I need help with ms access query. My current group by is adding additional rows with my result sets.
currently it is this:
schoolsName organization city agent total organization_award city_award agent_award
John Boscoe 0 0 2 2 10000
John Boscoe 0 26 0 26 1000
John Boscoe 0 2 2 2 4000 100000
John Boscoe 18 0 0 18 10000
John Boscoe 3 3 0 3 5000 10000
my current sql query for ms access is:
SELECT
schools.schoolsName, Count(schools.[organization]) AS organization,
Count(schools.[city]) AS city, Count(schools.[agent]) AS agent,
Count(schools.schoolsName) AS total,
IIf((schools.[organization]) Like 'yes',Sum(schools.[dollaramount]),'') AS organization_award,
IIf((schools.[city]) Like 'yes',Sum(schools.[dollaramount]),'') AS city_award,
IIf((schools.[agent]) Like 'yes',Sum(schools.[dollaramount]),'') AS agent_award
FROM schools
GROUP BY schools.schoolsName, schools.[organization], schools.[city], schools.[agent];
how do i change the above query to get this result set:
schoolsName organization city agent total organization_award city_award agent_award
John Boscoe 21 31 4 51 15000 15000 110000
not sure about the count part, but did you try this?
SELECT schools.schoolsName,
Count(schools.[organization]) AS organization,
Count(schools.[city]) AS city,
Count(schools.[agent]) AS agent,
Count(schools.schoolsName) AS total,
Sum(IIf((schools.[organization]) Like 'yes', schools.[dollaramount],0)) AS organization_award,
Sum(IIf((schools.[city]) Like 'yes', schools.[dollaramount],0)) AS city_award,
Sum(IIf((schools.[agent]) Like 'yes', schools.[dollaramount],0)) AS agent_award
FROM schools
GROUP BY schools.schoolsName;
Related
I have a count of a top 2
My table has this data
Name Age price visited size
Jon 34 53 2018-01-01 9
Don 22 70 2018-03-01 15
Pete 76 12 2018-11-09 7
Jon 34 55 2018-09-13 9
Paul 90 64 2018-07-08 6
Pete 76 31 2018-03-25 7
Jon 75 34 2018-06-06 8
select top 2
name,
count(name) as cnt
from
tbl1
group by name
order by cnt desc
Which returns my top 2 names
Jon 3
Pete 2
This name will change dynamically as the query is run depending on who has made the most visits in total (this is very simplified the actual table has 1000's of entries).
What I would like to do is then use the result of that query to get the following all of which needs to be in a single query;
Name Age price visited size
Jon 34 53 2018-01-01 9
Jon 34 55 2018-09-13 9
Jon 75 34 2018-06-06 8
Pete 76 12 2018-11-09 7
Pete 76 31 2018-03-25 7
In summary, count who has visited the most and then display all the records under those names.
Thanks in advance
Here's one option using in:
select *
from yourtable
where name in (
select top 2 name
from yourtable
group by name
order by count(*) desc
)
order by name
Online Demo
I have a large 'scores' table that resembles the following:
quizid userid score high_score
1 john 50 0
1 bob 60 0
1 bob 65 0
1 steve 40 0
2 bob 20 0
2 bob 30 0
2 bob 15 0
current the 'high_score' column is '0' as it was just added. what I need to do is make a simple query to flag this column with a '1' for every instance where a user's score for each quiz is the highest one that user has for that quiz - i.e. after running the query I should have this:
quizid userid score high_score
1 john 50 1
1 bob 60 0
1 bob 65 1
1 steve 40 1
2 bob 20 0
2 bob 30 1
2 bob 15 0
Any help would be appreciated!
i'm not sure and i have not tested below code but try it maybe it help you
update scores set high_score=1 where (quizid,userid,score) in
(select quizid,userid,max(score) from scores group by quizid,userid)
The query I'm trying to answer is 'How many sales above or equal to 60 has each person made?'
My table (sales$):
SaleID name salevalue
1 Steve 100
2 John 50
3 Ellen 25
4 Steve 100
5 Mary 60
6 Mary 80
7 John 70
8 Mary 55
9 Steve 65
10 Ellen 120
11 Ellen 30
12 Ellen 40
13 John 40
14 Mary 60
15 Steve 50
My code is:
select name,
COUNT(*) as 'sales above 60'
from Sales$
group by salevalue, name
having salevalue >= 60;
Which gives:
Ellen 1
John 1
Mary 2
Mary 1
Steve 1
Steve 2
The information is correct in that Mary & Steve both have 3 sales, however I'm forced by the HAVING command to group them out.
Any ideas? I'm sure I've just taken a wrong turning.
You can use conditional aggregation for this:
select name,
COUNT(case when salevalue >= 60 then 1 end) as 'sales above 60'
from Sales$
group by name
This way COUNT will take into consideration only records having salevalue >= 60.
I've swapped the HAVING statement for a WHERE and achieved the desired result:
select name, count(*) 'sales above 50'
from sales$
where salevalue >=60
group by name
(Lightbulb moment after posting)
I thought this would be a very simple query but for some reason, I can't seem to get the results I'm looking for. I have a table that has this structure. I just want a single entry for each account while summing the charges. I don't really care which date I keep, just one of them.
Account Charges Charges2 Date
1 100 50 1/1/2015
1 50 0 1/2/2015
2 50 0 2/4/2015
2 70 30 2/19/2015
3 100 0 1/12/2014
4 0 20 4/3/2015
4 40 20 4/9/2015
The result I want is:
Account Charges Charges2 Date
1 150 50 1/1/2015
2 120 30 2/4/2015
3 100 0 1/12/2014
4 40 40 4/3/2015
The result I currently get is:
Account Charges Charges2 Date
1 100 50 1/1/2015
2 70 30 2/19/2015
3 100 0 1/12/2014
4 40 40 4/9/2015
I thought this would be very simple and I tried below. But this doesn't sum them up, it just seems to return the rows where Charges2 is NOT 0.
SELECT Account, SUM(Charges) As TotCharges, SUM(Charges2) AS TotCharges2
FROM TABLE
GROUP BY Account
ORDER BY Account
You can apply the min() aggregate function to the date to limit the number of rows returned to one per account:
SELECT
Account,
SUM(Charges) AS TotCharges,
SUM(Charges2) AS TotCharges2,
MIN(Date) AS Date
FROM TABLE
GROUP BY Account
ORDER BY Account
Sample SQL Fiddle
I need a query that shows the JobIDs where the Worker has not been paid BUT where the Company has been paid. Below are the table columns and sample data:
tblInvoices columns:
-------------------
JobID
InvoiceID
WorkerPaidAmountTotal
CompanyPaidAmountTotal
Sample data
-----------
JobID | InvoiceID | WorkerPaidAmountTotal | CompanyPaidAmountTotal
1 30 100 150
1 31 0 100
2 32 0 75
3 33 25 50
3 34 10 30
4 35 0 0
I know how to get the SUM of the amounts paid to either a Worker or the Company. The results look like this:
JobID Worker Company
1 100 250
2 0 75
3 35 80
4 0 0
But what I need are the results of just the JobIDs where the Worker has got 0 and the company >0. The results I want should be this, but I can't figure out the query to do so:
JobID Worker Company
2 0 75
Use HAVING clause to filter the groups. Try this :
SELECT jobid,
Worker=Sum(WorkerPaidAmountTotal),
Company=Sum(CompanyPaidAmountTotal)
FROM tablename
GROUP BY jobid
HAVING Sum(WorkerPaidAmountTotal) = 0
AND Sum(CompanyPaidAmountTotal) > 0
select jobid, worker, company where WorkerPaidAmountTotal = 0 and CompanyPaidAmountTotal
Seems to plain to do it... may be i did'nt understand the question