I have 2 tables, one which contains Revenue data and one which contains Account data - the account data contains multiple rows per account ... the Revenue value assigned against FactPlanNo 327865 is $65,000 which is what I want to show, however because there are 4 rows in the RefGPNRoleMapping table for this account, it is multiplying $65,000 by 4
How do I stop this from happening so it brings back the following result:
AccountNumber AccountName Rev
0123456 MyAccount 65000 (instead of 260,000)
I currently have this query:
select
b.AccountNumber,
b.AccountName,
sum(a.Revenue) as rev
from mdfl.FactPlanNo a
inner join xyz.RefGPNRoleMapping b on
a.FactPlanNo = b.FactPlanNo
where b.FactPlanNo = '327865'
group by b.AccountNumber, b.AccountName
/* Revenue per "FactPlanNo" */
SELECT FactPlanNo
, Sum(Revenue) As rev
FROM mdfl.FactPlanNo
GROUP
BY FactPlanNo
/* Make it a subquery and join to that! */
SELECT b.AccountNumber
, b.AccountName
, revenues.rev
FROM (
SELECT FactPlanNo
, Sum(Revenue) As rev
FROM mdfl.FactPlanNo
GROUP
BY FactPlanNo
) As revenues
LEFT
JOIN xyz.RefGPNRoleMapping As b
ON b.FactPlanNo = revenues.FactPlanNo
WHERE b.FactPlanNo = '327865'
Related
table structure
I need to get names (FIO) of all the people that purchased product a and product b in any given day (but must be 2 purchases in a day) in april, or any other specified month.
What I tried to do is
with
purchased_items as
(
select customer_key
from purchase p
join product pr
on p.product_key = pr.product_key
where pr.name in ('Teddy bear', 'LEGO')
AND p.date_sold BETWEEN '01.04.2019' AND '30.04.2019'
group by customer_key
having count(distinct p.product_key) = 2
)
select *
from customer c
where exists (
select *
from purchased_items pui
where c.customer_key = pui.customer_key
);
But that only gives clients that bought 2 items in a month (not a single day).
I also suspect that it can be done by querying for Date, Client_name (FIO), array_agg(product.Name /*group by date */ ) , but I am not sure how to implemet it.
Thank you in advance for any help !
EDIT: figured it out.
with a as (
SELECT c.FIO, p.date_sold, pr.Name
FROM customer c
JOIN purchase p ON c.customer_key = p.customer_key
JOIN product pr ON p.product_key = pr.product_key
Where p.date_sold BETWEEN '01.04.2019' AND '30.04.2019' and (pr.name like '%LEGO%' OR pr.name like '%Teddy bear%') ),
count_name as (
select fio, count(distinct Name) as count, date_sold
from a
group by date_sold, fio)
select DISTINCT FIO
from count_name
where count=2
Although it's probably very subotimal
Query
select
a.id,
a.ba,
b.status,
b.custid
from balist as a
inner join customer as b
on a.ba = b.ba
I have a table "balist" that has a list of (ba) and i inner join table "customer" on (ba) and right now by output is like the following
id
ba
status
custid
1
ba-1234455
A
123-321-123-321a
2
ba-1234455
I
123-321-123-321a
3
ba-1234457
A
123-321-123-321b
4
ba-1234458
A
123-321-123-321c
5
ba-1234459
I
123-321-123-321d
and I want to return all A and I status but remove the row that has status I that also have a A status. Like the following.
I have a table customer like the following
id
ba
status
custid
1
ba-1234455
A
123-321-123-321a
3
ba-1234457
A
123-321-123-321b
4
ba-1234458
A
123-321-123-321c
5
ba-1234459
I
123-321-123-321d
You could use a row_number() to filter your resulting rows eg
SELECT
id,ba,status,custid
FROM (
SELECT
a.id,
a.ba,
b.status,
b.custid,
ROW_NUMBER() OVER (
PARTITION BY a.ba
ORDER BY b.status ASC
) as rn
FROM
balist as a
INNER JOIN
customer as b ON a.ba = b.ba
)
WHERE rn=1
Let me know if this works for you.
I've got 2 tables, one with sales and one with companies:
Sales Table
Transaction_Id Shop_id Sale_date Client_ID
92356 24234 11.09.2018 12356
92345 32121 11.09.2018 32121
94323 24321 11.09.2018 21231
94278 45321 11.09.2018 42123
Company table
Client_ID Company_name
12345 ABC
13322 ABC
32321 BCD
22221 BCD
What I want to achieve is distinct count of Clients from each Company for each pair of shops(Clients who had at least 1 transaction in both of shops) :
Shop_Id_1 Shop_id_2 Company_name Count(distinct Client_id)
12356 12345 ABC 31
12345 14278 ABC 23
14323 12345 BCD 32
14278 12345 BCD 43
I think that I have to use self join, but my queries even with filter for one week is killing DB, any thoughts on that? I'm using Microsoft SQL server 2012.
Thanks
I think this is a self-join and aggregation, with a twist. The twist is that you want to include the company in each sales record, so it can be used in the self-join:
with sc as (
select s.*, c.company_name
from sales s join
companies c
on s.client_id = c.client_id
)
select sc1.shop_id, sc2.shop_id, sc1.company_name, count(distinct sc1.client_id)
from sc sc1 join
sc sc2
on sc1.client_id = sc2.client_id and
sc1.company_name = sc2.company_name
group by sc1.shop_id, sc2.shop_id, sc1.company_name;
I think there are some issues with your question. I interpreted it as such that the company table contains the shop ID's, not the ClienId's.
First you can create a solution to get the shops as rows for each company. Here I chose a maximum of 5 shops per company. Don't forget the semicolon in the previous statement before the cte's.
WITH CTE_Comp AS
(
SELECT *, ROW_NUMBER() OVER (PARTITION BY CompanyName ORDER BY ShopID) AS RowNumb
FROM Company AS C
)
SELECT C1.ShopID,
C2.ShopID AS ShopID_2,
C3.ShopID AS ShopID_3,
C4.ShopID AS ShopID_4,
C5.ShopID AS ShopID_5,
C1.CompanyName
INTO ShopsByCompany
FROM CTE_Comp AS C1
LEFT JOIN CTE_Comp AS C2 ON C1.CompanyName= C2.CompanyName AND RowNumb = 2
LEFT JOIN CTE_Comp AS C2 ON C1.CompanyName= C3.CompanyName AND RowNumb = 3
LEFT JOIN CTE_Comp AS C2 ON C1.CompanyName= C4.CompanyName AND RowNumb = 4
LEFT JOIN CTE_Comp AS C2 ON C1.CompanyName= C5.CompanyName AND RowNumb = 5
WHERE C1.RowNumb = 1
After that, in a few steps, I think you could get the desired result:
WITH ClientsPerShop AS
(
SELECT ShopID,
COUNT (DISTINCT ClientID) AS TotalClients
FROM Sales
GROUP BY ShopID
)
, ClienstsPerCompany AS
(
SELECT CompanyName,
SUM (TotalClients) AS ClientsPerComp
FROM Company AS C
INNER JOIN ClientsPerShop AS CPS ON C.ShopID = CPS.ShopID
GROUP BY CompanyName
)
SELECT *
FROM ClienstsPerCompany AS CPA
INNER JOIN ShopsByCompany AS SBC ON SBC.CompanyName = CPA.CompanyName
Hopefully this will bring you closer to your solution, best of luck!
I have 3 tables:
Person (with a column PersonKey)
Telephone (with columns Tel_NumberKey, Tel_Number, Tel_NumberType e.g. 1=home, 2=mobile)
xref_Person+Telephone (columns PersonKey, Tel_NumberKey, CreatedDate, ModifiedDate)
I'm looking to get the most recent (e.g. the highest Tel_NumberKey) from the xref_Person+Telephone for each Person and use that Tel_NumberKey to get the actual Tel_Number from the Telephone table.
The problem I am having is that I keep getting duplicates for the same Tel_NumberKey. I also need to be sure I get both the home and mobile from the Telephone table, which I've been looking to do via 2 individual joins for each Tel_NumberType - again getting duplicates.
Been trying the following but to no avail:
-- For HOME
SELECT
p.PersonKey, pn.Phone_Number, pn.Tel_NumberKey
FROM
Persons AS p
INNER JOIN
xref_Person+Telephone AS x ON p.PersonKey = x.PersonKey
INNER JOIN
Telephone AS pn ON x.Tel_NumberKey = pn.Tel_NumberKey
WHERE
pn.Tel_NumberType = 1 -- e.g. Home phone number
AND pn.Tel_NumberKey = (SELECT MAX(pn1.Tel_NumberKey) AS Tel_NumberKey
FROM Person AS p1
INNER JOIN xref_Person+Telephone AS x1 ON p1.PersonKey = x1.PersonKey
INNER JOIN Telephone AS pn1 ON x1.Tel_NumberKey = pn1.Tel_NumberKey
WHERE pn1.Tel_NumberType = 1
AND p1.PersonKey = p.PersonKey
AND pn1.Tel_Number = pn.Tel_Number)
ORDER BY
p.PersonKey
And have been looking over the following links but again keep getting duplicates.
SQL select max(date) and corresponding value
How can I SELECT rows with MAX(Column value), DISTINCT by another column in SQL?
SQL Server: SELECT only the rows with MAX(DATE)
Am sure this must be possible but been at this a couple of days and can't believe its that difficult to get the most recent / highest value when referencing 3 tables. Any help greatly appreciated.
select *
from
( SELECT p.PersonKey, pn.Phone_Number, pn.Tel_NumberKey
, row_number() over (partition by p.PersonKey, pn.Phone_Number order by pn.Tel_NumberKey desc) rn
FROM
Persons AS p
INNER JOIN
xref_Person+Telephone AS x ON p.PersonKey = x.PersonKey
INNER JOIN
Telephone AS pn ON x.Tel_NumberKey = pn.Tel_NumberKey
WHERE
pn.Tel_NumberType = 1
) tt
where tt.rn = 1
ORDER BY
tt.PersonKey
you have to use max() function and then you have to order by rownum in descending order like.
select f.empno
from(select max(empno) empno from emp e
group by rownum)f
order by rownum desc
It will give you all employees having highest employee number to lowest employee number. Now implement it with your case then let me know.
I have a table called BB_BOATBKG which holds passengers travel details with columns Z_ID, BK_KEY and PAXSUM where:
Z_ID = BookingNumber* LegNumber
BK_KEY = BookingNumber
PAXSUM = Total number passengers travelled in each leg for a particular booking
For Example:
Z_ID BK_KEY PAXSUM
001234*01 001234 2
001234*02 001234 3
001287*01 001287 5
001287*02 001287 5
002323*01 002323 7
002323*02 002323 6
I would like to get a list of all Booking Numbers BK_KEY from BB_BOATBKG where the total number of passengers PAXSUM is different in each leg for the same booking
Example, For Booking number A, A*Leg01 might have 2 Passengers, A* Leg02 might have 3 passengers
Dependent of your RDBMs there might be several options availible. A solution that should work for most is:
SELECT A.Z_ID, A.BK_KEY, A.PAXSUM
FROM BB_BOATBKG A
JOIN (
SELECT BK_KEY
FBB_BOATBKGROM BB_BBK_KEY
GROUP BY BK_KEY
HAVING COUNT( DISTINCT PAXSUM ) > 1
) B
ON A.BK_KEY = B.BK_KEY
If your DBMS support OLAP functions, have a look at RANK() OVER (...)
It's a little counterintuitive, but you could join the table to itself on {BK_KEY, PAXSUM} and pull out only the records whose joined result is null.
I think this does it:
SELECT
a.BK_KEY
FROM
BB_BOATBKG a
LEFT OUTER JOIN BB_BOATBKG b ON a.BK_KEY = b.BK_KEY AND a.PAXSUM = b.PAXSUM
WHERE
b.Z_ID IS NULL
GROUP BY
a.BK_KEY
Edit: I think I missed anything beyond the trivial case. I think you can do it with some really nasty subselecting though, a la:
SELECT
b.BK_KEY
FROM
(
SELECT
a.BK_KEY,
Count = COUNT(*)
FROM
(
SELECT
a.BK_KEY,
a.PAXSUM
FROM
BB_BOATBKG a
GROUP BY
a.BK_KEY,
a.PAXSUM
HAVING
COUNT(*) = 1
) a
GROUP BY
a.BK_KEY
) b
INNER JOIN
(
SELECT
c.BK_KEY,
Count = COUNT(*)
FROM
BB_BOATBKG c
GROUP BY
c.BK_KEY
) c ON b.BK_KEY = c.BK_KEY AND b.Count = c.Count