2011-11-15 | 97
Basically, what I want to happen is get the latest price of grouped by ProductID.
The result should be like this :
| ID | ProductID | Price
| 2 | 2 | 12
| 3 | 3 | 25
| 4 | 4 | 17
| 5 | 12 | 97
If you notice, the first row is not there because there is a new price for ProductID 12 which is the row of ID 5.
Basically, it should be something like get ID,ProductID and Price grouped by productID where DateChanged is the latest.
SELECT ID, ProductId, Price
FROM
(
SELECT ID, ProductId, Price
, ROW_NUMBER() OVER (PARTITION BY ProductID ORDER BY DateChanged DESC) AS rowNumber
FROM yourTable
) AS t
WHERE t.rowNumber = 1
SELECT ID, ProductID,DateChanged, Price
FROM myTable
WHERE ID IN
(
SELECT MAX(ID)
FROM myTable
GROUP BY ProductID
)
select a.id, a.productid, a.price
from mytable a,
(select productid, max(datechanged) as maxdatechanged
from mytable
group by productid) as b
where a.productid = b.productid and a.datechanged = b.maxdatechanged
SELECT ID, ProductId, Price
from myTable A
where DateChanged >= all
(select DateChanged
from myTable B
where B.ID = A.ID);