Yield with delegate - vb.net

Question

Please see the code below:
Public Iterator Function Read(Of T)(ByVal sql As String, ByVal make As Func(Of IDataReader, T), ParamArray ByVal parms() As Object) As IEnumerable(Of T)
Using connection = CreateConnection()
Using command = CreateCommand(sql, connection, parms)
Using reader = command.ExecuteReader()
Do While reader.Read()
Yield make(reader) --line 7
Loop
End Using
End Using
End Using
End Function
Private Shared Make As Func(Of IDataReader, Member) =
Function(reader) _
New Member() With {
.MemberId = Extensions.AsId(reader("MemberId")),
.Email = Extensions.AsString(reader("Email")),
.CompanyName = Extensions.AsString(reader("CompanyName")),
.City = Extensions.AsString(reader("City")),
.Country = Extensions.AsString(reader("Country"))
}
Please see line 7. Make populates an object of type Member with values from the data reader row. I have read the following documentation: http://msdn.microsoft.com/en-us/library/9k7k7cf0.aspx. The documentation does not seem to explain what happens when you use a delegate i.e. Yield make(datareader), rather than Yield return datareader. Is control passed back to the calling function as well as the delegate (Make)?

Answer 1

Make(reader) is a shortcut for Make.Invoke(reader). I.e., you
invoke the delegate, passing reader as a parameter, which yields a value of type Member.
Then, you return that value using Yield.
It is equivalent to :
...
Do While reader.Read()
Dim myMember As Member = make(reader)
Yield myMember
Loop
...
PS: If you get a compile-time error in your code (you don't say so in your question): This is due to the fact that your method is declared to return an IEnumerable(Of T), when in fact it returns an IEnumerable(Of Member).